Oxidation and Reduction Definitions of oxidation and reduction Oxidation numbers Redox equations.
IB topic 9 Oxidation-reduction Define oxidation and reduction in terms of electron loss and gain.
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Transcript of IB topic 9 Oxidation-reduction Define oxidation and reduction in terms of electron loss and gain.
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9.2Redox equations
Deduce simple oxidation and reduction half-equations given the species involved in a redox reaction.
2Fe + 3Cl2 2FeCl3
Deduce the oxidation number of an element in a compound.
+ means loss, – gain of e-
Rules Elements Na, O2, S8 = 0 Group 1 = +1 H=+1 O = -2 halides -1 Many exceptions Ox. # add up to the charge on the species In covalent compounds more
electronegative is – ie NH3, CCl4
State the names of compounds using oxidation numbers.
MnO2, FeO, CuCl, Na2O Manganese (IV) oxide, iron (II)
oxide, Copper (I) chloride, sodium oxide
[Cu(H2O)6]2+ [CuCl4]2-
Hexaaquacopper(II) ion Tetrachlorocopper (II) ion
Deduce whether an element undergoes oxidation or reduction in reactions using oxidation numbers.
Ca + Sn2+ Ca2+ + Sn
4NH3 + 5O2 4NO + 6H2O
Disproportionation Cl2 + H2OHCl + HClO
Question 4
Deduce redox equations using half-equations.
Steps Assign O numbers and write half reactions Balance atoms other than H and O Balance O by adding H2O as needed Balance H by adding H+ as needed Balance Charges by adding e- to the +
side Equalize the e- by multiplying Add the half reactions together
Try NO3- + Cu NO + Cu2+
+5, -2, 0 on left +2,-2,+2 on right Cu Cu2+ ox NO3
- NO red 4H+ + NO3
- NO + 2 H2O Cu Cu2+ + 2e- 4H+ + NO3
- + 3e- NO + 2 H2O 8H+ + 2NO3
- + 6e- + 3Cu 2NO + 4H2O + 3Cu2+ + 6e-
Define the terms oxidizing agent and reducing agent.
A substance that gets reduced causes oxidation so it is an oxidizing agent
Identify the oxidizing and reducing agents in redox equations.
Fe2O3 + 3C 2Fe + 3CO2
Fe oxidizing C reducing IO3
- + 5I- + 6H+ 3I2 +3H2O
IO3- oxidizing I- reducing
question 6
9.3Reactivity
Deduce a reactivity series based on the chemical behavior of a group of oxidizing and reducing agents.
More reactive metals lose their e- more readily becoming a strong reducing agent
Zn + CuSO4
Stronger Mg, AL, Zn, Fe, Pb, Cu, Ag simulation
Deduce the feasibility of a redox reaction from a given reactivity series.
Yes or no ZnCl2 + Ag
2FeCl3 + 3 Mg
Cl2 + 2KI question 8
9:4 Voltaic Cells (battery)9:4 Voltaic Cells (battery)
Explain how a redox reaction is used to Explain how a redox reaction is used to produce electricity in a voltaic cellproduce electricity in a voltaic cell
Zn(s) Zn(s) → Zn→ Zn2+2+(aq) + 2e(aq) + 2e-- red. Agent red. Agent
Other half cellOther half cell
CuCu2+2+ + 2e + 2e-- → Cu(s) reduced → Cu(s) reduced
This combination is a voltaic cellThis combination is a voltaic cell
State that oxidation occurs at the State that oxidation occurs at the negative electrode (anode) and negative electrode (anode) and reduction occurs at the positive reduction occurs at the positive
electrode (cathode)electrode (cathode)Which is the anode (where eWhich is the anode (where e-- leave) leave) /cathode?/cathode?
Draw this setup.Draw this setup.
Animation Animation
Draw Zn/ZnDraw Zn/Zn2+2+ and Ag/Ag and Ag/Ag++ and give the and give the potential, show the flow of epotential, show the flow of e--
Where is oxidation and reductionWhere is oxidation and reduction
Connect these half cells with a salt bridgeConnect these half cells with a salt bridge
this is a spontaneous reactionthis is a spontaneous reaction
AnimationAnimation
Question 9Question 9
9:5 Electrolytic cells9:5 Electrolytic cells
Describe, using a diagram, the essential Describe, using a diagram, the essential components of an electrolytic cell.components of an electrolytic cell.
Opposite of a voltaic cellOpposite of a voltaic cell
Requires electrical energyRequires electrical energy
│ │ means + then – in diagramsmeans + then – in diagrams
AnimationAnimation
The power source pushes e- to the – The power source pushes e- to the – electrodeelectrode
-electrode attracts + ions-electrode attracts + ions
-electrode is the cathode cations gain e- -electrode is the cathode cations gain e- so are reducedso are reduced
Show the electrolysis of MgFShow the electrolysis of MgF22
Describe how current is conducted Describe how current is conducted in an electrolytic cellin an electrolytic cell
Do questions 10Do questions 10
Deduce the products of the Deduce the products of the electrolysis of a molten saltelectrolysis of a molten salt
Diagram the electrolysis of molten(melted) Diagram the electrolysis of molten(melted) NaClNaCl
Tell where oxidation and reduction occursTell where oxidation and reduction occurs
Do question 11Do question 11
19.1 Standard electrode 19.1 Standard electrode potentialspotentials
Describe the standard hydrogen electrode.Describe the standard hydrogen electrode.
Standard H cellStandard H cell
Conditions - Pt electrodeConditions - Pt electrode
HH22 gas at 1 atm pressure gas at 1 atm pressure
1 mol dm1 mol dm-3-3 H H++
298 K or 25298 K or 25ooCC
0.00 V0.00 V
Attach a half cell if e- flows to HAttach a half cell if e- flows to H22 it is – it is –
Like Zn which is -0.76 VLike Zn which is -0.76 V
conventionsconventions
Zn(s)/ZnZn(s)/Zn+2+2││H││H++(aq)/1/2 H(aq)/1/2 H22(g) (Pt)(g) (Pt)
Oxidation on left sideOxidation on left side
More – value of electrode potentials give More – value of electrode potentials give off e-off e-
Define the term Define the term standard electrodestandard electrodepotential potential ((E E Ö ) .Ö ) .
relative electrode potential compared under relative electrode potential compared under standard conditions with the standard standard conditions with the standard hydrogen electrodehydrogen electrode
Look at your data bookletLook at your data booklet
19.1.3 Calculate cell potentials 19.1.3 Calculate cell potentials usingusing
standard electrode potentials.standard electrode potentials.Try CrTry Cr22OO77
2- 2- and Br and Br22
Answer 0.26 VAnswer 0.26 V
Predict whether a reaction willPredict whether a reaction willbe spontaneous using standardbe spontaneous using standard
electrode potential values.electrode potential values.
Can a solution of tin II ions reduce a Can a solution of tin II ions reduce a solution of iron III ions?solution of iron III ions?
Yes 0.91VYes 0.91V
Can a solution of SnCan a solution of Sn4+4+ ions reduce Fe ions reduce Fe3+ 3+ to to FeFe
SnSn4+4+ + 2 e- + 2 e- → Sn→ Sn2+2+ E Eoo = +1.33 = +1.33No what does work No what does work
Do question 12Do question 12
19.2 Electrolysis19.2 Electrolysis
Predict and explain the products of Predict and explain the products of electrolysis of aqueous solutions.electrolysis of aqueous solutions.
For water need DC in a dilute solution of For water need DC in a dilute solution of HH22SOSO44
HH++ to H to H22 given off at the – electrode given off at the – electrode
OHOH-- to O to O22 at the + electrode at the + electrode
2H2H22O O 4H 4H++ + O + O22 + 4 e- + 4 e-
Electrolysis of NaClElectrolysis of NaCl(aq)(aq)
- electrode H- electrode H22
+ electrode dilute OH+ electrode dilute OH- - to Oto O22 conc Cl conc Cl-- to Cl to Cl22
Write half reactions Write half reactions
Do question 13Do question 13
Determine the relative amounts of Determine the relative amounts of thethe
products formed during electrolysis.products formed during electrolysis.
Position in the electrochemical seriesPosition in the electrochemical series
+ ions lower in the series will gain e- at the + ions lower in the series will gain e- at the – electrode (cathode) in preference to – electrode (cathode) in preference to those higherthose higher
Hydroxide ions release e- to form oxygen Hydroxide ions release e- to form oxygen and Hand H22O in preference to other anions at O in preference to other anions at
the positive electrodethe positive electrode
In some cases concentrations ( more In some cases concentrations ( more concentrated may be discharged)concentrated may be discharged)
Nature of the electrode C and Pt are inertNature of the electrode C and Pt are inert
List all the cations and anionsList all the cations and anions
Cations lower in the series gain e- more Cations lower in the series gain e- more readilyreadily
Describe the use of electrolysis inDescribe the use of electrolysis inelectroplating.electroplating.
CuSOCuSO4(aq)4(aq) with copper electrodes with copper electrodes
CuCu2+2+ goes to – electrode and plates Cu goes to – electrode and plates Cu
+ electrode Cu goes to Cu+ electrode Cu goes to Cu2+2+(use impure (use impure ore)ore)
ElectroplatingElectroplating
Object to be electroplated is put at the Object to be electroplated is put at the negatinegative ve electrode and is placed in a electrode and is placed in a solution of ions of the metal used to plate solution of ions of the metal used to plate it.it.
Factors affecting relative amountsFactors affecting relative amounts
Charge on the ionsCharge on the ions
NaNa+ + CuCu2+2+ Al Al3+3+ Al takes more energy to Al takes more energy to makemake
Quantity of e- (amperage and time) charge Quantity of e- (amperage and time) charge = current x time= current x time
Do question 14Do question 14