Genetics.2012

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    Genetics

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    Gregor Mendel(1822-1884)

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    Reproduction in Flowering Plants

    Pollen contains sperm

    Produced by the stamen

    Ovary contains eggs

    Found inside the flower

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    Pollen carries sperm to theeggs for fertilization

    Self-fertilization canoccur in the same flower

    Cross-fertilization can

    occur between flowers

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    Mendels

    Experiments

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    Antagonistic Pairs

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    Monohybrid

    Crosses

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    P1 Monohybrid Cross Trait: Seed Shape

    Alleles: R

    Round r

    Wrinkled

    Cross: Roundseeds x Wrinkled seeds

    RR x rr

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    R

    R

    rr

    Rr

    RrRr

    Rr

    Genotype:Rr

    Phenotype:Round

    GenotypicRatio: All alike

    Phenotypic

    Ratio: All alike

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    P1 Monohybrid Cross Review

    Homozygous dominant x Homozygousrecessive

    OffspringallHeterozygous(hybrids)

    Offspring calledF1 generation

    Genotypic & Phenotypic ratio isALLALIKE

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    F1 Monohybrid Cross Trait: Seed Shape

    Alleles: R

    Round r

    Wrinkled

    Cross: Roundseeds x Round seeds

    Rr x Rr

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    R

    r

    rR

    RR

    rrRr

    Rr

    Genotype:RR, Rr, rr

    Phenotype:Round &wrinkled

    G.Ratio: 1:2:1

    P.Ratio: 3:1

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    Mendels Laws

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    Law of Segregation

    During the formation of gametes (eggs or

    sperm), the two alleles responsible for a

    trait separate from each other.

    Alleles for a trait are then "recombined"

    at fertilization, producing the genotype for

    the traits of the offspring.

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    Applying the Law of Segregation

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    Law of Independent Assortment

    Alleles for differenttraits are

    distributed to sex cells (& offspring)

    independently of one another.

    This law can be illustrated using

    dihybrid crosses.

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    Dihybrid Cross

    A breeding experiment that tracksthe inheritance of two traits.

    Mendels Law of IndependentAssortment

    a. Each pair of alleles segregates

    independently during gamete formation b. Formula: 2n (n = # of heterozygotes)

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    Dihybrid Cross

    Traits: Seed shape & Seed color

    Alleles: R roundr wrinkledY yellow

    y green

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    RrYy x RrYy

    RY Ry rY ry RY Ry rY ry

    All possible gamete combinations

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    Dihybrid Cross

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    RY Ry rY ry

    RY

    Ry

    rY

    ry

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    Dihybrid Cross

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    RRYY

    RRYy

    RrYY

    RrYy

    RRYy

    RRyy

    RrYy

    Rryy

    RrYY

    RrYy

    rrYY

    rrYy

    RrYy

    Rryy

    rrYy

    rryy

    Round/Yellow: 9

    Round/green: 3

    wrinkled/Yellow: 3

    wrinkled/green: 1

    9:3:3:1 phenotypic

    ratio

    RY Ry rY ry

    RY

    Ry

    rY

    ry

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    Dihybrid Cross

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    Round/Yellow: 9

    Round/green: 3wrinkled/Yellow: 3wrinkled/green: 1

    9:3:3:1

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    Summary of Mendels laws

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    LAWPARENT

    CROSSOFFSPRING

    DOMINANCE TT x tttall x short

    100% Tttall

    SEGREGATIONTt x Tttall x tall

    75% tall25% short

    INDEPENDENTASSORTMENT

    RrGg x RrGground & green

    xround & green

    9/16 round seeds & green

    pods3/16 round seeds & yellow

    pods3/16 wrinkled seeds & green

    pods1/16 wrinkled seeds & yellow

    pods

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    Incomplete DominanceandCodominance

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    Incomplete Dominance

    F1 hybrids have an appearance somewhat inbetween the phenotypes of the two parentalvarieties.

    Example: snapdragons (flower)

    red (RR) x white (rr)

    RR = red flower

    rr = white flower

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    R

    R

    r r

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    Incomplete Dominance

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    Rr

    Rr

    Rr

    Rr

    R

    R

    r

    All Rr = pink(heterozygous pink)

    produces theF1 generation

    r

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    Incomplete Dominance

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    Codominance

    Two alleles are expressed (multiplealleles) in heterozygous individuals.

    Example: blood type

    1. type A = IAIA or IAi 2. type B = IBIB or IBi 3. type AB = IAIB 4. type O = ii

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    Codominance Problem

    Example: homozygous male Type B (IBIB)

    x heterozygousfemale Type A (IAi)

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    IAIB IBi

    IAIB IBi

    1/2 = IAIB

    1/2 = IBi

    IB

    IA i

    IB

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    Another Codominance Problem

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    Example: male Type O (ii)x

    female type AB (IAIB)

    IAi IBi

    IAi IBi

    1/2 = IAi1/2 = IBi

    i

    IA IB

    i

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    Codominance

    Question:If a boy has a blood type O and

    his sister has blood type AB,what are the genotypes andphenotypes of their parents?

    boy - type O (ii) X girl - typeAB (IAIB)

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    Codominance

    Answer:

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    IAIB

    ii

    Parents:

    genotypes = IAi and IBiphenotypes = A and B

    IB

    IA i

    i

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    Sex-linked Traits

    Traits (genes) located on the sexchromosomes

    Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carriedon X chromosome

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    Sex-linked Traits

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    Sex Chromosomes

    XX chromosome - female Xy chromosome - male

    fruit fly

    eye color

    Example: Eye color in fruit flies

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    Sex-linked Trait Problem Example: Eye color in fruit flies (red-eyed male) x (white-eyed

    female)XRY x XrXr

    Remember: the Y chromosome in malesdoes not carry traits. RR = red eyed Rr = red eyed rr = white eyed XY = male XX = female

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    XR

    Xr Xr

    Y

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    Sex-linked Trait Solution:

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    XR Xr

    XrY

    XR Xr

    XrY

    50% red eyedfemale

    50% white eyedmale

    XR

    Xr Xr

    Y

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    Female Carriers

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    Genetic PracticeProblems

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    Breed the P1 generation

    tall (TT) x dwarf (tt) pea plants

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    T

    T

    t t

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    Solution:

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    T

    T

    t t

    Tt

    Tt

    Tt

    Tt All Tt = tall(heterozygous tall)

    produces theF1 generation

    tall (TT) vs. dwarf (tt) pea plants

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    Breed the F1 generation

    tall (Tt) vs. tall (Tt) pea plants

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    T

    t

    T t

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    Solution:

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    TT

    Tt

    Tt

    tt

    T

    t

    T tproduces the

    F2 generation1/4 (25%) = TT1/2 (50%) = Tt

    1/4 (25%) = tt1:2:1 genotype3:1 phenotype

    tall (Tt) x tall (Tt) pea plants