How to calculate how much flotation you need in your...
Transcript of How to calculate how much flotation you need in your...
Lesson 5: Level Flotation
1
How to calculate how much flotation
you need in your boat.
For those who are math challenged, this lesson may seem a
bit daunting. Actually all you need to know is how to add,
subtract, multiply and divide. The formulas are not that
complex although at first glance they may seem so. If you
completed the lesson on displacement you can do this one.
I try to break it down into simple easy steps. (So I can
do it.) If you have problems contact me for help.
What do I use for flotation?
Most people use polyurethane foam. Some use polystyrene
foam, that is, styrofoam. There are other foams available
such as polyethylene foam but these are more expensive,
although I have seen it in some boats. Others use air
chambers. Air chambers that are integral with the hull are
not allowed for basic or level flotation. But they are
allowed on manually propelled boats, or boats with 2 HP
(1.49 KW) or less. Also, if this is a manually propelled
boat or 2 HP (1.49 KW) or less, you don't have to pass the
test with any of the air chambers punctured. Foam is a good
solution for most boats, but generally people who build
classic wooden boats don’t want plastic foam in their
boats. In that case they can use balsa, or build air
chambers into the boat or use air bags. There are other
solutions as well. Sometimes wooden boats without engines
will pass without any added flotation. However, if you add
an engine, the odds are you will need some flotation to
support the engine.
If you use foam and the foam is in the bilges, or anywhere
else where it can come in contact with oil, gasoline, or
bilge cleaners then it must meet the standards in the
following chart.
Lesson 5: Level Flotation
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FOAM USED IN THE FOLLOWING PLACES MUST MEET THE PRESCRIBED TESTS:
Engine Room Engine Room
Unless Open to
Atmosphere
Bilge
VAPOR TEST X
24 HR GAS X
30 DAY GAS X
24 HR OIL X
30 DAY OIL X
24 HR BILGE
CLEANER
X
30 DAY BILGE
CLEANER
X
But if you seal the foam in compartments, or in plastic or
fiberglass then you can use any type of foam.
Most builders use 2 pound (91 grams) density foam. That
means that one cubic foot weighs 2 pounds(91 grams) . All
of the examples in this lesson are based on 2 pound (91
grams) density foam.
Two pound density foam will support 62 pounds of weight in
salt water, and 60.4 pounds (27 KG) of weight in fresh
water. Salt water weighs 64 pounds per cubic foot (0.0283
cu m. 29 kg). 64 minus 2 = 62 Fresh water weighs 62.4
pounds per cubic foot. 0.0283 cu m, 28.3 kg) 62.4 minus 2
pounds = 60.4 (27.4 Kg). However, for air chambers you do
not subtract from the density of fresh water. All the
calculations here use 60.4 for fresh water. If the
flotation is calculated for fresh water it will support
more than that in salt water.
Some manufacturers like to use heavier structural foam,
that is, it has better sheer and crushing strength than two
pound, which is easily crushed or broken. In that case they
must know what it weighs, and adjust the formulas for the
density of the foam. For instance, if you used four pound
density foam you would have to subtract four pounds instead
of two from the density of water.
Lesson 5: Level Flotation
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However, you may achieve flotation in
any way you prefer. You are not required to use foam. You
can use other methods as long as the final result is the
same.
Milk Bottles – clever, but not recommended. The boat
failed due to metal caps on the bottles. Caps rusted and
leaked water into the bottles. Had they used plastic sealed
caps it might have passed the test.
Some builders have used flotation bags. They need to be
automatically inflating, but for really small boats this is
a good option. They also need to be fastened to the boat
in such a way that they won’t move or drift away. Actually
this is the most difficult part to accomplish.
Lesson 5: Level Flotation
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Flotation Calculations
To calculate the flotation needed you need to divide the
calculation up into three parts.
Flotation to support the hull and deck (the boat).
Flotation to support the people.
Flotation to support the engine, batteries and machinery.
Determining the amount of flotation needed: Factors used
in calculating the amount of flotation required:
Wh = Dry weight of hull below swamped waterline
Wd = Dry weight of deck and superstructure
We = Dry weight of factory installed equipment
hardware and accessories.
Wm = Dry weight of motor, batteries, & machinery
K = conversion factors for material from Table I in
ABYC H-8. All materials weigh less when in the
water, and some are actually buoyant, so this needs
to be accounted for. For instance wood adds to the
buoyancy, so if your fiberglass boat has wood in it
then the amount of flotation need is less. The table
gives you the factors to determine this.
B = Buoyancy of flotation material in pounds per cubic
foot. (or kg per cubic meter)
G = A percentage of the weight of Machinery (engines,
sterndrives, outboards, etc., usually 75%) For Outboards
See Appendix A at the end of this lesson.
Fb = Amount of Flotation need to support the swamped boat
Fp = Flotation needed to support propulsion equipment
Fc = Flotation needed to support persons and dead weight
B = 62.4 For Air Chambers (28.3 KG)
B = 60.4 For 2 pound density foam (fresh water)(27.4 KG)
Lesson 5: Level Flotation
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Formulas for determining the amount
of Flotation For Basic Flotation
Fb = (Wh x K1) + (Wd x K2) + (0.69 We) / B
B = 62.4 For Air Chambers
B = 60.4 For 2 pound density foam
The boat is an inboard with Fiberglass Hull and some
plywood floors and other parts.
The fiberglass portion of the boat weighs 600 lb (272.16
kg). The plywood going into the boat weighs 120 lbs (32.66
Kg). Various pieces of hardware weigh 50 lbs (22.7 kg).
The engine and battery weigh 900 lb (408.23 kg). The
maximum weight capacity is 2400 lb (1088.6 Kg) and the fuel
tank holds 40 gallons (151.4 L) of gasoline.
So how do you know what these weights are? There are two
ways to determine this. One is to weigh everything before
it goes into the boat. The other is to calculate the
weights based on the known weights of various materials.
For instance if you know that plywood weighs one half pound
per cubic foot, and you put 240 cubic feet into the boat
then you have 120 lb of plywood. Other materials can be
determined the same way. The weight of the engine comes
from the manufacturer’s engine specifications, and the same
for the battery and other equipment. But by far the
simplest way is to simply weigh everything before it goes
in the boat. Also you should weigh the completed boat and
keep a record of the weight. If you do this and over a
period of time ( a year is a good time) see an increase in
weight then you need to add flotation. Boats rarely get
lighter over a model run. Generally they get heavier as
you add equipment and options.
When calculating weights remember that some of the boat
will be submerged and some won’t. For those parts that are
not submerged use the full weight, do not multiply by the
factor. For parts that are submerged use the factor to
calculate the submerged weights.
BASIC FLOTATION EXAMPLE
Wh = 600 lb (272.16 kg) (Fiberglass)
Wd = 120 lbs (32.66 Kg) (Plywood)
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We = 50 lbs (22.7 kg)(Equipment
hardware and Access.)
Weight of the engine, battery, machinery = 900lb(408.23 kg)
K = Factor for each type of material to find submerged wt.
(see Table 1 H-8)
Fb = Flotation to support the swamped boat
Fb = (Wh x K1) + (Wd xK2) + (0.69 x Wp)
B
Fb = (600x0.33)+(120x -0.81)+(0.69x50)
60.4
Fb = (198 - 97.2 + 34.5)
60.4
Fb = 135.3
60.4
Fb = 2.24 Cubic Feet 2 Lb Density Foam (63.4 cu cm)
Fp = Flotation needed to support propulsion equipment
Engine: Weight of Propulsion System including sterndrive
and battery = 900 LB
Fp = G / B
G = 0.75 x installed weight of sterndrives & inboards
Example: Fp = G/B = (900 x.75) /60.4 = 675/60.4
Fp = 11.18 Cubic Ft 2 lb density foam (317 cu cm)
Fc = Flotation needed to support persons and dead weight.
Maximum Weight Capacity = 2400 lb.
Fuel tank = 40 gals = 240 lbs. (gasoline weighs about 6 lb
per gallon)
Fc = .25(Fc1 + Fc2)
B
Fc1 = Maximum Persons Capacity – Fuel Wt. = 2160 lb.
Fc2 = Maximum Weight Capacity - Maximum Persons Capacity =
2400 -2160 = 240 (Correct to 2400-2400 = 0
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Fc = 0.25 (Fc1 + Fc2) = .25((2400-240)
+ (2400 – 2400)
B 60.4
Fc = 540/60.4 = 8.94 Cubic ft 2 lb density foam (253 cu cm)
Total Basic Flotation Requirements:
Ft = Fb + Fp + Fc
2.24 Cu Ft - Round to 2.3 To float hull and deck
11.18 Cu Ft - Round to 11.2 to support engine
8.94 Cu Ft - Round to 9 to support people & dead wt
Ft = 2.3 + 11.2 + 9 = 22.5 Cubic Ft (637 cu cm)
LEVEL FLOTATION Example
See H-8 page 5, 8.8.2
Outboard Powered boat
HP = 140 (104.39 Kw)
MC = Maximum Weight Capacity = 1600 LB (725.75 kg)
PC = Maximum Persons Capacity = 887 LB (402.34 Kg)
Wh = Dry Weight of Hull Material
Whf = Weight of Fiberglass Hull = 500 Lb (226.8 kg)
Whp = Weight of Plywood in Hull = 220 Lb (99.8 kg)
Wd = Weight of deck & equipment = 185 lb 71.7 Kg)
K = Factor for each material to find submerged weight
Dead weight = Maximum Weight Capacity - Persons Capacity –
Engine weight, battery Controls and fuel tank weight.(from
Table 4 col. 6 or S-30 col. 10)
Fb = Flotation to float the swamped boat
Fb= (Wh x K) + Wd)
B
Where Wh x K = (Whf x Kf) + (Whp x Kp)
Fb= (500x 0.33) + (220 x -0.81) + (185)
60.4
Fb= (165-178.2+185)
60.4
Fb= 171.8/60.4 = 2.85 Cu Ft 2 lb density foam (80.7 cu cm)
Lesson 5: Level Flotation
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Calculation for flotation to support swamped engine.
HP = 140: see Appendix A for Table 4 33 CFR and ABYC tables
G = swamped weight from ABYC S-30 Table 1a Col. 4, for
outboards = 453 Pounds
Submerged Battery = 25 LB(S-30 Table 1a, Col. 8) (11.3 kg)
Engine:
Fp = G/B
Fp = (453 + 25) / 60.4
Fp = 478 / 60.4
Fp = 7.91 Cu. Ft. 2 lb density foam (224 cu cm)
Calculation for flotation needed to support persons
capacity and deadweight.
MC = Maximum Weight Capacity = 1600 lb.
140 HP Outboard (From table S-30 Col 10) = 713 lb.
PC = Persons Capacity = 887 lb.
Fc = 1/2(First 550 lb of PC) + 1/12 (Persons Capacity -
550) + .25 (Dead Weight) Divided by 60.4. If the Dead
weight is less than zero, that is, negative, use zero (0).
Fc = 1/2 (550)+ 1/12 (887-550) + .25 (deadweight)
60.4
Fc = 0.5(550) + 0.125(887-550) + (0.25(1600-887-740)
60.4
Fc = 275 +42.125 + 0
60.4
Fc = 317.125 /60.4 = 5.25 Cu Ft (148.7 cu cm)
Total Flotation Requirement
2.85 Cu Ft - round to 3.0 - to float deck & hull
7.91 Cu Ft - round to 6.3 - to float engine & equipment
5.25 Cu Ft - round to 5.3 - to float persons and deadweight
Lesson 5: Level Flotation
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Ft = Fb + Fp + Fc = 3 + 6.3 + 5.6
Ft = 14.6 Cu Ft. (413.4 cu cm)
All of the preceding examples were taken directly from ABYC
H-8 and the engine weights were taken from Table 1a in S-
30.
The amount of flotation for a modified level flotation boat
is calculated the same way as a level flotation boat,
except, there is no battery or fuel tank weight. The
engine weighs 25 lbs.
Sample Problems:
Basic Flotation example
19 foot inboard with fiberglass hull
Wh = Dry weight of hull (fiberglass) = 500 lb (226.8 kg)
Wh = Dry weight of hull (wood) = 200 lb (90.7 kg)
K = conversion factor for fiberglass = 0.33
K = conversion factor for wood = -.81
Wd = Dry Weight of deck = 200 lb (90.7 kg)
Wc = Equipment hard ware and accessories = 62 lb (28.1 kg)
B = Buoyancy of flotation in lb per cubic foot = 60.4
PC = Max Persons Capacity = 1000 lb(453.6 kg)
MC = Max Weight Capacity = 1400 lb(635 kg)
C = Max Weight Capacity–dry wt of engine=700 lb(317.5kg)
Engine (including batteries, drive unit, transmission,
shaft, and propeller) 165 hp inboard
Fuel Capacity = 40 gallons (240 lbs) (151.4 L, 108.9 kg)
There are four steps:
Divide up the boat into three parts, the hull, the
machinery weight, and the persons weight. Calculate the
flotation required for each. Then add up the amounts of
flotation.
Step 1: determine amount of flotation need to support the
boat.
Fb = (Wh X k) + (Wh X K) + Wd + 0.69 W(e)
60.4
Fb = (500 x .33) + (200 x -.81) + 200 + 42.78
60.4
Lesson 5: Level Flotation
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Fb = 203/60.4
Fb = 4.06 cu ft rounded up to 4.1 cubic ft. (116.1 cu cm)
Step 2: determine the amount of flotation to support the
swamped motor.
G = For inboards and sterndrives, 75% of the installed
weight of the engine, drive and battery (inboard), or the
engine, outdrive and battery (sterndrive) - in pounds to
the nearest whole number;
G = swamped weight of the motor = (.75 X 700)
Fp = G / B
Fp = (.75 X 700)/60.4 = 525/60.4=8.69 = 9 cu ft(256 cu cm)
Step 3: Determine flotation to support persons capacity and
dead weight.
PC = 1000 lb
Fc= .25 ( Fc1 + Fc2) /B
Fc1 = the maximum persons weight capacity minus the fuel
weight (fuel weight = six pounds/gallons times the tank
capacity in gallons).
Fc1 = 1000 -240 = 760
Fc2 = dead weight = maximum weight capacity minus maximum
persons weight. A negative number shall be raised to zero.
Fc2 = 1400 -1000 = 400
Fc = .25 ((1000-240) + (1400 – 1000))/B
= .25(760 + 400)/60.4 = 1160/60.4
= 4.8 Cu ft. round to 5 cu feet.
Step 4. Determine the total flotation material.
Ft = Fb + Fp + Fc = 4.1 + 9 + 5 = 18.1 Cu ft(512.5 cu cm)
Lesson 5: Level Flotation
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Level Flotation sample.
17 Foot Fiberglass Outboard Runabout
W(h) = Hull Weight = 800 lb (362.9 Kg)
Wd = Deck Weight = 200 lb (60.6 Kg)
(deck weight includes everything above the gunwale
including windshield, deck hardware and accessories)
W(hp)= Weight of wood in the hull = 0
PC = Maximum Persons Capacity = 900 lb (362.9 Kg)
MC = Maximum Weight Capacity = 1400 lb (635 kg)
HP = Maximum Horsepower Rating = 85 HP (63.38 Kw)
K(f) = conversion factor for fiberglass = 0.33
K(w) = conversion factor for wood
B = Buoyancy of flotation in lb per cubic foot = 60.4
C = Maximum Weight Capacity – Dry weight of engine
battery and portable fuel tank weight, see col 6 in Table
4, or col 10 in Table 1a and 1b.
Step 1: determine flotation to support the boat.
K = conversion factor for fiberglass = .33
Fb = (Wh x K) + Wd / 60.4
Where (Wh x K) = ((Whf x Kf) + (Whp x Kp))
There is no wood so Whp X kw = 0
(Wh x k) = (800 x .33)
This is a level flotation boat so the deck is not
submerged. Therefore use the dry weight of the deck.
Wd = 200 lb (60.6 Kg)
Fb = (800 x .33) + 200 / 60.4
Fb = 264 + 200 / 60.4 = 7.68
Flotation to support the boat =7.7 cu ft (218 cu cm)
Step 2: determine flotation to support the swamped motor.
Fp = (S/B)
S = Swamped weight of engine(Table 4 col 2)=352 lb 159.7 kg
Lesson 5: Level Flotation
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Fp = 352/60.4 = 5.8 cu Ft = 6 cu ft (170 cu cm)
Step 3. determine flotation to support the persons capacity
PC = 900 lb
C = MC – Engine Weight = 1400 – 550 = 850 lb (385.6 kg)
Fc= .5(first 550 lb of PC) +.125(PC-550) + .25(MC-PC-Eng)
60.4
Fc= .5(550) + .125(350) + .25(1400-900-602)
60.4
Fc= (275 + 43.75 + 0)/60.4 = 318.75/60.4 = 5.27
Flotation to support persons capacity= 5.27 cu ft(149 cu m)
Step 4. Determine total Flotation Needed
Ft = Fb + F(m) + F(pc)
Ft = 7.7 + 6 + 5.7 = 19.4 cubic feet (550 cu cm)
Flotation Calculation Data Sheets:
In Appendix B at the end of this lesson are three data
sheets for calculating flotation for outboard boats,
inboard boats, and manually propelled or less than 3 hp
boats. These are intended only as an aide in making
calculations. There may be material on the boat that is
not included on these sheets but that needs to be included
in the calculations.
If you have questions, please contact me.
Lesson 5: Level Flotation
15
Problems that cause the boat to fail
flotation requirements
Use the heaviest production tolerances; Boats grow in
weight. If the boats coming off the line are heavier than
that used in the calculations then the boat will fail.
Watch out for too much flotation. This sounds odd but is
true. Too much flotation in the wrong place can cause the
boat to heel too much, or in some cases roll over.
Be careful of the placement of flotation:
Too much in the bottom can cause the boat to roll over
Too high (out of the water) in the boat. If the boat has
too much flotation down low then flotation that is placed
high on the sides or under the gunwales will not even be
submerged and will provide no buoyancy at all.
Beware of changes in a model without looking at the amount
of flotation. This can result in increased weight or a
different weight distribution which affects the amount and
placement of the flotation.
Problems with foam Flotation material.
Water soaked foams
Foams that don’t foam properly
Too hot
Too cold
Humidity
Dirty &/or un-calibrated guns
Wrong ratios (two part foams)
Follow the foam Manufacturers Instructions
Lesson 5: Level Flotation
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Photos 1 & 2 are the good foam. The foam has expanded
evenly, formed a nice skin on the surface and is uniform
throughout.
Lesson 5: Level Flotation
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This is the bad. This foam was too cold. More than likely
it initially foamed up nicely but being against the skin of
the hull (the white shell) it cooled off quickly and shrunk
back down. So the foam is now about half the cubic footage
that it should have been.
Lesson 5: Level Flotation
19
.
This is just plain ugly. This foam got way too hot during
the exotherm, that is, when the chemical reaction occurs it
gives off heat (exotherm). If it gets too hot then the
cells get very thin walls, get brittle and start breaking.
They expand too much, which leaves foam that looks like
broken glass and it crumbles very easily. It also absorbs
water.
Problem solutions
Do a test shot before putting in the foam.
Check temperature of the shop, the chemicals and the boat.
Follow the foam manufacturer’s instructions.
Clean and calibrate the foam gun every single day.
Use block foam if possible.
Encase the foam.
RECALLS: If you get a recall you will have to make the
following choices.
How do you fix the problem?
More foam?
Or less capacity?
Change capacities and the label or add foam?
Lesson 5: Level Flotation
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Appendix A
Table 4 from 33CFR183
Weights of Outboard Motors and Related Equipment For
Various Boat Horsepower Ratings
Boat Horsepower
Rating
Motor and Control
Weight Battery weight
Full
Portable
Fuel Tank
Weight
column
Dry Swamped Dry Submerged 1+3+5
1 2 3 4 5 6
.01 to 2 25 20 - - - 25
2.1 to 3.9 40 34 - - - 40
4.0 to 7 60 52 - - 25 85
7.1 to 15 90 82 20 11 50 160
15.1 to 25 125 105 45 25 50 220
25.1 to 45 170 143 45 25 100 315
45.1 to 60 235 195 45 25 100 380
60.1 to 80 280 235 45 25 100 425
80.1 to 145 405 352 45 25 100 550
145.1 to 275 430 380 45 25 100 575
275.1 and up 605 538 45 25 100 750
Transoms Designed for Twin Motors
50.1 to 90 340 286 90 50 100 530
90.1 to 120 470 390 90 50 100 660
120.1 to 160 560 470 90 50 100 750
160.1 to 290 810 704 90 50 100 1000
290.1 to 550 860 760 90 50 100 1050
550.1 and up 1210 1076 90 50 100 1400
Below are tables 1a and 1b published in ABYC Industry
Conformity Standard S-30, Outboard Engine and Related
Equipment Weights. It is updated on a five year cycle and
contains the weights for four stroke outboards..
Lesson 5: Level Flotation
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Appendix B:
Outboard Motorboats Over 2 HP (1.49 KW) Fiberglass Wood
Wh = Boat Weight ________ + ________
Wd = Deck Weight ________ + ________
PC = Maximum persons weight ________
Wp = Swamped Motor & Controls + Battery ________ + ________ = ________
From Table 4 33 CFR or ABYC Tables 1a or 1b
Dead Weight = Maximum weight Capacity – Persons Capacity – Motor Controls Battery
Wdw = MC – PC – Wm Ignore if zero or less.
Fb = Flotation for Boat Weight (Wh + Wd) X K / 60.4 = Fb
Factors: Fiberglass 0.33 (cubic feet of 2 pound density
Aluminum 0.63 closed cell foam)
Plywood -0.81
ABS Plastic 0.11 ______ x _____ x K /60.4 = ________
Oak, White -0.18
Oak -0.56
Mahogany -0.72
Fc = Flotation For Persons Weight
Fc For boats over 550 lb PC = (0.5 X 550) + .125 (PC-550) + .25(Wdw)/60.4
275 + _______ + _______/60.4 = ________
Fc For boats with less than 550 lb PC = (0.5 x PC) + .25(Wdw) / 60.4
________ + ________ / 60.4 = ________
Fp = Flotation for swamped motor (Wp ) / 60.4
Wp comes from Table 4 or ABYC ________/ 60.4 = ________
Tables 1a or 1b
Amount of Flotation in Cubic feet Ft = Fb + Fc + Fp
_______ + _______ + ______ = ________
Lesson 5: Level Flotation
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Inboard Motorboats Fiberglass Wood
Wh = Boat Weight ________ + ________
Wd = Deck Weight ________ + ________
PC = Maximum persons weight ________
Wp = dry weight motor + drive + battery = ________
(includes motor, drive, propeller, shaft, battery and transmission)
Fb = Flotation for Boat Weight (Wb + Wd) X K / 60.4 = Fb
Factors: Fiberglass 0.33 (cubic feet of 2 pound density
Aluminum 0.63 closed cell foam)
Plywood -0.81
ABS Plastic 0.11 ______ x _____ x K /60.4 = ________
Oak, White -0.18
Oak -0.56
Mahogany -0.72
Fc = Flotation For Persons Weight
Fc = 0.25 (Fc1 + Fc2) / 60.4
Fc1 = PC – fuel weight 0.25 ( _____ + _______ ) = ________
Fc2 = MC – PC ( ______- _______ ) = ________
Fc = 0.25 (Fc1 + Fc2) / 60.4 0.25 ( _____+ ______ ) /60.4 = ________
Fp = Flotation for swamped motor (0.75 x Wp ) / 60.4
________/ 60.4 = ________
Amount of Flotation in Cubic feet Ft = Fb + Fc + Fp
_______ + _______ + ______ = ________
Lesson 5: Level Flotation
25
Outboard Motorboats 2 HP (1.49 KW) or less. Fiberglass Wood
Wh = Boat Weight ________ + ________
Wd = Deck Weight ________ + ________
PC = Maximum persons weight ________
Wp = Swamped Motor & Controls = ________
From Table 4 33 CFR or ABYC Tables 1a or 1b
Dead Weight = Maximum weight Capacity – Persons Capacity
Wdw = MC – PC Ignore if zero or less.
Fb = Flotation for Boat Weight (Wb + Wd) X K / 60.4 = Fb
Factors: Fiberglass 0.33 (cubic feet of 2 pound density
Aluminum 0.63 closed cell foam)
Plywood -0.81
ABS Plastic 0.11 ______ x _____ x K /60.4 = ________
Oak, White -0.18
Oak -0.56
Mahogany -0.72
Fc = Flotation For Persons Weight
Fc For boats over 550 lb PC = (0.5 X 550) + .125 (PC-550) + .25(Wdw)/60.4
275 + _______ + _______/60.4 = ________
Fc For boats with less than 550 lb PC = (0.5 x PC) + .25(Wdw) / 60.4
________ + ________ / 60.4 = ________
Fp = Flotation for swamped motor (Wp ) / 60.4
Wp comes from Table 4 or ABYC ________/ 60.4 = ________
Tables 1a or 1b
Amount of Flotation in Cubic feet Ft = Fb + Fc + Fp
_______ + _______ + ______ = ________