III. Electromechanical Energy Conversioncadirci/ele361/energy_conversion-1p.pdf ·...
Transcript of III. Electromechanical Energy Conversioncadirci/ele361/energy_conversion-1p.pdf ·...
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III. Electromechanical Energy Conversion
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copper losses core losses(field losses) mechanical losses
dteiRdtidtiVdW telec 2
losses mechanical output energy mechanicalnet mechdW
losses field fldmechelec dWdWdW
fldmechelec dWdWdW
Schematic representation of an electromechanical energy conversion device
Differential energy input from electrical source:
For a lossless magnetic energy storage system:
Differrential energy balance eqn.:
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1. Energy in Magnetic FielddteidWelec
idtdtdNdWelec
NiddWelec
ddWelec F
01
10
00
dd
W
dW
fld
elec
FF
F
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Coenergy
10F dF fldW
11F fldfld WW
with 0 = 0 and F0 = 0
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For a linear magnetic circuit:
1121 F fldfld WW
212
1 R
212
1PF
where R and P are the reluctance and permeance of the magnetic circuit respectively
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2. Energy & Force in Singly-Excited E.M.C device
Electromechanical relay
• Assume mobile armature is initially at open position
• When the coil is excited by i(t), (t) is produced in M.C. and an electromagnetic force ffld is exerted on mobile armature tendingto align it with the densest part of M.F.
• When the armature moves
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Armature Movement
• Slow motion case ( is gradually increased during motion)
• Fast motion case ( is constant during motion)
• Normal motion case
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(i) Slow motion
42210001 AAAAddW fld F F
mechfldelec WWW
Shaded area gives Wmech
F is constant during motion
3110
AAdWelec F
43 AAWWW fldelecmech
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(ii) Fast motion
is constant during motion
mechfldelec WWW
110
AdWelec F
43 AAWWW fldelecmech
Shaded area gives Wmech
4322100
01 F F AAAAAddW fld
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(iii) Normal motion
mechfldelec WWW
Shaded area gives Wmech
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• if dWmech > 0 then electical system does work on the armature
• if dWmech 0 then mechanical system does work on the armature
dxfdW fldmech
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(a) Mechanical force in fast motion
mechfldelec dWdWdW
dxfdWd fldfld F
dxfddW fldfld F
dxx
xWd
xWxdW fldfld
fld
,,,
Note that
So
xW fld ,F
x
xWf fld
fld
,and
is independent of x
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(a) Mechanical force in slow motion
Note that
xWxW fldfld F,FF,
xdWdxWd fldfld F,FF,
dxfddxWd fldfld FFdFF,
dxfxWd fldfld dFF,
So
FF,
xW fld
x
xWf fld
fld
F,and
F is independent of x
dx
xxW
dxW
xWd fldfldfld
,FF
F
,F,F
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For a linear magnetic circuit
F21
fldfld WW 2221
21 PFR
1. When is constant during motion
dxf fld
dR221
2. When F is constant during motion
dxdL
dxf ifld
2
21
21 2
dPF
where R and P are the reluctance and permeance of the magnetic circuit respectively
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Ex-1: Derive an expression for the electromagnetic force ffldproduced by the E.M.D. shown in the figure and then plot ffldagainst x.
Note: Initial gap length is c and i is constant during motion
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Ex-2: For the electromagnet shown below:(a) For V = 120 Vdc, determine the energy stored in magnetic field and the lifting force produced (b) For V = 120 Vac at 60 Hz, determine the average lifting force
produced
Note: Initial gap length is 5 mm, internal resistance of the winding r = 6, N = 300, Ac = Ag = 6 x 6 = 36 cm2.
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3. Rotating Machines
Torque
Te, Nm
Inertia
J, kg m2
Angular Speed, rad/s
Angular Displacement
, radRotational
Motion
Force
f, N
Mass
m, kg
Linear Speedv, m/s
Linear Displacement
x, mLinear Motion
,flde
WT
x
xWf fld
fld
,
F,flde
WT
x
xWf fld
fld
F,
fast motion
slow motion
For flux independent of during motion:
For mmf independent of during motion:
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(a) Singly-excited device
0 tr
For a linear M.C.
ddLiTe
221
remech TP dtd
r
dtdLiPmech
221
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Ex: The self inductance L in the figure as a function of rotor position is given by
L = L0 + L2 cos( 2)where the stator current is i(t) = Imsin(t)
(i) Obtain an expression for electromagnetic torque produced (instantaneous torque)
(ii) Let = rt + 0, find necessary condition for non-zero average torque
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(b) Doubly-excited device
tiMtiL 2111
tiMtiL 1222
dtde 1
1
dt
de 22
2111 MiiL
1222 MiiL
dtd
ddMi
dtdiM
dtd
ddLi
dtdiLe
221
11
11
dtd
ddMi
dtdiM
dtd
ddLi
dtdiLe
112
22
22 1111 irev 2222 irev
rωii
LMML
dd
ii
dtd
LMML
ii
rr
vv
2
1
2
1
2
1
2
1
2
1
2
1
2
1
00
dtd
r
Terminal voltage equation (in matrix form):
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2
1212211 v
viiivivTotal power
rTTTT
dd
dtdiviv
I
LI
ILIRIIVI 2211
Pcu
rrrelec ddLi
ddMii
ddLi
dtdiMi
dtdiiL
dtdiMi
dtdiiLririP
22
22112
11
22
222
11
112221
21 2
Pelec
Total electrical power input:
Copper loss Rate of increase in stored energy in MF + Electr.power converted to mech. en.
(in matrix form)
rωii
LMML
dd
ii
dtd
LMML
ii
rr
vv
2
1
2
1
2
1
2
1
2
1
2
1
2
1
00
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Magnetic stored energy
2211 didiW fld
21222
211 2
121 iMiiLiL
rrrfld ddMii
ddLi
ddLi
dtdiMi
dtdiiL
dtdiMi
dtdiiLP
2122
212
11
22
222
11
11 21
21
dtdW
P fldfld
fldcuelecmech PPPP
rrrmech ddMii
ddLi
ddLiP
2122
212
1 21
21
rrrelec ddLi
ddMii
ddLi
dtdiMi
dtdiiL
dtdiMi
dtdiiLririP
22
22112
11
22
222
11
112221
21 2
remech TP
ddMii
ddLi
ddLiTe 21
222
121 2
121
I
LI
ddT T
e 21
In matrix form:
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Ex1: Te ?
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Ex2: Te ?