Hay HEY STOP DANCING!!! >:( Note that, if I add down, the y's will cancel out. So I'll draw an...
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Transcript of Hay HEY STOP DANCING!!! >:( Note that, if I add down, the y's will cancel out. So I'll draw an...
Hey! Hey!Hey!
Hey! Hey!
Hey!
Hey!
Hey!Hey!
Hey!Hey!
Hey! Hey!
Hey! Hey!
Hay
Today TodayToday
Today!!!!!!!!!
We will be working on
solving system of equations by elimination !
BUT FIRST !!!!
RANDOM DANCE PARTY
!!!!!!
Okay now we’re ready to work
:D haha
But first.
We’re going to need to know a few things
aren’t we?
(this is where you say yes and nod your head so
Mrs. Austin thinks your smart and are
Paying attention)
How do you solve a system of equations
using elimination??
It’s actually a whole lot easier than you think.
So let’s get started!!!! HEY STOP
DANCING!!! >:(
Okay. Here’s our problem
2x + y = 93x – y = 16
Note that, if I add down, the y's will cancel out. So I'll draw an "equals"
bar under the system,
and add down
Then I get this.2x + y = 93x – y = 165x = 25
Now I can divide through to solve for
x = 5, and then back-
solve, using either of the original
equations, to find the value of y. The first equation
has smaller numbers,
so I'll back-solve in that one:2(5) + y = 9
10 + y = 9 y = –1
Then the solution is…..
RAVE DANCE TIME!!!
Haha!! Just Kidding!!!
(x, y) = (5, –1).
(x, y)
= (5, –
1).
(x, y) = (5, –
1).(x, y) = (5, –
1).
(x, y) = (5, –1).
(x, y)
= (
5,
–1
).
(x, y) = (5, –
1).
(x, y
) = (5
, –
1).
Some of you may bewondering what would
happen if I use the other equation.It doesn't matter which equation you use for the backsolving;
you'll get the same answer either way. If I'd used the second equation, I'd have gotten:
3(5) – y = 16 15 – y = 16 –y = 1
y = –1
...which is the same result as before.
Now…How is this all usedIn the real world?
Of course silly!When you become a
Algebra One teacher likeMrs. Austin.
Thank you for listening toMy presentation
But of course we can’t go Without one last thing….
DANCE PARTY!!!!!!
AND JUST TO GIVE YOU NIGHTMARES!!!!
End.