Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

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Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1

Transcript of Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Page 1: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Given x = -5, z = 3, a = 4. Evaluate each expression.

1. 2x

2. 25(2)z-1

3. 75(0.5)a+1

Page 2: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.
Page 3: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

f(x) = a · (b)x a: the starting value

b: rate of change (base)

x: variable of time (exponent)

Page 4: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Problem #1

Fold a piece of notebook paper 50 times & determine the number of layers of paper.

Page 5: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Number of Folds

0 1 2 3 4

# of layers of paper

1

Fold a piece of notebook paper 50 times & determine the number of layers of paper.

Page 6: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

f(x) = a · (b)x a: the starting value

b: rate of change (base)

x: variable of time (exponent)Answer:

f(50) = 1 · (2)50 = 1.126 x 1015 layers

Page 7: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Problem #2

The Population of the U.S. was 248,718,301 in 1990 and was projected to grow at a rate of about 8% per decade.

y = A(1 + r) t

Predict the population, to the nearest hundred thousand, for the years 2010 and 2025.

Page 8: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 1) To obtain the base (rate of change) for exponential growth, add the growth rate to 100%.

100% + 8% = 108%

Or

1.08

Page 9: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 2) Write the expression for the population x decades after 1990 (since 1990 is your starting year).

= 248,718,301 · (1.08)x

f(x) = a · (b)x

Page 10: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 3 a.) Since the year 2010 is 2 decades (20 years) after 1990, substitute 2 for x.

= 248,718,301 · (1.08)x

= 248,718,301 · (1.08)2

= 290,105,026.3

~290,100,000 people

Page 11: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 3 b.) Since the year 2025is 3.5 decades (35 years) after 1990, substitute 3.5 for x.

= 248,718,301 · (1.08)x

= 248,718,301 · (1.08)3.5

= 325,604,866

~325,600,000 people

Page 12: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Problem #3

Elimination The rate at which caffeine is eliminated from the bloodstream of an adult is about 15% per hour. An adult drinks a soda, and the caffeine in his bloodstream usually reaches a peak level of 30 milligrams

Predict the amount, to the nearest 10th of a milligram, of caffeine remaining 1 hour after the peak level & 4 hours after the peak level.

Page 13: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 1) To obtain the base (rate of change) for exponential decay, subtract the rate of decay from 100%.

100% - 15% = 85%

Or

.85

Page 14: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 2) Write the expression for the caffeine level x hours after the peak level.

= 30 · (0.85)x

f(x) = a · (b)x

Page 15: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 3 a.) Substitute 1 (1 hour) for x.

= 30 · (0.85)x

= 30 · (0.85)1

= 25.5 mg

Page 16: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Step 3 b.) Substitute 4 (4 hours) for x.

= 30 · (0.85)x

= 30 · (0.85)4

= 15.7 mg

Page 17: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Problem 4:The birth rate for a colony of ants is 60%. The

death rate is 46%. Assume that at the beginning of the observations the population was 650.

What will the population be in 5 years? 20 years?

Page 18: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

a)What is the difference between the birth and death rates?

b)Is the population increasing or decreasing?

c) Write an equation that could model this situation.

d) What is the population in 5 years and 20 years?

f(x) = a · (b)x

Page 19: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

a) 14%

b)Increasing

c)

d) 1252 in 5 years and 8933 in 20 years

650 1.14x

Page 20: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

Problem 5:The birth rate for a school of guppies is 56%. The death rate is 64%. Assume that at the beginning of the observations the population was 800.

What will the population be in 12 years? 50 years?

Page 21: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

a) What is the difference between the birth and death rates? b) Is the population increasing or decreasing? c) Write an equation that could model this situation. f(x) = a · (b)x d) What will the populations be in 12 and 50 years?

Page 22: Given x = -5, z = 3, a = 4. Evaluate each expression. 1. 2 x 2. 25(2) z-1 3. 75(0.5) a+1.

a) 8% b) decreasing c) f(x) = 800 · (.92)x d) 294 in 12 and 12 in 50 years