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E f f ec t o f S e lf We i g h t on a C a n t il e v e r B e a m

Introduction

T h is t u to r ia l wa s c o m pl e te d us i ng A N SY S 12 . 0 T h e p u rp o se o f t h e t u to r ia li s t o s ho w t he r eq u ir ed s te p s t oaccount f or t he w ei ght of an obj ect i n A N S Y S .

L o ad s w i ll n ot b e a p p li e d t o th e b e a m s h ow n b el o w i n or d er t o o b se r ve t h e d e fl e ct i on c a us e d b y t h e w e ig h t o ft he b ea m it se lf . T he b ea m is t o b e m ad e o f st ee l wi th a m od ul us o f el as ti ci ty o f 20 0 G Pa .

Pr ep r oce s s i ng: D e fi n i n g th e Pr ob l e m

1. Give exa mpl e a Tit le U t il i ty M en u > F i le > C ha n g e T it l e . . ./title, Effects of Self Weight for a Cantilever Beam

2 . O pe n p re pr oc es so r m en u ANSYS Main Menu > Preprocessor/PREP7

3. Defi ne Ke ypoi ntsP r eproces s or > Model i ng > C reat e > K eypoi nt s > I n A ct i ve C S . . .K,#,x,y,z

We a r e g o in g t o d e fi n e 2 k ey p o in t s f o r t h is b e a m a s g i ve n in th e f o ll o wi n g t a bl e :

4. Create Lines P r ep r oc e ss o r > Mo d e li n g > Cr e at e > Li n e s > Li n es > In A c ti v e C o or d

K e yp o i nt C o or d i na t e s ( x , y, z )

1 (0, 0)

2 (1000,0)

PROJECT :

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L,1,2

C re a te a l in e j oi ni ng K e yp o in ts 1 a n d 2

5. Defi ne the Ty pe of E leme nt P r epr oces s or > E l em ent T ype > A dd/ E dit / D elet e. . .

F o r t h is p r ob l em we w i ll us e t h e B E AM 3 ( B ea m 2 D e l as ti c ) e l em e nt . T h is e l em e nt ha s 3 d eg r ee s of r ee d o m (t r an s la t io n a l on g t h e X a n d Y a x e s, a n d r o ta t io n a b ou t t h e Z a x i s) .

6 . D ef in e Re al C on st an tsPreprocessor > Real Constants... > Add...

I n t he ' R eal C ons tant s f or B E A M 3' w i ndow, ent er t he f ol l ow i ng geom et ri c pr opert i es :i . C ro ss -s ec ti on al a re a A RE A: 5 00

i i. A re a m om en t o f i ne rt ia I ZZ : 4 1 66 .6 7i ii . To ta l b ea m h ei gh t: 10

T h is d e fi n es a b e a m w i th a h e ig h t o f 10 m m a n d a w i dt h of 5 0 m m .

7 . D ef i ne E le me n t M a te r ia l Pr op e rt i es P r epr oces s or > M at er i al P r ops > M at er ial M odel s > S t r uctur al > L i near > E l as t ic > I s ot ropi c

I n t h e w i nd o w t h at a p p e a rs , e n t er t h e f o ll o wi n g g e o me t ri c p r op e rt i es f o r s te e l:i . Yo un g' s m od ul us E X: 2 00 00 0

i i. P o is so n' s R at io PR XY: 0. 3

8 . D ef in e E le me nt D e ns it y

P r epr oces s or > M at er i al P rops > M at er i al M odel s > S t r uct ural > L i near > D ens i t y

I n t he w i ndow t hat appear s, ent er t he f ol l ow i ng dens i ty f or s t eel:i . D en si ty D EN S: 7 .8 6e -6

9. Def ine Mes h Si zeP r ep r oc e ss o r > Me s hi n g > S i z e C n tr l s > M a n ua l Si z e > L i n es > Al l L in e s. . .

F o r t h is e x a mp l e w e w i ll us e a n el e me n t e d g e l e ng t h o f 10 0 mm .

10. Mesh the frame

P r epr oces s or > M es hi ng > M es h > L i nes > cl i ck ' P ick A ll '

S o l ut i o n Pha se : A ssi gn i n g L o a ds a n d S o lv i n g

1 . D ef in e An al ys is Ty pe S o lu t io n > An a ly s is Ty p e > N e w A n al y si s > S t a ti cANTYPE,0

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2 . A pp ly C on st ra in tsS ol ut ion > D efi ne L oads > A ppl y > S t r uct ur al > D i spl acement > O n K eypoi nt s

F i x keypoi nt 1 ( i e al l D O F cons t rai ned)

3. Define Gravity

I t i s n e c es s ar y t o de f in e t h e d i re c ti o n a nd m a gn i tu d e o f g ra v it y f o r th i s p r ob l em .

{ Select S o lu t io n > D e fi n e L oa d s > A pp l y > S tr u ct ur a l > I n er t ia > G ra v it y. . .

{ T h e f o ll o wi n g wi n do w w i ll a p pe a r. F i ll i t i n a s s h ow n t o de f in e a n a c ce l er a ti o n o f 9 . 8 1m / s

2

i n t he ydirection.

Note: A c ce l e ra t io n is d e fi n ed i n t e rm s o f m e te r s ( n ot ' m m' as u s ed th r ou g h ou t t h e p r ob l em ) . T h is i sbecause the units of acceleration and mass must be consistent to give the product of force units( N ew t on s i n t h is c a se ) . A l so n o t e t h at a p o si t iv e a c c e l er a ti o n i n th e y d i re c ti o n s ti m ul a te s g r av i ty i nt he n e ga ti ve Y d ir ec ti on .

T he re s ho ul d n o w b e a r ed ar ro w p oi nt in g i n t he p o si ti ve y di re ct io n. T hi s i nd ic at es t ha t a naccel erat i on has been defi ned i n t he y di r ect i on.

DK,1,ALL,0, ACEL,,9.8

T h e a p p li e d l o ad s a n d c o n st r ai n ts s h ou l d n o w a p p ea r a s s h ow n i n t h e f i gu r e b e lo w.

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4. Solve the SystemS ol ut ion > S ol ve > C ur r ent L SSOLVE

Pos tp roc e s si n g: Vi e w i ng th e R e s u lts

1 . H an d C al cu la ti on s

H a nd c a l c ul a ti o ns w e re p e rf o rm e d t o v e ri f y t he s o lu t io n f o u nd u s in g A NS Y S:

T h e m a xi m um de f le c ti o n w a s s h ow n t o b e 5 . 7 77 m m

2 . S ho w t he d ef or ma ti on of th e b ea mG ener al P os tpr oc > P l ot R es ul ts > D ef orm ed S hape . . . > D ef + undef edgePLDISP,2

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A s o b se r ve d i n th e u p pe r l ef t h an d c o rn e r, t h e m a xi m u m d is p la c e me n t wa s f o un d t o b e 5 . 7 77 m m. T h is i si n agr eem ent w i th t he t heort i cal val ue.

C om ma nd F i le M od e o f S ol ut io n

T h e a b o ve e x am p le w a s s o lv e d u s in g a m i xt u re o f t h e G r ap h ic a l U s er I n te r fa c e ( o r G U I) a n d t h e c o m ma n dl anguage i nt erf ace of A N S Y S . T hi s pr obl em has al s o been s ol ved us i ng t he ANSYS command languageinterface t h at y o u ma y w a nt t o b ro w se . O pe n t h e f i le a n d s a ve i t t o yo u r co m pu t er. N o w g o t o ' Fi le > R ea dinput from...' and s el ect the f i l e.

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