Hilbert's fifth problem and applicationszoe/GTM/Goldbring-11.pdf · 2011-05-08 · Nonstandard...
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Hilbert’s fifth problem and applications
Isaac Goldbring
UCLA
Geometrie et Theorie des ModelesMay 6, 2011
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 1 / 57
Nonstandard Analysis
1 Nonstandard Analysis
2 Hilbert’s Fifth Problem
3 Local H5
4 Globalizing Locally Compact Local Groups
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 2 / 57
Nonstandard Analysis
Nonstandard Extensions
Start with a mathematical universe V containing all relevantmathematical objects, e.g.
N, R, our topological group G;various cartesian products of the above sets;the elements of the above sets and the power sets of the abovesets;
Then extend to a nonstandard mathematical universe V ∗:To each basic set A, we have its nonstandard extension A∗ ⊇ A;To every function f : A→ B between basic sets, we have thenonstandard extension f : A∗ → B∗.
Transfer Principle
If S is a bounded first-order statement about objects in V , then it istrue in V if and only if it is true in V ∗.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 3 / 57
Nonstandard Analysis
The Transfer Principle in Action
Example
Let (G, ·,1) be a group. Then the following are true in V :(∀x ∈ G)(∃y ∈ G)[(x · y = 1) and (y · x = 1)]
(∀x ∈ G)(x · 1 = 1 · x = x)
(∀x ∈ G)(∀y ∈ G)(∀z ∈ G)[(x · y) · z = x · (y · z)].By transfer, the following are true in V ∗:
(∀x ∈ G∗)(∃y ∈ G∗)[(x · y = 1) and (y · x = 1)]
(∀x ∈ G∗)(x · 1 = 1 · x = x)
(∀x ∈ G∗)(∀y ∈ G∗)(∀z ∈ G∗)[(x · y) · z = x · (y · z)].In other words, (G∗, ·,1) is not only a ∗group, but it is an actual group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 4 / 57
Nonstandard Analysis
Ultrafilters
Definition
Given a set I, a filter on I is a set F ⊆ P(I) such that:∅ /∈ FA,B ∈ F ⇒ A ∩ B ∈ F ;A ∈ F , A ⊆ B ⇒ B ∈ F .
A maximal filter is called an ultrafilter; equivalently, a filter U is anultrafilter if for all A ∈ P(I), either A ∈ U or I \ A ∈ U .
An ultrafilter U is principal if there is i ∈ I such thatU = A ∈ P(I) : i ∈ A.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 5 / 57
Nonstandard Analysis
Ultrapowers
Given a set X and a nonprincipal ultrafilter U on a set I, we setXU := X I/ ∼U , an ultrapower of X ; here f ∼U g if and only ifi ∈ I : f (i) = g(i) ∈ U .We identify X as a subset of XU via the diagonal embeddingx 7→ [(x , x , x , . . .)]U .Then XU serves as a nonstandard extension of X : a functionf : X → Y naturally extends to a function f : XU → YU byf ([(xi)]U ) := [f (xi)]U .The Transfer Principle is more comonly known as the Łostheorem.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 6 / 57
Nonstandard Analysis
Internal Sets
For each basic set X , it is possible to identify P(X )∗ with a subsetof P(X ∗). The elements of P(X )∗ are called internal subsets ofX ∗. Subsets of X ∗ that are not internal are called external.It is the case that A∗ for any A in V is internal, and any set definedfrom internal parameters in a first-order way is internal. (InternalDefinition Principle)In the ultraproduct construction, internal subsets of X ∗ are sets ofthe form
∏U Bi , where Bi ⊆ X for each i .
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 7 / 57
Nonstandard Analysis
Saturation
The particularly useful nonstandard extensions are very rich in acertain technical sense.
Definition
Let κ be an infinite cardinal. We say that V ∗ is κ-saturated if whenever(Oi | i < κ) is a family of internal sets such that any intersection of afinite number of them is nonempty, then the intersection of all of themis nonempty.
We will assume our V ∗ is κ-saturated for a suitably large κ.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 8 / 57
Nonstandard Analysis
An Example of Saturation: Infinitesimals
For i ∈ N, let Oi := x ∈ R∗ | 0 < |x | < 1i . By the internal
definition principle, each Oi is internal.Clearly any finite intersection of the Oi is nonempty and sosaturation yields that there is x ∈
⋂i∈NOi . Such an x is positive
but smaller than any standard real number, i.e. x is aninfinitesimal.Since R is an ordered field and the ordered field axioms arefirst-order, one has that R∗ is an ordered field extension of R.Hence, 1
x is an element of R∗ bigger than any standard realnumber, i.e. 1
x is an infinite element of R.In an ultraproduct with I = N, then [(1,2,3, . . .)]U ∈ N∗ is infiniteand [(1, 1
2 ,13 , . . .)]U ∈ R∗ is infinitesimal.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 9 / 57
Nonstandard Analysis
Infinitesimals in Hausdorff Spaces
Suppose X is a Hausdorff topological space. For any a ∈ X , weset µ(a) to be the intersection of the sets O∗, where O is aneighborhood of a. If a is not isolated, then by saturation we canfind a′ ∈ µ(a) \ a; such an a′ is infinitely close to a.We let Xns :=
⋃a∈X µ(a), the set of nearstandard elements of X ∗.
The Hausdorff axiom implies that µ(a) ∩ µ(b) = ∅ if a 6= b. Thus, ifa′ ∈ Xns, we can write st(a′), read the standard part of a′, for theunique element of X that a′ is infinitely close to. If a,b ∈ Xns aresuch that st(a) = st(b), we write a ∼ b.Important: If a is not isolated in X , then µ(a) is external. To seethis, suppose it were internal. Then the familyO∗ \ µ(a) | O a neighborhood of a of nonempty internal setswould have the finite intersection property (since a is not isolated)yet would have empty intersection.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 10 / 57
Nonstandard Analysis
Continuity and convergence
As an example of the utility of nonstandard extensions, we have thefollowing (intuitive) characterizations of continuity and convergence:
Lemma
Suppose X and Y are Hausdorff spaces, a is an element of X , andf : X → Y is a function. Then f is continuous at a if and only if for everya′ ∈ µ(a), we have f (a′) ∈ µ(f (a)).
Lemma
If X is a Hausdorff space, then a sequence (an) from X converges ifand only if aσ ∼ aν for all σ, ν ∈ N∗ \ N, in which caselimn→∞ an = st(aσ) for any σ ∈ N∗ \ N.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 11 / 57
Nonstandard Analysis
Nonstandard topology
We can characterize the interior and closure of a set in the followinguseful nonstandard way:
Lemma
Suppose that X is a Hausdorff space, F ⊆ X, a ∈ F.a ∈ int(F ) if and only if µ(a) ⊆ F ∗.a ∈ F if and only if µ(a) ∩ F ∗ 6= ∅.
In particular, if b ∈ Xns ∩ F ∗, then st(b) ∈ F.
Compactness also has a nice characterization:
Lemma
Suppose that X is a Hausdorff space. Then F ⊆ X is compact if andonly if F ∗ ⊆ Xns.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 12 / 57
Hilbert’s Fifth Problem
1 Nonstandard Analysis
2 Hilbert’s Fifth Problem
3 Local H5
4 Globalizing Locally Compact Local Groups
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 13 / 57
Hilbert’s Fifth Problem
Hilbert’s Fifth Problem
Definition
A topological group G is locally euclidean if there is a neighborhoodof the identity homeomorphic to some Rn.
Definition
G is a Lie group if G is a real analytic manifold which is also a groupsuch that the maps (x , y) 7→ xy : G ×G→ G and x 7→ x−1 : G→ Gare real analytic maps.
Hilbert’s Fifth Problem (H5)
If G is a locally euclidean topological group, is there a real analyticstructure on G compatible with the topology so that the groupoperations become real analytic?
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 14 / 57
Hilbert’s Fifth Problem
Positive Answers to H5
Linear Case: G can be continuously embedded into Gln(R) forsome n (von Neumann)Abelian Case (Pontrjagin)Compact Case (Weyl)
Theorem (Gleason, Montgomery, Zippin- 1952)
For a locally compact (hausdorff) group G, the following are equivalent:
1 G is locally euclidean;2 G has no small subgroups (NSS), i.e. there is a neighborhood of
the identity containing no nontrivial subgroups of G;3 G is a Lie group.
Nonstandard Exposition of the Full Solution: Hirschfeld (1990)
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 15 / 57
Hilbert’s Fifth Problem
Positive Answers to H5
Linear Case: G can be continuously embedded into Gln(R) forsome n (von Neumann)Abelian Case (Pontrjagin)Compact Case (Weyl)
Theorem (Gleason, Montgomery, Zippin- 1952)
For a locally compact (hausdorff) group G, the following are equivalent:
1 G is locally euclidean;2 G has no small subgroups (NSS), i.e. there is a neighborhood of
the identity containing no nontrivial subgroups of G;3 G is a Lie group.
Nonstandard Exposition of the Full Solution: Hirschfeld (1990)
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 15 / 57
Hilbert’s Fifth Problem
A Nonstandard Exercise
From now on, µ will denote µ(1); we call µ the set of infinitesimals ofG. Observe that µ is a normal subgroup of G∗.
Exercise
G is NSS if and only if µ has no internal subgroups other than 1.
The forward direction follows from the transfer principle.The backward direction follows from saturation.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 16 / 57
Hilbert’s Fifth Problem
A Model-Theoretic Application of H5
Theorem (Pillay-1988)
Suppose that G is a group definable in an o-minimal expansion of(R, <) and dimo-min(G) = n. Then there is a “definable” topology on G,called the t-topology, making G into a topological group, and adefinable t-open set U containing the identity of G such that U isdefinably homeomorphic to a definable open subset of Rn (with theinduced order topology). Consequently, G is an n-dimensional Liegroup.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 17 / 57
Hilbert’s Fifth Problem
One Parameter Subgroups
Definition
A one-parameter subgroup of G (1-ps of G) is a continuous groupmorphism X : R→ G.
Put L(G) := X : R→ G | X is a 1-ps of G.
We have the scalar multiplication map(r ,X ) 7→ rX : R× L(G)→ L(G), where (rX )(t) := X (rt).
We let O denote the trivial 1-ps of G, i.e. O(t) ≡ 1. Then:
0X = O and 1X = X ;r(sX ) = (rs)X .
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 18 / 57
Hilbert’s Fifth Problem
The Case of Lie Groups
Suppose G is a Lie group and X ∈ L(G). Then X is real analyticand so X ′(0) ∈ T1(G). We get a bijection
X 7→ X ′(0) : L(G)→ T1(G)
and the addition operation on L(G) that makes this an R-vectorspace isomorphism is given by
(X + Y )(t) = limn→∞
(X (1n
)Y (1n
))[nt].
Let n = dim G = dimR L(G) and make L(G) a real analyticmanifold so that the linear isomorphisms L(G) ∼= Rn are analyticisomorphisms.Then the exponential map X 7→ X (1) : L(G)→ G yields ananalytic isomorphism from an open neighborhood of O in L(G)onto an open neighborhood of 1 in G.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 19 / 57
Hilbert’s Fifth Problem
Plan of Proof for NSS implies Lie
Suppose G is locally compact and has NSS. One takes the followingsteps to prove that G is a Lie group.
1 Show that for any X ,Y ∈ L(G), there is an X + Y ∈ L(G) given by
(X + Y )(t) = limn→∞
(X (1n
)Y (1n
))[nt]
and that L(G) becomes an R-vector space under this addition andthe aforementioned scalar multiplication. (In this talk, we will justsketch the proof of the existence of X + Y .)
2 Equip L(G) with its compact-open topology and show that L(G)becomes a topological vector space.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 20 / 57
Hilbert’s Fifth Problem
Plan of Proof for NSS implies Lie (cont’d)
3. Show that the exponential map
X 7→ X (1) : L(G)→ G
maps an open neighborhood of O in L(G) onto an openneighborhood of 1 in G. Then since G is locally compact, so isL(G), whence we conclude that dimR(L(G)) <∞. (This alsoshows that G is locally euclidean.)
4. Use the adjoint representation of G on L(G) to conclude that G isa Lie group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 21 / 57
Hilbert’s Fifth Problem
Adjoint Representation
Let Ad : G→ Aut(L(G)) be defined by Ad(g)(X ) = gXg−1, where(gXg−1)(t) := gX (t)g−1. Then Ad is a continuous groupmorphism.Since G/ ker(Ad) continuously embeds into Aut(L(G)) ∼= Gln(R),where n := dimR(L(G)), von Neumann’s Theorem implies thatG/ ker(Ad) is a Lie group.If G is connected (which we may suppose it is), thenker(Ad) = center(G), which is abelian, and hence a Lie group byPontrjagin.Now use a result of Kuranishi which says that if N and G/N areLie groups and there exists a local cross-section G/N G (whichwill exist since G is NSS), then G is also a Lie group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 22 / 57
Hilbert’s Fifth Problem
Powers of Infinitesimals
Since µ is a group, we have that an ∈ µ for any a ∈ µ and n ∈ N. Whatabout infinite powers of a?
Internal Induction
If A ⊆ N∗ is internal, contains 0 and is closed under the successoroperation, then A = N∗.
Let a ∈ µ and let A = σ ∈ N∗ | aσ ∈ µ. Then A contains 0 and isclosed under successor by continuity of multiplication. The problem isthat A is not internal since µ is an external notion. Hence we cannotconclude that aσ ∈ µ for all σ ∈ N∗. In fact, if G has NSS, then aσ /∈ µfor some σ ∈ N∗ \ N.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 23 / 57
Hilbert’s Fifth Problem
Landau Notation
We will need to use the following notation:
Notation
Suppose i ∈ Z∗ and σ ∈ N∗ \ 0.Say i = o(σ) if |i | < σ
n for every n ∈ N;Say i = O(σ) if |i | < nσ for some n ∈ N.
Intuitively, i = o(σ) means that |i|σ is infinitesimal (so |i | is in a strictlysmaller archimedean class than σ) and i = O(σ) means that |i|σ is anelement of Rns (so |i | is not in archimedean class strictly greater thanσ.)
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 24 / 57
Hilbert’s Fifth Problem
Infinitesimal generators of 1-parameter subgroups
Fix σ ∈ N∗ \ N.
Definition
Let G(σ) := a ∈ µ | ai ∈ µ for all i = o(σ).
Lemma
If a ∈ G(σ), then ai ∈ Gns for all i = O(σ).
Proof.
Fix a compact neighborhood U of 1. If ai ∈ U∗ for all i = O(σ), we aredone. Otherwise, let j ∈ N∗ be minimal such that aj /∈ U∗. Observe thatσ = O(j) and aj ∈ Gns. For i = O(σ), write |i | = nj + m with m < j andn ∈ N. Then a|i| = (aj)n · am ∈ Gns (since Gns is a subgroup of G∗).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 25 / 57
Hilbert’s Fifth Problem
Infinitesimal generators of 1-parameter subgroups
Lemma
For a ∈ G(σ), define Xa : R→ G by Xa(t) := st(a[tσ]). Then Xa is a1-ps of G.
Proof.
It is easy to see that Xa is a homomorphism.To see that Xa is continuous, it suffices to check continuity at 0.Fix U a neighborhood of 1 in G and let V be a neighborhood of 1in G such that V ⊆ U.Let A = n ∈ N∗ | ak ∈ V ∗ for all k ∈ Z∗ with |k | < σ
n. ThenA ⊆ N∗ is internal and contains all elements of N∗ \ N byassumption.Thus, by “underflow,” there is n ∈ N ∩ A. Consequently,Xa(t) = st(a[tσ]) ∈ V ⊆ U for t ∈ (−1
n ,1n ).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 26 / 57
Hilbert’s Fifth Problem
Infinitesimal generators of 1-parameter subgroups ofG
Question
Which elements of L(G) are of the form Xa for some a ∈ G(σ)?
Answer
All of them! Suppose X ∈ L(G) and let a := X ( 1σ ) ∈ µ. Then if i = o(σ),
we have ai = X ( iσ ) ∈ µ, whence a ∈ G(σ), and
Xa(t) = st(a[tσ])) = st(X ([tσ]
σ)) = X (t).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 27 / 57
Hilbert’s Fifth Problem
Infinitesimal generators of 1-parameter subgroups ofG
Question
Which elements of L(G) are of the form Xa for some a ∈ G(σ)?
Answer
All of them! Suppose X ∈ L(G) and let a := X ( 1σ ) ∈ µ. Then if i = o(σ),
we have ai = X ( iσ ) ∈ µ, whence a ∈ G(σ), and
Xa(t) = st(a[tσ])) = st(X ([tσ]
σ)) = X (t).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 27 / 57
Hilbert’s Fifth Problem
Infinitesimal Generators of 1-parameter subgroups ofG
One can ask the question “When does Xa = O?” This happens if andonly if ai ∈ µ for all i = O(σ). Those infinitesimals are importantenough to merit a definition.
Definition
Go(σ) := a ∈ µ | ai ∈ µ for all i = O(σ).
So we have Xa = O if and only if a ∈ Go(σ) and observe that1 ∈ Go(σ), Go(σ) ⊆ G(σ) and Go(σ) is closed under inverses.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 28 / 57
Hilbert’s Fifth Problem
Gleason-Yamabe Lemmas
One next wants to show that G(σ) is a subgroup of µ with normalsubgroup Go(σ) and use this to help us put a group law on L(G). To dothis and more, we will need to know more about the growth rates ofpowers of elements of these sets. The ingenious idea of Hirschfeldwas to translate the very technical lemmas of Gleason and Yamabeinto clear and concise statements about such growth rates.
Lemma
Let a1, . . . ,aσ be an internal sequence in G∗ such that allai ∈ Go(σ). Then a1 · · · aσ ∈ µ;If a ∈ G(σ) and b ∈ Go(σ), then (ab)i ∼ ai for all i ≤ σ;Suppose a,b ∈ G(σ) are such that ai ∼ bi for all i ≤ ν. Thena−1b ∈ Go(σ).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 29 / 57
Hilbert’s Fifth Problem
Consequences of the Gleason-Yamabe Lemmas
The following theorem follows rather easily from the aforementionedconsequences of the Gleason-Yamabe Lemmas.
Theorem
G(σ) is a group and Go(σ) is a normal subgroup;The quotient group G(σ)/Go(σ) is abelian;For a,b ∈ G(σ), Xa = Xb if and only if a−1b ∈ Go(σ);The surjective map a 7→ Xa : G(σ)→ Go(σ) induces a bijectionaGo(σ) 7→ Xa : G(σ)/Go(σ)→ L(G).
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 30 / 57
Hilbert’s Fifth Problem
Group Law on L(G)
We make L(G) into an abelian group with the operation +σ so that theaforementioned bijection is an abelian group isomorphism. Morespecifically, Xa +σ Xb := Xab, or in other words,(X +σ Y )(t) = st((X ( 1
σ )Y ( 1σ ))[σt]). Using the Gleason-Yamabe lemmas
again, one can prove the following:
Fact
If σ, ν ∈ N∗ \ N, then X +σ Y = X +ν Y for all X ,Y ∈ L(G).
Corollary
X + Y exists in L(G), i.e. for every t ∈ R, we havelimn→∞(X ( 1
n )Y ( 1n ))[nt] exists.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 31 / 57
Hilbert’s Fifth Problem
Yamabe’s Theorem
Theorem (Yamabe)
If G is a locally compact group, then there is an open subgroup G′ of Gsuch that G′ is a generalized Lie group, that is, G′ is the projective limitof a sequence of Lie groups. More precisely, for every neighborhood Uof the identity in G′, there is a compact normal subgroup H of G′ suchthat G′/H is a Lie group.
The proof actually shows that there are arbitrarily small H such thatG′/H is NSS. It then follows from the H5 that G′/H is a Lie group.
Yamabe’s theorem is crucial in Hrushovski’s work on approximatesubgroups.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 32 / 57
Hilbert’s Fifth Problem
An Application: Gromov’s Theorem
Theorem (Gromov)
Let G be a finitely generated group of polynomial growth. Then G isvirtually nilpotent.
Let X be the asymptotic cone of the Cayley graph of G. ThenL := Isom(X ) is locally compact with its compact-open topology.One can use Yamabe (and other facts) to show that L is a Liegroup with finitely many connected components.Using that L is a Lie group, namely NSS and that L/ ker(Ad)embeds into a linear group (so one can use Jordan’s theorem onfinite subgroups of Gln and the Tits alternative), one gets asurjective homomorphism H → Z, where [G : H] <∞. This is thekey step in the proof of the theorem.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 33 / 57
Local H5
1 Nonstandard Analysis
2 Hilbert’s Fifth Problem
3 Local H5
4 Globalizing Locally Compact Local Groups
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 34 / 57
Local H5
What is a local group?
Definition
A local group is a tuple (G,1, ι,p) where:G is a hausdorff topological space with distinguished element1 ∈ G;ι : Λ→ G is continuous, where Λ ⊆ G is open;p : Ω→ G is continuous, where Ω ⊆ G ×G is open;1 ∈ Λ, 1 ×G ⊆ Ω, G × 1 ⊆ Ω;p(1, x) = p(x ,1) = x ;if x ∈ Λ, then (x , ι(x)) ∈ Ω, (ι(x), x) ∈ Ω, and
p(x , ι(x)) = p(ι(x), x) = 1;
if (x , y), (y , z) ∈ Ω and (p(x , y), z), (x ,p(y , z)) ∈ Ω, then
p(p(x , y), z) = p(x ,p(y , z)).Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 35 / 57
Local H5
The Local H5
The Local H5
Is every locally euclidean local group locally isomorphic to a Lie group?
Jacoby gave a “proof” of a positive answer to the local H5 in 1957.Jacoby’s proof was invalidated by Plaut in the early ’90s.We adapt the nonstandard methods employed by Hirschfeld togive a proof of a positive answer to the Local H5.Salvaging the Local H5 was a necessary endeavor. For example,the solution of Hilbert’s Fifth Problem for cancellative semigroupson manifolds rested on the truth of the Local H5.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 36 / 57
Local H5
A Simple Example of a Local Group
Let G = (−1,1). Then G is a local group under addition, where wetake Λ = G and Ω = (x , y) ∈ G | x + y ∈ G.
More generally, if H is a topological group and U is an openneighborhood of the identity, then we obtain a local group G := U,where the local group operations are those inherited from H,Λ = x ∈ G | x−1 ∈ G and Ω = (x , y) ∈ G ×G | xy ∈ G.
These are very special types of local groups, namely the globalizablelocal groups.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 37 / 57
Local H5
Further Notions Associated to Local Groups
Definition
Suppose G is a local group.1 G is locally euclidean if there is an open neighborhood of 1 in G
homeomorphic to some Rn;2 G is a local Lie group if G admits a real analytic structure such
that the maps ι and p are real analytic;3 Let U be an open neighborhood of 1 in G. Then the restriction of
G to U is the local group G|U := (U,1, ι|ΛU ,p|ΩU), where
ΛU := Λ ∩ U ∩ ι−1(U) and ΩU := Ω ∩ (U × U) ∩ p−1(U).
4 G is globalizable if there is a topological group H and an openneighborhood U of 1H in H such that G = H|U.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 38 / 57
Local H5
Not every local group is globalizable
Consider the local Lie group given by G = R,
Ω = (x , y) ∈ R2 | |xy | 6= 1, Λ = G \ 12,1,
with multiplication and inversion
p(x , y) =2xy − x − y
xy − 1, ι(x) =
x2x − 1
.
(Note that 0 is the neutral element.) Then G is not globalizable sincep(x ,1) = p(1, x) = 1 for all x 6= ±1.
Let U = |x | < 12. Then x 7→ x
x−1 : U → R shows that G|U isglobalizable.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 39 / 57
Local H5
The Local H5-Two Forms
Local H5-First Form
If G is a locally euclidean local group, then some restriction of G is alocal Lie group.
Local H5-Second Form
If G is a locally euclidean local group, then some restriction of G isglobalizable. (In short: Is G locally isomorphic to a group?)
The equivalence of the two forms follows from the positive solution tothe original H5 and the fact (due to Cartan) that every local Lie grouphas a restriction which is the restriction of a global Lie group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 40 / 57
Local H5
What was wrong with Jacoby’s Proof?
We say that G is globally associative if, given any finitesequence of elements from G, if there are two ways of introducingparentheses such that both products thus formed exist, then thetwo products are in fact equal.Jacoby’s Theorem 8 essentially claims that every local group isglobally associative.This is not true in general. In fact, it is a theorem of Mal’cev that alocal group is globally associative if and only if it is globalizable.Olver constructs local Lie groups which are associative up tosequences of length n for a given n but which are not associativefor sequences of length n + 1.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 41 / 57
Local H5
Associativity
Suppose a,b, c,d reside in a local group G and a(b(cd)) and((ab)c)d) are both defined. Why aren’t they necessarily equal, asJacoby thought they were?
The usual calculation:
a(b(cd)) = (ab)(cd) = ((ab)c)d .
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 42 / 57
Local H5
Associativity
Suppose a,b, c,d reside in a local group G and a(b(cd)) and((ab)c)d) are both defined. Why aren’t they necessarily equal, asJacoby thought they were?
The usual calculation:
a(b(cd)) = (ab)(cd) = ((ab)c)d .
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 42 / 57
Local H5
Associativity
Suppose a,b, c,d reside in a local group G and a(b(cd)) and((ab)c)d) are both defined. Why aren’t they necessarily equal, asJacoby thought they were?
a(b(cd)) = (ab)(cd) = ((ab)c)d .
Problem: (ab)(cd) may not be defined!
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 43 / 57
Local H5
Jacoby’s Paper
Why did it take so long for the flaw in Jacoby’s proof to be discovered?
His paper was written in Quine’s New Foundations.Of the 106 propositions in his paper, more than half say “ProofOmitted.”“A proof is omitted and no reference is given when it is believedthat a persion familiar with the classical theory of topologicalgroups can readily supply the proof. Frequently, the main difficultyis in finding a suitable statement of the local version of a globaltheorem; once the proper form is found the alteration of the proofis trivial. A proof is omitted and a reference is given in case theglobal version cannot yet be considered as classical.”
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 44 / 57
Local H5
Theorem 8
If G is a local group, if n,m ∈ N and if O ∈ ψG, then (i) for allA ∈ Φ(G,n + m),A ∈ Φ(G,n) ∩ Φ(G,m) and Am · An = Am+n; (ii) for all
A ∈ Φ(G,O,n) ∩ Φ(G,O,m)
so that A ⊆ A · A and Am · An ⊆ O, A ∈ Φ(G,O,n + m); (iii) for all
A ∈ Φ(G,O,n), A′ ∈ Φ(G,O,n)
and (A′)n = [An]′; (iv) for all A ∈ Φ(G,B,n) and B ∈ Φ(G,O,m),
A ∈ Φ(G,O,mn)
and Amn ⊆ Bm; (v) for all A ∈ Φ(G,O,mn), A ∈ Φ(G,O,m),Am ∈ Φ(G,O,n) and (Am)n = Amn.
Proof Omitted.Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 45 / 57
Local H5
Theorem 8
If G is a local group, if n,m ∈ N and if O ∈ ψG, then (i) for allA ∈ Φ(G,n + m),A ∈ Φ(G,n) ∩ Φ(G,m) and Am · An = Am+n; (ii) for all
A ∈ Φ(G,O,n) ∩ Φ(G,O,m)
so that A ⊆ A · A and Am · An ⊆ O, A ∈ Φ(G,O,n + m); (iii) for all
A ∈ Φ(G,O,n), A′ ∈ Φ(G,O,n)
and (A′)n = [An]′; (iv) for all A ∈ Φ(G,B,n) and B ∈ Φ(G,O,m),
A ∈ Φ(G,O,mn)
and Amn ⊆ Bm; (v) for all A ∈ Φ(G,O,mn), A ∈ Φ(G,O,m),Am ∈ Φ(G,O,n) and (Am)n = Amn.
Proof Omitted.Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 45 / 57
Local H5
Another example:
Theorem 9
If G is a local group, if O ∈ ΨG and if a, A, a · A ⊆ O, then[x : A : a · x ] maps A#D homeomorphically onto (a · A)#D; theinverse is
[x : a · A : a′ · x ].
Similarly, if b, B, B · b ⊆ O, then [x : B : x · b] maps B#D
homeomorphically onto (B · b)#D; the inverse is [x : B · b : x · b′].Finally, if C ⊆ O, then [x : C : x ′] maps C#D homeomorphically ontoC′#D; the inverse is [x : C′ : x ′].
Proof omitted.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 46 / 57
Local H5
Another example:
Theorem 9
If G is a local group, if O ∈ ΨG and if a, A, a · A ⊆ O, then[x : A : a · x ] maps A#D homeomorphically onto (a · A)#D; theinverse is
[x : a · A : a′ · x ].
Similarly, if b, B, B · b ⊆ O, then [x : B : x · b] maps B#D
homeomorphically onto (B · b)#D; the inverse is [x : B · b : x · b′].Finally, if C ⊆ O, then [x : C : x ′] maps C#D homeomorphically ontoC′#D; the inverse is [x : C′ : x ′].
Proof omitted.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 46 / 57
Local H5
A Way Around Global Associativity
It will be the case that we can “unambiguously multiply” sequences ofelements of any length, provided the elements are close enough to theidentity, as we now explain.
Definition
Let a1, . . . ,an,b ∈ G with n ≥ 1. We define the notion (a1, . . . ,an)→ bby induction on n as follows:
(a1)→ b iff a1 = b;(a1, . . . ,an+1)→ b iff for every i ∈ 1, . . . ,n, there existsb′i ,b
′′i ∈ G such that (a1, . . . ,ai)→ b′i , (ai+1, . . . ,an+1)→ b′′i ,
(b′i ,b′′i ) ∈ Ω, and b′i · b
′′i = b.
We say that a1 · · · an is defined if there exists a (necessarily unique)b ∈ G such that (a1 . . . ,an)→ b. If ai = a for each i , we say that an isdefined.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 47 / 57
Local H5
The Sets Un
Terminology
If W ⊆ Λ and ι(W ) ⊆W , we say that W is symmetric.For a set A, A×n := A× · · · × A︸ ︷︷ ︸
n times
;
Lemma
There are open symmetric neighborhood Un of 1 for n > 0 such thatUn+1 ⊆ Un and for all (a1, . . . ,an) ∈ U×n
n , a1 · · · an is defined.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 48 / 57
Local H5
G∗
Set µ := µ(1) ⊆ G∗. Note that µ× µ ⊆ Ω∗ and that µ is a group withthe induced multiplication from G∗. Here are some importantobservations that allow one to adapt Hirschfeld’s methods to the localgroup setting:
If (a,b) ∈ Ω and a′ ∈ µ(a) and b′ ∈ µ(b), then (a′,b′) ∈ Ω∗ anda′b′ ∈ µ(ab).If a ∈ G∗ns and b ∈ µ, then (a,b), (b,a) ∈ Ω∗ and ab,ba ∼ a.For any a ∈ G and a′ ∈ µ(a), if an is defined for some n ∈ N, then(a′)n is defined and (a′)n ∈ µ(an). In particular, the partial functionpn : G G given by pn(a) = an, if an is defined, has an opendomain and is continuous.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 49 / 57
Globalizing Locally Compact Local Groups
1 Nonstandard Analysis
2 Hilbert’s Fifth Problem
3 Local H5
4 Globalizing Locally Compact Local Groups
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 50 / 57
Globalizing Locally Compact Local Groups
A Central Question
Bad Question
Which local groups are globalizable?
Better Question
Which local groups are “locally” globalizable? In other words: Whichlocal groups are locally isomorphic to groups?
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 51 / 57
Globalizing Locally Compact Local Groups
A Central Question
Bad Question
Which local groups are globalizable?
Better Question
Which local groups are “locally” globalizable? In other words: Whichlocal groups are locally isomorphic to groups?
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 51 / 57
Globalizing Locally Compact Local Groups
Locally Compact Local Groups
Theorem (van den Dries, G.)
If G is a locally compact local group, then G is locally isomorphic to agroup.
Remarks
1 By Yamabe’s theorem, it follows that every locally compact localgroup is locally isomorphic to a generalized Lie group.
2 The above theorem was proven for local Lie groups by Cartan andholds for locally euclidean local groups as a corollary of theaffirmative solution to the local H5.
3 The above theorem is optimal in the sense that the locallycompact assumption cannot be removed. Indeed, there are localBanach-Lie groups which are not locally isomorphic to groups.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 52 / 57
Globalizing Locally Compact Local Groups
Ingredient #1: A Theorem of Swierczkowski
In the proof of the above theorem, we use the following result, which isa special case of a more general result do to Swierczkowski.
Fact
If there is a surjective strong morphism G→ L|V , where L is a Liegroup and V is a symmetric open neighborhood of 1 in L, then G islocally isomorphic to a topological group.
(A morphism f : G→ H is strong if, for all a,b ∈ G, we have (a,b) ∈ ΩGif and only if (f (a), f (b)) ∈ ΩH , in which case f (ab) = f (a)f (b).)
Proof Idea
Use “local group cohomology” to identify the obstruction toglobalizability. In the setting of our fact, this cohomology can bereformulated into a statement about H2(L) and H2(L) = 0 for a simplyconnected Lie group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 53 / 57
Globalizing Locally Compact Local Groups
Ingredient #2: A Local Yamabe
Theorem (G.)
If G is locally compact, then there is a restriction G|U of G and acompact normal subgroup N of G|U such that (G|U)/N has NSS.
By the above theorem, given locally compact G, we can assume,without loss of generality, that there is a compact subgroup N of Gsuch that G/N is NSS.By the solution to the local H5, we have that G/N is locallyisomorphic to a Lie group L.Thus the surjective strong morphism G→ G/N restricts to asurjective strong morphism G|U → L|V for appropriate U and V .Thus, by Swierczkowski, we have that G|U (and hence G) islocally isomorphic to a group.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 54 / 57
Globalizing Locally Compact Local Groups
A Key Nonstandard Ingredient
Lemma
Suppose V is a neighborhood of 1 in G. Then V contains a compactsubgroup H of G and a neighborhood W of 1 in G such that everysubgroup of G contained in W is contained in H.
To see this, fix an internally open neighborhood W of 1 containedin µ.By the local Gleason-Yamabe Lemmas (see next slide), for everyinternal sequence E1, . . . ,Eν of internal subgroups of G∗
contained in W , we have that E1 · · ·Eν is defined and contained inµ.Let S be the union of all such E1 · · ·Eν . Then S is an internalsubgroup of G∗ contained in µ and every internal subgroup of G∗
contained in W is contained in S.Let H be the internal closure of S in G∗. Use transfer with this Hand W .
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 55 / 57
Globalizing Locally Compact Local Groups
A Nonstandard Gleason-Yamabe Lemma
Lemma
Suppose ν > N and a1, . . . ,aν ∈ µ is an internal sequence such thatai ∈ Go(ν) for all i ∈ 1, . . . , ν. Then a1 · · · aν is defined anda1 · · · aν ∈ µ.
The proof that a1 · · · aν ∈ µ if a1 · · · aν is defined mimics the proof ofthe global version of the lemma and is a consequence of theGleason-Yamabe Lemmas. We will now indicate how to prove thata1 · · · aν is defined.
Fix an internal E ⊆ µ. We will prove the following:
Claim
If b1, . . . ,bν is an internal sequence such that bji is defined and bj
i ∈ Efor all i , j ∈ 1, . . . , ν, then b1 · · · bν is defined.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 56 / 57
Globalizing Locally Compact Local Groups
A Nonstandard Gleason-Yamabe Lemma (cont’d)
Claim
If b1, . . . ,bν is an internal sequence such that bji is defined and bj
i ∈ Efor all i , j ∈ 1, . . . , ν, then b1 · · · bν is defined.
We prove the claim by internal induction on ν. At the induction step,the induction hypothesis allows us to assume that b1 · · · bν is definedand bi · · · bν+1 is defined for every i ∈ 2, · · · , ν + 1. By the first partof the proof of the Lemma, we can conclude, for every i ∈ 1, . . . , ν
(b1 · · · bi ,bi+1 · · · bν+1) ∈ µ× µ ⊆ Ω∗,
which by the transfer of the associativity condition is enough toconclude that b1 · · · bν+1 is defined.
The claim finishes the proof of the theorem by taking E to be theinternal set of all aj
i where i , j ∈ 1, . . . , ν.Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 57 / 57
Globalizing Locally Compact Local Groups
L. van den Dries and I. GoldbringGlobalizing locally compact local groupsJournal of Lie Theory 20 (2010), 519-524.
I. GoldbringHilbert’s fifth problem for local groupsAnnals of Math 172 (2010), 1269-1314.
J. HirschfeldThe nonstandard treatment of Hilbert’s fifth problemTransactions of the AMS 321 (1990), 379-400.
R. JacobySome theorems on the structure of locally compact local groupsAnnals of Math. 66 (1957), 36-69.
P. OlverNon-associative local Lie groupsJournal of Lie Theory 6 (1996), 23-51.
Isaac Goldbring ( UCLA ) Hilbert’s fifth problem and applications GTM May 6, 2011 57 / 57