Hon dacodon

4
Hon da co don 1/4 = 148 1 1 2 3 4 - F 1 2 3 - - - C Standard tuning 1 1 3 0 0 3 3 3 0 0 3 0 1 0 2 1 3 0 0 0 1 0 0 N-Gt 6 F 3 2 1 1 1 0 3 0 1 0 0 1 0 3 0 1 3 1 1 3 0 0 1 0 11 Co hon da co don sot xa Dung o do co sao mot minh phai chang da cung 1 3 0 0 3 3 3 0 3 1 0 2 1 3 0 0 2 0 2 3 0 1 1 16 that tinh hoa niem dau voi ta Co chi gio bay ngang qua 1 0 3 1 2 4 1 0 3 3 1 3 0 0 3 3 3 5 3

Transcript of Hon dacodon

Page 1: Hon dacodon

Hon da co don

1/4

= 148

1123 4-

F

123- - -

C

Standard tuning

1

1

3

0

03 3

3

0

03

01

02

1 3 0

0

0

10

0

N-Gt

6F

3

21

11

0

3

0

10 0 1 0

3

01 3 1 1

3

0

01

0

11

Co hon da co don sot xa Dung o do co sao mot minh phai chang da cung

1

3

0

03 3

3

03 1

02

1 3 0

0

2 0 2

3

0 1 1

16

that tinh hoa niem dau voi ta Co chi gio bay ngang qua

10

3

12 4

10

3

3 1

3

0

03 3

3

5 3

Page 2: Hon dacodon

2/4

21

khe nhe vuot mat tam hon minh nay cau trai that tinh buon lam chi hoi

1

02

1 3 0

0

2 0 2

3

0 1 10

3

04

1 3

26

em

F

1

3

0

03 3

3

0

03

01

02

1 3 0

0

0

10

0

3

21

1

31

Co giot nuoc roi

10

3

0

10 0 1 0

3

01 3 1 1

3

0

01

01

3

0

03

36

tren mi khe nhe tham sot sa trong long hinh nhu nuoc cung biet rang

3

3

03 1

02

1 3 0

0

2 0 2

3

0 1 1 1

3

0

41

nang da xa cach ta Oi giot nuoc dau thuong kia oi cho voi khoc khien

2 41

0

3

3

3

1

3

0

03 3

3

03 1

02

1 3

Page 3: Hon dacodon

3/4

46

ta them buon Vi ta cung da biet rang nang da xa cach ta

0

0

2 0 2

3

0 1 1 1

3

0 2 41

03

3

0

03

51F

3

3

0

03

01

02

1 3 0

0

0

10

0

3

21

11

0

3

0

56

Khi nang lo quay lung ra di

10 0 1 0

3

01 3 1 1

3

0

01

01

3

0

03 3

3

03

61

Dau con chut van vuong trong long thi nguoi yeu oi ta biet rang nang da xa cach

1

02

1 3 0

0

2 0 2 2

3

0 15

1

3

0 2 41

0

3

66

ta Ta om mot chut dau thuong thoi giau that kin mai trong tam hon

3

3

1 1

3

0

03 3

3

03 1

02

1 3 0

0

2 0 2

Page 4: Hon dacodon

4/4

71

vi nguoi yeu oi ta biet rang nang se quen mat ta

2

3

0 1 1 1

3

0 2 41 3

3

1

3

0

03 3

3

0

03

0

76F

1

02

1 3 0

0

0

10

0

3

21

11

0

3

0

10 0 1 0

3

81

01 3 1 1

3

0

03 3

3

0

03

01

02

1 3 0

0

0

10

0

86

= 143 = 139F C

3

21

11

0

3

0

10 0 1 0

3

01 3 1

3

01023