LECTURE # 19 Dennis Papadopoulos - spp.astro.umd.edu

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1 LECTURE # 19 Dennis Papadopoulos End of Classical Physics Quantization – Bohr Atom Chapters 38‐39 PHYS 270-SPRING 2011 April 14, 2011

Transcript of LECTURE # 19 Dennis Papadopoulos - spp.astro.umd.edu

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LECTURE#19DennisPapadopoulos

EndofClassicalPhysicsQuantization–BohrAtom

Chapters38‐39

PHYS 270-SPRING 2011

April14,2011

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HOWTOMEASURESPECTRA

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Spectroscopy:UnlockingtheStructureofAtoms

• Hot, self-luminous objects, such as the sun or an incandescent light bulb, emit a continuous spectrum in which a rainbow is formed by light being emitted at every possible wavelength.

• In contrast, the light emitted by a gas discharge tube (such as those used to make neon signs) contains only certain discrete, individual wavelengths. Such a spectrum is called a discrete spectrum.

There are two types of spectra, continuous spectra and discrete spectra:

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AbsorptionandEmissionLines

CloseexaminationofthespectrafromtheSunandother stars reveals that the rainbowof colors hasmanydark lines in it, calledabsorptionlines. Theyare produced by the cooler thin gas in the upperlayers of thestars absorbingcertain colors of lightproducedbythehotterdenselowerlayers.Youcanalsoseetheminthereflected lightspectrumfromplanets.Someofthecolorsinthesunlightreflectingofftheplanetsareabsorbedbythemoleculesontheplanet'ssurfaceorinitsatmosphere.Thespectraofhot, thin (low density) gas clouds are a series ofbright lines calledemission lines. In bothof thesetypesofspectrayouseespectralfeaturesatcertain,discretewavelengths(orcolors)andnowhereelse.

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Seealsohttp://www.learner.org/teacherslab/science/light/color/spectra/spectra_1.html

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ATOMIC HYDROGEN SPECTRUM

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Balmer‐Numerology

Balmermathschoolteacherlikedtoamusehimselfbytakingfournumbersandthenfindinganequationthatdescribedtheirrelationship.Whileplayingwiththefournumbershefoundsomethingveryinterestingaboutthenumbera=3.645µmTheyfollowedtheprogression

9a/5,16a/12,25a/21,36a/32

λ µm 6.6 4.8 4.3 4.1 Hydrogen Spectrum

1234

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hf = hc /λ = (hc /a) n2 − 4n2

E1 = (hc /a)(5 /9)9a/5,16a/12,25a/21,36a/32

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CurrentthroughthewaterdecomposesittoHydrogenandOxygen–Bubblesofthemcomeoutnearelectrodes

Cl‐‐>Cl+e‐

Faraday:Electrolysiscanbeunderstoodonthebasisofatomictheoryofmatter‐Chargeassociatedwitheachatomormoleculeinthesolution.Positiveandnegativeions.

Matter is composed of atoms that are a combination of positive and negative ions

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Batteryvs.FuelCell

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GaseousDischarges

1.  Currentflowsdrivingdischarge2.  Dischargecolordependsongas(N2,Neon)3.  Cathodeglow–Independentofgas

Connectionbetweencoloroflightandtypeofatomsinthedischarge

Unificationofmatter‐electricity‐lightSPECTROSCOPY

NEONEXAMPLEReduce gas pressure (good pumps) 1.  Bright colored glow reduces and

becomes extinct 2.  Cathode glow fills tube 3.  Put a metal object creates shadow

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CathodeRaysIMPROVEDPUMPS‐>LOWPRESSURE‐>CATODEGLOWDOMINATES+GLASSEMITSGREENISHGLOW(FLUORESCENCE)

SOMETHINGBLOCKINGFLOW

Crooke’sTubesledto1. Electriccurrentassociatedwithcathoderays2. Theraysaredeflectedbyamagneticfieldlikeanegativecharge3. Cathodesofanymetalproducecathoderays.Raypropertiesindependentofmetaltype.4. Rayscanexertforcesonobjects.Thinfoilgetshotandglowsred.

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AreCathodeRaysChargedParticles?

EnterJ.J.Thomson–OKforNaClbutwhataboutHe(monatomicgas)‐RoentgenX‐rays

Atomsshouldbecomposedofpositiveandnegativeparts

Confirmedthatcathoderayswerenegativelychargedparticlesbutcouldnotmeasuretheq/m

d v dt

=qm( v × B )

r = mv /qB

Deflectiondependsonq/mandv

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Cross–FieldExperiment

d v dt

=qm( E + v ×

B )

d v dt

= 0

vx = E /Br = mv /qB = (m /q)(E /B2)

Thomsonfoundq/m=1011Cb/kgForHydrogenq/m=108Cb/kgCathoderayparticlehaseithermuchlargerchargeormuchsmallermass.

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FOUNDTHATNEGATIVEPARTICLESEMITTEDFROMMETALSHAVETHESAMEq/m.

‐>ELECTRONSARECONSTITUENTOFALLMATTER

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Using Thomson’s technique measured radioactive rays emitted from U samples •  as beta rays (q/m =-e/me similar to cathode rays – electrons) penetrate .1 inch of metal •  as alpha rays with q/m = e/2mH.

Alpha ray value indicates either singly charged H2 (q=e m=2mH) or doubly ionized He atom (q=2e, m=4mH

Ra

A few days later created a discharge and looked at the spectrum. He found He but not H Alpha particles nuclei of He

Enter Rutheford

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RutherfordandtheDiscoveryoftheNucleus•  In 1896 Rutherford’s

experiment was set up to see if any alpha particles were deflected from gold foil at large angles.

• Not only were alpha particles deflected at large angles, but a very few were reflected almost straight backward toward the source!

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Fig. 4-10, p. 120

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The discovery of the atomic nucleus: Rutherford Back Scattering

what Rutherford expected from the “plum pudding” model

the clever experiment

the (surprise!) result

“It was almost as incredible as if you had fired a 15-inch shell at a piece of tissue paper and it came back and hit you."

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Atomic number Z number of electrons and number of positive charges nucleus

Puzzle atom mass more than Zmp -> neutron

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IntotheNucleus•  The atomic number Z of an element describes the

number of protons in the nucleus. Elements are listed in the periodic table by their atomic number.

•  There are a range of neutron numbers N that happily form a nucleus with Z protons, creating a series of nuclei having the same Z-value but different masses. Such a series of nuclei are called isotopes.

• An atom’s mass number A is defined to be A = Z + N. It is the total number of protons and neutrons in a nucleus.

•  The notation used to label isotopes is AZ, where the mass number A is given as a leading superscript. The proton number Z is not specified by an actual number but, equivalently, by the chemical symbol for that element.

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Chemical properties controlled by Z.

Isotopes

24He

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TheEmissionofLight

Hot, self-luminous objects, such as the sun or an incandescent lightbulb, form a rainbow-like continuous spectrum in which light is emitted at every possible wavelength. The figure shows a continuous spectrum.

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TheEmissionofLightThe light emitted by one of Faraday’s gas discharge tubes contains only certain discrete, individual wavelengths. Such a spectrum is called a discrete spectrum. Each wavelength in a discrete spectrum is called a spectral line because of its appearance in photographs such as the one shown.

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IFMATTERCOMPOSEDOFATOMSWHATATOMSARECOMPOSEDOF?

• FARADAY–ELECTROLYSIS

• THOMSON–ELECTRONSq/m

• MILLIKAN–ELECTRONICq

• RUTHERFORD–NUCLEARMODEL

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• positive charge is concentrated at the center of the atom in an area ~1/1000th the size of the atom

• the mass of the electron is very small compared to the mass of the atom (one thousand times less than the hydrogen atom

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What’s wrong with this picture?

The attractive Coulomb force between the positive nucleus and the orbiting electron could provide the attractive force which keeps the electron in it’s orbit, much as the planets orbit the sun with gravity providing the centripetal force.

Accelerating charges radiate. Could this electromagnetic radiation be the source of the spectral lines?

No. This radiation must come at the expense of the kinetic energy of the orbiting electron!

It will eventually spiral into the nucleus. The atom would be unstable!

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r=n2aB,

aB=(h/2π)2/(ke2m)=.0529nm

En=‐E1/n2

E1=13.6eV

BohrAtom

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TheSpectrumofHydrogen• Hydrogen is the simplest atom, with one electron orbiting a proton, and it also has the simplest atomic spectrum. • The emission lines have wavelengths which correspond to two integers, m and n. • Every line in the hydrogen spectrum has a wavelength given by

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Bohr’sModelofAtomicQuantization1. Anatomconsistsofnegativeelectronsorbitingavery

smallpositivenucleus.

2. Atomscanexistonlyincertainstationarystates.Eachstationarystatecorrespondstoaparticularsetofelectronorbitsaroundthenucleus.Thesestatescanbenumbered2,3,4,...,wherenisthequantumnumber.

3. EachstationarystatehasanenergyEn.Thestationarystatesofanatomarenumberedinorderofincreasingenergy:E1<E2<E3<…

4. ThelowestenergystateoftheatomE1isstableandcanpersistindefinitely.Itiscalledthegroundstateoftheatom.OtherstationarystateswithenergiesE2,E3,E4,...arecalledexcitedstatesoftheatom.

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Bohr’sModelofAtomicQuantization

5.Anatomcan“jump”fromonestationarystatetoanotherbyemittingorabsorbingaphotonoffrequency

wherehisPlanck’sconstantandandΔEatom=|Ef–Ei|.

EfandEiaretheenergiesoftheinitialandfinalstates.Suchajumpiscalledatransitionor,sometimes,aquantumjump.

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6.AnatomcanmovefromalowerenergystatetoahigherenergystatebyabsorbingenergyΔEatom=Ef–Eiinaninelasticcollisionwithanelectronoranotheratom.

Bohr’sModelofAtomicQuantization

Thisprocess,calledcollisionalexcitation,isshown.

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Emission

Absorption

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Emission

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LineSpectra

Toexplaindiscretespectra,Bohrfoundthatatomsobeythreebasicrules:

1.  Electronshaveonlycertainenergiescorrespondingtoparticulardistancesfromnucleus.Aslongastheelectronisinoneofthoseenergyorbits,itwillnotloseorabsorbanyenergy.Theenergyorbitsareanalogoustorungsonaladder:electronscanbeonlyonrungsoftheladderandnotinbetweenrungs.

2.Theorbitsclosertothenucleushavelowerenergy.

3.Atomswanttobeinthelowestpossibleenergystatecalledthegroundstate(allelectronsasclosetothenucleusaspossible).

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Notice that there are fewer absorption than emission lines

ABSORPTION AND EMISSION SPECTRA

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MatterWavesandEnergyQuantization

In1924deBrogliepostulatedthatifamaterialparticleofmomentump=mvhasawave‐likenature,thenitswavelengthmustbegivenby

wherehisPlanck’sconstant(h=6.63×10−34Js).ThisiscalledthedeBrogliewavelength.

E = hf = pcλ = c / f = h / p

Photons

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DB considered a matter wave to be a travelling one. Suppose however that the particle is confined in a small region and cannot escape. How do the wave properties show up?

λn = 2L /n,n =1,2,3,4...λ = h /mvvn = n(h /2Lm),n =1,2,3En = n2(h2 /8mL2) ≡ n2E1

Probability

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Standing waves (harmonics)

Ends (or edges) must stay fixed. That’s what we call a boundary condition.

This is an example of a Bessel function.

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QuantizationofEnergy• ConsideraparticleofmassmmovinginonedimensionasitbouncesbackandforthwithspeedvbetweentheendsofaboxoflengthL.We’llcallthisaone‐dimensionalbox;itswidthisn’trelevant.

• Awave,ifitreflectsbackandforthbetweentwofixedpoints,setsupastandingwave.

• AstandingwaveoflengthLmusthaveawavelengthgivenby

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QuantizationofEnergyUsingthedeBroglierelationshipλ=h/mv,astandingwavewithwavelengthλnformswhentheparticlehasaspeed

Thustheparticle’senergy,whichispurelykineticenergy,is

DeBroglie’shypothesisaboutthewave‐likepropertiesofmatterleadsustotheremarkableconclusionthattheenergyofaconfinedparticleisquantized.

En = −E1n2

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L = mevr = n n =1,2,3... = h /2π

In order to understand quantum mechanics, you must understand waves!

an integer number of wavelengths fits into the circular orbit

where

λ is the de Broglie wavelength

Photonsp=hf/c=h/λ

Phasecancellation

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BlackBodyRadiation

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BlackbodyRadiationThe heat energy Q radiated in a time interval Δt by an object with surface area A and absolute temperature T is given by

where σ = 5.67 ×10−8 W/m2K4 is the Stefan-Boltzmann constant. The parameter e is the emissivity of the surface, a measure of how effectively it radiates. The value of e ranges from 0 to 1. A perfectly absorbing—and thus perfectly emitting—object with e = 1 is called a blackbody, and the thermal radiation emitted by a blackbody is called blackbody radiation.

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Wien’lawλ∼1/Τ or fm~T

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Fig. 3-11, p. 78

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RedoscillatorsBlueoscillatorsGreenoscillators…

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B

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Lava glows when hot

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The wavelength of the peak in the intensity graph is given by Wien’s law (T must be in kelvin):

BlackbodyRadiation

Wien’s Displacement Law

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