Ic In One Shot

105
with ABHISHEK K R B.Tech - Aerospace, Alliance University CBSE Expert | Inventor of RocketPro 6+ Years Teaching Exp | Mentored more than 5000 students Helped 1000s of students get 10 CGPA in CBSE X Force and Laws of Motion In One Shot

Transcript of Ic In One Shot

with

ABHISHEK K RB.Tech - Aerospace, Alliance University

CBSE Expert | Inventor of RocketPro6+ Years Teaching Exp | Mentored more than 5000 studentsHelped 1000s of students get 10 CGPA in CBSE X

Force and Laws of Motion In One Shot

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Balanced & Unbalanced Forces

Momentum & Second law of Motion

Inertia & 1st law of motion

Third law of motion & Conservation of momentum

For

ce &

law

s of

Mot

ion

Force

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Force is a Push or Pull

To push or pull heavy objects more force is required. Thus force has Magnitude

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Force is a Push or Pull

To push or pull heavy objects more force is required. Thus force has Magnitude

Force has direction tooForce is a vector Quantity

Balanced & Unbalanced Forces

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Balanced Forces

In a system, when net force is equal to zero, it is called Balanced Force system

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Unbalanced Forces

In this system, the net force is towards the left and it will cause the box move towards left.

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Unbalanced Forces

In a system, when net force is not equal to zero, it is called Unbalanced Force system

Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.

12 14

9 15

A B

C D

Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.

12 14

9 15

A B

C D

Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.

Newton’s First Law

As the friction force is zero, there is no force applying on the ball to decrease its speed.

The ball will continue to move with the same constant speed.

Thus the Speed of an object cannot be changed without a force.

This is known as Newton’s first law!

Newton’s first law

An object remains in a state of rest or in uniform motion in a straight line unless an external unbalanced force is applied on it.

Mass & Inertia

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

The property of maintaining state of rest or to keep moving with uniform velocity is called inertia of the body.

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

https://www.stickmanphysics.com/stickman-physics-home/forces/

Heavy objects tends to resist more towards change in state of motion.

Objects with greater mass has greater INERTIA.

To decrease its speed

To increase its speed

To resist any change in its state of motion

To decelerate due to friction

A B

C D

Q2. The inertia of an object tends to cause the object

To decrease its speed

To increase its speed

To resist any change in its state of motion

To decelerate due to friction

A B

C D

Q2. The inertia of an object tends to cause the object

Move forward Move backward

Be unaffected Rise upwards

A B

C D

Q3. A water tanker filled up to 2/3 of its height is moving with a uniform speed. On sudden application of the brake, the water in the tank would

Move forward Move backward

Be unaffected Rise upwards

A B

C D

Q3. A water tanker filled up to 2/3 of its height is moving with a uniform speed. On sudden application of the brake, the water in the tank would

Momentum

Force required for motion is directly related to mass and velocity

F ∝ Velocity (v)

F ∝ Mass (m)

We can say that there is a quantity relating mass and velocity affecting force

This Quantity is called Momentum

Momentum can be defined as “mass in motion”

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

SI Unit of momentum is Kgm/s

It is denoted by P.P= mv

Momentum is the product of mass and velocity.

Momentum is a vector Quantity .Its direction is same as direction of velocity

Unchanged Zero

Quadrupled Doubled

A B

C D

Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be

Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be

Unchanged Zero

Quadrupled Doubled

A B

C D

Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be

15000 Kg m/s 15000 Kg Km/hr

54000 Kg m/s 54000 g m/s

A B

C D

Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?

Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?

15000 Kg m/s 15000 Kg Km/hr

54000 Kg m/s 54000 g m/s

A B

C D

Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?

Newton’s 2nd law

Change in momentum is directly proportional to force

F ∝ p2― p1

Change in momentum is directly proportional to force

the force is inversely proportional to the time taken for change of momentum

F ∝ p2― p1

F ∝ 1/t

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

F = ma

DERIVATION

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Newton’s second law of motion gives the measure of force acting on an object as the product of its mass and acceleration

Force applied on an object is the rate of change of momentum

50 N 100 N

200 N 10 N

A B

C D

Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.

Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.

50 N 100 N

200 N 10 N

A B

C D

Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.

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Newton’s 3rd law

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

While swimming

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Action and reaction force are equal in magnitude and opposite in direction. But acceleration of the objects depends upon their masses.

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

In simple terms, “EVERY ACTION HAS AN EQUAL AND OPPOSITE REACTION.”

Weight of the arrow

Arrow pushing against bow string

Air resistance against the bow

Grip of the archers hand on the bow

A B

C D

Q7. An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. What will be the reaction force?

Weight of the arrow

Arrow pushing against bow string

Air resistance against the bow

Grip of the archers hand on the bow

A B

C D

Q7. An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. What will be the reaction force?

Conservation of Momentum

Momentum of Ball a → maua

Momentum of Ball b → mbub

Before Collision

After Collision

Total momentum before collision =maua + mbub

Total momentum after collision = mava + mbvb

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

By newton’s third law

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Force applied by ball a on ball b (Fab) will be

Force applied by ball b on ball a (Fba) will be

FAB = -FBA

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

FAB = -FBA

Solving further, We get

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

We can see that,

The total momentum before collision and total momentum after collision remains same provided no external force acts. This is called Law of Conservation of Momentum.

Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc

We can see that,

The total momentum before collision and total momentum after collision remains same provided no external force acts. This is called Law of Conservation of Momentum.

For an ideal collision, no external force acts on the system.

0.1 m/s 1 m/s

0.01 m/s 0

A B

C D

Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?

Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?

0.1 m/s 1 m/s

0.01 m/s 0

A B

C D

Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?

0.1 m/s 2.5 m/s

5 m/s 0

A B

C D

Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?

Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?

0.1 m/s 2.5 m/s

5 m/s 0

A B

C D

Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?

Q10. A bullet of mass 25 g is horizontally fired with a velocity 200 ms-1 from a pistol of mass 2.5 kg. What is the recoil velocity of pistol?

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