Helen Spiropoulos Benjamin Mills Nicoleta Bikrogiannis Jessica El-chaar.

•Helen Spiropoulos•Benjamin Mills

•Nicoleta Bikrogiannis•Jessica El-chaar

•Models the mycareer website (www.mycareer.com.au)

•This database models the real world process of searching and applying for jobs. It can be applied both to job seekers and recruiters who are looking to increase the efficiency of sorting and searching their data.•Allows jobseekers to search for and apply for jobs•Jobs can be searched via a range of attributes such as salary, location, description, date of posting etc

•Job seekers must register in order to apply for jobs•Jobs must belong to a location and sector•Recruiters can search for applicants who have applied to certain jobs within a chosen sector and notify them of future listings

LocIDLocCityLocCountry

Location

CanEmailCanFirstNameCanLastNameCanSexCanBirthYear

Candidate

SecIDSecTitleSecDesc

Sector

JobID*CanEmail*

Application

JobIDJobPostDateJobSalaryJobPositionLocID*SecID*JobDesc

Job

SQL Queries on a Single Entity/ Table

Projecting tables’ contents using ‘SELECT’

select * select * fromfrom carnie_mycareer_candidate;carnie_mycareer_candidate;

select sectitle, secdesc from select sectitle, secdesc from carnie_mycareer_sectorcarnie_mycareer_sector;;

Selecting Everything in a table

Selecting a couple of columns

from a table

canemail canfirstname canlastname canSex canbirthyear

[email protected] Chris Carnie M 08-01-1981

[email protected] David Saddington M 21-06-1980

[email protected] Katie Lenehan F 04-04-1978

[email protected] Sussie Kelly F 24-11-1969

[email protected] Ron Howard M 01-01-2000

secTitle secDesc

Accounting All aspects of accounting disipline

IT IT industry including sales, technical, support

Administration Reception, admin and supporting roles

Construction Building, Plumbing, Electrical, Labouring

Retail Shop assistance, customer service

Restrict using ‘WHERE’

** Show all male candidates

Restricts the rows shown

select * from carnie_mycareer_candidate where cansex = 'M';

canEmail canFirstName

canLastName canSex canBirth



[email protected] Katie Lenehan F 04-04-1978

[email protected] Sussie Kelly F 24-11-1969


canEmail canFirstName

canLastName canSex canBirth




Project and Restrict combo

Can use to project a combination of columns and rows.

Example:

List the last name and email address of all male candidates over 30yrs

select canlastname,canemail

from carnie_mycareer_candidate

where canbirthyear < 1977 and cansex = 'M';

canLastName canEmail

Carnie [email protected]

Howard [email protected]

IS NULL

List the last name and email address of the candidates where the candidate has no email address entered.

select canlastname, canemail from carnie_mycareer_candidate where canemail is null;

canlastname | canemail ------------------+----------(0 rows)

There are no null entries so nothing appears in the table!

IS NOT NULL

List the last name and email address of the candidates who have an email address.

select canlastname, canemail from carnie_mycareer_candidate where canemail is not null;

canLastName canEmail

Carnie [email protected]

Saddington [email protected]

Lenehan [email protected]

Kelly [email protected]

Howard [email protected]

IN

Used when you want to return various values. Example;

List the job position and salary of all jobs position available from Sydney, Canberra and Wellington.

select Jobposition, jobsalary from carnie_mycareer_job where locid in (1,2,5) ;

It’s the same as doing the below but easier!

Select Jobposition, Jobsalary from carnie_mycareer_job where locid = 1 OR locid = 2 OR locid = 5;

jobPosition jobSalary

Senior 50000

CFO 120000

Jr 45000

Reception 20000

Team Member 45000

2IC 60000

NOT IN

Used when you want to exclude various values. Example;

List the job position and salary of all jobs position available except those from Sydney, Canberra and Wellington.

select Jobposition, jobsalary from carnie_mycareer_job where locid not in (1,2,5) ;

It’s the same as doing the below but easier!

Select Jobposition, Jobsalary from carnie_mycareer_job where locid <> 1 AND locid <> 2 and locid <> 5;

jobPosition jobSalary

Graduate 38000

Team Member 85000

Logistics 75000

ORDERING COLUMNS

The order stated after the select statement is the order that the Columns will appear. Example;

select canfirstname, canlastname from CARNIE_MYCAREER_CANDIDATE;

select canfirstname, canlastname from CARNIE_MYCAREER_CANDIDATE;

canFirstName canLastName

Chris Carnie

David Saddington

Katie Lenehan

Sussie Kelly

Ron HowardcanLastName canFirstName

Carnie Chris

Saddington David

Lenehan Katie

Kelly Sussie

Howard Ron

ORDER ROWS: ‘ORDER BY’

List the Lastnames and Firstnames of all candidates. Order the candidates in alphabetical order by their last name.

select canlastname, canfirstname from CARNIE_MYCAREER_CANDIDATE ORDER BY canlastname;

canLastName canFirstName

Carnie Chris

Howard Ron

Kelly Sussie

Lenehan Katie

Saddington David

CALCULATING

PostgreSQL can even do calculations (Such as divide, times and present them for you! Maybe you want to work out how much money the jobs available will be earning per week instead of per year! (Assumption that there are 52 paid weeks per year)

select jobposition, jobsalary / 52 AS SalaryPerWeek

FROM CARNIE_MYCAREER_JOB ;

‘AS’ allows you to name your calculation results to whatever you wish. In this case we rename it to salaryperweek

jobPosition SalaryPerWeek

Senior 961

CFO 2307

Jr 865

Reception 384

Graduate 730

Team Member 1634

.. etc …

Two ways to use count:

COUNT(*) – This is used to count ALL of the rows. Remember * means everything…

Example: How many candidates are registered?

Select count(*) from CARNIE_MYCAREER_CANDIDATE;

COUNT(NameofCollumn) – This can be used to count the number of non null values in the column. See the next slide …

BUILT IN FUNCTIONS: COUNT

count

5

The second way to use count:

COUNT(NameofCollumn) – This can be used to count the number of non null values in the column. Here is an example of using it with DISTINCT in order to see how many different types of values are in a specified collumn.

Example: How many different countries does MyCareer cater to?

Select count(distinct loccountry) from CARNIE_MYCAREER_LOCATION ;

If we did not use the distinct, it would return the same values as COUNT(*) since we have no NULL data values in this database.Thus COUNT(Collumn) had no use for us in this example.

BUILT IN FUNCTIONS: COUNT

count

4

OTHER BUILT IN FUNCTIONS: MAX, MIN, AVG & SUM

The above built in functions are mostly only useful when dealing with numbers such as price, salaries, quantities etc.

What is the highest Salary?

select MAX(jobsalary) from carnie_mycareer_job;

What is the name of the job of the lowest Salary?

select MIN(jobsalary) from carnie_mycareer_job;

What is the average Salary?

select AVG(jobsalary) from carnie_mycareer_job;

SUM (jobsalary) could be used to add all of the salaries together.

Max

120000

Min

20000

Avg

59777.7777777778

LIKE – PATTERN MATCHING

List all candidates with a last name starting with ‘S’

select canfirstname, canlastname from CARNIE_MYCAREER_CANDIDATE where canlastname LIKE 'S%';

List all candidates with a first name which contains ‘ie’

select canfirstname, canlastname from CARNIE_MYCAREER_CANDIDATE WHERE canfirstname LIKE '%ie%';


David Saddington


Katie Lenehan

Sussie Kelly

LIKE – PATTERN MATCHING

List all candidates with ‘i’ as the fourth letter in their first name

SELECT canfirstname, canlastname FROM CARNIE_MYCAREER_CANDIDATE WHERE canfirstname LIKE '___i%';

List all candidates who do not have ‘i’ in their first name

select canfirstname, canlastname from CARNIE_MYCAREER_CANDIDATE WHERE canfirstname NOT LIKE '%i%‘ AND canfirstname NOT LIKE '%I%';


Chris Carnie

David Saddington

Katie Lenehan


Ron Howard

DISTINCT

Distinct removes duplicate rows. For example:

List the different countries where jobs are available.

SELECT distinct loccountry FROM CARNIE_MYCAREER_LOCATION ;

locCountry

Australia

Iraq

New Zealand

USA

INSERTING ROWS

INSERT INTO CARNIE_MYCAREER_CANDIDATE VALUES ('[email protected]', 'Robert', 'Pratt', 'M', '09-04-1963');

… OR …

INSERT INTO CARNIE_MYCAREER_CANDIDATE (canemail, canfirstname, canlastname, cansex,canbirthyear) VALUES ('[email protected]', 'Robert', 'Pratt', 'M', '09-04-19-63');

canemail canfirstname canlastname canSex canbirthyear

[email protected] Robert Pratt M 09-04-1963

… etc …

Foreign Keys & Natural Joins

The Natural Join

SELECT jobid, jobsalary, jobposition, locid, secid, canemail FROM carnie_mycareer_job NATURAL JOIN carnie_mycareer_application;

jobid jobsalary jobposition Locid secid appid canemail

1 50000 Senior 1 1 1 [email protected]



2 120000 CFO 1 1 4 [email protected]

3 45000 Jr 1 2 5 [email protected]

5 38000 Graduate 3 1 6 [email protected]




8 60000 2IC 2 2 10 [email protected]

8 60000 2IC 2 2 11 [email protected]

9 75000 Logistics 4 3 12 [email protected]

9 75000 Logistics 4 3 13 [email protected]

Cross Product Joins

SELECT jobid, jobsalary, jobposition, locid, secid, canemail FROM carnie_mycareer_job, carnie_mycareer_applicationWHERE carnie_mycareer_job.jobID = carnie_mycareer_application.jobID;

This query produces the same result as a natural join, making use of the cross product function:

jobid jobsalary jobposition Locid secid appid canemail




2 120000 CFO 1 1 4 [email protected]

3 45000 Jr 1 2 5 [email protected]

… etc …

Cross Product Joins versus Natural Joins

Natural join simply takes two or more selected tables and joins them via the common column(s) that each of them share. For example:

Select *

from carnie_mycareer_job natural join carnie_mycareer_application;

The common column in this case is “jobID” (see previous slides).

Cross product joins essentially do the same thing, however, the user must specify the join:

Select * from carnie_mycareer_job, carnie_mycareer_application Where carnie_mycareer_job.jobID = carnie_mycareer_application.jobID

Entities & Relationships

SecIDSecTitleSecDesc

SectorJobIDJobPostDateJobSalaryJobPositionLocID*SecID*Job Desc

Job

Foreign Key

The Sector – Job 1:m relationship

secid jobid jobposition jobsalary

1 1 Senior 50000

1 2 CFO 120000

2 3 Jr 45000

3 4 Reception 20000

1 5 Graduate 38000

4 6 Team Member 85000


2 8 2IC 60000

3 9 Logistics 75000

secid sectitle

1 Accounting

2 IT

3 Administration

4 Construction

5 Retail

JobIDJobPostDateJobSalaryJobPositionLocID*SecID*Job Desc

Job

LocIDLocCityLocCountry

Location

Foreign Key

The Location – Job 1:m relationship

locid jobid jobposition jobsalary

1 1 Senior 50000

1 2 CFO 120000

1 3 Jr 45000

2 4 Reception 20000

3 5 Graduate 38000



2 8 2IC 60000

4 9 Logistics 75000

locid loccity loccountry locpostcode

1 Sydney Australia New South Wales

2 Wellington New Zealand

3 Albany USA New York

4 Baghdad Iraq

5 Canberra Australia ACT


Candidate

JobID*CanEmail*

Application


Job

The Job – Candidate m:m relationship

jobid | jobpostdate | jobsalary | jobposition | -------+-------------+-----------+-------------+ 1 | 01-01-2005 | 50000 | Senior | 2 | 01-01-2005 | 120000 | CFO | 3 | 01-03-2005 | 45000 | Jr | 4 | 05-03-2005 | 20000 | Reception | 5 | 07-02-2005 | 38000 | Graduate | (5 rows)

jobid | canemail ------+------------------------- 1 | [email protected] 1 | [email protected] 1 | [email protected] 2 | [email protected] 3 | [email protected] 5 | [email protected] 5 | [email protected] 5 | [email protected] 5 | [email protected] 8 | [email protected] (10 rows)

canemail | canfirstname |-------------------------+--------------+ [email protected] | Chris | [email protected] | David | [email protected] | Katie | [email protected] | Sussie | [email protected] | Ron |(5 rows)

The Job – Candidate m:m relationship (cont.)

As demonstrated by the ERD on the previous slide, the links between the separate entities show that one candidate can have many applications, while one job can also have many applications. Furthermore, as a result of this link, a candidate can have one application to one specific job, however, can have numerous applications, each for a different job. Therefore a many-to-many relationship is formed between candidates and jobs.

An example of creating a view

CREATE VIEW CREATE VIEW ausjobs

(JobID,PostDate,Salary,Position,City,Sector,Description)

AS SELECT AS SELECT jobid,jobpostdate,jobsalary,jobposition,loccity,sectitle,jobdesc

FROMFROM carnie_mycareer_job job, carnie_mycareer_sector sec,

carnie_mycareer_location loc

WHEREWHERE job.secid = sec.secid ANDAND job.locid = loc.locid

ANDAND loc.loccountry = 'Australia';

An example of querying a view

•Query exactly as if a table

SELECT jobid, postdate, salary, position, city, sector FROM ausjobs WHERE

salary >= 50000;

jobID postdate salary position city sector

2 01-01-2005 120000 CFO Sydney Accounting

1 01-01-2005 50000 Senior Sydney Accounting

Group by, sub-queries and complex joins

The GROUP BY clause is an elementary form of control break reporting. It permits

grouping of rows that have the same value for a specified column or columns, and

it produces one row for each different value of the grouping column(s)

SQL’s built- in functions (COUNT, SUM, AVERAGE, MIN, and MAX) can be used

with the GROUP BY clause

select SecTitle, AVG(JobSalary) AS AvgSalary

from CARNIE_MYCAREER_JOB, CARNIE_MYCAREER_SECTOR

where CARNIE_MYCAREER_JOB.SecID= CARNIE_MYC

AREER_SECTOR.SecID

GROUP BY SecTitle;

SecTitle Avgsalary

Accounting 69333.333333333333

Construction 65000.000000000000

Administration 47500.000000000000

IT 52500.000000000000

GROUP BY

Report by sector the average value for salary

select SecTitle, COUNT (*), AVG(JobSalary) As AvgSalary

from CARNIE_MYCAREER_JOB, CARNIE_MYCAREER_SECTOR

where CARNIE_MYCAREER_JOB.SecID= CARNIE_MYCAREER_SECTOR.SecID

GROUP BY SecTitle;

SecTitle Count Avgsalary

Accounting 3 69333.333333333333

Construction 2 65000.000000000000

Administration 2 47500.000000000000

IT 2 52500.000000000000

Another example of GROUP BY – with COUNT(*)

Report by Sector the average value for salary

select CanEmail, AVG(JobSalary) As AvgSal

from CARNIE_MYCAREER_APPLICATION, CARNIE_MYCAREER_JOB

where CARNIE_MYCAREER_APPLICATION.JobId = CARNIE_MYC

AREER_JOB.JobID

GROUP BY CanEmail

HAVING COUNT (*) <= 3;

Canemail Avgsal

[email protected] 54333.333333333333

[email protected] 47666.666666666667

[email protected] 69333.333333333333

HAVING – Like WHERE, but after the grouping

Show candidates’ email and report those with less than three applications and their average salary

Subqueries

SELECT JobPosition, JobSalary

FROM CARNIE_MYCAREER_JOB

WHERE JobSalary > (

SELECT AVG(JobSalary) from CARNIE_MYCAREER_JOB);

Jobposition Jobsalary

CFO 120000

Team Member 85000

2IC 60000

Logistics 75000

avg

59777.777777777778

(1 row)

Report all Job Positions with a Job Salary greater than the average of all job salaries

SELECT LocID

FROM CARNIE_MYCAREER_LOCATION

WHERE LocCountry = ‘Australia’ and LocID <= all (

SELECT LocID

from CARNIE_MYCAREER_LOCATION

where LocCountry = ‘Australia’);

LocID

1

(1 row)

locid

1

5

(2 rows)

Subquery - returns one value

Returns



WHERE JobSalary >= (

SELECT max(JobSalary)

from CARNIE_MYCAREER_JOB

where LocID = 1);

max

120000

(1 row)

Using subqueries to find the maximum (or minimum)


CFO 120000

Team Member 85000

Logistics 75000



WHERE JobSalary >= ALL (

SELECT JobSalary

from CARNIE_MYCAREER_JOB

where LocID = 1);

jobsalary

50000

120000

45000

(3 rows)

Alternate way to find the maximum (or minimum): “ALL”


CFO 120000

Team Member 85000

Logistics 75000



WHERE JobSalary <= ALL

(SELECT JobSalary from CARNIE_MYCAREER_JOB);

That’s equivalent to …

Where JobSalary =

(SELECT min(JobSalary) from CARNIE_MYCAREER_JOB);

Another example

jobposition jobsalary

Reception 20000

jobsalry

50000

120000

45000

20000

38000

85000

45000

60000

75000

(9 rows)min

20000

(1 row)

SELECT DISTINCT JobPosition


WHERE LocID = ANY ( SELECT LocID

FROM CARNIE_MYCAREER_LOCATION

WHERE LocCountry = 'Australia‘ );

Any operator

locid

1

5

(2 rowms)

jobposition

CFO

Jr

Senior

Team Member

In: an Alternate to ANY

SELECT DISTINCT JobPosition


WHERE LocID IN ( SELECT LocID

FROM CARNIE_MYCAREER_Location

WHERE LocCountry = 'Australia‘ );

jobposition

CFO

Jr

Senior

Team Member

locid

1

5

(2 rowms)

LEFT Outer Join

SELECT jobID, appID, canEmail, jobsalary, jobposition

FROM carnie_mycareer_application LEFT JOIN carnie_mycareer_job

USING (jobid)

where jobsalary < 60000;

jobID appID canEmail jobSalary jobPosition

1 1 [email protected] 50000 Senior



3 5 [email protected] 45000 Jr

5 6 [email protected] 38000 Graduate

… etc …

Not a great example as all applicationsmatch a job

RIGHT Outer Join

SELECT jobID, appID, canEmail, jobsalary, jobposition

FROM carnie_mycareer_application RIGHT JOIN carnie_mycareer_job

USING (jobid)

where jobsalary < 60000;

jobID appID canEmail jobSalary jobPosition


… etc …

4 20000 Reception





7 45000 Team Member

SELF Join

SELECT job.jobid, can1.canlastname AS applicant1, can2.canlastname AS

applicant2

FROM carnie_mycareer_candidate can1, carnie_mycareer_candidate

can2, carnie_mycareer_application app1, carnie_mycareer_application app2,

carnie_mycareer_job job

WHERE can1.canemail = app1.canemail ANDcan2.canemail = app2.canemail

AND job.jobID = app1.jobID AND job.jobID = app2.jobID AND app1.jobID = 9

AND app2.canemail < app1.canemail;

Joining a table to itself. In this case, carnie_mycareer_candidate is joined to itself

jobID Applicant1 Applicant2

9 Lenehan CarnieProduces

Data Integrity with SQL

jobid | jobpostdate | jobsalary | jobposition | locid | secid | jobdesc-------+-------------+-----------+-------------+-------+-------+----------------------------------------------- 1 | 01-01-2005 | 50000 | Senior | 1 | 1 | Account manager, blue chip company 2 | 01-01-2005 | 120000 | CFO | 1 | 1 | CFO of big four bank 3 | 01-03-2005 | 45000 | Jr | 1 | 2 | Entry level Database position. Great start!! 4 | 05-03-2005 | 20000 | Reception | 2 | 3 | Basic office admin, phones and coffee making 5 | 07-02-2005 | 38000 | Graduate | 3 | 1 | Great start for a fresh graduate 6 | 25-06-2005 | 85000 | Team Member | 4 | 4 | Help rebuild peoples lives in Iraq 7 | 25-06-2005 | 45000 | Team Member | 5 | 4 | Anti-Terror proofing parliment house 8 | 25-06-2005 | 60000 | 2IC | 2 | 2 | Second in command of well run NZ IT company 9 | 25-06-2005 | 75000 | Logistics | 4 | 3 | Team player with excellent organisation skills

Job

locid | loccity | loccountry | locstate-------+------------+-------------+----------------- 1 | Sydney | Australia | New South Wales 2 | Wellington | New Zealand | 3 | Albany | USA | New York 4 | Baghdad | Iraq | 5 | Canberra | Australia | ACT

Loc

Foreign KeyPrimary Key

Creating the linked tables:

CREATE TABLE CARNIE_MYCAREER_JOB(….Individual fields go hereLocID INTEGER NOT NULL,CONSTRAINT PKJobID PRIMARY KEY (JobID),CONSTRAINT FKLocID FOREIGN KEY (LocID) REFERENCES CARNIE_MYCAREER _LOCATION ON DELETE RESTRICT,CONSTRAINT FKSecID FOREIGN KEY (SecID) REFERENCES CARNIE_MYCAREER_SECTOR ON DELETE RESTRICT);

CREATE TABLE CARNIE_MYCAREER_LOCATION(LocID INTEGER NOT NULL,LocCity VARCHAR NOT NULL,LocCountry VARCHAR NOT NULL, CONSTRAINT PKLocID PRIMARY KEY (LocID) );

CHECK constraints example

CREATE TABLE Carnie_MyCareer_Candidate (

… fields go here …

CONSTRAINT Invalid_CanGender CHECK (CanGender IN (‘M’,’F’)));

Name of constraint

Checks that no error has been made when entering the candidates’ gender (CanGender)

SQL Syntax for Actions

CREATE TABLE CARNIE_MYCAREER_APPLICATION ( JobID INTEGER NOT NULL, CanEmail INTEGER NOT NULL, CONSTRAINT PkApplication PRIMARY KEY (JobID, CanEmail),

CONSTRAINT FkJobID FOREIGN KEY (JobID) REFERENCES CARNIE_MYCAREER_JOB

ON DELETE CASCADEON DELETE CASCADEON UPDATE CASCADEON UPDATE CASCADE,

CONSTRAINT FkCanID FOREIGN KEY (CanEmail) REFERENCES CARNIE_MYCAREER_CANDIDATE

ON DELETE CASCADEON DELETE CASCADEON UPDATE CASCADEON UPDATE CASCADE

);

Will delete all applications to a job if the job is deleted

Normalization

Problem: Some of the non-key fields only depends on part of the key.Solution: split into two or more tables (see next slide)

An example of 1st normal form (1NF)

JobID LocID JobPosition JobSalary SecName LocCity LocCountry

1 1 Senior 50000 Accounting Sydney Australia

2 1 CFO 120000 Accounting Sydney Australia

3 1 Jr 45000 IT Sydney Australia

4 2 Reception 20000 Administration Wellington New Zealand

Primary Key

JobID JobPosition, JobSalary, Sector

LocID LocCity, LocCountry

After splitting the table on the previous slide …

JobID JobPosition JobSalary SecName LocID

1 Senior 50000 Accounting 1

2 CFO 120000 Accounting 1

3 Jr 45000 IT 1

4 Reception 20000 Administration 2

Primary Key

LocID LocCity LocCountry

1 Sydney Australia

2 Wellington New Zealand

Primary Key

Foreign Key

Something in the non-key is determined by (the key and also) something else in the non-key.

JobPosition JobSalary

Problem with second normal form

JobID JobPosition JobSalary

10 Burger Flipper Grade 1 30000




Primary Key

Solution: split into two or more tables (see next slide)

Suppose that for a given job title the salary is always the same …

Primary Key


JobID JobPosition

10 Burger Flipper Grade 1




Primary Key

JobPosition JobSalary

Burger Flipper Grade 1 30000

Burger Flipper Grade 2 45000

Foreign Key

Primary Key

Canemail everything else …but also …CanePhone Canemail CaneTaxNo Canemail

Something in the non-key also determines the key.

Problem with third normal form

Primary Key

Solution: split into two or more tables (see next slide)

More than one attribute can determine a person or thing … …

Primary Key

Canemail canLastName canSex CanePhone CaneTaxNo

[email protected] Carnie M 0414 123456 123456

[email protected] Saddington M 0414 456123 654321

[email protected] Kelly F 0414 654321 135791


Primary Key Primary Key

The above tables are in Boyce Codd Normal Form (BCNF)

Canemail canLastName canSex

[email protected] Carnie M

[email protected] Saddington M

[email protected] Kelly F

Canemail CanePhone CaneTaxNo

[email protected] 0414 123456 123456

[email protected] 0414 456123 654321

[email protected] 0414 654321 135791

An example of creating a view

CREATE VIEW CREATE VIEW ausjobs

(JobID,PostDate,Salary,Position,City,Sector,Description)

AS AS

SELECT SELECT jobid,jobpostdate,jobsalary,jobposition,loccity,sectitle,jobdesc

FROMFROM carnie_mycareer_job job, carnie_mycareer_sector sec,

carnie_mycareer_location loc

WHEREWHERE job.secid = sec.secid ANDAND job.locid = loc.locid

ANDAND loc.loccountry = 'Australia';

An example of querying a view

•Query exactly as if a table

SELECT jobid, postdate, salary, position, city, sector

FROM ausjobs

WHERE salary >= 50000;

jobID postdate salary position city sector

2 01-01-2005 120000 CFO Sydney Accounting

1 01-01-2005 50000 Senior Sydney Accounting

Helen Spiropoulos Benjamin Mills Nicoleta Bikrogiannis Jessica El-chaar.

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Transcript of Helen Spiropoulos Benjamin Mills Nicoleta Bikrogiannis Jessica El-chaar.