Instrument (Conveyor System)
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Transcript of Instrument (Conveyor System)
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Instrumentation and Measurement
Techniques
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1.0 Introduction
2.0 Application Selection3.0 System Development Methodology
4.0 Hardware Selection
- Sensor Selection
-Working Principle of Sensor
-DAQ
-Hardware Setup
-Design of Conveyor System
5.0 Software Development
-Algorithm Flow Chart
-Calibration
-Front Panel & Block Diagram
6.0 Conclusion
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Introduction & ApplicationSelection
Objective:*To design and develop an instrument.
Physical Quantities Selection:
*Displacement
*Speed
Application Selection:
*Conveyor System
Sensors Selection:
*Linear potentiometer
*Hall-effect sensor
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System DevelopmentMethodology
Planning
Analysis
Design
Implementation
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Hardware Selection
AdvantagesLinear Potentiometer Hall Effect Sensor
Easily available. Non-contact operation so there is
no wear and friction.
Low cost. Can be used over wider range of
speed operation.
Easy to understand and use. Able to measure zero speed.
High amplitude output. Immune to dust, air, water.
Proven technology. Wide temperature range.
Highly repeatable operation.
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Linear Potentiometer:
Hall-Effect Sensor:
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White wire ( To convert analog signal
to digital signal) connected to the AI0 for linear
potentiometer sensor and A11 to the
Hall-Effect sensor
Red Wire (Supply voltage to sensor)
Connected to 5V
Black Wire
Connected to the ground
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Linear potentiometer
Linear potentiometer senses the displacement
caused by the mass.
measured and translated into mass reading
through the LabVIEW program.
Conveyor belt
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Hall Effect sensor produce one output perrevolution.
translated into the speed reading through the
LabVIEW program.
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Software Development
f RPM V mm kg
No No
Yes Yes Yes
Start
UnderloadOverload OK
Display
mass = 5
1.726
0.1141 6
Read mass
Display
speed
= 60
Read speed
Stop
m < 9 kgm > 11 kg m > 9 kg
= 0.1885
Display
speed
f m/s
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Displacement(m
m)
Voltage(V)
0 4.90884
1 2.92276
2 2.09777
3 1.52741
4 1.38482
5 1.12001
6 1.03853
7 0.92650
8 0.82465
9 0.69224
10 0.32558
y = -0.3382x + 3.3065
-1
0
1
2
3
4
5
6
0 2 4 6 8 10 12
Voltage,
(V)
Displacement, (mm)
Voltage vs Displacement
= 0.3382 + 3.3065
, = 0.3382 /
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Displacement(mm)
Voltage(V)
6 1.038537 0.92650
8 0.82465
9 0.69224
y = -0.1141x + 1.726
0
0.2
0.4
0.6
0.8
1
1.2
0 2 4 6 8 10
Voltage
,(V)
Displacement, (mm)
Voltage vs DisplacementSample calculation at7mm:
Gradient, m = -0.1141
y-intercept, c= 1.726
= 0.1141 + 1.726
,
= 0.1141 /
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From Newtons second law:
F = mg-------(1)From Hookes law:
F = kx-------(2)
(1)=(2)mg = kx
m = (k/g) x
Let m = 15kg and Xrange = 0.003m
m = (k / 9.81) (0.003)
k = 49050 N/m
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m = ( 49050/9.81)x
m = 5000x-----(m)
m = 5x-----(mm)
Using offset 6 mm,
x = [(v-c)/m] - 6
Hence,
When x = 7.007, m = 5[(7.007) -6] = 5.035kg
5.035kg will displaced 1 mm. As 3 mm are used, thus it will reach
max mass of 15.015kg.
= 5 1.7260.1141 6
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Displacement (mm) Expected mass reading (kg)
1 5.035
2 10.070
3 15.105
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The average frequency is about 4 RPS, or 240 RPM. This reading can be verified by anothersensor, which is the tachometer. A tachometer is an instrument measuring the rotation speed of a
shaft or disk, as in a motor or other machine. The reading shown by the tachometer is about 4
RPS too.
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Period,
T
Rotational speed,
=1
= ()
= 60
1 = 60
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*
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THANKYOU