Key stage 3_mathematics_level_6_revision_

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Key Stage 3 Mathematics Key Facts Level 6

Transcript of Key stage 3_mathematics_level_6_revision_

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Key Stage 3

Mathematics

Key Facts

Level 6

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Level 6

Number and Algebra

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Solve the equationx³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too Small/Correct

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Solve the equationx³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too Small/Correct

3 3³ + 3 = 30 Too Big

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Solve the equationx³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too Small/Correct

3 3³ + 3 = 30 Too Big

2 2³ + 2 = 10 Too Small

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Solve the equationx³ + x = 20

Using trial and improvement and give your answer to the nearest tenth

Guess Check Too Big/Too Small/Correct

3 3³ + 3 = 30 Too Big

2 2³ + 2 = 10 Too Small

2.5 2.5³ + 2.5 =18.125 Too Small

2.6

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Amounts as a %

• Fat in a mars bar 28g out of 35g. What percentage is this?

Write as a fraction

• =28/35

Convert to a percentage (top ÷ bottom x 100)

• 28 ÷ 35 x 100 = 80%

top ÷ bottom converts a

fraction to a decimal

Multiply by 100 to make a

decimal into a percentage

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A percentage is a fraction out of 100

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The ratio of boys to girls in a class is 3:2

Altogether there are 30 students in the class.

How many boys are there?

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The ratio of boys to girls in a class is 3:2

Altogether there are 30 students in the class.

How many boys are there?

The ratio 3:2 represents 5 parts (add 3 + 2)

Divide 30 students by the 5 parts (divide)30 ÷ 5 = 6

Multiply the relevant part of the ratio by the answer (multiply)

3 × 6 = 18 boys

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23

211

+ =2233

633

+

=2833

A common multiple of 3 and 11 is 33, so change both fractions to equivalent

fractions with a denominator of 33

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23

14

- = 812

312

-

= 512

A common multiple of 3 and 4 is 12, so change both fractions to equivalent fractions with a

denominator of 12

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Find the nth term of this sequence

6 13 20 27 34

7 7 7 7

Which times table is this pattern based on? 7

nth term = 7n - 1

Each number is 1 lessHow does it compare to the 7 times table?

7 14 21 28 35

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Find the nth term of this sequence

6 15 24 33 42

9 9 9 9

Which times table is this pattern based on? 9

nth term = 9n - 3

Each number is 3 lessHow does it compare to the 9 times table?

9 18 27 36 45

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- -

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4p + 5 = 3p75 -

4p + 5 = 3p75 -

Swap Sides, Swap Signs

=4p 75

3p

+ -

5

=7p 70

= p 10

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2 4 6-6 -4 -2

2

4

6

-6

-4

-2

y axis

x axis

-5 -3 -1 1 3 5-1

-3

-5

1

3

5

(3,6)

(2,4)

(1,2)

(-3,-6)

The y coordinate is always double the x coordinate

y = 2x

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Straight Line Graphs

1 2 3 4-4 -3 -2 -10

2

4

8

6

10

-2

-4

-8

-6

-10

y = ½ x

y = x

y = -x

y = 2x y = 3x

y = 4x

y = 5x

y axis

x axis

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1 2 3 4-4 -3 -2 -10

2

4

8

6

10

-2

-4

-8

-6

-10

y = 2x

+1

y = 2x

- 5

y = 2x

+6

y = 2x

- 2y axis

x axis

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All straight line graphs can be expressed in the form

y = mx + c

m is the gradient of the line

and c is the y intercept

The graph y = 5x + 4 has gradient 5 and cuts the

y axis at 4

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Level 6

Shape, Space and Measures

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Cube Cuboid

Triangular Prism

Hexagonal Prism

Cylinder

Square based

PyramidTetrahedron

Cone

Sphere

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Using Isometric Paper

Which Cuboid is the odd one out?

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50a

Alternate angles are equal

a = 50

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76

b

Interior angles add up to 180

b = 180 - 76 = 104

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50

c

Corresponding angles are equal

c = 50

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114

d

Corresponding angles are equal

d = 114

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112

e

Alternate angles are equal

e = 112

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50f

Interior angles add up to 180

f = 130

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Polygon Sides(n)

Sum of Interior Angles

Triangle 3 180

Quadrilateral 4

Pentagon 5

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

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Polygon Sides(n)

Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

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Polygon Sides(n)

Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5 540

Hexagon 6

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

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Polygon Sides(n)

Sum of Interior Angles

Triangle 3 180

Quadrilateral 4 360

Pentagon 5 540

Hexagon 6 720

Heptagon 7

Octagon 8

The Sum of the Interior Angles

What is the rule that links the Sum of the Interior Angles to n?

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For a polygon with n sides

Sum of the Interior Angles = 180 (n – 2)

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A regular polygon has equal sides and equal angles

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Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square

Regular Pentagon

Regular Hexagon

Regular Heptagon

Regular Octagon

If n = number of sides

e = 360 ÷ n

e + i = 180

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Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon

Regular Hexagon

Regular Heptagon

Regular Octagon

If n = number of sides

e = 360 ÷ n

e + i = 180

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Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon 108 72

Regular Hexagon

Regular Heptagon

Regular Octagon

If n = number of sides

e = 360 ÷ n

e + i = 180

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Regular Polygon Interior Angle (i) Exterior Angle (e)

Equilateral Triangle 60 120

Square 90 90

Regular Pentagon 108 72

Regular Hexagon 120 60

Regular Heptagon

Regular Octagon

If n = number of sides

e = 360 ÷ n

e + i = 180

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Translate the object by 4-3 ( )

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Translate the object by 4-3 ( )

Image

Move each corner of theobject 4 squaresacross and 3 squares down

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C

Rotate by 90 degrees anti-clockwise about c

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C

Rotate by 90 degrees anti-clockwise about C

Image

Remember to ask for tracing paper

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Triangle

Area = base × height ÷ 2

A = bh/2

Parallelogram

Area = base × height

A = bhTrapezium

A = ½ h(a + b)h

b

ab

h

h

b

The formula for the trapezium is given in the front of the SATs paper

We divide by 2 because the area of the triangle is half that of the rectangle that surrounds it

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Circumference = π × diameter

Where π = 3.14 (rounded to 2 decimal places)

diameter

The circumference of a circle is the distance around the outside

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The radius of a circle is 30m. What is the circumference?

r=30, d=60

C = π d

C = 3.14 × 60

C = 18.84 m

r = 30d = 60

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Circle Area = πr2

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πd πr²

π = 3. 141 592 653 589 793 238 462 643

Need diameter = distance across the middle of a circle

Need radius = distance from the centre of a circle to the edge

Area = π × 100= 3.142 × 100= 314.2 cm²

10cm

Circumference = π × 20= 3.142 × 20= 62.84 cm

10cm

The distance around the outside of a circle

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9 cm4 cm

10 cm

Volume of a cuboid

V= length × width × height

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9 cm4 cm

10 cm

Volume of a cuboid

V= length × width × height

V= 9 × 4 × 10

= 360 cm³

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Level 6

Data Handling

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Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class

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Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class

Add the frequencies to find the total

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Colour Frequency

Blue 5

Green 3

Yellow 2

Purple 2

Pink 4

Orange 1

Red 3

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class

DIVIDE 360° by the total to find the angle for 1 person

360 ÷ 20 = 18Add the frequencies to find the total

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Colour Frequency Angle

Blue 5 5 × 18 = 90

Green 3 3 × 18 = 54

Yellow 2 2 × 18 = 36

Purple 2 2 × 18 = 36

Pink 4 4 × 18 = 72

Orange 1 1 × 18 = 18

Red 3 3 × 18 = 54

TOTAL 20

Draw a Pie Chart to show the information in the table below

A pie chart to show the favourite colour in our class

DIVIDE 360° by the total to find the angle for 1 person

360 ÷ 20 = 18Add the frequencies to find the total

Multiply each frequency by the angle for 1 person

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Colour Frequency Angle

Blue 5 5 × 18 = 90

Green 3 3 × 18 = 54

Yellow 2 2 × 18 = 36

Purple 2 2 × 18 = 36

Pink 4 4 × 18 = 72

Orange 1 1 × 18 = 18

Red 3 3 × 18 = 54

TOTAL 20

Draw a Pie Chart to show the information in the table below

A bar chart to show the favourite colour in our class

Blue

Green

YellowPurple

Pink

Orange

Red

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Length of string

Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20

40 < x ≤ 60 45

60 < x ≤ 80 32

80 < x ≤ 100 0

Draw a frequency polygon to show

the information in the table

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frequency

x

f

Length of string (x)

Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20

40 < x ≤ 60 45

60 < x ≤ 80 32

80 < x ≤ 100 0

Draw a frequency polygon to show

the information in the table

Plot the point using the midpoint of the interval

Use a continuous scale for the x-axis

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Length of string

Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20

40 < x ≤ 60 45

60 < x ≤ 80 32

80 < x ≤ 100 0

Draw a histogram to show

the information in the table

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x

ffrequency

Length of string (x)

Frequency

0 < x ≤ 20 10

20 < x ≤ 40 20

40 < x ≤ 60 45

60 < x ≤ 80 32

80 < x ≤ 100 0

Draw a histogram to show

the information in the table

Use a continuous scale for the x-axis

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A Scatter Diagram to compare the marks of students in 2 maths tests

0

20

40

60

80

100

120

140

0 20 40 60 80 100 120 140

Test A

Te

st

B

Describe the correlation between the marks scored in test A and test B

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Describe the correlation between the marks scored in test A and test B

A Scatter Diagram to compare the marks of students in 2 maths tests

0

20

40

60

80

100

120

140

160

0 20 40 60 80 100 120 140 160

Test A

Te

st

B

The correlation is positive because as marks in test A increase so do the marks in test B

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Negative Correlation

0

2

4

6

8

10

12

0 2 4 6 8 10 12

y

x

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The sample or probability space shows all 36 outcomes when you add two normal dice together.

2 3 4 5 6 7

3 4 5 6 7 8

7 8 9 10 11 12

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

1 2 3 4 5 6

1

2

6

3

4

5

Dice 1

Dice 2

Total Probability

1 1/36

2

3

4

5 4/36

6

7

8

9

10

11

12

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Dice 1

Dice 2

Total Probability

0

1 10/36

2

3

4 4/36

5

The sample space shows all 36 outcomes when you find the difference between the scores of two normal dice.

0 1 2 3 4 5

1 0 1 2 3 4

5 4 3 2 1 0

2 1 0 1 2 3

3 2 1 0 1 2

4 3 2 1 0 1

1 2 3 4 5 6

1

2

6

3

4

5

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The total probability of all the mutually exclusive outcomes of an experiment is 1

A bag contains 3 colours of beads, red, white and blue.

The probability of picking a red bead is 0.14

The probability of picking a white bead is 0.2

What is the probability of picking a blue bead?

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The total probability of all the mutually exclusive outcomes of an experiment is 1

A bag contains 3 colours of beads, red, white and blue.

The probability of picking a red bead is 0.14

The probability of picking a white bead is 0.2

What is the probability of picking a blue bead?

0.14 + 0.2 = 0.34

1 - 0.34 = 0.66

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© Dave Cavill