IGNOU Mca Network Solved Assignment
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Transcript of IGNOU Mca Network Solved Assignment
MCS-042 Solved Assignment By IGNOU CLOUD (www.ignoucloud.com) Solved By Praveen Soni
IGNOU Solved Assignment By www.ignoucloud.com
Q 1: Assume a data stream is made of “000010” Encode this stream
(i) Manchester
(ii) Differential Manchester
(iii) UNI polar
(iv) Polar NR Z-1
(v) RZ
Also discuss the usefulness of each scheme.
Q 2: (i) Illustrate constellation diagram of 8- PSK and 8- QAM.
Solution-
(ii) Given a 10 bit sequence frame: 1001111001 and a divisor (polynomial)
of 1011, Find the CRC.
Q 3: How are problems of Hidden Station and Exposed Station resolved in
wireless LAN? Explain in detail.
Solution-
There are two fundamental problems associated with a wireless network. Assume that there are four
nodes A, B, C and D. B and C are in the radio range of each other. Similarly A and B are in the radio
range of each other. But C is not in the radio range of A. Now, suppose that there is a transmission
going on between A and B (Figure 2 (a)). If C also wants to transmit to B, first, it will sense the
medium but will not listen to A’s transmission to B because, A is outside its range. Thus, C will create
garbage for the frame coming from A if, it transmits to B. This is called the hidden station problem.
The problem of a station not being able to detect another node because that node is too far away is
called hidden station problem. Now, let us consider the reverse situation called the exposed station
problem. (Figure 2 (b).)
Figure 2: Hidden and exposed station problem
In this case, B is transmitting to A. Both are within radio range of each other. Now C wants
to transmit to D. As usual, it senses the channel and hears an ongoing transmission and
falsely concludes that it cannot transmit to D. But the fact is transmission between C and D
would not have caused any problems because, the intended receivers C and D are in a
different range. This is called exposed station problem.
Q 4: Explain the 3-way handshake method. How is it different from 2-way
handshake method?
Solution
3-Way Handshake
The TCP three-way handshake in Transmission Control Protocol (also called the TCP-
handshake; three message handshake and/or SYN-SYN-ACK) is the method used by TCP set
up a TCP/IP connection over an Internet Protocol based network. TCP's three way
handshaking technique is often referred to as "SYN-SYN-ACK" (or more accurately SYN,
SYN-ACK, ACK) because there are three messages transmitted by TCP to negotiate and start
a TCP session between two computers. The TCP handshaking mechanism is designed so that
two computers attempting to communicate can negotiate the parameters of the network TCP
socket connection before transmitting data such as SSH and HTTP web browser requests.
This 3-way handshake process is also designed so that both ends can initiate and negotiate
separate TCP socket connections at the same time. Being able to negotiate multiple TCP
socket connections in both directions at the same time allows a single physical network
interface, such as ethernet, to be multiplexed to transfer multiple streams of TCP data
simultaneously.
TCP 3-Way Handshake Diagram
Below is a (very) simplified diagram of the TCP 3-way handshake process. Have a look at
the diagram on the right as you examine the list of events on the left.
Synchronize and Acknowledge messages are indicated by a either the SYN bit, or the ACK
bit inside the TCP header, and the SYN-ACK message has both the SYN and the ACK bits
turned on (set to 1) in the TCP header.
TCP knows whether the network TCP socket connection is opening, synchronizing,
established by using the Synchronize and Acknowledge messages when establishing a
network TCP socket connection.
When the communication between two computers ends, another 3-way communication is
performed to tear down the TCP socket connection. This setup and teardown of a TCP socket
connection is part of what qualifies TCP a reliable protocol. TCP also acknowledges that data
is successfully received and guarantees the data is reassembled in the correct order.
Note that UDP is connectionless. That means UDP doesn't establish connections as TCP
does, so UDP does not perform this 3-way handshake and for this reason, it is referred to as
an unreliable protocol. That doesn't mean UDP can't transfer data, it just doesn't negotiate
how the connection will work, UDP just transmits and hopes for the best.
2-way handshake
Connection Establishment 2-way Handshake
Initiator sends connection request (w. id)
Responder sends accept or reject (w. id)
Responder assumes connection exists when it sends the ack
Initiator assumes connection exists when it receives the ack
OK if network service reliable and CO
If not? (consider lost, old conn reqs/ack)
Q 5: How does BGP work? How does it solve the Count to Infinity
problem?
Solution
BGP: The Exterior Gateway Routing Protocol
The purpose of Border Gateway Protocol is to enable two different ASes to exchange routing
information so that, IP traffic can flow across the AS border. A different protocol is needed between
the ASes because the objectives of an interior gateway and exterior gateway routing protocol are
different. Exterior gateway routing protocol such as BGP is related to policy matters. BGP is
fundamentally a distance vector protocol but, it is more appropriately characterised as path vector
protocol.
Instead of maintaining just the cost to each destination, each BGP router keeps track of the path used
[Ref.1]. Neighbouring BGP routers, known as BGP peers exchange detailed information along with
the list of ASes on a path to a given destination rather than record cost information.
The main advantage of using BGP is to solve the count to infinity problem which is illustrated in the
following Figure 4.
In this Figure 4 there are A, B, C, D, E, F, G, H, I, J and K routers.
Now consider G’s routing table. G uses G C D K path to forward a packet to K. As discussed earlier
whenever a router gives any routing information, it provides a complete path.
For ex. From A, the path used to send a packet to K is ABCDK
From B-the path used is BCDK
From C-the path used is CGJK
From E-EFGJK
From H-HIJK.
After receiving all the paths from the neighbours, G will find the best route available. It will outright
reject the path from C and E, since they pass through G itself. Therefore, the choice left is between a
route announced by B and H. BGP easily solves count to infinity problems. Now, suppose C
crashes or the line B-C is down.
Then if B receives, two routes from its 2 neighbours: ABCDK and FBCDK, then these which can be
rejected because it passes through C itself. Other distance vector algorithms make the wrong choice
because, they cannot tell which of their neighbours have independent routes to their destination or not.
Q 6: Explain Diffie Hellman algorithm-with the help of an example.
Solution
Diffie-Hellman is a commonly used public-key algorithm for key exchange. It is generally
considered to be secure when sufficiently long keys and proper generators are used. The
security of Diffie-Hellman relies on the difficulty of the discrete logarithm problem (which is
believed to be computationally equivalent to factoring large integers). Diffie-Hellman is
claimed to be patented in the United States, but the patent expired on April 29, 1997. There
are also strong rumours that the patent might in fact be invalid (there is evidence of it having
been published over an year before the patent application was led). Diffie-Hellman is
sensitive to the selection of the strong prime, size of the secret exponent, and the generator.
The “Diffie-Hellman Method For Key Agreement” allow two hosts to create and share a secret key.
1) First the hosts must get the “Diffie-Hellman parameters”. A prime number, ‘p’ (larger than 2)
and “base”, ‘g’, an integer that is smaller than ‘p’. They can either be hard coded or fetched
from a server.
2) The hosts each secretly generate a private number called ‘x’, which is less than “p – 1”.
3) The hosts next generate the public keys, ‘y’. They are created with the function:
y = g^x % p
4) The two host now exchange the public keys (‘y’) and the exchanged numbers are converted
into a secret key, ‘z’.
z = y^x % p
‘z’ can now be used as the key for whatever encryption method is used to transfer
information between the two hosts. Mathematically, the two hosts should have generated
the same value for ‘z’.
z = (g^x % p)^x' % p = (g^x' % p)^x % p
All of these numbers are positive integers
x^y means: x is raised to the y power
x%y means: x is divided by y and the remainder is returned
Example:
Prime Number p = 353 and primitive root of 353, in this case is g = 3. Let A is sender B is
receives A & B select secret key as XA = 97 and XB = 233. Now A & B computes their public
keys. YA = 3233. Now A & B computes their public keys.
YA = 397 mod 353 = 40
YB = 3233 mod 353 = 248
After exchanging their public keys, A & B can compute the common secret key: A computes:
Z=(YB) mod 253
B computes = 24897 mod 353 = 160
Z = (YA)xbmod353 = 40233 mod 353 = 160
Q 7: What is the utility of digital certificate? How are these signatures
created?
Solution
This is a certificate issued by the Certifying Authority (Figure 11) to the holder of the public key. The
contents of a digital certificate are issued by a CA as, a data message and are always available online.
• Sr. No of the Certificate
• Applicant’s name, Place and Date of Birth, Name of the Company
• Applicant’s legal domicile and virtual domicile
• Validity period of the certificate and the signature
• CA’s name, legal domicile and virtual domicile
• User’s public key
• Information indicating how the recipient of a digitally signed document can verify the sender’s
public key
• CA’s digital signature.
Uses of Digital Signature
• Contracts: The next time you purchase a car, a home, or an insurance policy, you may never
need to meet with an agent or sales representative. You may be able to review and sign all
documents online, and save secure backup copies to your own disk.
• Checks and money orders: Buying online is now easy with a credit card, but digital checks or
money orders (authenticated by secure digital signatures) may be preferable for some transactions,
especially when you don’t want to face a large credit card bill.
• Letters and memos: Businesses already transmit many letters and memos online, especially
those that are only distributed internally. But when a letter or memo needs the weight of a
manager’s signature, it must be printed, signed, duplicated, and distributed manually or through
the mail. Digital signatures will save companies the time and expense of this manual process.
• Approvals: Many kinds of documents are collaborative works, such as legal briefs, contracts,
reports, and others. Using digital signatures, people can collaborate on documents online and
approve final drafts, before/prior to releasing them for use.
CREATION OF DIGITAL SIGNATURES
Ravi works at the company’s certificate authority centre. Ravi can create a digital certificate for
Ram by using Ram’s public key as well as some information Ram (Figure 10).
Ram’s co-workers can verify Ram’s trusted certificate to make sure that his public key truly
belongs to him. In fact, no one at Ram’s company accepts a signature for which there does
not exist a certificate generated by Ravi. This gives Ravi the power to revoke signatures if
private keys are compromised, or no longer needed. There are even more widely accepted
certificate authorities that certify Ravi.
If Ram sends a signed document to Shayam, to verify the signature on the document,
Shayam’s software first uses Ravi’s (the certificate authority’s) public key to check the
signature on Ram’s certificate. Successful de-encryption of the certificate proves that Ravi
created it. After the certificate is de-encrypted, Shayam’s software can check if Ram is in
good standing with the certificate authority and that the certificate information concerning
Ram’s identity has not been altered.
Shayam’s software then takes Ram’s public key from the certificate and uses it to check
Ram’s signature. If Ram's public key de-encrypts the signature successfully, then Shayam is
assured that the signature was created using Ram’s private key, for Ravi has certified the
matching public key. And of course, if the signature is valid, then we know that Mohan didn’t
try to change the signed content.
Q 8: Differentiate between the following:
(i) Leaky Bucket Traffic Shaper and Token bucket Traffic Shaper
(ii) Distance vector routing and Link state routing
Solution
(i) Leaky Bucket Traffic Shaper and Token bucket Traffic Shaper
(ii) Distance vector routing and Link state routing
"Distance Vector" and "Link State" are terms used to describe routing protocols which are
used by routers to forward packets between networks. The purpose of any routing
protocol is to dynamically communicate information about all network paths used to
reach a destination and to select the from those paths, the best path to reach a destination
network. The terms distance vector and link state are used to group routing protocols into
two broad categories based on whether the routing protocol selects the best routing path
based on a distance metric (the distance) and an interface (the vector), or selects the best
routing path by calculating the state of each link in a path and finding the path that has the
lowest total metric to reach the destination.
DISTANCE VECTOR
Distance
Distance is the cost of reaching a destination, usually based on the number of hosts the
path passes through, or the total of all the administrative metrics assigned to the links in
the path.
Vector
From the standpoint of routing protocols, the vector is the interface traffic will be
forwarded out in order to reach an given destination network along a route or path
selected by the routing protocol as the best path to the destination network.
Distance vector protocols use a distance calculation plus an outgoing network interface (a
vector) to choose the best path to a destination network. The network protocol (IPX, SPX,
IP, Appletalk, DECnet etc.) will forward data using the best paths selected.
Common distance vector routing protocols include:
Appletalk RTMP
IPX RIP
IP RIP
IGRP
Advantages of Distance Vector Protocols
Well Supported
Protocols such as RIP have been around a long time and most, if not all devices that
perform routing will understand RIP.
LINK STATE
Link State protocols track the status and connection type of each link and produces a
calculated metric based on these and other factors, including some set by the network
administrator. Link state protocols know whether a link is up or down and how fast it is
and calculates a cost to 'get there'. Since routers run routing protocols to figure out how to
get to a destination, you can think of the 'link states' as being the status of the interfaces
on the router. Link State protocols will take a path which has more hops, but that uses a
faster medium over a path using a slower medium with fewer hops.
Because of their awareness of media types and other factors, link state protocols require
more processing power (more circuit logic in the case of ASICs) and memory. Distance
vector algorithms being simpler require simpler hardware.
A Comparison: Link State vs. Distance Vector
See Fig. 1-1 below. If all routers were running a Distance Vector protocol, the path or
'route' chosen would be from A B directly over the ISDN serial link, even though that
link is about 10 times slower than the indirect route from A C D B.
A Link State protocol would choose the A C D B path because it's using a faster
medium (100 Mb ethernet). In this example, it would be better to run a Link State routing
protocol, but if all the links in the network are the same speed, then a Distance Vector
protocol is better.