Lesson 02 class practices

31
Statistics 2 Dr. Ning DING IBS I.007 [email protected]

description

IBS students 2nd Year, Hanze University of Applied Science

Transcript of Lesson 02 class practices

Page 1: Lesson 02 class practices

Statistics 2Statistics 2

Dr. Ning DING

IBS I.007

[email protected]

Page 2: Lesson 02 class practices

Table of Content

1. Review of Chapter 5

2. Sampling Distribution

3. SPSS

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Quiz Answer

In 2003, 1.4 million students took the SATs. The mean of SAT score is 1026 and the standard deviation is 209.

a. What proportion of all students had SAT scores of less than 820?

b. What proportion of all students had SAT scores of more than 820?

z = (820-1026)/209 =-0.99

P=0.3389

P=0.5-0.3389=0.1611

P=0.5+0.3389=0.8389

Quiz

Review

Sampling Distribution

SPSS

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Quiz Answer

It was found that the probability of Americans spending their leisure time for two weeks is 0.45; one week is 0.10, and 0.20 for three or more weeks. Suppose we have surveyed 20 Americans,

a. What is the probability that 8 have 2 weeks of vacation of time?

b. What is the probability that only one American has one week of vacation time?

c. What is the probability that at most 2 of the workers have three or more weeks of vacation time?

n=20, p=0.45 P=0.1623

n=20, p=0.10 P=0.2702

n=20, p=0.20 P=0.0115+0.0576+0.1369=0.2060

Quiz

Review

Sampling Distribution

SPSS

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Review

BionomialDistribution

Poisson Distribution

Discretewithin a range

Normal Distribution

continuousDiscretewith mean

Probability of r successes in n trials =

n!

r ! (n-r) !

pr qn-rλ: mean

A-3 A-13 A-1

Quiz

Review

Sampling Distribution

SPSS

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Review

1. Visualization is very useful !

5-37 Normal Distribution, μ=6.4 σ=2.7

(a). P(4<X<5)=?

Chapter 5, No. 5-37 P.270

Z2=(5-6.4)/2.7=-0.89P0.89=0.3133

Z1=(4-6.4)/2.7=-0.52P0.52=0.1985

P(4<X<5)=0.3133-0.1985=0.1148

Quiz

Review

Sampling Distribution

SPSS

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Review

2. From Binomial Distribution to Normal Approximation

5-38

Chapter 5, No. 5-38 P.270

Normal approximation

N=50 p=0.25

(a). P(x>10)=?

Quiz

Review

Sampling Distribution

SPSS

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Review

BionomialDistribution

Discretewithin a range

Normal Distribution

continuous

Step 1: Is it allowed?When n*p>=5 AND n*q>=5

Step 2: μ =n*pσ =√n*p*q

Step 3: Find CCF (Continuity Correction Factor)

Quiz

Review

Sampling Distribution

SPSS

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Review

BionomialDistribution

Discretewithin a range

Normal Distribution

continuous

Step 3: Find CCF (Continuity Correction Factor)

Discrete:

Continuous:

1 2 3 4 5 6 7 8

1 2 3 4 5 6 7 8

X>3

CCF X>3.5

X>=3

CCF X>2.5

X<3

CCF X<2.5

X=<3

CCF X<3.5

Quiz

Review

Sampling Distribution

SPSS

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Review

2. From Binomial Distribution to Normal Approximation

5-38

Chapter 5, No. 5-38 P.270

Normal approximation

N=50 p=0.25

(a). P(x>10)=?

Step 1: n*p=50*0.25=12.5 >5AND n*q=50*0.75=37.5 >5 Yes, it is allowed.

Step 2: n*p=50*0.25=12.5 =μσ=√n*p*q= √50*0.25*0.75=3.062

Step 3: CCF X=10.5 P(x>10.5)=? z=(10.5-12.5)/3.062 =0.65

Quiz

Review

Sampling Distribution

SPSS

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Review

2. From Binomial Distribution to Normal Approximation

5-38

Chapter 5, No. 5-38 P.270

Normal approximation

N=50 p=0.25

(a). P(x>10)=?Step 3: CCF X=10.5 P(x>10.5)=? z=(10.5-12.5)/3.062 =0.65

P0.65=0.2422

P(x>10)=0.2422+0.5=0.7422

Step 4: Visualization

Quiz

Review

Sampling Distribution

SPSS

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Review

3. If P is known, but cannot be found in the table, it is allowed to use the closest one.

5-39

Chapter 5, No. 5-39 P.270

Normal Distribution σ=5.0 X=21 P=0.14(a). μ=?

(b). X1? P(X<X1)= 4%

Visualization Pz=0.50-0.14=0.36 z=1.08

(21-μ)/5.0=1.08 μ=15.6

(X1-15.6)/5.0=-1.75X1=6.85

Pz=0.5-0.04=0.46 z=1.75

Quiz

Review

Sampling Distribution

SPSS

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Review

5-41

Chapter 5, No. 5-41 P.270

μ=100, P(X<115)=0.9(a). σ=?

Visualization

z =1.28

z =1.28=(115-100)/σσ=11.72

Quiz

Review

Sampling Distribution

SPSS

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Review

5-41

Chapter 5, No. 5-41 P.270

μ=100, P(X<115)=0.9(a). σ=11.72

(b). Stock at least ___?

Visualization

(X-100)11.72=1.645 z =1.645 X=119.28

Therefore, we’d better stock at least 120 tubes.

Quiz

Review

Sampling Distribution

SPSS

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The Normal Distribution

Molly earned a score of 940 on a national achievement test. The mean test score was 850 with a standard deviation of 100. What proportion of students had a higher score than Molly?

(A) 0.10 (B) 0.18 (C) 0.50 (D) 0.82 (E) 0.90

Group Discussion

Quiz

Review

Sampling Distribution

SPSS

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Self-Practice

Chapter 5, No. 5-37 P.270

Given that a random variable, X, has a normal distribution with mean 6.4 and standard deviation 2.7, find

Q1. P (4.0<x<5.0)

Q2. P(x>20)

Q3. P(x<7.2)

Q4. P((x<3.0) or (x>9.0))

Quiz

Review

Sampling Distribution

SPSS

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Chapter 5, No. 5-37 P.270

Given that a random variable, X, has a normal distribution with mean 6.4 and standard deviation 2.7, find

Q1. P (4.0<x<5.0)

Q2. P(x>20)

Q3. P(x<7.2)

Q4. P((x<3.0) or (x>9.0))

Self-Practice

Quiz

Review

Sampling Distribution

SPSS

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Sampling and Sampling Distribution

Population

= all items chosen for study

Sample

= a portion chosen from the population

Parameter Statistic

Greek or capital letters Lowercase Roman letters

Quiz

Review

Sampling Distribution

SPSS

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Standard Error

µ = 100σ = 25

=95

=106

=101

Population Range=80~240

Sample Range=90~120

Standard Error of mean

Standard Deviation of population____

Quiz

Review

Sampling Distribution

SPSS

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Standard Error

Sample size

Dispersion of means

Standard Error

Quiz

Review

Sampling Distribution

SPSS

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The Normal DistributionSPSS Tip: Descriptive Statistics

The data can be downloaded from:

Blackboard – Inductive Statsitics STA2—SPSS--Week 2 Creating Graphs.sav

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Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Type data into SPSS- Gender- Age- Satisfaction with STA2

1 2 3 4 5

Hate it -------- Not like it --------- So so------------Like it-----Addicted to it

SPSS Tip: Descriptive Statistics

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Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Type data into SPSS- Gender- Age- Satisfaction with STA2

1 2 3 4 5

Hate it -------- Not like it --------- So so------------Like it-----Addicted to it

2. Click on “Values” to define variables

e.g. 0=male; 1=female

1. Use the Variable View Tab

SPSS Tip: Descriptive Statistics

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Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Type data into SPSS- Gender- Age- Satisfaction with STA2

4. Input data into each column

3. Use the Data View Tab

SPSS Tip: Descriptive Statistics

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Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Type data into SPSS- Gender- Age- Satisfaction with STA2

5. Don’t forget to choose the measurement level.

* . You can edit the variables again.

SPSS Tip: Descriptive Statistics

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Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

SPSS Tip: Descriptive Statistics6. Analyze—descriptive statistics--Descriptive

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SPSS Tip: Descriptive Statistics

Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Now you get it!

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SPSS Tip: Descriptive Statistics

Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

7. Analyze—descriptive statistics--Frequencies

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SPSS Tip: Descriptive Statistics

Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

8. Choose the variable you need to analyze

9. Click “Statistcs” to choose more

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SPSS Tip: Descriptive Statistics

Quiz

Sampling

Random Sampling

Experiment Design

Sampling Distribution

More about Sampling

Now you get it!

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Summary

1. Review of Chapter 5

2. Sampling Distribution

3. SPSS