Inverse Trig Functions and Differentiation By Dr. Julia Arnold.
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Transcript of Inverse Trig Functions and Differentiation By Dr. Julia Arnold.
![Page 1: Inverse Trig Functions and Differentiation By Dr. Julia Arnold.](https://reader036.fdocuments.in/reader036/viewer/2022062423/5697bf821a28abf838c85fee/html5/thumbnails/1.jpg)
Inverse Trig Functions and Differentiation
ByDr. Julia Arnold
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Since a function must pass the horizontal line test to have an inverse function, the trig functions, being periodic, have to have their domains restricted in order to pass the horizontal line test.For example: Let’s look at the graph of sin xon [-2pi, 2 pi].
-6.0-5.0-4.0-3.0-2.0-1.0 1.02.03.04.05.06.07.0
-1.0
1.0
x
y
Flunks thehorizontalline test.
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By restricting the domain from [- pi/2, pi/2] we produce a portion of the sine function which will pass the horizontalline test and go from [-1,1].
The inverse sine function is written as y = arcsin(x)which means that sin(y)=x.Thus y is an angle and x is a number.
-1.0 1.0
-1.0
1.0
x
y-1.0 1.0
-1.0
1.0
x
y
Y = sinx
Y = arcsin x
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We must now do this for each of the other trig functions:
1.0 2.0 3.0x
Y = cos x on [0, pi]Range [-1,1]
-1.0 1.0 2.0
-2.0
-1.0
1.0
2.0
3.0
x
y
Y= arccos (x) on [-1,1]range [0, pi]
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arctan(x) has a range of (- pi/2, pi/2)
arccot(x) has a range of (0, pi)
arcsec(x) has a range of [0, pi], y pi/2
arccsc(x) has a range of [- pi/2, pi/2], y 0
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Evaluate without a calculator:
2
1arcsin
x2
1arcsin
Step 1: Set equal to x
Step 2: Rewrite as 2
1sin
x
Step 3: Since the inverse is only defined in quadrants 1 & 4 for sin we are looking for an angle in the 4th quadrant whose value is -1/2.
The value must be - pi/6.
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Evaluate without a calculator:
0arccos
x0arccosStep 1: Set equal to x
Step 2: Rewrite as 0cos x
Step 3: The inverse is only defined in quadrants 1 & 2 for cos so we are looking for the angle whose value is 0.
The value must be pi/2.
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Evaluate without a calculator:
3arctan
x3arctan
3tan x
Step 3: The inverse is only defined in quadrants 1 & 4 for tan so we are looking for the angle whose tan value is sqr(3).
The tan 60 = sqr(3) or x = pi/3
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Evaluate with a calculator:
3.arcsin
x3.arcsin
Check the mode setting on your calculator. Radianshould be highlighted.Press 2nd function sin .3 ) Enter.The answer is .3046
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Inverse Properties
If -1 < x < 1 and - pi/2 < y < pi/2 then sin(arcsin x)=x and arcsin(siny)=y
If - pi/2 < y < pi/2 then tan(arctan x)=x and arctan(tany)=y
If -1 < x < 1 and 0 < y < pi/2 or pi/2 < y < pi then sec(arcsec x)=x and arcsec(secy)=y
On the next slide we will see how these properties are applied
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Inverse Properties Examples
If - pi/2 < y < pi/2 then tan(arctan x)=x and arctan(tany)=y
Solve for x:
Thus: tan arctan(2 3) tan
4x
132 x
2
42
x
x
arctan(2 3)4
x
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Inverse Properties Examples
If where 0 < y < pi/2 find cos y
Solution: For this problem we use the right triangle
Sin(y) = x, thus the opp side must be xand the hyp must be 1, so sin y = x
x 1
By the pythagorean theorem, this makesthe bottom side
21 x21 x
Cos(y) = 21 x
arcsin( )y x
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Inverse Properties Examples
If find tan y
Solution: For this problem we use the right triangle
1
By the pythagorean theorem, this makesthe opp side
114525 22
tan(y) =
2
5
2
1
5sec
2y arc
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Derivatives of the Inverse Trig Functions
21
)arcsin(
u
u
dx
ud
21
)arccos(
u
u
dx
ud
21
)arctan(
u
u
dx
ud
21
)cot(
u
u
dx
uarcd
1
)sec(2
uu
u
dx
uarcd 1
)csc(2
uu
u
dx
uarcd
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Examples Using the Derivatives of the Inverse Trig Functions
21
)arcsin(
u
u
dx
ud
Find the derivative ofarcsin 2x
Let u = 2x du/dx = 2
Note: u’ = du/dx
2 2
arcsin(2 ) 2 2
1 41 2
d x
dx xx
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Examples Using the Derivatives of the Inverse Trig Functions
21
)arctan(
u
u
dx
ud
Find the derivative ofarctan 3x
Let u = 3x du/dx = 3
Note: u’ = du/dx
2
arctan(3 ) 3
1 9
d x
dx x
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Examples Using the Derivatives of the Inverse Trig Functions
Find the derivative of
Letx
x
edx
du
eu
2
2
2
1
)sec(2
uu
u
dx
uarcd
1
2
1
2)sec(4222
2
xxx
x
eee
e
dx
uarcd
2sec( )xarc e
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Some more examples:
3sec arctan sec( )
5x
Solution: Use the right triangle on the coordinate graph
Let
5
3tan
5
3arctan
x
x
Now using the triangle we can find sec x after we find the hyp.
3425953 22 34
5
34)sec( x
find
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Some more examples:
Write the expression in algebraic form x3arctansec
Solution: Use the right triangle
xy
yx
3tan
3arctan
Now using the triangle we can find the hyp.
Letthen
y
3x
1
222 9131 xx 291 x
22
911
91sec x
xy
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Some more examples:
Find the derivative of: 21
arctanarctan)( xxxf
Let u = 21
x
xdx
du
2
1
xxx
xxf
12
1
1
2
1
)( 2
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Please let us know if this presentation has been beneficial.
Thanks.