L05 - Equilibrium

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    January 20/21, 2014

    ECOR 1101 Mechanics I

    Sections C and F

    Jack Vandener!

    Lecture 04 – Equilibrium and FBDs

    (Chapter 3 – Sections 3.!3.4"

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    O"ecti#es

    Learn the concept o# #ree!bod$ dia%rams

    Learn to sol&e problems in&ol&in% particles in equilibrium

    Learn to use equilibrium equations usin% cartesian &ector

    coordinates

    2

    'D and 3D Equilibrium o# a particle

    ECOR1101 –Mechanics I

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    Equilibrium o# a article

    ) particle is in equilibrium i#*

    +t remains at rest under action o# a s$stem o# #orces, or, +t continues in its state o# motion -ith constant &elocit$

    under action o# a s$stem o# #orces.

    For a particle to be in equilibrium the resultant o# all

    #orces actin% on it must be ero.

    Satis#ies /e-tons st la- o# motion

    1he abo&e equation represents the necessar$ and

    su##icient condition #or equilibrium o# a particle in

    space.

    3

    F R=   F  x ∑   +   F  y +   F  z = 0∑∑

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    )ccordin% to /e-tons 'nd la- o# motion, i# ΣF = ma = 0,

    the particle is in equilibrium since a = 0 and   ΣF = 0 i.e. the particle is under constant &elocit$ or is at rest

    1he equilibrium equation can be used to sol&e problems

    dealin% -ith equilibrium o# a particle in&ol&in% no more

    than three un2no-ns

    4

    Equilibrium o# a article

    ECOR1101 –Mechanics I

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    1o appl$ the equations o# equilibrium to a particle all

    #orces (2no-n and un2no-n" must be accounted #or. 1he best -a$ to do this is to isolate the particle #rom its

    surroundin%s to #orm a #ree!bod$ dia%ram (FBD".

    1hen appl$ all the #orces (2no-n and un2no-n" actin%

    on the particle

    5

    Free!bod$ Dia%rams (FBD"

    ECOR1101 –Mechanics I

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    +solate particle #rom its surroundin%

    S2etch outline shape o# particle -ith all #orces (acti&e

    and reacti&e" indicated

    Label all #orces (2no-n and un2no-n" -ith both their

    ma%nitudes and directions

    +# $ou 2no- that an un2no-n #orce is in tension, do $ou

    dra- it a-a$ or to-ards the particle5

     

    6

    rocedure #or dra-in% FBD

    ECOR1101 –Mechanics I

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    Free Bod$ Dia%rams (FBDs"

    7

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    FBDs

    8

    6i%id Bodies

    Sprin%s 7oo2es la-

    F 8 2 s

    F 8 sprin% constant 9 displacement

    Cables (assumptions"

    :ust be in tension /e%li%ible -ei%ht

    Do not stretch

    Frictionless pulle$

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    FBDs

    9

    Draw a FBD of the cable AB and of the joint C.

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    Sample roblem

    ) '00!2% c$linder is hun% b$ means o# t-ocables AB and AC, -hich are attached to the

    top o# a &ertical -all. ) horiontal #orce $ 

    perpendicular to the -all holds the c$linder in

    the position sho-n. Determine the ma%nitude

    o# P and tension in each cable

    10ECOR1101 –Mechanics I

    !

    10 !

    1" !1." !

    " !

     A

    B

    C

     A

    B

    C

    P

    P

    w

    TAC

    TABk

    i  j

    +ntroduce unit &ectors i, ", k alon%

    ortho%onal a9es and resol&e #orces

    P  # P i $ 0 j $ 0k 

    % = 0i $ 0 j % mg k 8

    8 0i $ 0 j ! '00×;.

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    11ECOR1101 –Mechanics I

    r AB # &%1."!'i % &!' j $ &10!' k

    r AC # &%1."!'i $ &10!' j$ &10!'k

    ( ) ( )( ) ( )

    mk, jir

    u

    mk, jir

    u

    m

    m

    ACAC

    ABAB

    7046.07046.00846.0

    778.0622.0093.0

    193.1410102.1

    862.121082.1222

    222

    ++−==

    +−−==

    =++−=

    =+−+−=

     AC 

     AB

     AC 

     AB

    0

    0

    =+++∴

    =++=∑ ∑ ∑ ∑

    ACAB

    zyx

    uuWP

    FFFF

     AC  ABT T 

    (ince the c)linder is *nder e+*ilibri*!,

    X AB AC AB AC

    y AB AC AB AC

    z Ab AC AB AC

    AB

    AC

    F 0 P 0 0.093T 0.0846T 0 P 0.093T 0.0846T

    F 0 0 0 0.622T 0.7046T 0 T 1.133T

    F 0 0 1962 0.778T 0.7046T 0 T 0.9056T 2521.851

    T 1401.6 N 1.40 kN

    T 1237.1 N 1.24 kN

    P 235 N

    = ⇒ + − − = ⇒ = +

    = ⇒ + − + = ⇒ =

    = ⇒ − + + = ⇒ = − +

    = =

    = =

    =

    ∑∑

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    Cables, Sprin%s and ulle$s

    Cables (or cords", in %eneral,

    are assumed to ha&e the

    #ollo-in% properties

    >ei%htless

    Supports onl$ tension in the

    direction o# the cable (cannotbe pushed"

    Cannot stretch (i.e. increase

    in len%th under load"

    ) cable passin% o&er a#rictionless pulle$ has a constant

    ma%nitude

    12ECOR1101–Mechanics I

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    Cables, ulle$s and Sprin%s

    Sprin%s, -hen de#ormed, e9ert

    a #orce proportional to the

    amount o# de#ormation.

    Sprin%s are o#ten de#ined b$ the

    sprin% constant or sti##ness k  

    1he ma%nitude o# #orce e9ertedon a linearl$ elastic sprin% -ith

    sti##ness k  is %i&en b$* F = ks

     s = l − l o ,

    l o = unstretched len%th,l = stretched len%th

    13ECOR1101–Mechanics I

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    Coplanar Force S$stems ('D"

    14ECOR1101–Mechanics I

    F1

    F2

     x 

    F 1x 

    F 2x 

    F 2y 

    F 1y 

    1he t-o equations o# equilibrium can

    be sol&ed #or at most t-o un2no-ns.

    )pplication o# the equation must ta2e

    into account direction o# components

    o# the #orce

    +# a particle sub?ected

    to a s$stem o# coplanar#orces (9!$ plane", then

    the #orces can be

    resol&ed and

    equilibrium equations

    applied.

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    Establish x-y a9es

    Dra- a #ree!bod$ dia%ram

    Dra- and label all #orces (2no-n and un2no-n" -ith

    ma%nitudes, sense and direction

    Choose an arbitrar$ direction #or un2no-n #orces

    6esol&e #orces in x-y a9es

    )ppl$ equations o# equilibrium

    )ssume a @&e direction #or the purpose o# -ritin% $our

    equation o# equilibrium

    Sol&e #or un2no-n #orces Compare $our ans-ers to $our ori%inal assumption (not to

    the @&e direction -hen -ritin% $our equations"

    6edra- $our FBD -ith all Forces as positi&e numbers

    15

    rocedure For )nal$sis o# Coplanar ('D" Force Equilibrium

    ECOR1101–Mechanics I

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    1hree!Dimensional (3D" Force S$stems

    Conditions #or equilibrium

    6esol&e #orces into respecti&e

    Cartesian components, i, j, k 

    16ECOR1101–Mechanics I

     x 

    F1

    F1zF1x

    F1y

    F2

    F2y

    F2z

    F2x

    0 F  =∑

    00

    0

    0

    0

    =+ + =

    =

    =

    =

    ∑∑ ∑ ∑

    F

    i j k  x y z 

     x

     y

     z 

     F F F 

     F 

     F 

     F 1he three equation o# equilibrium are al%ebraic sums

    o# #orce components and can be used to #ind at most

    three un2no-ns (coordinate direction an%les or

    ma%nitudes o# #orces actin% on a particle"

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    Establish x-y-z  a9es

    Dra- a #ree!bod$ dia%ram

    Dra- and label all #orces (2no-n and un2no-n" -ith

    ma%nitudes, sense and direction

    Choose an arbitrar$ direction #or un2no-n #orces

    6esol&e #orces in x-y-z  a9es

    )ppl$ equations o# equilibrium

    )ssume a @&e direction #or the purpose o# -ritin% $our

    equation o# equilibrium

    Sol&e #or un2no-n #orces Compare $our ans-ers to $our ori%inal assumption (not to

    the @&e direction -hen -ritin% $our equations"

    17

    rocedure For )nal$sis o# 3D Force S$stems

    ECOR1101–Mechanics I

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    Sample roblem

    1he shear le% derric2 is

    used to haul the '00!2% net

    o# #ish onto the doc2.

    Determine the compressi&e

    #orce alon% each o# the

    le%s )B and CB and the

    tension in the -inch cable

    DB. )ssume the #orce in

    each le% acts alon% its a9is.

    18ECOR1101–Mechanics I

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    19ECOR1101–Mechanics I

    W!"# "$# %&&d!na"#' (& )&!n"' A, B, C, and

    *, )&'!"!&n +#%"&', n!" +#%"&', F&%#

    -#%"&'

    A2m, 0, 0/

    B0, 4m, 4m/

    C2m, 0, 0/

    *0, 5.6m, 0/

    W

    FBD

     x 

    FBA

    FBC

    B

     A

    D

    "

    -

    -./

    "

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    20ECOR1101–Mechanics I

    rBA=  2mi  4m j  4mk

    rBC=  2mi  4m j  4mk  

    rBD= 0mi  9.6m j  4mk 

    W = 0i  0 j  200×9.81/k 

    = 0i  0 j  1962Nk 

    ,BA  = BA

    r BA

    =2!− 4− 4k 

    2/2

    + −4( )2

    + −4( )2

    = 0.333!−0.667−0.667k

    ( ) ( ) , m

    r  BC k  ji

    k  jiru BCBC   667.0667.0333.0

    44/2

    442

    222−−−=

    −+−+−

    −−−==

    ( ) ( ) , m

    r  BDk  ji

    k  jiru   BDBD   385.0923.00

    46.9/0

    46.90

    222−−=

    −+−+

    −−==

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    21ECOR1101–Mechanics I

    kN

    kN

    kN N 

    WuuuF BDBCBA

    65.3

    52.2

    52.285.2521

    01962385.0667.0667.00

    445.1

    0923.0667.0667.00

    0333.0333.00

    00

    =

    −=

    −=−=

    =−−−−⇒=

    −=∴

    =−−−⇒=

    =∴

    =−⇒=

    =+++⇒=

    ∑∑

     DB

     BC 

     BA

     BD BC  BA z 

     BA BD

     BD BC  BA y

     BC  BA

     BC  BA x

     BD BC  BA

     F 

     F 

     F 

     F  F  F  F 

     F  F 

     F  F  F  F 

     F  F 

     F  F  F 

     F  F  F 

    W

    FBD

     x 

    FBA

    FBC

    B

     A

    D

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    roblem F3!<

    22

    Deter!ine the tension deeloed in cables AB2 AC2 and AD.

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    roblem 3!A;

    23

    Deter!ine the !a3i!*! wei4ht of the crate that can be s*orted

    fro! cables AB2 AC2 and AD so that the tension deeloed in an)one of the cables does not e3ceed "0 lb.

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    roblem 3!=

    24

    If cable AD is ti4htened b) a t*rnb*c5le and deelos a tension of

    12600 lb2 deter!ine the tension deeloed in cables AB and ACand the force deeloed alon4 the antenna tower AE at oint A.

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    roblem 3!

    25

    7he joint of a sace fra!e is s*bjected to fo*r !e!ber forces.

    Me!ber OA lies in the 3%) lane and !e!ber OB lies in the )%8lane. Deter!ine the forces actin4 in each of the !e!bers re+*ired

    for e+*ilibri*! at the joint.