Lect01 Electrical Quantities and Laws Electrical Eng for Mech 802307
Lect01-2P-C (1).pdf
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1
Analog Electronics
Section 2Prof. Dr. Murat Aşkar
D-211E-mail: [email protected]
Web: www.eee.metu.edu.tr/~askar
Analog and Digital Signals
3
Bio-eng: Neuronal implants
Linear Amplifiers (1)Multiply amplitude of a signal by a constant scalar quantity
xo(t) = A xi(t)
Non-scalar or non-uniform amplification is called distortion
4
Linear Amplifiers (2)• Symbol for a single-ended
input linear voltage amplifier.
• Ideally provides linear voltage gain regardless of the amplitude of the input signal
• Real amplifiers have powersupplies that limit theamplitude of the output
• If input is too large, outputclamps
Transfer Characteristics (1)Plot of amplifier output versus amplifier input
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Transfer Characteristics (2)
• Gain = Slope• To operate amplifier in its linear region, the input
must be kept small enough
Real Transfer Characteristics
• Each circle represents a different DC component for the input and output signals – called an operating point
• Location of operating point has an effect on• input signal range• amplifier gain magnitude• amount of distortion
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Operating Point (1)Voltage gain, output DC voltage, allowable input magnitude range are affected
Operating Point (2)
Derivative of transfer characteristic gives measure of amplifier gain linearity (and distortion)
Input and output signal amplitude ranges are maximized when operating point is near middle of linear region
7
Signal Convention (1)• DC magnitudes in uppercase symbol and
subscript– Example: ID, VD
• Ac signal quantities in lowercase symbol & subscript
– Example: id(t), vd(t)• Total DC + ac signal quantities in lowercase
symbol, uppercase subscript– Example: iD(t), vD (t)
Signal Convention (2)In general
vD(t) = VD + vd(t)
iC(t) = IC + ic(t)
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Superposition• If the amplifier is linear, superposition can be
applied. Each component can be determined seperately.
• Determine the DC magnitude of the output using DC model (i.e capacitors are open circuited, inductors are short circuited)
– Example: IO, VO
• Determine the ac signal component of the output using the ac model (i.e., DC sources are killed and capacitors are short circuited, inductors are open circuited) as
– Example: vo(t) = Av vi(t)
Amplifier Classification
CurrentCurrentCurrent
TransresistanceVoltageCurrent
TransconductanceCurrentVoltage
VoltageVoltageVoltage
TypeOutputInput
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+vi
-
+vo
-
Ideal Voltage Amplifier
Avi
+
RoAvi
+vi-
+vo-
Ri
+
Real Voltage Amplifier
Loaded Ideal Voltage Amplifier
Avi
+vi-
+vo-
+RL
Rsvs
+
Avv
s
o =
10
Loaded Voltage Amplifier
RoAvi
+vi-
+vo-
Ri
+RL
Rsvs
+
Lo
L
is
i
s
oRR
RRR
RAv
v++=
Ideal Current Amplifier
Real Current Amplifier
Aii
ii io
Aii
ii ioRi Ro
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Loaded Ideal Current Amplifier
Aii
s
o =
Aii RL
iiRsis
io
Loaded Current Amplifier
Aii RL
iiRSis
ioRi Ro
Lo
o
is
s
s
oRR
RRR
RAi
i++=
12
To determine Input Resistance Ri
RoAvi
+vi-
+vo-
Ri
+• Apply input voltage vi
(or input current ii) • Determine the input
current ii (or input voltage vi)
ThenRi = vi / iiAii
ii ioRi Ro
ii
+vi-
Voltage Amplifier
Current Amplifier
To determine Output Resistance Ro
RoAvi
+vi-
+vx-
Ri
+• Kill the input signal
(set vi or ii to zero)• Apply a test voltage
vx to the output node• Determine the current
ix that the source delivers to the circuit
ThenRo = vx / ix
Aii
ii ixRi Ro
ii
+vi-
Voltage Amplifier
Current Amplifier
+vx-
ix