Geometry Review August 2011. 5 7 10 12 P Q R S T P Q R S T.
Transcript of Geometry Review August 2011. 5 7 10 12 P Q R S T P Q R S T.
Geometry ReviewAugust 2011
5
7
10
๐ฅ
12
๐ฅ+10 512
=10๐ฅ+10
5 (๐ฅ+10 )=1205 ๐ฅ+50=120
5 ๐ฅ=705๐ฅ5
=705
๐ฅ=14
P
Q
RS
TP
Q
RS
T
7
25
๐2+๐2=๐2
72+๐2=252
49+๐2=625๐2=576
โ๐2=โ576๐=24
๐=โ (๐ฅ2โ๐ฅ1 )2+( ๐ฆ2โ ๐ฆ1 )2
๐=โ (9โ1 )2+(2โโ4 )2
๐=โ (8 )2+ (6 )2
๐=โ64+36๐=โ100๐=10
๐ ๐ฆโ๐๐ฅ๐๐ (๐ฅ , ๐ฆ )โ (โ ๐ฅ , ๐ฆ )
30
80 180โ30โ80=70
4 ๐ฅ+2 ๐ฆ=142 ๐ฆ=โ4 ๐ฅ+14๐ฆ=โ2๐ฅ+7
๐=โ2๐โฅ=โ2
๐ฆ=โ2๐ฅ+๐2=โ2 (2 )+๐2=โ4+๐6=๐
๐ ๐ฆ=๐ฅ (๐ฅ , ๐ฆ )โ (๐ฆ ,๐ฅ )๐ ๐ฆ=๐ฅ (โ3๐ ,4๐ )โ (4๐ ,โ3๐ )
A
M
5
25
2
B
๐ฆ=4
XX
P
Q
R2 ๐ฅ
3 ๐ฅ
5 ๐ฅ
2 ๐ฅ+3 ๐ฅ+5 ๐ฅ=18010 ๐ฅ=180๐ฅ=18
2 ๐ฅ=2 โ18=363 ๐ฅ=3 โ18=545 ๐ฅ=5 โ18=90
๐
๐
If the diagonals do not bisect each other, then the quadrilateral can not be a parallelogram!
๐ฅ+2 ๐ฆ=32 ๐ฆ=โ๐ฅ+32 ๐ฆ2
=โ๐ฅ2
+32
๐ฆ=โ12๐ฅ+32
๐=โ12
๐โฅ=2
๐= h๐ต๐ต=๐๐๐ ๐๐๐๐๐๐ต=
12h๐
๐ต=12โ6 โ4
๐ต=12
๐=12 โ10๐=120
6 2 4
๐ฅ
๐ฅ
8
๐ด๐ธ โ๐ธ๐ต=๐ถ๐ธ โ๐ท๐ธ8 โ 4=๐ฅ โ๐ฅ32=๐ฅ2
โ32=โ๐ฅ2โ32=๐ฅ
โ16 โ2=๐ฅ4โ2=๐ฅ
๐=(๐โ2 )180๐=(6โ2 )180๐=(4 )180๐=720
h๐ธ๐๐ ๐ผ๐๐ก๐๐๐๐๐=7206
h๐ธ๐๐ ๐ผ๐๐ก๐๐๐๐๐=120
๐๐ h๐ธ๐๐ ๐ธ๐ฅ๐ก๐๐๐๐๐=
3606
h๐ธ๐๐ ๐ธ๐ฅ๐ก๐๐๐๐๐=60
h๐ธ๐๐ ๐ผ๐๐ก๐๐๐๐๐=180โ60h๐ธ๐๐ ๐ผ๐๐ก๐๐๐๐๐=120
๐๐ด๐ต=๐ฆ2โ ๐ฆ1๐ฅ2โ๐ฅ1
๐๐ด๐ต=6โ20โ8
๐๐ด๐ต=4โ8
๐๐ด๐ต=โ12
๐โฅ=2
๐๐๐๐ฅ=๐ฅ2+๐ฅ12
๐๐๐๐ฅ=8+02
๐๐๐๐ฅ=82
๐๐๐๐ฅ=4
๐๐๐๐ฆ=๐ฆ2+๐ฆ 12
๐๐๐๐ฅ=2+62
๐๐๐๐ฅ=82
๐๐๐๐ฅ=4
๐๐๐๐ด๐ต=(4,4 )
๐ฆ=๐๐ฅ+๐4=2 โ4+๐4=8+๐โ4=๐
๐ฆ=2 ๐ฅโ4
๐2+๐2=๐2
72+๐ฅ2= (๐ฅ+1 )2
๐ฅ2+49=(๐ฅ+1 ) (๐ฅ+1 )๐ฅ2+49=๐ฅ2+๐ฅ+๐ฅ+1๐ฅ2+49=๐ฅ2+2๐ฅ+1โ๐ฅ2โ๐ฅ2
49=2๐ฅ+148=2๐ฅ24=๐ฅ๐ฅ+1=24+1=25
In a trapezoid, the bases are parallel.
Parallel lines intercept congruent arcs between them.
180โ80=1001002
=50
5050
๐ต๐ถ=50
๐=43๐ ๐3
๐=43๐ โ93
๐=43๐ โ729
๐=972๐
๐ถ๐๐๐ก๐๐โ (5 ,โ4 )๐=6
(๐ฅโ5 )2+(๐ฆ+4 )2=62
(๐ฅโ5 )2+(๐ฆ+4 )2=36
Statements Reasons
1.โ ๐ด๐ถ๐ตโ โ ๐ด๐ธ๐ท 1. Given
2 .โ ๐ดโ โ ๐ด 2. Reflexive Postulate
3. ฮ ๐ด๐ต๐ถ ฮ ๐ด๐ท๐ธ 3. AA AA
A
B
C
6
4
3
2 6
4
3
2 ๐ถ๐๐๐ก๐๐๐๐ : (7,5 )
180โ70=1101102
=55
55
55
180โ55=125
125
180โ125โ28=27
27
is not isosceles because all the angles have different measures, which means all the sides have different lengths, making the triangle scalene, not isosceles.
๐ท2 ๐ โ3,1
Gโโ
Sโโ
Hโโ
๐ฅ+2๐ฅ
=๐ฅ+64
4 (๐ฅ+2 )=๐ฅ (๐ฅ+6 )4 ๐ฅ+8=๐ฅ2+6 ๐ฅโ4 ๐ฅโ4 ๐ฅ
8=๐ฅ2+2๐ฅโ8โ80=๐ฅ2+2๐ฅโ80=(๐ฅ+4 ) (๐ฅโ2 )๐ฅ+4=0๐ฅ=โ4
๐ฅโ2=0๐ฅ=2Reject
x
y
A
B
C
10
8
5
410
4
5
2D E
F
๐=๐๐๐ ๐๐๐ข๐
๐๐ด๐ท=54
๐๐ท๐ธ=06=0
๐๐น๐ธ=54
๐๐ด๐น=06=0
Since the opposite sides of ADEF have equal slopes, they are parallel. Since the opposites sides of ADEF are parallel, ADEF is a parallelogram.
๐๐ด๐ท :๐2+๐2=๐2
๐๐ด๐ท :52+42=๐2
25+16=๐241=๐2
โ 41=๐6.4=๐๐๐ท๐ธ=6
Since two consecutive sides of parallelogram ADEF are not congruent, then ADEF is not a rhombus.
6.4
6