Kinematics in one dimension -1

7/30/2019 Kinematics in one dimension -1

1/4


2/4

Particle D: is moving in negative x- direction with decreasing speed.

In the given position- time i.e. x-t graph markcorrectly A, B C and D.

11- Let a particle moves with uniform velocity on the x-axis. If at times t= 1 and t = 4 , itspositions( x ) are 20 m and -16 m respectively, then the particle must be at the origin at time t=

12-Position x(t) time (t) graph for a particle moving on a line is shown.What is the ratio of the velocities at the instants t =2 & t =4 ?

13- Position x(t) time (t) graph for a particle moving ona line is shown. What is represented by the slope of the line AB ?

14- Position x(t) time (t) graph for a particle moving on a line is shown.What is represented by the slope of the tangent drawn at the point

A of the graph ?(a) velocity at time t = T0 (b) velocity at time t = T

15- A particle is moving on the x axis. Its position at time t is x = 12+8t t2.(i) Is the motion uniformly(ii) What is the velocity at the time t =0?(iii) When the particle stops momentarily? What is the displacement in 3rd second

of the motion?(iv) Draw v-t graph.

16- If position x= t2 at time t for a particle moving on x-axis, then

(i) average velocity ,in time interval t = 0.95 to t = 1.05 , will be nearly......(ii) the velocity at the instant t = 1 will be ...............

From these two answers what we should conclude?

17- The velocity v of a particle moving on a straight line is changing with time t as v= 10-4t m/s.

(i ) Find displacement in fi rst 4 seconds(ii) Find the displacement in 4th second of motion.(ii i) Wi ll displacement in 3rd second of motion and distance covered in 3rd second

will be same?(iv) Find distance covered in 3rd second of motion(v) If the position of the particle at time t =0 is at x = 16 m, get the expression of

the x(t),(vi) Draw x(t) t graph.

18- Mark true /false in the following statements regarding motion on a straight line :

(i) The slope of position-time graph equals velocity.(ii) The slope of velocity-time graph equals acceleration .(iii)Area under the velocity time graph ,equals displacement.(iv) Area under the displacement time graph ,equals velocity.(v) Slope of the velocity-time graph equals displacement.(vi) If the acceleration is constant, velocity-time graph will be of straight line shape.(vii) Area under the acceleration-time graph equals change in the velocity.(viii) If velocity of a particle at time t sec is 5t m/s, then acceleration is zero at time t=0.(ix) If the velocity is constant then displacement-time graph will be of straight line shape.(x) If the acceleration-time graph is parallel to the time axis, then velocity will be constant.

2 /1D-A/ PHYSICS / 11+ AIEEE/AIPMT/JEE-D/


3/4

19- A particle is moving on a line which extends along west-east. The east is along positive x-direction. At time t =0, velocity of the particle is 12 ms-1 towards west and position of theparticle is at x= 16 m. The acceleration of the particle is 4 ms-2 in east direction.

(i) The particle will momentarily stop at position x =(a) 0 m (b) 2 m (c) 2m (d) -4 m(ii)The particle will be seen at the position x = 16 m again at time t =

(a) 6 s (b) 3 s (c) 4 s (d) 12 s(iii)The particles displacement in nth second will be(a) 4n +14 m in east (b) 4n +10 m in east (c) 4n -14 m in east

20- For the previous problem, position x(t)-time (t) graph will look like as given in

21- Velocity-time graph for a particle a particle moving ona straight line is shown. Which of the following two position-timegraph may correctly represent this motion ?

22- Position x(t) time (t) graph for a particle moving on a lineis shown. Mark true / false against following statements:

(i) velocity of the particle at time t =3 is zero(ii) velocity at time t =2 is 5 m/s(iii) at time t =8, the direction of motion is reversed(iv) distance covered in total 14 sec is 52 m(v) displacement in 4th second of motion is 16 m.(vi) displacement from time t =2 s to t = 8 s, will be 28 m

(vii) acceleration at time t =5 s , is zero

23- Position x(t) time (t) graph for a particle moving on a lineis shown. Mark true / false against following statements:

(i) at time t = T0 , the particle is momentarily at rest.(ii) direction of motion is in negative x- direction before time T0(iii) speed of the particle is decreasing from time t =0 to T0(iv) acceleration is zero at time t =T0(v) direction of acceleration is along direction of motion at time < T0(vi) direction of acceleration is along direction of motion at time > T0(vii) direction of acceleration is always along positive x direction

24- Acceleration-time graph for a particle moving on a line

is shown where acceleration and time are in SI unit system. Theparticle was initially i.e. at time t =0, at rest.(i) velocity at time t =6 s will be ...........(ii) velocity will be of maximum magnitude at time t =.....(iii) displacement in time interval t =2 to t = 4 will be ......

25-In the previous problem, how the velocity-time graph will look like ?26- Examine the following position-time graph and then commentwhether such graph is possible or not ?

27- For uniformly accelerated particle , moving along a line the



4/4

displacement in nth second of motion is 8 + 2n meters. Its velocity at the instant t =nsecond will be ................


Kinematics in one dimension -1

Documents

Transcript of Kinematics in one dimension -1