Function and Graph - Extended

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    FUNCTION AND GRAPH

    Chapter 1.2 PROPERTIES OF FUNCTION

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    Function Lets assume we have a function :

    Y = x2 This function can be written as:

    f(x) = x2

    Horizontal line

    In graph willrepresent

    x axis and

    Vertical line will

    represent f(x)

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    Finding graph of a function

    f(x) = x

    2

    Now, if

    x = 0; thn f(0) = (0)2 =0

    x = 1; thn f(1) = (1)2 =1

    x = 2; thn f(2) = (2)2 =4 x = 3; thn f(3) = (3)2 =9

    .

    x = -1; thn f(-1) = (-1)2 =1

    x = -2; thn f(-2) = (-2)2 =4 x = -3; thn f(-3) = (-3)2 =9

    ..

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    Graph co-ordinates

    So, the coordinates of x2

    are, (x, f(x))

    =(0,0), (1,1), (2,4), (3, 9), (-1,1), (-2,4), (-3, 9) as

    far as u can go

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    DOMAIN

    u can find out graph of any function u are givenusing the method I just showed.

    Assume a value of x and find out the value of f(x)

    against tht value.

    f(x) = x2x = 3; thn f(3) = (3)2 =9

    Here for a function like x2u can choose any value of x.

    HOWEVER,,, some functions has limitation, u can not just put any

    value for x. For example :

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    How to find domain

    f(x) =

    Value of x MUST

    BE POSITIVE;

    f(x)=

    Value of x MUST NOT

    BE ZERO;

    1. Value inside square-root must be POSITIVE(cz square-root cant process negative numbers

    2. Denominator must not be ZERO

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    Example:

    Find the Domain of the following equations:y2 + x2= 25

    Solution:

    y2 + x2= 25y2 = 25 - x2

    y = +

    f(x)= | |

    so,25 - x2 > 0

    x2

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    ..continuation of previous slide

    value of x will be equal to 5 or less thn 5 andmore thn -5 can e written as

    -5

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    ..continuation of previous slide

    HINTS:

    FOR,

    FOR, -

    find f(5), f(4), f(3), f(2), f(1), f(0), f(-1), f(-2), f(-3), f(-4), f(-5) For and

    draw the graph AND

    find f(5), f(4), f(3), f(2), f(1), f(0), f(-1), f(-2), f(-3), f(-4), f(-5) For - anddraw the graph

    U can chk previous slide no 3 for more details

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    THE GRAPH OF THE MATH WILL LOOK

    LIKE THIS:

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    Summary

    Find f(x) from y2

    + x2

    = 25 Which is f(x)= | |

    Find domain of x which is -5

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    Properties of graph.

    x , x2

    , x3,

    , 1/x, sin x, cos x, tanx,

    All of them has different type of shapes whn u

    convert them into graph.

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    JUST REMEMBER THIS SHAPES OF GRAPHSACCORDING TO THEIR EQUATIONS.

    ONCE U SEE AN EQUATION, IF CAN REMEMER

    THE PROPERTIES , U CAN IMAGINE HOW THEGRAPH WILL LOOK LIKE..

    SO JUST FIND DOMAIN & RANGE, put them into

    the graph and draw the shape..u dnt hav to go toevery single coordinate to find the shape.

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    DOMAIN & RANGE

    IF f(x)=

    THN, domain : -5

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    HOMEWORK

    Find domain range and graph for :a.) y = 1/(x-5)

    b) y = (1/x) -5

    c) y2= x2-4

    d) y = 9 - x2

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    Tricky Example:

    f(x) = (x

    2

    - 4) / (x-2) f(x) = (x2- 4) / (x-2)

    = (x - 2) (x+2) / (x-2)

    = x + 2

    so, f(x) = x+2

    this is the tricky part.. u can put any value for x when f(x) = x+2;

    BUT..

    our main function is f(x) = (x2- 4) / (x-2)

    HERE, x MUST NOT BE 2. cz if x = 2 thn denominator is is 2-2 = 0.

    so... even though f(x) = x+2 , domain is any value of X except 2.

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    Example: DRAW THE GRAPH of f(x)

    this math, there are 3 conditions of f(x)according to the value x.

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    solution:

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    ..continuation of previous slide

    so...

    f(-3) = 0

    f (-2) = 0

    f(-1) = 0

    f(0) = 1f( 1) = 0

    f(2) =2

    f(3) =3

    f(4) = 4

    ....

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    TRY these at home

    find the graph off(x) = tanx (hints: tanx =sinx/cosx ; so cosx must NOT be 0)

    ((hints: x-1 > 0 so, x > 1...so find out f(1),

    f(2)..till f() f(5) or, f(6)