Genetics.2012
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Transcript of Genetics.2012
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Genetics
copyright cmassengale 1
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copyright cmassengale 2
Gregor Mendel(1822-1884)
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Reproduction in Flowering Plants
Pollen contains sperm
Produced by the stamen
Ovary contains eggs
Found inside the flower
copyright cmassengale 3
Pollen carries sperm to theeggs for fertilization
Self-fertilization canoccur in the same flower
Cross-fertilization can
occur between flowers
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Mendels
Experiments
copyright cmassengale 4
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Antagonistic Pairs
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copyright cmassengale 6
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copyright cmassengale 8
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Monohybrid
Crosses
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P1 Monohybrid Cross Trait: Seed Shape
Alleles: R
Round r
Wrinkled
Cross: Roundseeds x Wrinkled seeds
RR x rr
copyright cmassengale 10
R
R
rr
Rr
RrRr
Rr
Genotype:Rr
Phenotype:Round
GenotypicRatio: All alike
Phenotypic
Ratio: All alike
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P1 Monohybrid Cross Review
Homozygous dominant x Homozygousrecessive
OffspringallHeterozygous(hybrids)
Offspring calledF1 generation
Genotypic & Phenotypic ratio isALLALIKE
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F1 Monohybrid Cross Trait: Seed Shape
Alleles: R
Round r
Wrinkled
Cross: Roundseeds x Round seeds
Rr x Rr
copyright cmassengale 12
R
r
rR
RR
rrRr
Rr
Genotype:RR, Rr, rr
Phenotype:Round &wrinkled
G.Ratio: 1:2:1
P.Ratio: 3:1
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Mendels Laws
copyright cmassengale 13
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Law of Segregation
During the formation of gametes (eggs or
sperm), the two alleles responsible for a
trait separate from each other.
Alleles for a trait are then "recombined"
at fertilization, producing the genotype for
the traits of the offspring.
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copyright cmassengale 15
Applying the Law of Segregation
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Law of Independent Assortment
Alleles for differenttraits are
distributed to sex cells (& offspring)
independently of one another.
This law can be illustrated using
dihybrid crosses.
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Dihybrid Cross
A breeding experiment that tracksthe inheritance of two traits.
Mendels Law of IndependentAssortment
a. Each pair of alleles segregates
independently during gamete formation b. Formula: 2n (n = # of heterozygotes)
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Dihybrid Cross
Traits: Seed shape & Seed color
Alleles: R roundr wrinkledY yellow
y green
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RrYy x RrYy
RY Ry rY ry RY Ry rY ry
All possible gamete combinations
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Dihybrid Cross
copyright cmassengale 19
RY Ry rY ry
RY
Ry
rY
ry
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Dihybrid Cross
copyright cmassengale 20
RRYY
RRYy
RrYY
RrYy
RRYy
RRyy
RrYy
Rryy
RrYY
RrYy
rrYY
rrYy
RrYy
Rryy
rrYy
rryy
Round/Yellow: 9
Round/green: 3
wrinkled/Yellow: 3
wrinkled/green: 1
9:3:3:1 phenotypic
ratio
RY Ry rY ry
RY
Ry
rY
ry
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Dihybrid Cross
copyright cmassengale 21
Round/Yellow: 9
Round/green: 3wrinkled/Yellow: 3wrinkled/green: 1
9:3:3:1
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Summary of Mendels laws
copyright cmassengale 22
LAWPARENT
CROSSOFFSPRING
DOMINANCE TT x tttall x short
100% Tttall
SEGREGATIONTt x Tttall x tall
75% tall25% short
INDEPENDENTASSORTMENT
RrGg x RrGground & green
xround & green
9/16 round seeds & green
pods3/16 round seeds & yellow
pods3/16 wrinkled seeds & green
pods1/16 wrinkled seeds & yellow
pods
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Incomplete DominanceandCodominance
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Incomplete Dominance
F1 hybrids have an appearance somewhat inbetween the phenotypes of the two parentalvarieties.
Example: snapdragons (flower)
red (RR) x white (rr)
RR = red flower
rr = white flower
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R
R
r r
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Incomplete Dominance
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Rr
Rr
Rr
Rr
R
R
r
All Rr = pink(heterozygous pink)
produces theF1 generation
r
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Incomplete Dominance
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Codominance
Two alleles are expressed (multiplealleles) in heterozygous individuals.
Example: blood type
1. type A = IAIA or IAi 2. type B = IBIB or IBi 3. type AB = IAIB 4. type O = ii
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Codominance Problem
Example: homozygous male Type B (IBIB)
x heterozygousfemale Type A (IAi)
copyright cmassengale 28
IAIB IBi
IAIB IBi
1/2 = IAIB
1/2 = IBi
IB
IA i
IB
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Another Codominance Problem
copyright cmassengale 29
Example: male Type O (ii)x
female type AB (IAIB)
IAi IBi
IAi IBi
1/2 = IAi1/2 = IBi
i
IA IB
i
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Codominance
Question:If a boy has a blood type O and
his sister has blood type AB,what are the genotypes andphenotypes of their parents?
boy - type O (ii) X girl - typeAB (IAIB)
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Codominance
Answer:
copyright cmassengale 31
IAIB
ii
Parents:
genotypes = IAi and IBiphenotypes = A and B
IB
IA i
i
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Sex-linked Traits
Traits (genes) located on the sexchromosomes
Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carriedon X chromosome
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Sex-linked Traits
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Sex Chromosomes
XX chromosome - female Xy chromosome - male
fruit fly
eye color
Example: Eye color in fruit flies
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Sex-linked Trait Problem Example: Eye color in fruit flies (red-eyed male) x (white-eyed
female)XRY x XrXr
Remember: the Y chromosome in malesdoes not carry traits. RR = red eyed Rr = red eyed rr = white eyed XY = male XX = female
copyright cmassengale 34
XR
Xr Xr
Y
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Sex-linked Trait Solution:
copyright cmassengale 35
XR Xr
XrY
XR Xr
XrY
50% red eyedfemale
50% white eyedmale
XR
Xr Xr
Y
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Female Carriers
copyright cmassengale 36
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Genetic PracticeProblems
copyright cmassengale 37
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Breed the P1 generation
tall (TT) x dwarf (tt) pea plants
copyright cmassengale 38
T
T
t t
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Solution:
copyright cmassengale 39
T
T
t t
Tt
Tt
Tt
Tt All Tt = tall(heterozygous tall)
produces theF1 generation
tall (TT) vs. dwarf (tt) pea plants
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Breed the F1 generation
tall (Tt) vs. tall (Tt) pea plants
copyright cmassengale 40
T
t
T t
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Solution:
i ht l 41
TT
Tt
Tt
tt
T
t
T tproduces the
F2 generation1/4 (25%) = TT1/2 (50%) = Tt
1/4 (25%) = tt1:2:1 genotype3:1 phenotype
tall (Tt) x tall (Tt) pea plants