General Chemistry

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Science is a systematic or organized body of knowledge obtained through observation and experimentation. Chemistry is a branch of science that deals with the study of matter(properties, structure, composition, changes and principles/laws that govern changes in matter).

Transcript of General Chemistry

Page 1: General Chemistry

Science is a systematic or organized body of knowledge obtained through observation and experimentation.

Chemistry is a branch of science that deals with the study of matter(properties, structure, composition, changes and principles/laws that govern changes in matter).

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Measurement SI Units commonly used

Length Meter (m) Meter (m)

Mass Kilogram (kg) Gram (g)

Volume Cubic meter(m3) Liter (l) , ml.

Amount of Substance

Mole(mol) Mole(mol)

Temperature Kelvin (K) Celsius( ◦ C)

1ml=1cm3 (or cc.); 1Liter = 1000 ml.=1000 cm3 (or cc.) = 1dm3

* 273 K = 0 ◦ C = 32◦ F

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Prefix Symbol Meaning Tera T 1012 Giga G 109 Mega M 106

Kilo k 103

Deci d 10-1 or 1/10

Centi c 10-2 or 1/100

Milli m 10-3 or 1/1000

Micro u 10-6 1/1000,000

Nano n 10-9

Pico p 10-12

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Temperature:

◦ F = 9 ◦ C + 32; 5

◦ C = 5 ( ◦ F - 32) 9

K= 273 + ◦ C

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Density: D(g/ml) = Mass/Volume ; D (g/L ) = M / V

for solids and liquids for gas

Accuracy tells how close a measurement is to the true value.

Precision tells how close two or more measurements agree with one another.

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Accuracy – how close a measurement is to the true valuePrecision – how close a set of measurements are to each other

Accurate &Precise Precise but

not accuratenot precise &

not accurate

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Properties of Matter

Properties –qualities or characteristics by which a given substance is identified.

Physical Properties qualities that can be observed with the senses,without changing the composition of the susbstance. Ex. colors, shapes, size

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Chemical Properties

qualities that can be observed after alteration of composition of the substance

Ex: iron rust, hydrogen is flammable

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Extrinsic or Extensive Properties• are properties that depend on the amount of the

substance in a sample • Ex: volume, length, mass

Intrinsic or Intensive Properties do not depend on the amount of substance ex.

density, boiling pt. melting pt

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Changes of Matter

Physical Change change in size, shape, physical state, no change in nature or compositon.Ex: freezing of water, pulverizing salt distillation of wine

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Chemical Change • change in the compositon of the

substance • a new substance is formed.• ex iron nail (Fe) → rust (Fe2O3) • charcoal (C) Δ CO2

• Fermentation of fruit juice

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Molecules = aggregate of two or more atoms held by a chemical bond.

I. Diatomic molecule is composed of two atoms.

a. with two similar atoms (element) ex: H2, N2, Cl2, F2

b. with two different atoms (compound) ex. HI, HF, CO, HCl

2. Polyatomic molecule is composed of three or more atoms.

a. with three similar atoms ex: O3 b. with three different atoms ex: HCN,

NH3, CaCO3, C6H12O6

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Ion = an atom or a group of atoms that has a positive(+) or negative(-) charge.

a. Cations are positively charged ions ( formed when there is a loss of one or more

electrons) ex: Na + , Ca +2, Al+3

Na◦atom 11p +11 e- = O; Na+cation11p + 0 e- = +1

b. Anions are negatively charged ions (formed when there is a gain of one or more

electrons) ex: Cl- , O -2

Cl◦ atom 17p + 17 e- = o; Cl- anion17p + 18e- = -1

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Mass number (A) = the total number of protons + number of neutrons

Atomic number (Z) = the number of protons in the nucleus of an atom.

A X

Z

12

6 C17

9 Cl

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Isotopes of Hydrogen

2 1 H

1

1 H3

1 H

Protons = _

Neutrons=_

Protons = _

Neutrons=_Protons = _

Neutrons =_

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Isotopes of Hydrogen

2 1 H

1

1 H3

1 H

Protons = 1

Neutrons= 0

Protons =1

Neutrons= 1Protons = 1

Neutrons = 2

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Isotopes of Uranium

235 92 U

234

92 U238

92 U

Protons = 92

Neutrons=

Protons =92

Neutrons=Protons = 92

Neutrons =

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Isotopes of Carbon and % Abundance

13 6C

12

6 C

Protons = 6

Neutrons= 6 Protons = 6

Neutrons= 7

% abundance =98.89%% Abundance = 1.11%

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Computations:12 x 0.9889 =11.866813 x 0.0111 = 0.1443 12.0111 atomic weight 12. atomic mass (mass no.)Mass no.- the whole no. nearest to the exact

atomic weight

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Atomic Structure : Atom- basic unit of an element that can enter into a chemical reaction, retains the identity of element

Electron (discovered by Joseph John Thomson) is negatively charge(-) particle

Neutron (discovered by James Chadwick) is electrically neutral particle.

Proton and atomic nucleus (by Ernest Rutherford) positively charged(+) particle.

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Chemical formula represents the composition of one molecule or ionic compound in terms of chemical symbols. a. Molecular formula shows the actual number of atoms of elements in a molecule.

ex: C6H 12O6 ( sucrose), C6H6 (benzene ) ,C2H2 (acetylene) .

b.Empirical formula gives the simplest whole number ratio of atoms of elements in a molecule ex: C H2 O ( sucrose), C H (benzene ) , C H (acetylene)

c.Lewis formula shows the valence electrons of atoms of elements in a molecule. .. .. ..

ex: H: O : O: H (hydrogen peroxide) H: O :H (water) .. .. .. d. Structural formula shows the binding of atoms of elements in a molecule.

ex: H-O –O -H (hydrogen peroxide) H- O -H (water)

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Electronic Structure of Atoms

Aufbau PrincipleAtomic orbitalsElectronic configurationOctet RuleHund’s Rule

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Reduction Oxidation Reaction

Molecular Equation (Valence Change Method)NaNO2+ K2Cr2O7 + H2SO4 = NaNO3 +K2SO4 + Cr2 (SO4) 3+ H2O

Ionic Equation (Valence Change Method) NO2 + Cr2O7 + H + = NO3 -1 + Cr + H2O

Half Reaction or Ion-electron method NO2

-1 = NO3 -1

Cr2O7 -2 = Cr+3

+3

-2 -1

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Redox

Balance the eq. using Valence change or Ion electron method . Answer #1-10MnO4

-1 + ClO2

-1 +H2O = MnO2 + ClO4 -1 + OH-

___1. Oxidation no. of Mn in MnO4 -1

___2. Oxidation no. of Cl in ClO 4 -1

___3. electron lost/mole ___9. coefficient of ClO2-1

___4. electron gained/mole ___10. coefficient of MnO2

___5 Identify the OA___6. Which is the RA?___7. Which is the reduction product?___8. Which is the oxidation product?

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Concentration Units

Molarity – moles of solute per liter of solutionM= moles solute moles = g solute liter of solution molar mass g solute M = molar mass liter solution

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Normality – no of equivalents of solute per liter of solution

N = equivalents of solute liter of solution

g soluteN = eq wt liter of solution

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molality - moles of solute per kg solvent g solute m = molar mass kg solvent

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% by mass = mass solute X 100 mass of solution

Mole fraction solute (X2) = mole solute mole solution

Mole fraction solvent (X1) = mole solvent mole solution

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Concentration Units

1.Calculate the % by mass of the solute in: a. 5.50 g NaBr in 78.2 g solutionb. 31.0 g KCl in 152.0 g water 2.A solution is prepared by mixing 62.5 ml C6H6 (MW 78g/mol) with 80.3 ml toluene(MW 92.0g/mol) density C6H6 0.867 g/ml

density C7H8 0.87 g/ml.