Instrument (Conveyor System)

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    Instrumentation and Measurement

    Techniques

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    1.0 Introduction

    2.0 Application Selection3.0 System Development Methodology

    4.0 Hardware Selection

    - Sensor Selection

    -Working Principle of Sensor

    -DAQ

    -Hardware Setup

    -Design of Conveyor System

    5.0 Software Development

    -Algorithm Flow Chart

    -Calibration

    -Front Panel & Block Diagram

    6.0 Conclusion

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    Introduction & ApplicationSelection

    Objective:*To design and develop an instrument.

    Physical Quantities Selection:

    *Displacement

    *Speed

    Application Selection:

    *Conveyor System

    Sensors Selection:

    *Linear potentiometer

    *Hall-effect sensor

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    System DevelopmentMethodology

    Planning

    Analysis

    Design

    Implementation

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    Hardware Selection

    AdvantagesLinear Potentiometer Hall Effect Sensor

    Easily available. Non-contact operation so there is

    no wear and friction.

    Low cost. Can be used over wider range of

    speed operation.

    Easy to understand and use. Able to measure zero speed.

    High amplitude output. Immune to dust, air, water.

    Proven technology. Wide temperature range.

    Highly repeatable operation.

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    Linear Potentiometer:

    Hall-Effect Sensor:

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    White wire ( To convert analog signal

    to digital signal) connected to the AI0 for linear

    potentiometer sensor and A11 to the

    Hall-Effect sensor

    Red Wire (Supply voltage to sensor)

    Connected to 5V

    Black Wire

    Connected to the ground

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    Linear potentiometer

    Linear potentiometer senses the displacement

    caused by the mass.

    measured and translated into mass reading

    through the LabVIEW program.

    Conveyor belt

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    Hall Effect sensor produce one output perrevolution.

    translated into the speed reading through the

    LabVIEW program.

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    Software Development

    f RPM V mm kg

    No No

    Yes Yes Yes

    Start

    UnderloadOverload OK

    Display

    mass = 5

    1.726

    0.1141 6

    Read mass

    Display

    speed

    = 60

    Read speed

    Stop

    m < 9 kgm > 11 kg m > 9 kg

    = 0.1885

    Display

    speed

    f m/s

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    Displacement(m

    m)

    Voltage(V)

    0 4.90884

    1 2.92276

    2 2.09777

    3 1.52741

    4 1.38482

    5 1.12001

    6 1.03853

    7 0.92650

    8 0.82465

    9 0.69224

    10 0.32558

    y = -0.3382x + 3.3065

    -1

    0

    1

    2

    3

    4

    5

    6

    0 2 4 6 8 10 12

    Voltage,

    (V)

    Displacement, (mm)

    Voltage vs Displacement

    = 0.3382 + 3.3065

    , = 0.3382 /

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    Displacement(mm)

    Voltage(V)

    6 1.038537 0.92650

    8 0.82465

    9 0.69224

    y = -0.1141x + 1.726

    0

    0.2

    0.4

    0.6

    0.8

    1

    1.2

    0 2 4 6 8 10

    Voltage

    ,(V)

    Displacement, (mm)

    Voltage vs DisplacementSample calculation at7mm:

    Gradient, m = -0.1141

    y-intercept, c= 1.726

    = 0.1141 + 1.726

    ,

    = 0.1141 /

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    From Newtons second law:

    F = mg-------(1)From Hookes law:

    F = kx-------(2)

    (1)=(2)mg = kx

    m = (k/g) x

    Let m = 15kg and Xrange = 0.003m

    m = (k / 9.81) (0.003)

    k = 49050 N/m

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    m = ( 49050/9.81)x

    m = 5000x-----(m)

    m = 5x-----(mm)

    Using offset 6 mm,

    x = [(v-c)/m] - 6

    Hence,

    When x = 7.007, m = 5[(7.007) -6] = 5.035kg

    5.035kg will displaced 1 mm. As 3 mm are used, thus it will reach

    max mass of 15.015kg.

    = 5 1.7260.1141 6

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    Displacement (mm) Expected mass reading (kg)

    1 5.035

    2 10.070

    3 15.105

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    The average frequency is about 4 RPS, or 240 RPM. This reading can be verified by anothersensor, which is the tachometer. A tachometer is an instrument measuring the rotation speed of a

    shaft or disk, as in a motor or other machine. The reading shown by the tachometer is about 4

    RPS too.

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    Period,

    T

    Rotational speed,

    =1

    = ()

    = 60

    1 = 60

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    *

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    THANKYOU