The battle of New Orleans Journal of Genevieve Gibbs Bourgeois January 8, 1815.
Gibbs Lecture 8 (1)
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Transcript of Gibbs Lecture 8 (1)
1
Gibbs free energy and
Equilibrium
Gibbs Free Energy
Gibbs free energy is a measure of chemical
energy
Gibbs free energy for a phase:
G = H - TS
Where:
G = Gibbs Free Energy
H = Enthalpy (heat content)
T = Temperature in Kelvins
S = Entropy (can think of as randomness)
Entropy Change in the Universe
The universe is composed of the system and the surroundings.
Therefore,
Suniverse = Ssystem + Ssurroundings
For spontaneous processes
Suniverse > 0
Entropy Change in the Universe
This becomes:
Suniverse = Ssystem +
Multiplying both sides by T,
TSuniverse = Hsystem TSsystem
Hsystem
T
2
Gibbs Free Energy
TSuniverse is defined as the Gibbs free
energy, G.
When Suniverse is positive, G is
negative.
Therefore, when G is negative, a
process is spontaneous.
Under standard conditions
∆Gosys = ∆Ho
sys - T∆Sosys
An isolated system is said to be in chemical equilibrium if no changes occur in the chemical composition of the system. The criterion for chemical equilibrium is based on the second law of thermodynamics, and for a system at a specified temperature and pressure it can be expressed as For the reaction where the v's are the stoichiometric coefficients.
© The McGraw-Hill Companies, Inc.,1998
Equilibrium Criterion Equilibrium Criterion Criterion for Chemical Equilibrium Criterion for Chemical Equilibrium
3
The four Gibbs fundamental equations
Relations from the fundamental equations
PdVSdTda
VdPTdSdh
VdPSdTdg
PdVTdSdu TS
u
V
P
V
u
S
TS
h
P
V
P
h
S
PV
a
T
S
T
a
V
VP
g
T
S
T
g
P
Inspection of above equations gives the eight
Coefficient Relations below
Pv s
h
s
uT
Ts v
a
v
uP
Pv T
g
T
as
Ts P
g
P
hv
Maxwell Relations
4
Deriving Maxwell Relations
First, start with a known equation of state such as that of internal energy
Next, take the total derivative of with respect to the natural variables. For example, the
natural of internal energy are entropy and volume.
dVV
UdS
S
UdU
SV
Deriving Maxwell Relations
TS
U
V
P
V
U
S
Now that we have the total derivative with respect to its natural variables, we can refer
back to the original equation of state and define, in this example, T and P.
dVV
UdS
S
UdU
SV
Maxwell Relations
f(x,y)
x
y
df
1
2
dx
dy
yxxy y
f
xx
f
y
yxx
M
y
L
Now, let’s assume that the partial derivatives themselves are state
functions of x and y, as well, where:
yx
fL
xy
fM
MdyLdxdf
yxff ,
dyy
fdx
x
fdf
xy
Let’s consider an arbitrary state function of two variables,
let’s write the total differential of that function.
Deriving Maxwell Relations
We must now take into account a rule in partial derivatives
When taking the partial derivative again, we can set both sides equal
and thus, we have derived a Maxwell Relation
5
Derivation of Maxwell's Equations from Mixed Second
Derivatives
sv
u
s
u
vv
T
svs
2
vs
u
v
u
ss
P 2
vv
vs s
P
v
T
By comparison we get
1st Maxwell equation
Maxwell Relations
VSU , dVV
UdS
S
UdU
SV
PdVTdSdU
VS S
P
V
T
PSH ,
VTA ,
PTG ,
dPP
HdS
S
HdH
SP
dVV
AdT
T
AdA
TV
dPP
GdT
T
GdG
TP
VdPTdSdH
PdVSdTdA
VdPSdTdG
PS S
V
P
T
VT T
P
V
S
PT T
V
P
S
yxx
M
y
L
dy
y
fdx
x
fdf
xy
MdyLdxdf yxff ,
We now apply this analysis to our thermodynamic state functions …
and obtain the well known Maxwell relations.
• The Maxwell relations are
• The equations that relate
the partial derivatives of
properties P, v, T, and s of
a simple compressible
substance to each other
are called the Maxwell
relations. They are
obtained from the four
Gibbs equations,
Variation of G with P
G
pV
V V V
T
gas liquid solid
gas
liquid
solid
p
G
6
Pressure dependence of G
)()( liquids, and solidsfor
)/ln()()( :gasesfor
)()(
12
1212
12
2
1
2
1
2
1
PGPG
PPnRTPGPG
VdPpGpG
VdPdGVP
G
P
P
P
P
P
PT
Variation of G with T
G
TS
S S S
p
gas liquid solid
gas
liquid
solid
T
G
Gibbs-Helmholz Equation
2
22
)/(
1
T
H
T
TG
T
H
T
G
T
G
T
T
HGS
T
G
p
p
p
T Dependence of G
121
1
2
2
2
2
11)()(
)/(
)/(
2
1
2
1
TTH
T
TG
T
TG
T
dTHTGd
T
H
T
TG
T
T
T
T
p
7
Chemical Potential
• The chemical potential of substance A in a
mixture of nA moles A, nB moles B, nC
moles C, etc. is the ratio of dG to dnA
when the composition, temperature, and
pressure remain constant.
,...,,, CB nnPTA
An
G
Ideal Gas Mixture
A
pure
AA
pure
A
pure
mm
xRTPPRT
PPRTP
PPRTPGPG
PPnRTPGPG
ln/ln
:mixture gas idealan in A substancefor
)/ln()(
)/ln()()(
)/ln()(=)(
:substance pure afor
0
A
0
00
00
Chemical Potential
Chemical potential is defined as
, , j i
i i
i T P n
GG
n
• The last quantity in the above expression is the partial molar
Gibbs energy.
• This expression shows how the free energy changes as one
changes the number of moles of component i holding T, P and all
other components fixed.
• This is the potential that drives the flow of mass during a
chemical process or a phase change.
Activities (solvent)
Start with the definition of the chemical potential of a real or ideal
solvent
0
0ln A
A A
A
pRT
p
• If the solvent obeys Raoult’s law, , we can write
0 lnA A ART x
• If the solvent does not obey Raoult’s law (i.e. not ideal) we can
preserve the above equation by writing
0 lnA A ART a
*
A A AP x P
8
Activities (solvent) The activity of the solvent approaches the mole fraction as xA
1
1A A Aa x as x
• A convenient way of expressing this convergence is to introduce the
activity coefficient
1 1A A A A Aa x as x
• The chemical potential of the solvent becomes
0 ln lnA A A ART x RT
Gibbs Free Energy
Chemical Reactions
If G is negative, the reaction is spontaneous
in the forward direction.
If G is zero, the reaction is at equilibrium.
There is no driving force tending to make the
reaction go in either direction.
If G is positive, the reaction is
nonspontaneous in the forward direction.
G allows us to predict whether a process is
spontaneous or not (under constant
temperature and pressure conditions):
G < 0 spontaneous in forward direction
G > 0 non-spontaneous in forward
direction/spontaneous in reverse
direction
G = 0 at equilibrium
© The McGraw-Hill Companies, Inc.,1998
Equilibrium Criterion Equilibrium Criterion
9
Criterion for Chemical Equilibrium Criterion for Chemical Equilibrium
Gibbs free energy and
Phase Equilibrium
Clapeyron Equation
Liquid/Vapour Phase Equilibrium Liquid/Vapour Phase Equilibrium
The multicomponent multiphase system is in phase equilibrium when the specific Gibbs function of each
component is the same in all phases
10
Equilibrium Diagram for a Two-Phase Mixture of Oxygen and Nitrogen at 0.1 MPa
Equilibrium Diagram for a Two-Phase Mixture of Oxygen and Nitrogen at 0.1 MPa
Equilibrium between 2 phases (pure components)
Liq or solid
p
I
gas, liq, or sol
II
nI moles of phase I; nII moles of phase II
G = nIgI + nIIgII = a minimum at equilibrium
gI, gII = molar free energies of phases I and II
dGT,p = dnIgI + dnIIgII = dnI(gI – gII)
Because dnI = - dnII
gI = gII
chemical equilibrium: analogous to thermal equilibrium
(TI = TII) and mechanical equilibrium (pI = pII)
dG caused by transferring dnI moles to II
No inert gas
Phase equilibria Fixed P, T processes and the Gibbs function
'' '' ''' ''' '' '' ''' '''
1 2 1 1 2 2
'' ''' '' '''
1 1 2 2also (conservation of particles)
G G n g n g n g n g
n n n n
Combined, these constraints lead to: g'' = g'''
P, T P, T
V1 V2
Gas
Liquid
Two phases are said to be in phase equilibrium
when there is no transfor-mation from one phase
to the other. Two phases of a pure substance are
in equilibrium when each phase has the same
value of specific Gibbs function. That is,
gf = gg
11
Clapeyron equation for phase change
Since on a co-existence curve,
Therefore, for a first order
phase transformation,
Where is the latent heat from phase 1 to 2.
• The Clapeyron equation enables us to determine
the enthalpy change associated with a phase
change from a knowledge of P, v, and T data
alone. It is expressed a
12
12
ldP
dT T v'' v'
23
23
ldP
dT T v''' v''
13
13
ldP
dT T v''' v'
solid-liquid
(melting)
liquid-vapor
(vaporization)
solid-vapor
(sublimation)
The Clapeyron equation
Temperature
Pre
ssu
re
Liquid
Gas
Solid
-.007oC atm-1
Vapor
Water
Water &
Vapor
Volume (V)
Pre
ssu
re (
e)
Ice & Vapor 0oC
T
Ice
Ice & Water
Triple Line
(courtesy F. Remer)
12
• For liquid-vapor and solid-vapor phase-change
processes at low pressures, the Clapeyron
equation can be approximated as
Integrated Clausius-Clapyron equation
For modest temp. range, CP term can be neglected, so hvap ≈ constant
• Integrate the Clausius-Clapyron equation:
T
1
T
1
R
h
p
pln
ref
v ap
ref,sat
sat
• alternate form:
T/BApln sat
R
hBpln
RT
hA
v ap
ref,sat
ref
v ap
lnpsat
slope = -hvap/R
1/T
Vapor-Liquid Equilibrium
(VLE) of Binary Systems
13
Overall all Objectives
Qualitative VLE analysis.
The thermodynamics of solutions: The ideal
solution reference states.
Raoult’s law
Deviation from Raoult’s law and the introduction
of the activity coefficient
Azeotropes
Thermodynamics and distillation
The description for binary
mixtures
The thermodynamics of solutions
Our goal is to calculate pressure, temperature
and compositions of a phase in equilibrium.
We need to define a model solution system.
Ideal gas
Ideal solution
(macroscopic definition)
0
ln
ln
ideal solution ideal
mixing mixing
ideal solution
mixing i i
ideal solution
mixing i i
V H
S R x x
G RT x x
14
Phase Equlibrium in Multicomponent Systems
Two-component liquid at equilibrium with its vapor.
At constant P and T,
2 1 21 2 2
1 1 21 2 1
1 1
1 1, , , , , , , ,
2 2
2 2, , , , , , , ,
g g gl l l
g g gl l l
l g
l g
P T n n n P T n n n
l g
l g
P T n n n P T n n n
G GdG dn dn
n n
G Gdn dn
n n
1 1 2 2Since 0, 0, andl g l gdn dn dn dn
1 2,g gn n
1 2,l ln n
2 1 2
1
1 , , , ,
, etc.g gl
l
l
P T n n n
G
n
1 1 2 2,l g l g
Assuming the vapor behaves as an ideal gas, the chemical potential of substance
j in the solution is
0
0( ) ln
jl g
j j j
PT RT
P
For the pure substance j,
*
* * 0
0( ) ln
jl g
j j j
PT RT
P
0because ( ) doesn't depend on mole fractions. It follows thatj T
*
*ln
jl l
j j
j
PRT
P
Ideal Solutions and Raoult’s Law
If the partial vapor pressure of each component in a solution obeys the relation
*
j j jP x P
where is the mole fraction of component in the liquid phase,j
j
i
i
nx j
n
sol * lnj j jRT x
the solution is called ideal. Ideal solutions follow Raoult’s law,
sol
*
Here is the chemical potential of (liquid) component in the solution
and is the chemical potential of the pure substance.
j
j
j
15
Ideal Solutions/Raoult’s Law
Ap*
p*B
Mole Fraction of A, x A
Pressure
Total Pressure
Partial
Pressure of A
Partial
Pressure of B
Mixtures which obey Raoult’s
Law throughout the
composition range are Ideal
Solutions
Phenomenology of Raoult’s
Law: 2nd component inhibits
the rate of molecules leaving
a solution, but not returning
rate of vaporization XA
rate of condensation pA
at equilibrium rates equal
implies pA = XA p*A
Vapor Pressure of Ideal Two-Component Solutions
* * * * * * *
1 2 1 1 2 2 1 1 1 2 1 1 2 2 1(1 ) ( ) (linear in )P P P x P x P x P x P x P P P x
The mole fraction of
component 1 in the liquid
phase is
*
21 * *
1 2
P Px
P P
P *
1P
*
2P
P
1P
2P
1x 10
11
* * * * *
1 1 2 1 1 2
* * * * * *
1 1 2 2 1 2 1 2
(Dalton's law)
1
Py
P
x P P P P P P
x P x P P P P P P P
Calculate the mole fraction y1 of component 1 in the vapor phase at a given
value P of the vapor pressure using Dalton’s law of partial pressures:
1
1
1
depends linearly on .
depends nonlinearly
(hyperbolically) on (and on )!
x P
y
P x
*
1P
*
2P
1 vs. P x
1 1 or x y10
1 vs. P y
liquid-vapor coexistence
Applying Henry’s Law & Raoult’s Law
Henry’s law applies to the
solute in ideal dilute
solutions
Raoult’s law applies to
solvent in ideal dilute
solutions and solute &
solvent in ideal solutions
Real systems can (and
do ) deviate from both
Bp*
BK
Mole Fraction of B, x B
Pressure
B is solvent
B is solute
Henry's Law
Raoult's Law
16
Deviations from Raoult’s Law Raoult’s Law works well when components of a mixture are structurally similar
Wide deviations possible for dissimilar mixtures
Ideal-Dilute Solutions
Henry’s Law (William Henry)
For dilute solutions, v.p. of solute is proportional to the mole fraction (Raoult’s
Law) but v.p. of the pure substance is not
the constant of proportionality
Empirical constant, K, has dimensions
of pressure
pB = xBKB (Raoult’s Law says pB =
xBpB)
Mixtures in which the solute obeys Henry’s Law
and solvent obeys Raoult’s Law are called Ideal
Dilute Solutions
Differences arise because, in dilute soln,
solute is in a very different molecular
environment than when it is pure
The thermodynamics of ideal solutions
On the microscopic scale Interactions between species is the same
Non-Ideal Solutions
P *
j j jP x P
*
1P
*
2P
P
1P
2P
1x 10
attractive interactions between
different molecules dominate
* as 1 onlyj j j jP x P x
*
1P
*
2P
P
1P
2P
1x 10
repulsive interactions between
different molecules dominate
Azeotropes
Sometimes interactions between the molecules distort the phase diagram. If the liquid’s free energy is less concave than that of the gas, the curves can intersect in two places.
Therefore, at this T, there are two composition ranges at which a combination of gas and
liquid is more stable. At lower T, G of gas moves up faster than G of liquid due to the entropy
difference, so the intersections move closer together until finally the two curves touch each
other at a single point. The composition at this point is the so-called azeotrope; at this concentration, the mixture boils at a well-defined boiling temperature, just as a pure
substance would.
17
Water-Ethanol Mixture
For the water-ethanol mixture, the azeotrope concentration corresponds to ~95% of ethanol
in the mixture. This is the limit that can be
reached by distillation of a less-alcohol-rich
mixture.
Activities (solvent) The activity of the solvent approaches the mole fraction as xA
1
1A A Aa x as x
• A convenient way of expressing this convergence is to introduce the
activity coefficient
1 1A A A A Aa x as x
• The chemical potential of the solvent becomes
0 ln lnA A A ART x RT
The Phase Rule
• The Gibbs phase rule is a fundamental relation between the number of components in a chemical system, the number of phases present, and the number of variables that can be independently varied while maintaining equilibrium (the variance, D).
• Consider a system of C components with f coexisting phases. How many free parameters are there?
• Total number of parameters: P, T, and C–1 compositional parameters for each phase = (C+1)f
• Total number of constraints: • P must be equal in all phases: f–1 constraints • T must be equal in all phases: f–1 constraints • for each component must be equal in all phases: C(f–1) • in special cases (critical, singular points, etc.), other constraints
• Remaining degrees of freedom: (C+1)f – (C+2)(f–1) = C – f + 2
D C f 2 other
Spontaneity involves
S
H
G = H – TS
Spontaneity is favoured by increasing S and
H is large and negative.
18
Tabulated data of Gfo can be used to calculate
standard free energy change for a reaction as
follows:
)(reactantsGm(products)GnG of
of
o
Stoichiometric coefficients
Free Energy and Temperature
How is change in free energy affected by
change in temperature?
G = H – TS
H S -TS G = H - TS
+
+ +
+
+
+ - - -
-
-
-
-
+ at all temp
- at all temp
- at high temp
+ at low temp
+ at high temp
- at low temp
Class test
A steam power plant operates on the ideal reheat
Rankine cycle. Steam enters the high pressure
turbine at 8 Mpa and 500 C and leaves at 3 Mpa.
Steam is then reheated at constant pressure to
500 C before it expands to 20 kPa in the low
pressure turbine. Determine the turbine work
output, in kJ/kg and the thermal efficiency of the
cycle. Also show the cycle on a T-s diagram with
respect to the saturation lines.