Hw5
3
H.W(5) Problem (5.1): Givens: and Required: [Q] , [S] , [ ] and [ ] Solution: = = 0.03 Δ= 1- = 1-(0.3*0.03) = 0.991 [ [ ] = [ ] [S] = [ ] = [ ] [ ] = [ ] = [ ] [ ] = [ ] = [ ] Problem (5.2): Givens: θ = 60 , , and Required: safety factor
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Transcript of Hw5
H.W(5)
Problem (5.1):
Givens: and
Required: [Q] , [S] , [ ] and [ ]
Solution:
=
= 0.03
Δ= 1- = 1-(0.3*0.03) = 0.991
[ [
] = [
]
[S] = [ ] = [
]
[ ] = [
] = [
]
[ ] = [ ] = [
]
Problem (5.2):
Givens: θ = 60 , , and
Required: safety factor
Solution:
Cos(θ) = C = 0.5 and Sin(θ) = S = 0.866
[T] = [
] = [
]
[
] = [T]*[
] = [
]
From table 1.1 using material carbon epoxy (AS4\3501-6)
and and
By comparing results:
And and
so, F.S =
=
= 8.656
Problem (5.3):
Given: θ = 45 Cos(θ) = C = 0.707 and Sin(θ) = S = 0.707
Required: [ ̅]
[T] = [
] = [
]
[ ̅] = [ ]*[Q]*[T] = [
]
Problem (5.4):
Given: θ = 90 Cos(θ) = C = 0 and Sin(θ) = S = 1
[T] = [
] = [
]
[ ̅] = [ ]*[Q]*[T] = [
]
