Intro to exponents edmodo 2013 14
-
Upload
shumwayc -
Category
Technology
-
view
129 -
download
0
Transcript of Intro to exponents edmodo 2013 14
POD 22 AugEvaluate
•5x4; for x = 3
•(-3x)2; for x = 4
•(43 + 25) + 4
POD 29 Aug
• Solve for x1. 2x + 5 = 25
2. 30 + 5x = 50
3. 5x + 3x + 7 = 47
4. 25 = 2x + 5
For Printing
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Exponents determine the number of times you use the
base as a factor.
32 = 3 x 3
54 = 5·5·5·5
11
What if the exponent is zero?What if the exponent is zero?
330334 = 81333 = 27332 = 9331 = 3330 =
Let’s Follow a PatternLet’s Follow a Pattern
=–1
–1
÷3
÷3
–1÷3
–1÷3
xx0=
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
?
Any number other than zero raised to the 0 power is always equal to 1 .
20 = 1,0000 =
100 = 300,0000 =
500 = x0 =
Any number raised to the first power is always equal to that number _itself_ .
11 = 21 = 181 = 141 = 1061 =
xx1= x
Parentheses• When a negative is enclosed in
parentheses the negative with the term
(-2)2 = (-2)(-2)
• When a negative is NOT enclosed in parentheses only the BASE is raised to a power
-22 = - 2·2
Parentheses
When a term is enclosed in parentheses the entire term is raised to the power
(2x)2 =
When a term is not enclosed in parentheses only the base is raised to a power
2x2 =
Parentheses
• When a term is enclosed in parentheses the ______________ is raised to the power
(2x)2 = 2x·2x• When a term is not enclosed in
parentheses _______________ is raised to a power
2x2 = 2·x·x
Lets try some with Numbers and Variables
X2 =
2X2 =
(2x)2 =
y3 = 4xy4 = 6x2y3 =
Lets try some with Numbers and Variables
X2 = x·x2X2 = 2·x·x(2x)2 = 2x·2x y3 = y·y·y4xy4 = 4·x·y·y·y·y6x2y3 = 6·x·x·y·y·y
For Printing
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Now You Try:Z0= __________7,5631 = _________________4x5 = __________(3ab)3 = __________6ab2 = __________9a4b2c3 = ______________
Now You Try:Z0= __________7,5631 = _________________4x5 = __________(3ab)3 = __________6ab2 = __________9a4b2c3 = ______________
Quick Check
• Evaluate1. 52
2. (-5)2
3. -52
4. 50
5. 51
Expand6. (5x)2
7. 5x2
POD 30 Aug
Evaluate•-122
•(-12)2
•121
•120
Extension: Negative ExponentsExtension: Negative Exponents
332 = 9331 = 3330 = 1
Let’s Extend the PatternLet’s Extend the Pattern
–1 ÷3
–1 ÷3
–1 ÷3
33-1 = 1/3
33-2–1
÷3
= 1/9
=xx -1x1
xx –nxxn1=
=xx -1x1
xx –nxxn1=
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
Mat h Zone
A =
L x
W
y = mx + b
3x+ 5 = 14
A = pr 2
To Evaluate Negative Exponents
• Take the Reciprocal of the base.• Change the negative exponent to a
positive exponent.• A negative exponent will always be a
value between 0 and 1. (Fraction or Decimal)
101 10 10-1 1 0.1
102 100 10-2 2 0.01
103 1000 10-3 3 0.001
100 = 1
1
10
10
1
1
100
10
1
10
1
1
1000
21 2 2 2-1
22 2x2 4 2-2
23 2x2x2 8 2-3
12
1
22
1
20 = 1
2
1
4
1