INTERMEDIATE 2 – ADDITIONAL QUESTION BANK UNIT 2 : Statistics You have chosen to study: Please...
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Transcript of INTERMEDIATE 2 – ADDITIONAL QUESTION BANK UNIT 2 : Statistics You have chosen to study: Please...
INTERMEDIATE 2 – ADDITIONAL QUESTION BANK
UNIT 2 :Statistics
You have chosen to study:
Please choose a question to attempt from the following:
1
EXITBack to
Unit 2 Menu
2 3 4 5
STATISTICS : Question 1
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A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
(b) A similar experiment was conducted with a second company. The results for this were….
mean = 12 and standard deviation = 1.88
How does the second company compare to the first?
Get hint
STATISTICS : Question 1
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A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
(b) A similar experiment was conducted with a second company. The results for this were….
mean = 12 and standard deviation = 1.88
How does the second company compare to the first?
nmean
n
Draw a table comparing data
to mean.Then square
values.
2
1
x xSD
n
When comparing data sets always
make comment on the average (which is bigger etc.) and the spread of the data.
What would you like to do now?
(b)The second company has a longer average response time. The smaller standard deviation means their arrival time is more predictable.
STATISTICS : Question 1
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Go to Statistics MenuEXIT
A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
(b) A similar experiment was conducted with a second company. The results for this were….
mean = 12 and standard deviation = 1.88
How does the second company compare to the first?
(a) Mean = 8 3.87SD
What would you like to do now?
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Question 1
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A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
(a)
Mean = (3+5+10+7+7+15+9)7 = 8
1. Calculate mean.
So = 8
and no.pieces of data = n = 7
x
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Question 1
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A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
2. Draw table comparing data to mean.
x
3 -5 25
5 -3 9
10 2 4
7 - 1 1
7 -1 1
15 7 49
9 1 1
(x - )2 = 90x
8x
x x 2x x
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Question 1
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A taxi company was phoned each night of the week and the response time in minutes of their cars were noted. They were ….
3 5 10 7 7 15 9
(a) Find the mean and standard deviation for this data.
3. Use formula to calculate standard deviation.
2
1
x xSD
n
90
6SD
3.87SD
Just found!!
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Question 1
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1. Always compare mean and standard deviation.(b) A similar experiment was
conducted with a second company. The results for this were….
mean = 12 and standard deviation = 1.88
How does the second company compare to the first?
(b)The second company has a
longer average response time.
The smaller standard deviation means their arrival time is more
predictable.
8x 3.87SD What would you like to do now?
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3. Use formula to calculate standard deviation.
2
1
x xSD
n
90
6SD
3.87SD
Check the list of Formulae for the Standard Deviation Formula:
The second formula can be used in the calculator paper.The calculator must be in Stats. Mode to allow the data to be entered.
22
2( )
x( ) or
1 1
xx x nn n
STATISTICS : Question 2
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Weeks of training
Tim
e(s
)
A TV personality takes part in a 20 week training schedule to copy a 100m sprinter. Her times are recorded every 2 weeks and plotted in the graph then a line of best fit is drawn.
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STATISTICS : Question 2
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Weeks of training
Tim
e(s
)
(i) Find the equation of the line in terms of T and W.
(ii) Use answer (i) to predict (a) her time after 12 weeks of training
(b) the week when her time was 11.5secs
(i) Find the equation of the line in terms of T and W.
(ii) Use answer (i) to predict (a) her time after 12 weeks of training
(b) the week when her time was 11.5secs
Use your equation and substitute W = 12.
STATISTICS : Question 2
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Weeks of training
Tim
e(s
) Find gradient and
note intercept of T axis.
Use your equation and substitute T = 11.5
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STATISTICS : Question 2
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Weeks of training
Tim
e(s
)
(i) Find the equation of the line in terms of T and W.
(ii) Use answer (i) to predict (a) her time after 12 weeks of training
(b) the week when her time was 11.5secs
T = -¼ W + 15
12secs.
14 weeks
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1. Find gradient and note intercept of T axis.
(i) Find the equation of the line in terms of T and W.
Go to graph
m = (y2 – y1)(x2 – x1)
(a) 10 - 15 20 - 0
=
Intercept at 15
Equation is T = -¼ W + 15
= -¼
(ii) Use answer (i) to predict
(a) her time after 12 weeks of training
(b) the week when her time was 11.5secs
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Question 2
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2. Use your equation and substitute
W = 12.
(b)(i) If w = 12 then T = -¼ W + 15
becomes T = (-¼ x 12) + 15= -3 + 15
= 12
Time at 12 weeks is 12secs.
(ii) Use answer (i) to predict
(a) her time after 12 weeks of training
(b) the week when her time was 11.5secs
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Question 2
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3. Use your equation and substitute
T = 11.5
(b)(i) If t = 11.5 then T = -¼ W + 15
becomes -¼ W + 15 = 11.5(-15) (-15)
-¼ W = -3.5 x (–4)
W = 14
Reach a time of 11.5sec after 14 weeks.
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1. Find gradient and note intercept of T axis.
m = (y2 – y1)(x2 – x1)
(a) 10 - 15 20 - 0
=
Intercept at 15
Equation is T = -¼ W + 15
= -¼
To find the equation of a line from the graph:
Must Learn:
y = mx + c
gradient intercept
So you need to find these!!
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1. Find gradient and note intercept of T axis.
m = (y2 – y1)(x2 – x1)
(a) 10 - 15 20 - 0
=
Intercept at 15
Equation is T = -¼ W + 15
= -¼
m = verticalhorizontal
Note: Always draw the horizontal before the vertical:
horizontal (+ve)
vertical (-ve)
(a) What percentage liked Shrek but not the Simpsons?
(b) If someone is picked at random what is the probability that
(i) they liked the Simpsons but not Shrek?
(ii) they liked neither?
STATISTICS : Question 3
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Get hint
A sample of 180 teenagers were asked their opinions on the TV series the “Simpsons” & the movie “Shrek” and their responses were displayed in the following table… Like
Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
(a) What percentage liked Shrek but not the Simpsons?
(b) If someone is picked at random what is the probability that
(i) they liked the Simpsons but not Shrek?
(ii) they liked neither?
STATISTICS : Question 3
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Reveal EXIT
A sample of 180 teenagers were asked their opinions on the TV series the “Simpsons” & the movie “Shrek” and their responses were displayed in the following table… Like
Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
Remember all entries in table must add to total sample size
To find probabilities use:
P = no of favourable / no of data
What would you like to do now?
(a) What percentage liked Shrek but not the Simpsons?
(b) If someone is picked at random what is the probability that
(i) they liked the Simpsons but not Shrek?
(ii) they liked neither?
STATISTICS : Question 3
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EXIT
A sample of 180 teenagers were asked their opinions on the TV series the “Simpsons” & the movie “Shrek” and their responses were displayed in the following table… Like
Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
10%
1/12
7/60
What now?
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Question 3
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1. Use P = no of favourable / no of dataLike Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
(a)What percentage liked Shrek but not the Simpsons?
(a) Like Shrek but not Simpsons
= 180 – 126 – 15 – 21
= 18
% = 18/180 = 1/10 = 10%
NB: There are 180 in survey!!
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Question 3
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1. Use P = no of favourable / no of dataLike Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
what is the probability that(i) they liked the Simpsons but not Shrek?
(b)(i) Prob = 15/180 = 1/12
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Question 3
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1. Use P = no of favourable / no of dataLike Simpsons
Like Shrek
Don’t like Simpsons
Don’t like Shrek
126
2115
?
(ii) they liked neither?
(b)(ii) Prob = 21/180 = 7/60
What would you like to do now?
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1. Use P = no of favourable / no of data
(a) Like Shrek but not Simpsons
= 180 – 126 – 15 – 21
= 18
% = 18/180 = 1/10 = 10%
NB: There are 180 in survey!!
Note: To change a fraction to a % multiply by 100%
18180
= x 100% 18180
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1. Use P = no of favourable / no of data
(b)(i) Prob = 15/180 = 1/12
Probability =
Number of favourable outcomes Number of possible outcomes
To calculate simple probabilities:
(b) If a combination is selected at random what is the probability that it is ……
STATISTICS : Question 4
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Get hint
On a college course you have to pick a language plus a
leisure activity from the following lists
LANGUAGE
FRENCH
GERMAN
SPANISH
LEISURE
MUSIC
VIDEO PRODUCTION
BASKETBALL
SWIMMING
(a) Make a list of all possible combinations of courses.
(i) Includes Spanish?
(ii) Includes swimming?
(iii) Doesn’t include French but includes music?
(b) If a combination is selected at random what is the probability that it is ……
STATISTICS : Question 4
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EXIT
On a college course you have to pick a language plus a
leisure activity from the following lists
LANGUAGE
FRENCH
GERMAN
SPANISH
LEISURE
MUSIC
VIDEO PRODUCTION
BASKETBALL
SWIMMING
(a) Make a list of all possible combinations of courses.
(i) Includes Spanish?
(ii) Includes swimming?
(iii) Doesn’t include French but includes music?
Use a tree diagram & “branch out” with
each language.
From each language “branch
out” with each leisure activity.
Now list the pairs
of subjects.
Use your list of possible
combinations to find probabilities.
What would you like to do now?
(b) If a combination is selected at random what is the probability that it is ……
STATISTICS : Question 4
Full solution
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Stats Menu
EXIT
On a college course you have to pick a language plus a
leisure activity from the following lists
LANGUAGE
FRENCH
GERMAN
SPANISH
LEISURE
MUSIC
VIDEO PRODUCTION
BASKETBALL
SWIMMING
(a) Make a list of all possible combinations of courses.
(i) Includes Spanish?
(ii) Includes swimming?
(iii) Doesn’t include French but includes music?
1/3
1/4 1/6
CLICK
GERMAN
FRENCH
SPANISH
BASKETBALL
VIDEO
MUSIC
SWIMMING
BASKETBALL
VIDEO
MUSIC
SWIMMING
BASKETBALL
VIDEO
MUSIC
SWIMMING
(a)French/Music
French/Video
French/Bsktbll
French/Swim
German/Music
German/Video
German/Bsktbll
German/Swim
Spanish/Music
Spanish/Video
Spanish/Bsktbll
Spanish/Swim
Hints
Use a tree diagram & “branch out” with each language.
From each language “branch out” with each leisure activity.
Now list the pairs of subjects.
Hints
Have list of combinations handy.
Remember to simplify.
French/Music
French/Video
French/Bsktbll
French/Swim
German/Music
German/Video
German/Bsktbll
German/Swim
Spanish/Music
Spanish/Video
Spanish/Bsktbll
Spanish/Swim
= 1/3
= 1/4
(b)(i) Prob
(b)(ii) Prob
= 4/12
= 3/12
(b)(iii) Prob = 2/12 = 1/6
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(i) Includes Spanish?
(ii) Includes swimming?
(iii)Doesn’t include French
but includes music?
What is probability:
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GERMAN
FRENCH
SPANISH
BASKETBALL
VIDEO
MUSIC
SWIMMING
BASKETBALL
VIDEO
MUSIC
SWIMMING
BASKETBALL
VIDEO
MUSIC
SWIMMING
(a)French/Music
French/Video
French/Bsktbll
French/Swim
German/Music
German/Video
German/Bsktbll
German/Swim
Spanish/Music
Spanish/Video
Spanish/Bsktbll
Spanish/Swim
No. of possible outcomes
= 3 x 4 = 12
Probability =
Number of favourableNumber of possible
To calculate simple probabilities:
The delivery times for a fast food company are shown in the following cumulative frequency table.
Time No. Deliveries
up to 4 mins 5
up to 8 mins 13
up to 12 mins 37
up to 16 mins 53
up to 20 mins 60
(b) Use the data to construct a cumulative frequency graph.
(c) Use the graph to find the median and semi-interquartile range for this data.
(a) How many deliveries took longer than 16 mins?
STATISTICS : Question 5
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Get hint
The delivery times for a fast food company are shown in the following cumulative frequency table.
Time No. Deliveries
up to 4 mins 5
up to 8 mins 13
up to 12 mins 37
up to 16 mins 53
up to 20 mins 60
(b) Use the data to construct a cumulative frequency graph.
(c) Use the graph to find the median and semi-interquartile range for this data.
(a) How many deliveries took longer than 16 mins?
STATISTICS : Question 5
Full solution
Comments
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Reveal ans
For how many greater than
16 find difference
between end value of
values up to 16.
Median is middle
value- so we want
halfway-point on
frequency axis.
SIQR = ½(Q3 – Q1)
Q1 – 25% point & Q3 – 75% point
What would you like to do now?
The delivery times for a fast food company are shown in the following cumulative frequency table.
Time No. Deliveries
up to 4 mins 5
up to 8 mins 13
up to 12 mins 37
up to 16 mins 53
up to 20 mins 60
(b) Use the data to construct a cumulative frequency graph.
(c) Use the graph to find the median and semi-interquartile range for this data.
(a) How many deliveries took longer than 16 mins?
STATISTICS : Question 5
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= 7
Median = 11 mins SIQR = 2.75 mins
Delivery time(mins)
Cum freq
Q2
11
Q1
8.5
Q3
14
½ of 60 = 30
¼ of 60 = 15
¾ of 60 = 45
(C) Median = 11mins. (c) SIQR = ½(Q3 – Q1) = (14 – 8.5) 2 = 2.75mins
(a) Deliveries taking longer than 16 mins = 60 – 53 = 7
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Time Deliveries
4 5
8 13
12 37
16 53
20 60What would you like to do now?
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Cumulative Frequency
DeliveryTime
60
20
50%
11
Note: In a Cumulative Frequency Diagram:
On y-axis (cumulative frequency)
Q1 at 25%, Q2 at 50%,
Q3 at 75%
And read values from the delivery time scale (x-axis).
End of Statistics