Holt CA Course 1 9-5 Area of Composite Figures Warm Up Warm Up Lesson Presentation Lesson...
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Transcript of Holt CA Course 1 9-5 Area of Composite Figures Warm Up Warm Up Lesson Presentation Lesson...
Holt CA Course 1
9-5 Area of Composite Figures
Warm UpWarm Up
Lesson Presentation
California StandardsCalifornia Standards
PreviewPreview
Holt CA Course 1
9-5 Area of Composite Figures
Warm Up
Find each area. Round to the nearest tenth, if necessary.
1. a rectangle with length 10 cm and width 4 cm
2. a parallelogram with base 18 ft and height 12 ft
3. a triangle with base 16 cm and height 8 cm
4. a circle with radius 5 in.
40 cm2
216 ft2
64 cm2
78.5 in2
Holt CA Course 1
9-5 Area of Composite Figures
MG2.2 Estimate and compute the area of more complex or irregular two-and three-dimensional figures by breaking the figures down into more basic geometric objects.
California Standards
Holt CA Course 1
9-5 Area of Composite FiguresAdditional Example 1A: Finding the Area of
Composite Figures by Adding
Find the shaded area. Round to the nearest tenth, if necessary.
A = bh
A = 12 • 6
A = 72 m2
8 m
8 m
area of the rectangle:
2 m
6 m
Divide the figure into a rectangle and a trapezoid.
2 m
6 m
12 m
4 m
Holt CA Course 1
9-5 Area of Composite FiguresAdditional Example 1A Continued
Find the shaded area. Round to the nearest tenth, if necessary.
8 m
area of the trapezoid:
2 m
6 m
2 m
6 m
A = h(b1 + b2)12
__
A = 2(4 + 2)12
__
A = (12) 12
__
A = 6 m2 Add the area of the rectangle and the area of the trapezoid.total area: A = 72 + 6 = 78 m2.
4 m
Holt CA Course 1
9-5 Area of Composite FiguresAdditional Example 1B: Finding the Area of
Composite Figures by Adding
Find the shaded area. Round to the nearest tenth, if necessary.
A = bh
A = 20 • 8
A = 160 in2
12 in.
area of the rectangle:
20 in.
8 in.
Divide the figure into a rectangle and a semicircle.
8 in.8 in.
Holt CA Course 1
9-5 Area of Composite Figures
area of the semicircle:
A = (r2)12__
A (3.14 • 42)12
__
A (50.24) 12
__
A 25.1 in2
Additional Example 1B Continued
Find the shaded area. Round to the nearest tenth, if necessary.
12 in.
20 in.
8 in.
8 in.
Add the area of the rectangle and the area of the semicircle.total area: A = 160 + 25.1 = 185.1 in2.
Holt CA Course 1
9-5 Area of Composite Figures
A = bh
A = 8 • 9
A = 72 yd2
area of the rectangle:
Check It Out! Example 1A
Find the shaded area. Round to the nearest tenth, if necessary.
Divide the figure into a rectangle and a triangle.
10 yd
9 yd
8 yd
Holt CA Course 1
9-5 Area of Composite FiguresCheck It Out! Example 1A Continued
Find the shaded area. Round to the nearest tenth, if necessary. area of the triangle:
A = bh12__
A = (2 • 9)12
__
A = (18) 12
__
A = 9 yd2
Add the area of the rectangle and the area of the triangle.total area: A = 72 + 9 = 81 yd2
10 yd
9 yd
8 yd
Holt CA Course 1
9-5 Area of Composite Figures
Check It Out! Example 1B
Find the shaded area. Round to the nearest tenth, if necessary.
A = bh
A = 22 • 10
A = 220 m2
12 m
area of the rectangle:
22 m
Divide the figure into a rectangle and a semicircle.
10 m
10 m
Holt CA Course 1
9-5 Area of Composite Figures
area of the semicircle:
A = (r2)12__
A (3.14 • 52)12
__
A (78.5) 12
__
A 39.3 m2
Check It Out! Example 1B Continued
Find the shaded area. Round to the nearest tenth, if necessary.
Add the area of the rectangle and the area of the semicircle.total area: A = 220 + 39.3 = 259.3 m2
12 m
22 m
10 m
10 m
Holt CA Course 1
9-5 Area of Composite FiguresAdditional Example 2: Finding the Area of Composite
Figures by SubtractingFind the shaded area.
A = bh
A = 12 • 9 = 108 ft2
Area of the rectangle:
Area of the triangle:
A = bh12
__
A = • (6)(7)12__
A = • 42 = 21 ft212
__Shaded area:
Subtract the area of the triangle from the area of the rectangle.
A = 108 – 21 = 87 ft2
5 ft
12 ft
6 ft9 ft
Holt CA Course 1
9-5 Area of Composite FiguresCheck It Out! Example 2
Find the shaded area.
A = bh
A = 16 • 8 = 128 in2
Area of the rectangle:
Area of the triangle:
A = bh12
__
A = • (5)(7)12__
A = • 35 = 17.5 in212
__Shaded area:
Subtract the area of the triangle from the area of the rectangle.
A = 128 – 17.5 = 110.5 in2
9 in.
16 in.
5 in.8 in.
Holt CA Course 1
9-5 Area of Composite Figures
Additional Example 3: Landscaping Application
What is the area of the room floor shown in the figure? Round to the nearest tenth.
To find the area, divide the composite figure into a square, a rectangle, and a semicircle.
6 ft
6 ft
12 ft12 ft
18 ft
Holt CA Course 1
9-5 Area of Composite FiguresAdditional Example 3 Continued
A = s2
A = 62 = 36 ft2
Area of the square: 6 ft
6 ft
12 ft12 ft
A = bh
A = 18 • 6 = 108 ft2
Area of the rectangle:
A = r212__
A • 3.14 • (9)212
__
A (254.34)
127.17 ft2
12
__
Area of the semicircle:
18 ft
Holt CA Course 1
9-5 Area of Composite Figures
Additional Example 3 Continued
What is the area of the room floor shown in the figure? Round to the nearest tenth.
6 ft
6 ft
12 ft12 ft
18 ft
The area of the room is approximately 271.2 ft2.
A = 36 + 108 + 127.17 = 271.17 ft2
Area of the room:
Holt CA Course 1
9-5 Area of Composite Figures
Check It Out! Example 3
What is the area of the stage floor shown in the figure? Round to the nearest tenth.
To find the area, divide the composite figure into a square, a rectangle, and a semicircle.
5 ft
5 ft
10 ft10 ft
15 ft
Holt CA Course 1
9-5 Area of Composite FiguresCheck It Out! Example 3 Continued
A = s2
A = 52 = 25 ft2
Area of the square: 5 ft
5 ft
10 ft10 ft
A = bh
A = 15 • 5 = 75 ft2
Area of the rectangle:
A = r212__
A • 3.14 • (7.52)12
__
A (314)
88.3 ft2
12
__
Area of the semicircle:
15 ft
Holt CA Course 1
9-5 Area of Composite Figures
Check It Out! Example 3 Continued
What is the area of the room floor shown in the figure? Round to the nearest tenth.
5 ft
5 ft
10 ft10 ft
15 ft
The area of the room is 188.3 ft2.
A = 25 + 75 + 88.3 = 188.3 ft2
Area of the room:
Holt CA Course 1
9-5 Area of Composite FiguresLesson Quiz: Part l
Find the perimeter and area of each figure. Round to the nearest tenth, if necessary.
1.
2.
111 ft2
188.9 mm2
5 ft3.
45.9 in2
Holt CA Course 1
9-5 Area of Composite Figures
Lesson Quiz: Part ll
4. The figure gives the dimensions of a backdrop for a school play. Find the area of the backdrop.
97 ft2