GPRS Session 4 Power Control Twn01Q4
18
NORTEL NETWORKS CONFIDENTIAL CHT - GPRS presentation Session 4 Power control Joseph Joseph - - Andre MATTEI Andre MATTEI Network Optimization Network Optimization S S olutions olutions 23 23 rd rd October October 2001 2001
Transcript of GPRS Session 4 Power Control Twn01Q4
NO
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NFI
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L
CH
T -G
PRS
pres
enta
tion
Sess
ion
4Po
wer
con
trol
Jose
phJo
seph
-- And
re M
ATT
EIA
ndre
MA
TTEI
Net
wor
k O
ptim
izat
ion
Net
wor
k O
ptim
izat
ion
SS olu
tions
olut
ions
2323rdrd
Oct
ober
Oct
ober
2001
2001
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S pr
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ion
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Scop
e
This
four
thG
PRS
pres
enta
tion
(ses
sion
4):
•Pre
sent
s th
e G
PRS
pow
er c
ontr
ol
algo
rithm
and
the
asso
ciat
ed p
aram
eter
s
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Age
nda
•Po
wer
con
trol
des
crip
tion
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Pow
er c
ontr
ol fo
r GPR
SPr
esen
tatio
n•
RF
pow
er c
ontr
olIs
em
ploy
edto
min
imiz
e th
etra
nsm
it po
wer
requ
ired
by M
S or
BSS
whi
lst
mai
ntai
ning
the
qual
ityof
the
radi
o lin
ks.
By m
inim
izin
g th
etra
nsm
it po
wer
leve
ls, i
nter
fere
nce
to c
o-ch
anne
l use
rs
is re
duce
d.
•Po
wer
con
trol
for G
PRS
(pac
ket o
rient
ed c
onne
ctio
n) is
mor
e co
mpl
icat
ed th
anfo
r GSM
(circ
uit s
witc
hed
conn
ectio
n) s
ince
:Th
ere
isno
con
tinuo
us tw
o-w
ay c
onne
ctio
n,Bu
ta O
N/O
FF d
ata
traffi
cw
ithve
ry o
ften
shor
t UL
ON
per
iods
.
•In
the
Nor
tel G
PRS
V12.
4 C
Acc
ess
Net
wor
k re
leas
e:D
L po
wer
con
trol i
s no
t use
d(w
ithU
SF: m
ore
com
plic
ated
and
less
effic
ient
).U
L po
wer
con
trol i
s im
plem
ente
d in
ord
er to
dec
reas
e:Th
e ov
eral
l int
erfe
renc
e le
vel i
n th
e ce
ll(s
pect
rum
effic
ienc
y),
The
MS
batte
ry c
onsu
mpt
ion.
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Pow
er c
ontr
ol fo
r GPR
SA
lgor
ithm
•Th
eR
F ou
tput
pow
er P
CH
to b
e em
ploy
edby
the
MS
on
each
UL
GPR
S ph
ysic
al c
hann
el(P
DC
H) s
hall
be(in
dB
m): P C
H=
min
(Γ0
-ΓC
H-α
* (C
+ 4
8); P
MA
X)
Γ CH
= M
S an
d ch
anne
l spe
cific
pow
er c
ontro
l par
amet
er, s
ent t
o th
e M
S in
the
PUA
SR
LC/M
AC c
ontro
l mes
sage
Γ 0=
39 d
Bmfo
r GSM
900
and
36 d
Bmfo
r DC
S180
0α
=sy
stem
par
amet
er b
road
cast
on
BCC
H S
I 13
and
sent
to th
e M
S in
the
PUA
SR
LC/M
AC c
ontro
l mes
sage
C=
norm
aliz
ed re
ceiv
edsi
gnal
leve
l at t
heM
SP M
AX
= m
axim
um a
llow
edou
tput
pow
er in
the
cell
= M
S_TX
PWR
_MA
X_C
CH
(GSM
par
amet
er)
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Pow
er c
ontr
ol fo
r GPR
SA
lgor
ithm
•V1
2.4
C im
plem
enta
tion
No
DL
Pow
er C
ontro
l:P B
TS=
bsTx
PwrM
ax(G
SM p
aram
eter
)
Ope
n-lo
op c
ontro
l for
UL
pow
er c
ontro
l alg
orith
mα
= 1
Γ CH
char
acte
ristic
s:-K
eptc
onst
ant i
n th
e ce
ll-F
ixed
by th
e ta
rget
rece
ived
sign
al v
alue
at B
TS s
ide
i.e. b
tsSe
nsiti
vity
The
outp
ut p
ower
is b
ased
on th
e re
ceiv
edsi
gnal
leve
lC a
ssum
ing
the
sam
e pa
th lo
ssin
UL
and
DL
(see
05.
08) w
hich
is u
sefu
lin
the
begi
nnin
gof
a p
acke
ttra
nsm
issi
on.
•Th
eM
S R
F ou
tput
pow
er P
CH
shal
l be
(in d
Bm
):P C
H=
min
( Γ 0
- ΓC
H-C
-48
; PM
AX)
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Pow
er c
ontr
ol fo
r GPR
SA
lgor
ithm
•C
ompu
tatio
n of
ΓC
H(a
tPC
U s
ide)
R
ecei
ved
sign
al s
treng
th a
t the
MS:
C =
bsT
xPw
rMax
-Pa
th_L
oss
MS
outp
ut p
ower
:P C
H=
Γ 0-Γ
CH
-C -
48
BTS
rece
ived
sign
al s
treng
th ta
rget
valu
e=
btsS
ensi
tivity
btsS
ensi
tivity
= P C
H-P
ath_
Loss
•Th
us:
Γ CH
= Γ 0
- bsT
xPw
rMax
- bts
Sens
itivi
ty-4
8
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Pow
er c
ontr
ol fo
r GPR
SA
lgor
ithm
•Th
e PC
U c
ompu
tes
Γ CH
acco
rdin
gto
Γ 0,bsTxPwrMax
andbtsSensitivity
prov
ided
by
the
BSC
in th
e TD
MA
Con
figR
eque
stm
essa
ge o
f the
OAM
Agp
rs in
terfa
ce.
•W
hen
the
MS
rece
ives
new
ΓC
Hva
lues
, its
hall
upda
te P
CH.
•Th
e sa
me
P CH
isus
edon
all
4 bu
rsts
with
in1
radi
o bl
ock.
•To
acc
ess
a ce
llon
RAC
H, b
efor
e re
ceiv
ing
the
1st p
ower
con
trol p
aram
eter
s in
PU
AS,
the
MS
shal
l use
PC
H=
P MA
X.
Γ 0, b
sTxP
wrM
axan
d bt
sSen
sitiv
ity11
Γ CH
22
33
P CH
MS
BTS
BSC
PCU
Γ CH
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Pow
er c
ontr
ol fo
r GPR
SA
lgor
ithm
•Fo
r giv
en ra
dio
cond
ition
s:
C is
fixe
dbt
sSen
sitiv
ityin
fluen
ce:
btsS
ensi
tivity
(ΓC
H)=
> P C
H(le
sspo
wer
con
trol
)bt
sSen
sitiv
ity(Γ
CH
)=>
P CH
(mor
e po
wer
con
trol
)
•Fo
r a g
iven
pow
er c
ontr
ol:
btsS
ensi
tivity
is fi
xed
Rad
io c
ondi
tions
influ
ence
:C
=> P
CH
C=>
PC
H
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•bt
sSen
sitiv
ity(B
TSO
bjec
t): C
lass
e 3
Targ
et v
alue
for r
ecei
ved
sign
al s
treng
that
BTS
sid
e.Va
lue
rang
e: [0
to 2
55]
Def
ault
valu
e: 0
NB
:x
valu
e at
the
OM
C-R
MM
I -x
dBm
Doe
sno
t hav
ean
y im
pact
on
the
BTS.
As
itde
fines
the
targ
et p
ower
to b
e re
ceiv
ed b
y th
e BT
S, th
e M
S ha
s to
asse
ssth
e D
L pa
th lo
ss a
nd a
djus
t its
tran
smis
sion
pow
er in
or
der t
o en
sure
that
the
BTS
rece
ives
the
sign
al a
t the
pow
er le
vel
defin
ed b
y bt
sSen
sitiv
ity:
Incr
easi
ng it
s va
lue
wou
ldpe
rmit
toav
oid
losi
ng s
igna
lling
pack
ets
from
th
e M
S(li
kePDAN
) and
as
a co
nseq
uenc
e av
oid
a lo
ss o
f thr
ough
put.
The
fact
that
the
MS
shal
l tra
nsm
it w
ith a
hig
her p
ower
wou
ldno
t cre
ate
mor
e U
L in
terfe
renc
e as
the
GPR
S tra
ffic
is m
ostly
a D
L tra
ffic.
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•nA
vgW
&nA
vgT
(BTS
Obj
ect)
Cla
ss 3
Perm
itto
com
pute
the
mul
tifra
mes
filte
ring
perio
dsT av
g_w
& T
avg_
Tfo
r pow
er
cont
rol r
espe
ctiv
ely
in P
acke
t Idl
e M
ode
& in
Pac
ket T
rans
ferM
ode.
Va
lue
rang
e: [0
to 2
5]D
efau
ltva
lue:
0
•Th
e hi
gher
T avg
_w:
The
high
er p
ast m
easu
rem
ents
impa
ct.
The
high
er th
e nu
mbe
r of m
ultif
ram
es to
upd
ate
C.
•Th
ese
valu
es in
fluen
ce th
e ca
lcul
atio
n of
C.
Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
MS
uses
Pa
MS
uses
Pb
MS
uses
Pc
Pack
et Id
le M
ode
Pack
et T
rans
fer M
ode
Ca
Cb
Cc
Cd
Ck’
C
i’
T T
T T
T A
vg_W
A
vg_T
A
vg_W
A
vg_T
A
vg_T
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s•
Com
puta
tion
of C
(rec
eive
dsi
gnal
str
engt
h at
MS
side
)Pa
cket
Idle
mod
eTh
eM
S sh
all p
erio
dica
lly m
easu
re th
e re
ceiv
edsi
gnal
leve
lof e
ach
BCC
H p
agin
gbl
ock
mon
itore
d.Th
e no
rmal
ised
C v
alue
is g
iven
for e
ach
radi
o bl
ock
by C
bloc
kn ,
mea
nof
the
rece
ived
sign
al le
velo
f the
four
nor
mal
bur
sts
that
com
pose
the
bloc
k.Th
e C
bloc
kn
valu
es a
re fi
ltere
d w
itha
runn
ing
aver
age
filte
r:C
n=
(1-a
)*C
n-1
+ a
*Cbl
ock
nW
here
ais
the
forg
ettin
g fa
ctor
:-I
f a =
1, t
hen
Cn
past
val
ues
are
not t
aken
into
acc
ount
.-I
f a te
nds
to 0
, the
n m
ore
impo
rtanc
e is
giv
en to
Cn
past
mea
sure
men
tsAn
dn
is th
e ite
ratio
nin
dex:
-The
filte
r sha
ll be
rest
arte
d ev
ery
time
a ne
w c
ell i
s se
lect
ed.
-Whe
n en
terin
g Pa
cket
Idle
mod
e, th
e fil
ter s
hall
cont
inue
from
the
nan
d C
nva
lues
obt
aine
d du
ring
Pack
et T
rans
ferm
ode.
Th
e cu
rrent
Cn
valu
e sh
all b
e us
edin
PC
Hfo
rmul
a to
cal
cula
te th
eou
tput
pow
er w
hen
the
MS
trans
fers
its
first
radi
o bl
ock.
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s•
Com
puta
tion
of C
(rec
eive
dsi
gnal
st
reng
th a
tMS
side
)Pa
cket
Idle
mod
eTh
e fo
rget
fact
ora
perm
its to
giv
e m
ore
or le
ss im
porta
nce
to C
npa
st v
alue
s.
a =
1 / M
in (n
; Max
(5; T
AVG
_W* N
DR
X))
T AVG
_Wis
bro
adca
ston
BC
CH
SI 1
3 an
d re
pres
ents
the
mul
tifra
mes
filte
ring
win
dow
forC
nco
mpu
ting
(in n
umbe
r ofm
ultif
ram
es):
T AVG
_W=
[2^(
n Avg
W/2
)]/6
ND
RX
aver
age
num
bero
f mon
itore
dbl
ocks
per
mul
tifra
me
acco
rdin
gto
its
pagi
nggr
oup
in D
RX
mod
e ND
RX
= 1
/BS_
PA_M
FRM
S
BS_
PA_M
FRM
S is
bro
adca
ston
BC
CH
SI 3
(noO
fMul
tifra
mes
Bet
wee
nPag
ing)
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•C
ompu
tatio
n of
C (r
ecei
ved
sign
al s
tren
gth
atM
S si
de)
Pack
etId
lem
ode
Exam
ple
1BS
_PA_
MFR
MS
= 5
and
n Avg
W=
0th
en:
a =
1/M
in (n
;Max
(5;1
/6*1
/5))
= 1
/Min
(n;5
)
If n
> 5
i.e. t
he M
S co
mpu
tes
mor
e th
an 5
itera
tions
ofC
nw
hich
is li
kely
to
occu
r as
it is
incr
emen
ted
by 1
at e
ach
itera
tion
sinc
e th
e se
lect
ion
of
the
cell,
then
:a
= 1
/5
Cn
= 4/
5 * C
n-1
+ 1/
5 * C
bloc
kn
80%
of C
nco
mes
from
the
past
val
ue a
nd 2
0% fr
om th
e cu
rrent
val
ue.
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•C
ompu
tatio
n of
C (r
ecei
ved
sign
al s
tren
gth
atM
S si
de)
Pack
etId
lem
ode
Exam
ple
2:BS
_PA_
MFR
MS
= 5
and
nAv
gW=
25th
en:
a =
1/M
in (n
;Max
(5;(
2^12
.5) /
30))
= 1
/Min
(n;M
ax(5
;193
))
If n
> 19
3i.e
. the
MS
com
pute
s m
ore
than
193
iter
atio
ns o
fCn,
case
ofa
MS
cam
ping
in th
e cu
rrent
cel
l for
abo
ut 3
min
47
sec
= 19
3*5
*235
ms
(235
ms
= C
CC
H 5
1-m
ultif
ram
edu
ratio
n). T
hen:
a =
1/1
93
Cn
= 0.
995
* Cn-
1+
0.00
5 C
bloc
kn
99.5
% o
fCn
com
esfro
m th
e pa
st v
alue
and
0.5
% fr
om th
e cu
rrent
val
ue.
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Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•C
ompu
tatio
n of
C (r
ecei
ved
sign
al
stre
ngth
atM
S si
de)
Pack
et T
rans
ferm
ode
In V
12.4
C, t
he M
S is
ask
ed in
SI1
3 or
in tr
ansf
er to
mak
e re
ceiv
edsi
gnal
leve
l m
easu
rem
ents
on th
e se
rvin
g ce
llB
CC
Hca
rrie
r (PC
_MEA
S_C
HA
N =
0).
The
mea
sure
men
ts s
hall
be fi
ltere
d w
itha
runn
ing
aver
age
filte
r:
Cn
= (1
-b)*
Cn-
1+
b *S
S n
Whe
re:
SSn
is th
e re
ceiv
edsi
gnal
leve
lof t
he m
easu
rem
ent s
ampl
es,
bis
the
forg
ettin
g fa
ctor
(sam
e fu
nctio
nas
a),
And
nis
the
itera
tion
inde
x:W
hen
ente
ring
Pack
et T
rans
fer m
ode,
the
filte
r sha
llco
ntin
ue fr
om th
en
and
Cn
valu
es o
btai
ned
durin
g Pa
cket
Idle
mod
e.
The
curre
nt C
nva
lue
shal
l be
used
in P
CH
form
ula
to c
alcu
late
the
outp
ut
pow
er w
hen
the
MS
trans
fers
its
first
radi
o bl
ock.
V12
.4 C
GPR
S pr
esen
tatio
n -
Sess
ion
328
thSe
pt. 2
001
-16
NO
RTE
L N
ETW
OR
KS
CO
NFI
DEN
TIA
L
Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•C
ompu
tatio
n of
C (r
ecei
ved
sign
al s
tren
gth
atM
S si
de)
Pack
etTr
ansf
erm
ode
The
forg
etfa
ctor
b pe
rmits
to
give
mor
e or
less
impo
rtanc
e to
Cn
past
va
lues
.b
= 1
/ (6
* TA
VG_T
)
T AVG
_Tis
bro
adca
ston
BC
CH
SI 1
3 an
d re
pres
ents
the
mul
tifra
mes
filte
ring
win
dow
forC
nco
mpu
ting
(in n
umbe
r ofm
ultif
ram
es):
T AVG
_T=
[2^(
n Avg
T/2
)]/6
In th
is m
ode,
the
MS
deco
des
1 BC
CH
blo
ck p
erm
ultif
ram
e.
V12
.4 C
GPR
S pr
esen
tatio
n -
Sess
ion
328
thSe
pt. 2
001
-17
NO
RTE
L N
ETW
OR
KS
CO
NFI
DEN
TIA
L
Pow
er c
ontr
ol fo
r GPR
SA
ssoc
iate
d pa
ram
eter
s
•C
ompu
tatio
n of
C (r
ecei
ved
sign
al s
tren
gth
atM
S si
de)
Pack
etTr
ansf
erm
ode
Exam
ple
1n A
vgT
= 0
then
:b
= 1
/(6
*1/6
)) =
1C
n=
SSn
100
%of
Cn
com
esfro
m th
e m
easu
red
valu
e.Ex
ampl
e2
n Avg
T=
25th
en:
b =
1/(
2^12
.5)=
1.7
e-4
Cn
= C
n-1
0,01
7% o
f Cn
com
esfro
mth
e cu
rrent
val
ue a
nd 0
,999
83%
com
ing
from
pa
st v
alue
s.
