Grade 12 Pre-Calculus Mathematics [MPC40S] Chapter 7

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Grade 12 Pre-Calculus Mathematics [MPC40S] Chapter 7 Exponential Functions Chapter 8 Logarithmic Functions Outcomes R7/8, R9, R10 12P.R.7. Demonstrate an understanding of logarithms. 12P.R.8. Demonstrate an understanding of the product, quotient, and power laws of logarithms. 12P.R.9. Graph and analyze exponential and logarithmic functions. 12P.R.10. Solve problems that involve exponential and logarithmic equations.

Transcript of Grade 12 Pre-Calculus Mathematics [MPC40S] Chapter 7

Grade 12 Pre-Calculus Mathematics

[MPC40S]

Chapter 7

Exponential Functions

Chapter 8

Logarithmic Functions

Outcomes

R7/8, R9, R10

12P.R.7. Demonstrate an understanding of logarithms. 12P.R.8. Demonstrate an understanding of the product, quotient, and power laws of logarithms. 12P.R.9. Graph and analyze exponential and logarithmic functions. 12P.R.10. Solve problems that involve exponential and logarithmic equations.

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Chapter 7/8 – Homework

Section Page Questions

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Chapter 7: EXPONENTIAL FUNCTIONS

7.1 – Characteristics of Exponential Functions Exponential Function: A function of the form _________________________________ where 𝑐 is a constant (𝑐 > 0) and π‘₯ is a variable. Constant β†’ Base Variable β†’ Exponent Let’s look at some graphs of exponential functions. 𝑦 = 𝑐π‘₯ where 𝑐 > 1 𝑦 = 𝑐π‘₯ where 0 < 𝑐 < 1 Increasing Function Decreasing Function Domain: (βˆ’βˆž, ∞) Domain: (βˆ’βˆž, ∞) Range: (0, ∞) Range: (0, ∞) Asymptote: 𝑦 = 0 Asymptote: 𝑦 = 0 Point on the graph: (0,1) Point on the graph: (0,1)

R9

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Example #1

Sketch the graph of 𝑓(π‘₯) = 2π‘₯

Notes:

β€’ The base of this exponential function is ______________

β€’ Thus, the function is _____________________________

β€’ The graph passes through the point _________________

β€’ There is a horizontal asymptote at __________________ (since y cannot be negative)

β€’ The domain is ________________

β€’ The range is _________________

β€’ The graph approaches _______________ when ______________

π‘₯ 𝑦

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Example #2

Sketch the graph of 𝑦 = (1

2)

π‘₯

Example #3

Sketch the graph of 𝑓(π‘₯) = 3π‘₯

π‘₯ 𝑦

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Example #4

Sketch the graph of 𝑓(π‘₯) = 𝑒π‘₯

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Chapter 7: EXPONENTIAL FUNCTIONS

7.2 – Transformations of Exponential Functions

𝑦 = π‘Ž βˆ™ 𝑐𝑏(π‘₯βˆ’β„Ž) + π‘˜

Example #1

Sketch each of the following exponential functions. a) 𝑓(π‘₯) = 2π‘₯ + 1 _________________________________ _________________________________ _________________________________

b) 𝑦 = βˆ’3π‘₯+1 _________________________________ _________________________________ _________________________________ _________________________________

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c) 𝑔(π‘₯) = 4βˆ’π‘₯ βˆ’ 1 ______________________________ ______________________________ ______________________________

d) 𝑦 = 31

2π‘₯

______________________________ ______________________________ ______________________________

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Example #2

a) Sketch the graph of 𝑦 = 2(3)π‘₯βˆ’1 βˆ’ 4 _______________________________ _______________________________ _______________________________ _______________________________ b) Write the equation of the asymptote. Note: The β€˜2’ is a constant and doubles all of the y values.

If 𝑓(π‘₯) = (3)π‘₯ is the original function, then 𝑦 = 2𝑓(π‘₯ βˆ’ 1) βˆ’ 4 would be the equation of this function.

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Chapter 7: EXPONENTIAL FUNCTIONS

7.3 – Solving Exponential Equations Before solving exponential equations, let’s review the exponent laws.

(π‘₯4)(π‘₯3) = __________ (π‘₯4)2 = __________ π‘₯15

π‘₯3 = __________

___________________ ___________________ ___________________ ___________________ ___________________ ___________________ Big Idea!

If 𝑐π‘₯ = 𝑐𝑦 then

For example, 3π‘₯+2 = 37 then we can say that

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Solving Exponential Equations Algebraically When solving exponential equations, we need both sides of the equation to have the same base. Example #1

Solve 2π‘₯+1 = 32 Example #2

Solve 34π‘₯βˆ’1 = 272π‘₯

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Example #3

Solve (3π‘₯)(27) = 812π‘₯βˆ’1 Example #4

Solve 4π‘₯+1 = (2π‘₯)(√2)

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Example #5

Solve 1

3π‘₯βˆ’1 = 81

Example #6

Solve (βˆ’8)5

3 = 2 (4π‘₯

2)

Note: We cannot yet solve equations with different bases (i.e. 10π‘₯+1 = 7π‘₯)

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Chapter 8: LOGARITHMIC FUNCTIONS

8.1 – Understanding Logarithms The logarithmic function is the inverse of the exponential function. Remember, to find the inverse of a function, we switch the π‘₯ and 𝑦 values and then

solve for 𝑦. Exponential Function Inverse Function 𝑦 = 𝑏π‘₯ π‘₯ = 𝑏𝑦 Notice that the 𝑦 value is now an exponent. Right now, we do not know how to isolate the 𝑦 value! In order to isolate and manipulate exponents, we must use something called the logarithmic function. Logarithmic Function: A function of the form _________________________________ where 𝑏 > 0 and 𝑏 β‰  1, that is the inverse of the exponential function 𝑦 = 𝑏π‘₯ 𝑦 = log𝑏 π‘₯ where b β†’_____________________________ 𝑦 β†’_____________________________ π‘₯ β†’_____________________________

R7/8

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Example #1

Express each of the following in logarithmic form. a) 34 = 81

b) π‘š = 4𝑛

c) 𝑦 = 8(π‘₯+1)

d) 26 = 64

Example #2

Express each of the following in exponential form. a) log2 8 = 3

b) log7 343 = 3

c) log4 π‘₯ = 3

d) log2 16 = π‘₯ + 1

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Example #3

Evaluate the following expressions

a) log2 16 = π‘₯

b) log2 (1

4) c) log3(βˆ’27)

Common Logarithm: A logarithm ______________________________. When you write a common logarithm, you do not need to write the base. For example, log 3 means log10 3 Natural Logarithm: A logarithm ______________________________.

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Some Basic Logs to Remember: β€œQuicksnappers”

a) =1log c

b) =cclog

c) =y

c clog

d) =ycclog

e) 𝑙𝑛𝑒 =

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Example #4

Evaluate the following

a) log2 8

b) 4log55

c) log 1000

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Example #5

Solve each of the following equations.

a) logπ‘₯ 5 =1

2

b) log π‘₯ = βˆ’3

c) log16 π‘₯ =3

4

d) log2(log3 81) = π‘₯

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Example #6

Estimate the following values a) log2 30

b) log 20

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Chapter 8: LOGARITHMIC FUNCTIONS

8.2 – Transformations of Logarithmic Functions Recall: The logarithmic function is the inverse of the exponential function. Remember, to find the inverse of a function, we switch the π‘₯ and 𝑦 values and then

solve for 𝑦. Exponential Function Inverse Function 𝑦 = 𝑏π‘₯ π‘₯ = 𝑏𝑦 which is equivalent to 𝑦 = log𝑏 π‘₯ Example #1

Sketch the graphs of the functions 𝑦 = 2π‘₯ and 𝑦 = log2 π‘₯. Note that these two functions are inverses of each other.

Note: The graph of 𝑦 = log2 π‘₯ has a _________________________________________ because ______________________________________________________________

π‘₯ 𝑦

π‘₯ 𝑦

R9

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Example #2

Sketch the graphs of the following functions on the same Cartesian plane. a) 𝑦 = log3 π‘₯ b) 𝑦 = log4 π‘₯ c) y = log π‘₯ d) 𝑦 = ln π‘₯

Note: All the graphs pass through the point (1,0). The base of the logarithm determines the next point. Base 3 β†’ (3,1) 𝑦 = log3 π‘₯ β†’ 3𝑦 = π‘₯ β†’ 31 = 3 β†’ (3, 1)

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Example #3

a) Sketch the graph of the function 𝑦 = log5(π‘₯ + 2) βˆ’ 1 b) Sate the domain and range. Domain: __________________ Range: ___________________ c) State the equation of the asymptote. d) Determine the x – intercept.

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Example #4

a) Sketch the graph of the function 𝑦 = log3(3 βˆ’ π‘₯) + 1 b) Sate the domain and range. Domain: __________________ Range: ___________________ c) State the equation of the asymptote. d) Determine the y – intercept and the x – intercept.

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Chapter 8: LOGARITHMIC FUNCTIONS

8.3 – Law of Logarithms 1. Example: log4 10 + log4 2 = Example: log2 6 = 2. Example: log3 15 βˆ’ log3 5 =

Example: logπ‘₯8

3=

3.

Example: log3 √6 = Example: 3log2 5 =

logπ‘Ž 𝑀𝑁 = logπ‘Ž 𝑀 + logπ‘Ž 𝑁

logπ‘Ž

𝑀

𝑁= logπ‘Ž 𝑀 βˆ’ logπ‘Ž 𝑁

logπ‘Ž 𝑀π‘₯ = π‘₯ logπ‘Ž 𝑀

R7/8

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4. Example: log2 7 =

The l log button on a calculator is of base 10. Therefore, this button can only be used

to find solutions with base 10. For example, log2 7 cannot be entered into the calculator. We must use the β€œchange of base” law to convert this expression to base 10 and then a calculator can be used to solve it.

log2 7 =log 7

log 2=

Example #1

Expand following expression so that it is written in terms of individual logarithms.

log5π‘‹π‘Œ

𝑍

Example #2

Expand the expression logπ‘Ž (𝐴√𝐢

𝐡2𝐷)

logπ‘Ž π‘₯ =log π‘₯

log π‘Ž

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Example #3

Simplify the expression so that it is written as a single logarithm. a) log5 𝐴 + 3log5 𝐡 βˆ’ log5 𝐢

b) 2 log π‘₯ βˆ’ (log 𝑦 βˆ’1

3log 𝑧)

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Example #4

Simplify and then evaluate the following expressions using laws of logarithms: a) log6 8 + log6 9 βˆ’ log6 2

b) 2 log2 12 βˆ’ (log2 6 +1

3log2 27)

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Example #5

If logπ‘Ž 2 = 0.30 and logπ‘Ž 3 = 0.48 and logπ‘Ž 5 = 0.70, then evaluate the following expressions: a) logπ‘Ž 150

b) logπ‘Ž √10

3

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Chapter 8: LOGARITHMIC FUNCTIONS

8.4 – Logarithmic and Exponential Equations We have now learned everything we need to know to solve equations! Example #1

Solve log3 π‘₯ βˆ’ log3 5 = βˆ’1

Example #2

Solve log6(2π‘₯ βˆ’ 1) = log6 11

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R10

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Example #3

Solve log(π‘₯ βˆ’ 3) βˆ’ log(π‘₯ βˆ’ 5) = log 5 Example #4

Solve 2log π‘₯ βˆ’ log(π‘₯ + 2) = log(2π‘₯ βˆ’ 3)

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Example #5

Solve log4(11 βˆ’ π‘₯) + log4(π‘₯ + 6) = 2

_________________________________ _________________________________ _________________________________ _________________________________ _________________________________ _________________________________

Example #6

Solve log6(π‘₯ + 3) = 1 βˆ’ log6(π‘₯ + 4)

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When the bases of exponents cannot be changed to the same value we must use logarithms to solve the equation. Example #6

Solve the exponential equation 3π‘₯ = 8

__________________________________ __________________________________ __________________________________ __________________________________ __________________________________ __________________________________ __________________________________ __________________________________ __________________________________

Example #7

Solve 5 = 2π‘₯βˆ’2. Express the answer correct to 3 decimal places.

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Example #8

Solve the following equation. Express the answer correct to 3 decimal places.

19π‘₯βˆ’5 = 32π‘₯+1

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Example #9

Solve the following equation. Express the answer correct to 3 decimal places.

2(3π‘₯) = 63π‘₯βˆ’1 Example #10

Solve the following equation. Express the answer correct to 3 decimal places. 𝑒π‘₯βˆ’1 = 2π‘₯+1

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Chapter 8: LOGARITHMIC FUNCTIONS

8.4 – Applications of Logarithmic & Exponential Functions Example #1

The Richter magnitude, M, of an earthquake is defined as 𝑀 = log (𝐴

𝐴0)

where A is the amplitude of the ground motion and A0 is the amplitude associated with a β€œstandard” earthquake. a) In 1946, in Haida Gwaii, British Columbia, an earthquake with an amplitude measuring 107.7 times A0 struck. Determine the magnitude of this earthquake on the Richter scale. b) The strongest recorded earthquake in Haida Gwaii was in 1949 and had a magnitude of 8.1 on the Richter scale. Determine how many times stronger this earthquake was than the one in 1946.

R10

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Example #2

The pH scale is used to measure the acidity or alkalinity of a solution. It is defined as 𝑝𝐻 = βˆ’ log(𝐻+) where H+ is the concentration of hydrogen ions measured in moles per litre (mol/L). A neutral solution, such as pure water, has a pH of 7. The closer the solution is to 0, the more acidic the solution. The closer the solution is to 14, the more alkaline the solution is. A cola drink has a pH of 2.5 whereas milk has a pH of 6.6. How many times as acidic as milk is a cola drink? This is calculated by comparing the number of ions in each substance.

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Example #3

The human ear is able to detect sounds of different intensities. The intensity level, 𝛽, in

decibels, is defined as 𝛽 = 10 log𝐼

𝐼0 where 𝐼 is the intensity of the sound measured in

watts per square metre (W/mΒ²), and 𝐼0 is 10βˆ’12 W/mΒ² which is the threshold of hearing (the faintest sound that can be heard by a person of normal hearing). a) A truck emits a sound intensity of 0.001 W/mΒ². Determine its decibel level. b) It is recommended a person wears protective ear gear when the intensity level is 85 dB or greater. The MTS Centre measures 110 dB when the Jets score a goal. How many times louder is the MTS Centre than the recommended maximum sound intensity?

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Example #4

Compound interest is a good example of an increasing exponential function. P = initial value A = final value n = # of times the interest is compounded in one year r = interest rate, as a decimal (ex: 5% = 0.05) t = time, in years An amount of $5000 is invested at a rate of 3.1% compounded monthly. a) Determine how much interest is earned after 20 years. b) Determine how much time is needed for the initial investment to double in size.

𝐴 = 𝑃 (1 +π‘Ÿ

𝑛)

𝑛𝑑

Interest Earned = A – P

Note: Annually 1 time/year Semi-annually 2 times/year Quarterly 4 times/year Monthly 12 times/year Biweekly 26 times/year Weekly 52 times/year Daily 365 times/year

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Example #5

There are 500 mice found in a field on June 1. On June 20, 800 mice are counted. If the population of mice continues to increase at the same rate, determine how many mice there will be on June 28.

Use 𝐴 = π‘ƒπ‘’π‘Ÿπ‘‘ where P = initial value

A = final value t = time, in days r = rate of increase or decrease

Note: If r > 0, then the function increases exponentially If r < 0, then the function decreases exponentially