Fourth Six Weeks’ Test Review. For the purposes of this presentation...

74
Fourth Six Weeks’ Test Review

Transcript of Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Page 1: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Fourth Six Weeks’ Test Review

Page 2: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

For the purposes of this presentation...

Page 3: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Assume that triangles which appear to be right triangles are.

Page 4: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Assume that lines that appear to be perpendicular are.

Page 5: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

4

25x =10

Page 6: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The The Pythagorean Pythagorean TheoremTheorem

Page 7: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

6

8

x =10

Page 8: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

12

18

x 21.63

Page 9: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

20

16

x=12

Page 10: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

1515

24

x

Page 11: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

1515

24

X= 9

1212

Page 12: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Special Right Special Right TrianglesTriangles

Page 13: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

45o

x

12 2

=12

Page 14: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

x

10

1010 2

Page 15: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

30o

20x

y

10

10 3

Page 16: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

10 10

10

x5 3

Page 17: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the Geometric mean between 4 and 25.

=10

Page 18: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

NM=9, MK=4, Find JM.

=6

Page 19: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What equation can be formed?

g

t

m

2 2 2g t m

Page 20: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What kind of triangle has sides 41, 40 and 9?

Right

Page 21: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What kind of triangle has sides of 8, 12 and 18? Obtuse

Page 22: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the leg of the right triangle:

15

17

x =8

Page 23: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find x

8

8

x 8 2

Page 24: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

An equilateral triangle has a side of 12. What is its altitude?

6 3

Page 25: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Which ratio is: The opposite leg over the hypotenuse?

Page 26: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The Sine Ratio

Page 27: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Which ratio is: The adjacent leg over the hypotenuse?

Page 28: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The Cosine Ratio

Page 29: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What makes up the tangent ratio?

Page 30: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The opposite leg over the adjacent leg

Page 31: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Set Up the Trig Set Up the Trig ratio to find xratio to find x

Page 32: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

20

28o

x

cos 2820

x

17.66

Page 33: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

9x

50o

9sin 50

x

11.75

Page 34: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

x21

32

Page 35: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

x21

32

Tan x = 21/32

Page 36: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

x21

32

1 21tan

32x

33.27

Page 37: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What’s true about an interior and exterior angle of a polygon?

Supplementary

Page 38: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

For polygons to “fit” around a vertex, the sum of their interior angles must be 360

Page 39: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

A regular n-gon has lines of symmetry and rotational of360/n degrees

n

Page 40: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the sum of the interior angles of a decagon:

1440

Page 41: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the measure of 1 interior angle of a regular 18-gon

160

Page 42: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the sum of the exterior angles of a 55-gon

360

Page 43: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find the measure of one exterior angle of a regular 24-gon

15

Page 44: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The sum of the interior angles of what polygon is 4500? 27-gon

Page 45: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The measure of 1 interior angle of what regular polygon is 170?

36-gon

Page 46: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The measure of 1 exterior angle of what regular polygon is 8?

45-gon

Page 47: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

A regular octagon has 8 lines of symmetry and what degree of rotation? 45

Page 48: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The sum of its interior angles is 4 times the sum of its exterior angles. decagon

Page 49: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

?

What regular polygon is missing

Another hexagon

Page 50: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What regular polygon is missing

?

Another Octagon

Page 51: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What’s the symmetry of a regular decagon?

10 lines, 36 degr. rotational

Page 52: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Find x (Given a regular octagon)

x

X = 90 degrees

Page 53: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

What 3 regular polygons will tessellate the plane?

Page 54: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Equilateral triangles

Page 55: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Regular Hexagons

Page 56: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Squares

Page 57: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Which special quadrilateral has the symmetry described...

Page 58: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

- No lines

- 180o rotational

Page 59: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Answer: Parallelogram

Page 60: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Complete the Complete the Theorem….Theorem….

Page 61: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The diagonals of a parallelogram_________.

Page 62: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

…bisect each other.

Page 63: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Opposite sides of a parallelogram are__________.

Page 64: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

…congruent.(They are also parallel, but that is in the definition, not a theorem.)

Page 65: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

If the opposite angles of a quadrilateral are congruent, then__________

Page 66: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

…then the quadrilateral is a parallelogram.

Page 67: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Consecutive angles of a parallelogram are ____________.

Page 68: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Supplementary.

Page 69: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Always, Always, Sometimes, or Sometimes, or Never...Never...

Page 70: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The diagonals of a parallelogram ____ bisect each other.

Page 71: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Always

Page 72: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

A quadrilateral is _____ a parallelogram,

Page 73: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

Sometimes

Page 74: Fourth Six Weeks’ Test Review. For the purposes of this presentation...

The End