Friction

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Friction

description

Friction. Frictional Forces. Friction has its basis in surfaces that are not completely smooth:. Static Friction. Static Friction. Static friction keeps an object from starting to move when a force is applied. - PowerPoint PPT Presentation

Transcript of Friction

Page 1: Friction

Friction

Page 2: Friction

Frictional ForcesFrictional Forces Friction has its basis in surfaces that are not completely smooth:

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Static Friction

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•Static friction keeps an object from starting to move when a force is applied.

•Static frictional force has a maximum value, but may take on any value from zero to the maximum,

Static FrictionStatic Friction

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5/29

Static Frictional ForcesStatic Frictional Forces

(6-2)

where

(6-3)

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Kinetic Friction

Fpush > fk = kn

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Kinetic FrictionKinetic Friction

Kinetic friction: the friction experienced by surfaces sliding against one another

Kinetic frictional force depends on the normal force:

(6-1)

Constant is called the coefficient of kinetic friction.

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kinetic friction is independent of relative speed of the surfaces, and of their area of contact.

Kinetic Friction and SpeedKinetic Friction and Speed

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Coefficients of FrictionCoefficients of Friction

Typically, s>kfs max = sFn fk = kFnfs sFn

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Horizontal Retarding Friction

xk

a

g

A cruise-ship passenger uses a shuffleboard cue to push a shuffleboard disk of mass 0.40 kg horizontally along the deck, so that the disk leaves the cue at a speed of 8.5 m/s. The disk then slides a distance of 8.0 m.

What is the coefficient of kinetic friction between the disk and deck?

0 0y yneta F

nF mg

xnet k k nF f F

k xmg ma x ka g2 2

0 02 ( )x x xv v a x x 2

2

4.516 /

9.8 /0.46

k

m s

m s

m = 0.40 kg

v0x = 8.5 m/s

x = 8.0 m

x0 = 0

vx = 0

220

2

8.54.516

2 2 8.0x

x

mv s ma

sx m

0 0

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Friction ACT1

a. F1>F2 b. F1=F2 c. F1<F2

d. Need to know brick areas to answer

You push two identical bricks across a tabletop with constant speed v. Which Case, as shown above, requires more force Fn?

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Suppose a 20 kg object is sliding down a 50o inclined plane. If µk = 0.4 between the plane surface and the object, what is the object’s acceleration down the plane? How long will it take the object to slide 5.0 m if it starts from rest?.

y-axis: cos cosn w mg

||x-axis: F = F

sin

sin cos

net k

net k

net k

f

F w n

F mg mg

sin coskma mg mg

k||F

F

Inclined Plane Friction

2 2

(sin cos )

9.8 (sin 50 0.4cos50 ) 4.99

k

o o

a g

m mas s

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Friction with Component of Tension

0ynet n yF F T mg

Two children sitting on a sled at rest in thesnow ask you to pull them. You oblige by pullingon the sled’s rope, which makes an angle of 40°with the horizontal. The children have acombined mass of 45 kg, and the sled has amass of 5.0 kg. The coefficient of kinetic friction is k=0.15. Find the acceleration of the sled and children if the rope tension is 140 N.

cosnet x k xF ma T f ma

2

cos 140 cos 40 602.63

50

ok

x

T f N N masm kg

cosxT T sinyT T

sinnF T mg

sin (50 )(9.8 / ) 140 sin(40 ) 400onF mg T kg N kg N N

0.15 400 60k k nf F N N

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Antilock Brakes

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Antilock Brakes

22 2 0

0 2 and 0, so 2

vv v a x v x

a

A car is traveling at 30 m/s along a horizontal road. The coefficients of friction are s=0.50 and k=0.40.(a) What is the braking distance xa with antilock brakes?(b) What is the braking distance xb if the brakes lock?

and a s b ka g a g

2 20

2

(30 m/s)91.7 m

2 2(0.5)(9.81 m/s )as

vx

g

2 20

2

(30 m/s)114.7 m

2 2(0.4)(9.81 m/s )bk

vx

g