Francis turbine part load resonance risk analytical assessment

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Francis turbine part load resonance risk analytical assessment C. Nicolet, C. Landry, S. Alligné, A. Béguin SHF/AFM 2019, Sion, Switzerland, November 06-07,2019 Power Vision Engineering sàrl 1, ch. des Champs-Courbes CH-1024 Ecublens Switzerland http://www.powervision-eng.ch

Transcript of Francis turbine part load resonance risk analytical assessment

Page 1: Francis turbine part load resonance risk analytical assessment

Francis turbine part load resonance risk analytical assessment

C. Nicolet, C. Landry, S. Alligné, A. Béguin

SHF/AFM 2019, Sion, Switzerland, November 06-07,2019

Power Vision Engineering sàrl1, ch. des Champs-CourbesCH-1024 EcublensSwitzerlandhttp://www.powervision-eng.ch

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Context and Key goals

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• Massive penetration of alternative renewable energies (Solar, wind power)

• Stochastic nature of the renewable energy production

Mean annual growth rates of electricity production 2002-2012

• To maintain balanced production:✓ Sufficient reserve capacity

✓ Primary and secondary control capabilities

→ Hydropower plants

→ Off-design operation

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Context and Key goals

• Frequent power transients:✓ Require a wide operating range

✓ May induce high levels of vibration and large pressure fluctuations

Part load condition

[0.2 – 0.4] • Turbine rotational speed

* Favrel et al., 2013

HYPERBOLE (ERC/FP7-ENERGY-2013-1-Grant 608532)

Full load condition

* Müller et al. ,2013

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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SIMSEN software

Modelingfrom

water to wire 8

• SIMSEN software✓ Hydraulic circuit

✓ Electrical installations

✓ Rotating inertias

✓ Control system

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Electrical Analogy• Mass and momentum equations:

• Electrical analogy:✓ (Bergeron, 1950; Paynter, 1953 )

R/2Lh/2Lh/2

C

Rh

R/2

Hi

Hci

Qi QiHi+1

2

0H a Q

t gA x

+ =

02

12

=+

+

Q

gDA

Q

t

Q

gAx

H

0

01

=+

+

=

+

IRt

IL

x

U

x

I

Ct

U

ee

e

Storage

Losses

Inertia

Datum.

Q1Q2

D, a, dx

H1 H2

• Assumptions:✓ Uniform flow

✓ 1-D approach

✓ Convective terms neglected

✓ Vertical displacements neglected

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Eigenvalue computation

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• Set of differential equations

( ) ( )XdX

A B X X Cdt

+ =

• Small perturbation

0X X X= +

( )( )

0

0

d X Xf X X

dt

+= +

1det 0

l lI s A B

+ =

• Eigenfrequency

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Natural frequencies

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• Hydraulic system modelled by an equivalent pipe

1

n

tot ii

l l=

=

1

totequ n

i

ii

la

la

=

=

2

equ equk

totk

a af k

l= =

Total length Equivalent wave speed Natural frequency (Order k)

Standing wave

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First natural frequency of the cavitating draft tube

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• Simplified hydroacoustic model of the frictionless cavitating draft tube

2DT DT

DTDT

l g AC

a

= DT

DT DT

lL

g A=

1 1 12 2

DTo

DTDT DT

af

lL C = =

lDT = DT length [m]ADT = DT cross section area [m2]aDT = DT wave speed [m/s]

* Jacob, 1993

Draft tube

Cavitation compliance Draft tube inductance First natural frequency

Sim

ilar

to

a s

pri

ng–

mas

s sy

stem

𝑘 ≈1

𝐶𝐷𝑇𝑚 ≈ 𝐿𝐷𝑇 𝑓0 =

1

𝑘

𝑚≈

1

1

𝐶𝐷𝑇𝐿𝐷𝑇

𝑘

𝑚

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1 1 12 2

DTo

TR DT DTDT TR

TR

af

L C Al l

A

= =

First natural frequency of the cavitating draft tube

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• Simplified hydroacoustic model of the frictionless cavitating draft tube

lTR = TR pipe length [m]ATR = TR pipe cross section area [m2]

TRTR

TR

lL

g A=

* Dörfler, 2013

Draft tube

2DT DT

DTDT

l g AC

a

=

Cavitation compliance Tailrace pipe inductance First natural frequency

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DTo

DTDT TR

TR

af

Al l

A

=

Analytical equations

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• Summary

1st order1

2DT

oDT

af

l=

2equ equ

ktotk

a af k

l= =

2equ equ

ktotk

a af k

l= =

2equ equ

ktotk

a af k

l= =

1 2equ equ

totk

a af

l= =

2nd-6th order

Equivalent pipe

Draft tube without TR

Draft tube with TR

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Example of applications

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• Hydraulic system 1

PenstockL = 300 mD = 1.2 ma = 1’250 m/sλ = 0.012 -

Draft tubeL = 10 mD = 1.2 ma = [50-100] m/sλ = 0.012 -

TurbinePn = 5 MWQn = 5.0 m3/sHn = 100 mWCNn = 750 rpmDref = 0.846 mNq = 53 -

Nn = 750 rpm = 12.5 Hz➔fexcitation = [0.2 – 0.4]·fn

➔fexcitation = [2.5 – 5 Hz]

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Example of applications

• Hydraulic system 1

1st Pressure mode 1st Discharge modeElastic mode shape

Elastic mode shape✓ Non-Linear amplitude variation of

pressure in the TR as function of the length

✓ Non-constant amplitude variation of discharge in the TR as function of the length

11

12

equ equ

tot

a af

l= =

1

2DT

oDT

af

l=

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Analytical

calculation

Eigen value

calculation

a DT (min) a DT (min) Relative error

[m/s] [m/s] [%]

f0 [Hz] 0.8 1.24 -35.48

f1 [Hz] 1.14 1.24 -8.06

f2 [Hz] 2.27 2.09 8.61

f3 [Hz] 3.41 3.67 -7.08

f4 [Hz] 4.55 4.18 8.85

f5 [Hz] 5.68 5.99 -5.18

f6 [Hz] 6.82 6.15 10.89

System 1

Example of applications

• Hydraulic system 1

fexcitation = [2.5 – 5 Hz]

• 1st order: Better agreement with f1

• 2nd-6th order: Rather good agreement for natural frequencies Maximum error of 14%.

• Risk of resonance with the draft tube in red.

a =

50

m/s

11

12

equ equ

tot

a af

l= =

1

2DT

oDT

af

l=

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Example of applications

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• Hydraulic system 2

PenstockL = 300 mD = 1.2 ma = 1’250 m/sλ = 0.012 -

Tailrace pipeL = 100 mD = 1.2 ma = 1’250 m/sλ = 0.012 -

TurbinePn = 5 MWQn = 5.0 m3/sHn = 100 mWCNn = 750 rpmDref = 0.846 mNq = 53 -

Draft tubeL = 10 mD = 1.2 ma = [50-100] m/sλ = 0.012 -

Nn = 750 rpm = 12.5 Hz➔fexcitation = [0.2 – 0.4]·fn

➔fexcitation = [2.5 – 5 Hz]

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Example of applications

• Hydraulic system 2

1st Pressure mode 1st Discharge modeRigid column mode shape

Rigid column mode shape✓ Linear amplitude variation of

pressure in the TR

✓ Constant amplitude variation of discharge in the TR

→ Similar to surge tank mass oscillation between TR pipe and DT compliance

11

12

equ equ

tot

a af

l= =

12

DTo

DTDT TR

TR

af

Al l

A

=

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Analytical

calculation

Eigen value

calculation

a DT (max) a DT (max) Relative error

[m/s] [m/s] [%]

f0 [Hz] 0.5 0.55 -9.09

f1 [Hz] 1.19 0.55 116.36

f2 [Hz] 2.38 2.1 13.33

f3 [Hz] 3.57 4.05 -11.85

f4 [Hz] 4.76 4.88 -2.46

f5 [Hz] 5.95 6.18 -3.72

f6 [Hz] 7.14 6.36 12.26

System 2

Analytical

calculation

Eigen value

calculation

a DT (min) a DT (min) Relative error

[m/s] [m/s] [%]

f0 [Hz] 0.25 0.27 -7.41

f1 [Hz] 0.96 0.27 255.56

f2 [Hz] 1.92 2.04 -5.88

f3 [Hz] 2.88 2.53 13.83

f4 [Hz] 3.85 4.12 -6.55

f5 [Hz] 4.81 4.87 -1.23

f6 [Hz] 5.77 5.16 11.82

System 2

Example of applications

• Hydraulic system 2

fexcitation = [2.5 – 5 Hz]

• 1st order: Good agreement with f0

• 2nd-6th order: Rather good agreement for natural frequencies Maximum error of 14%.

• Risk of resonance with the draft tube in red.

a =

50

m/s

a =

10

0 m

/s

11

12

equ equ

tot

a af

l= =

12

DTo

DTDT TR

TR

af

Al l

A

=

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Example of applications

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• Hydraulic system 3

PenstockL = 300 mD = 1.2 ma = 1’250 m/sλ = 0.012 -

Tailrace pipeL = 100 mD = 2 ma = 1’250 m/sλ = 0.012 -

TurbinePn = 5 MWQn = 5.0 m3/sHn = 100 mWCNn = 750 rpmDref = 0.846 mNq = 53 -

Draft tubeL = 10 mD = 1.2 ma = [50-100] m/sλ = 0.012 -

fexcitation = [2.5 – 5 Hz]

Nn = 750 rpm = 12.5 Hz➔fexcitation = [0.2 – 0.4]·fn

➔fexcitation = [2.5 – 5 Hz]

Page 25: Francis turbine part load resonance risk analytical assessment

Example of applications

• Hydraulic system 3

1st Pressure mode 1st Discharge modeRigid column mode shape

Rigid column mode shape✓ Linear amplitude variation of

pressure in the TR

✓ Constant amplitude variation of discharge in the TR

→ Similar to surge tank mass oscillation between TR pipe and DT compliance

11

12

equ equ

tot

a af

l= =

12

DTo

DTDT TR

TR

af

Al l

A

=

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Analytical

calculation

Eigen value

calculation

a DT (max) a DT (max) Relative error

[m/s] [m/s] [%]

f0 [Hz] 0.84 0.81 3.70

f1 [Hz] 1.19 0.81 46.91

f2 [Hz] 2.38 2.1 13.33

f3 [Hz] 3.57 4.03 -11.41

f4 [Hz] 4.76 4.72 0.85

f5 [Hz] 5.95 6.14 -3.09

f6 [Hz] 7.14 6.55 9.01

System 3

Analytical

calculation

Eigen value

calculation

a DT (min) a DT (min) Relative error

[m/s] [m/s] [%]

f0 [Hz] 0.42 0.42 0.00

f1 [Hz] 0.96 0.42 128.57

f2 [Hz] 1.92 2.04 -5.88

f3 [Hz] 2.88 2.55 12.94

f4 [Hz] 3.85 4.12 -6.55

f5 [Hz] 4.81 4.84 -0.62

f6 [Hz] 5.77 6.16 -6.33

System 3

Example of applications

• Hydraulic system 3

fexcitation = [2.5 – 5 Hz]

• 1st order: Good agreement with f0

• 2nd-6th order: Rather good agreement for natural frequencies Maximum error of 14%.

• Risk of resonance with the draft tube in red.

a =

50

m/s

a =

10

0 m

/s

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Contents• Context and key goals

• Eigenvalue computation

✓Numerical equations

✓Analytical equations

• Examples of application

✓Hydraulic system 1

✓Hydraulic system 2

✓Hydraulic system 3

• Conclusions / Take away message

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Conclusions• Analytical approach to determine the possible risk of resonance with the draft tube vortex rope

excitation (2.5-5Hz)

• 1st order: Better agreement with f1 for the hydraulic system without a tailrace pipe (hydraulic system 1) → Elastic mode shape

• 1st order: Good agreement with f0 for the hydraulic system with a tailrace pipe (hydraulic system 2 & 3) → rigid column mode shape

• 2nd-6th order: Rather good agreement for natural frequencies (Maximum error of 14%).

• Limitations of the methodology✓ Parallel branches:

• Modelling by a single branch with equivalent parameters to obtain a first order of magnitude.• Real system will feature much more complex and numerous eigenvalues (hydraulic system asymmetry, diameters,

bifurcations)

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Take away Message• This analytical method is included as ANNEXE E.2 of the new IEC

Technical Specification 62882 ED1 (to be issued in 2020)

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DTo

DTDT TR

TR

af

Al l

A

=

2equ equ

ktotk

a af k

l= =

Without a tailrace pipe

With a tailrace pipe

2equ equ

ktotk

a af k

l= =

2equ equ

ktotk

a af k

l= =

1st order

1st order

2nd–6th order

2nd–6th order

Hydraulic machines – IEC Technical specification for Francis turbine pressure fluctuation

Page 30: Francis turbine part load resonance risk analytical assessment

Thank you for your attention!

Power Vision Engineering Sàrl1, ch. Des Champs-CourbesCH-1024 [email protected]

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Example of applications