Honors Chemistry
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Transcript of Honors Chemistry
Honors Chemistry
Chapter 4: Reactions in Aqueous Solutions
4.1 Aqueous Solutions
• Solution – homogeneous mixture• Solute – gets dissolved, often smaller quantity• Solvent – dissolves solute, often greater quantity• Aqueous solution – solvent is water!
• Electrolyte – conducts electricity when dissolved in water
• Strong electrolyte – good conductor• Weak electrolyte – poor conductor• Nonelectrolyte – does not conduct when dissolved
4.1 Aqueous Solutions
• Dissolution process• Solvation – solute surrounded by solvent
molecules• Hydration – solvation with water molecules
• Strong• NaCl (s) Na+ (aq) + Cl- (aq)
• Weak• HF (g) H+ (aq) + F- (aq)
• Equilibrium
4.2 Precipitation Reactions
• Formation of an insoluble product• Solubility Rules
• Always soluble– Alkalai metal salts and ammonium salts– Nitrates, bicarbonates, and chlorates
• Usually soluble– Halides (except Ag+, Hg2+, Pb2+)– Sulfates (except Ag+, Ca2+, Sr2+, Ba2+, Hg2+, Pb2+)
• Usually insoluble– Carbonates, phosphates, chromates, sulfides,
hydroxides
4.2 Ionic Equations
• Molecular Equation• Formulas written out as normal• Pb(NO3)2 (aq) + 2 KI (aq) PbI2 (s) + 2 KNO3 (aq)
• Ionic Equation• Dissolved substances shown as free ions• Pb2+ (aq) + 2 NO3
- (aq) + 2 K+ (aq) + 2 I- (aq) PbI2 (s) + 2 K+ (aq) + 2 NO3
- (aq)
• Net Ionic Equation• Remove “spectator ions”• Pb2+ (aq) + 2 I- (aq) PbI2 (s)
4.2 Ionic Equations
• Try this…• Write a molecular equation, ionic equation, and
net ionic equation for the reaction between silver nitrate and iron (III) chloride
• 3 AgNO3 (aq) + FeCl3 (aq) 3 AgCl (s) + Fe(NO3)3 (aq)
• 3 Ag+ (aq) + 3 NO3- (aq) + Fe3+ (aq) + 3 Cl- (aq)
3 AgCl (s) + Fe3+ (aq) + 3 NO3- (aq)
• Ag+ (aq) + Cl- (aq) AgCl (s)
4.3 Acid-Base Reactions
• Arrhenius definition
• Acid• produces H+ ion in aqueous solution• HCl (g) H+ (aq) + Cl- (aq)
• CH3COOH (l) H+ (aq) + CH3COO- (aq)
• Base• produces OH- ion in aqueous solution• NaOH (s) Na+ (aq) + OH- (aq)
• NH3 (g) + H2O (l) NH4+ (aq) + OH- (aq)
4.3 Acid-Base Reactions
• Properties of Acids• Sour taste (vinegar, citrus fruits)• React with metals to liberate hydrogen gas
• Zn (s) + 2 HCl (aq) ZnCl2 (aq) + H2 (g)
• React with carbonates and bicarbonates
• 2 HCl (aq) + CaCO3 (s) CaCl2 (aq) + H2O (l) + CO2 (g)
• Properties of Bases• Bitter taste• Feel slippery (saponification)
• Indicators – change color in acid / base solutions
4.3 Brønsted Theory
• Define based on movement of H+ ion• Acid = proton donor• Base = proton acceptor
• HCl (g) + H2O (l) H3O+ (aq) + Cl- (aq)• acid base conjugate acid conjugate base
• H3O+ is the hydronium ion• Same as H+ (aq)• Shows a water of hydration
• NH3 (aq) + H2O (l) NH4+ (aq) + OH- (aq)
• base acid CA CB
4.3 Brønsted Theory
• Strong acid• HNO3 + H2O H3O+ + NO3
-
• Weak acid• HBr + H2O H3O+ + Br-
• Diprotic acid• H2SO4 + H2O H3O+ + HSO4
-
• HSO4- + H2O H3O+ + SO4
2-
• Triprotic acid• 3 ionizations, e. g., H3PO4
4.3 Autoprotolysis of Water
• HOH (l) H+ (aq) + OH- (aq)• Water is both a weak acid and a weak base• Using Brønsted theory,• H2O + H2O H3O+ (aq) + OH- (aq)• B A CA CB• [H3O+] = 1.0 x 10-7 M in pure water• Define pH = -log [H3O+] • pH = 7 in pure water• Acid = lower pH; Base = higher pH
4.3 Acid-Base Neutralization
• Acid + base salt + water• HCl (aq) + NaOH (aq) NaCl (aq) + H2O• Ionic equation
• H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) Na+ (aq) + Cl- (aq) + H2O (l)
• Net ionic equation• H+ (aq) + OH- (aq) H2O (l)• All neutralizations reduce to this
• Try this: H2SO4 (aq) + Mg(OH)2 (aq)
4.4 Redox Reactions
• Oxidation-reduction reaction
• Electron transfer reactions
• Oxidation – loss of e- (higher charge)
• Reduction – gain of e- (lower charge)
• 2 Ca (s) + O2 (g) 2 CaO (s)
• Ca goes from neutral to 2+ ..... Oxidation
• O goes from neutral to 2- ..... Reduction
4.4 Half-Reactions
• Separate oxidation from reduction
• 2 Ca (s) + O2 (g) 2 CaO (s)
• 2 Ca 2 Ca2+ + 4 e- oxidation
• O2 + 4 e- 2 O2- reduction
• Ca is reducing agent• Donates e-, gets oxidized
• O is oxidizing agent• Accepts e-, gets reduced
4.4 Half-Reactions
• Try this...• Write half reactions for
Zn + 2 HCl ZnCl2 + H2
• Zn + 2 H+ + 2 Cl- Zn2+ + 2 Cl- + H2
• Cl- ion is a spectator• Ox: Zn Zn2+ + 2 e-
• Red: 2 H+ + 2 e- H2
• Zn is reducing agent, H+ is oxidizing agent
4.4 Oxidation Numbers
• Charge an atom has within a molecule• Free element: ox # = 0• Monatomic ions: ox # = charge• Oxygen: always 2- (except peroxides)• Hydrogen: +1 (except in alkalai hydrides)• Fluorine: always -1• Neutral molecule: all ox #’s add up to 0• Ox #’s can occasionally be fractions
4.4 Oxidation Numbers
• Try this…
• Find oxidation numbers for all elements:
• Al2O3
• H2SO4
• PO43-
• Fe3O4
4.4 Types of Redox Reactions
• Combination Reactions (synthesis)• Two or more substances combine, single product
• S + O2 SO2
• Decomposition Reactions• Compound breaks down into components
• 2 KClO3 2 KCl + 3 O2
• Displacement Reactions• One ion displaces another in a compound
• Zn + 2 HCl ZnCl2 + H2
4.4 Displacement Reactions
• Hydrogen Displacement• IA and IIA metals displace H+ from water
• 2 Na + 2 HOH 2 NaOH + H2
• Most metals displace H+ from acid
• Metal Displacement• Cu + AgNO3 Cu(NO3)2 + Ag
• Activity series shows who can displace whom• p. 134• Cu is higher in series and so can displace Ag
4.4 Redox Reactions
• Halogen Displacement• F > Cl > Br > I
• 2 NaCl + F2 2 NaF + Cl2• NaCl + Br2 NR
• Disproportionation Reactions• Same element is oxidized and reduced
• 2 H2O2 2 H2O + O2
• O starts with 1- charge
• Ends with 2- charge in H2O and 0 charge in O2
4.5 Concentration of Solutions
• Molarity (M)• Number of moles solute in 1 L of solution• n
M = ---- V
• Find the Molarity of 15 g NaCl in 250 mL.• 15 g 1 mol
------ x --------- = 0.256 mol 1 58.5 g
• M = 0.256 mol / 0.250 L = 1.03 M
4.5 Concentration of Solutions
• How would you make 175 mL of a 0.500 M solution of CaCl2?
• n0.500 M = ----------- 0.175 L
• n = 0.0875 mol• 0.0875 mol 111 g
--------------- x -------- = 9.71 g 1 1 mol
4.5 Dilution of Solutions
• Reduce the concentration by adding water
• Moles of solute stay constant
• From M = n/V, we get n = MV
• Since n for soln 1 equals n for soln 2,
• M1V1 = M2V2
• Try this...• How would you prepare 500 mL of a 0.75 M HCl
solution from a 11.7 M stock HCl solution?
4.6 Gravimetric Analysis
• Lab technique based on measuring mass• Used to find percent composition• E.g., find % Cl in NaCl• AgNO3 + NaCl NaNO3 + AgCl• Collect AgCl precipitate and mass• Determine mass of Cl in precipitate• Use it to find percent Cl in original sample• We’ll do this in lab
4.7 Acid-Base Titration
• Titration• solution of known concentration is reacted with
solution of unknown concentration• Reaction must go to completion• Calculate the unknown concentration
• Standard Solution• Solution whose concentration is accurately known• KHP (Potassium Hydrogen Phthalate)• Used to standardize base solution• Base solution then used to titrate an unknown acid
4.7 Acid-Base Titration
• Equivalence Point• Point where acid and base have neutralized• Added in exact stoichiometric ratio• Need an indicator to show end point
• Titration Equation• mol acid = mol base at equivalence point
• MaVa = MbVb
• If we know the Molarity and volume of base, we can measure the volume of acid used and calculate its Molarity
4.8 Redox Titration
• Titration can be done with redox reactions
• Often need to use a reactant whose color changes during the reaction
• Takes the place of an indicator
• Works just like acid-base titration
• End of chapter 4 – Finally!