For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2....

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Transcript of For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2....

Page 1: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.
Page 2: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form.

1. 2.

Simplify each expression.

3. 4.

Page 3: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

A set of three nonzero whole numbers a, b, and c such that a2 + b2 = c2 is called a Pythagorean triple.

Page 4: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the missing side length. Tell if the side lengths form a Pythagorean triple. Explain.

a2 + b2 = c2

142 + 482 = c2 Substitute 14 for a and 48 for b.

Pythagorean Theorem

2500 = c2 Multiply and add.

50 = c Find the positive square root.

The side lengths are nonzero whole numbers that satisfy the equation a2 + b2 = c2, so they form a Pythagorean triple.

Page 5: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

The converse of the Pythagorean Theorem gives you a way to tell if a triangle is a right triangle when you know the side lengths.

Page 6: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

You can also use side lengths to classify a triangle as acute or obtuse.

A

B

C

c

b

a

Page 7: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

To understand why the Pythagorean inequalities are true, consider ∆ABC.

Page 8: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

By the Triangle Inequality Theorem, the sum of any two side lengths of a triangle is greaterthan the third side length.

Remember!

Page 9: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Tell if the measures can be the side lengths of a triangle. If so, classify the triangle as acute, obtuse, or right.

5, 7, 10

Step 1 Determine if the measures form a triangle.

By the Triangle Inequality Theorem, 5, 7, and 10 can be the side lengths of a triangle.

Page 10: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Step 2 Classify the triangle.

c2 = a2 + b2? Compare c2 to a2 + b2.

102 = 52 + 72

? Substitute the longest side for c.

100 = 25 + 49

?Multiply.

100 > 74 Add and compare.

Since c2 > a2 + b2, the triangle is obtuse.

Page 11: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Tell if the measures can be the side lengths of a triangle. If so, classify the triangle as acute, obtuse, or right.

5, 8, 17

Step 1 Determine if the measures form a triangle.

Since 5 + 8 = 13 and 13 > 17, these cannot be the side lengths of a triangle.

Page 12: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Tell if the measures can be the side lengths of a triangle. If so, classify the triangle as acute, obtuse, or right.

7, 12, 16

Step 1 Determine if the measures form a triangle.

By the Triangle Inequality Theorem, 7, 12, and 16 can be the side lengths of a triangle.

Page 13: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Step 2 Classify the triangle.

c2 = a2 + b2?

Compare c2 to a2 + b2.

162 = 122 + 72

?Substitute the longest side for c.

256 = 144 + 49?

Multiply.

256 > 193 Add and compare.

Since c2 > a2 + b2, the triangle is obtuse.

Page 14: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Justify and apply properties of 45°-45°-90° triangles.

Justify and apply properties of 30°- 60°- 90° triangles.

Page 15: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

A diagonal of a square divides it into two congruent isosceles right triangles. Since the base angles of an isosceles triangle are congruent, the measure of each acute angle is 45°. So another name for an isosceles right triangle is a 45°-45°-90° triangle.

A 45°-45°-90° triangle is one type of special right triangle. You can use the Pythagorean Theorem to find a relationship among the side lengths of a 45°-45°-90° triangle.

Page 16: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.
Page 17: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the value of x. Give your answer in simplest radical form.

By the Triangle Sum Theorem, the measure of the third angle in the triangle is 45°. So it is a 45°-45°-90° triangle with a leg length of 8.

Page 18: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Rationalize the denominator.

Page 19: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the value of x. Give your answer in simplest radical form.

By the Triangle Sum Theorem, the measure of the third angle in the triangle is 45°. So it is a 45°-45°-90° triangle with a leg length of

x = 20 Simplify.

Page 20: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the value of x. Give your answer in simplest radical form.

The triangle is an isosceles right triangle, which is a 45°-45°-90° triangle. The length of the hypotenuse is 16.

Rationalize the denominator.

Page 21: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Jana is cutting a square of material for a tablecloth. The table’s diagonal is 36 inches. She wants the diagonal of the tablecloth to be an extra 10 inches so it will hang over the edges of the table. What size square should Jana cut to make the tablecloth? Round to the nearest inch.

Jana needs a 45°-45°-90° triangle with a hypotenuse of 36 + 10 = 46 inches.

Page 22: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

A 30°-60°-90° triangle is another special right triangle. You can use an equilateral triangle to find a relationship between its side lengths.

Page 23: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the values of x and y. Give your answers in simplest radical form.

22 = 2x Hypotenuse = 2(shorter leg)

11 = x Divide both sides by 2.

Substitute 11 for x.

Page 24: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the values of x and y. Give your answers in simplest radical form.

Rationalize the denominator.

Hypotenuse = 2(shorter leg).

y = 2x

Simplify.

Page 25: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the values of x and y. Give your answers in simplest radical form.

Hypotenuse = 2(shorter leg)

Divide both sides by 2.

y = 27 Substitute for x.

Page 26: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the values of x and y. Give your answers in simplest radical form.

y = 2(5)

Simplify.y = 10

Page 27: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Find the values of x and y. Give your answers in simplest radical form.

Hypotenuse = 2(shorter leg)24 = 2x

Divide both sides by 2.12 = x

Substitute 12 for x.

Page 28: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

An ornamental pin is in the shape of an equilateral triangle. The length of each side is 6 centimeters. Josh will attach the fastener to the back along AB. Will the fastener fit if it is 4 centimeters long?Step 1 The equilateral triangle is divided into

two 30°-60°-90° triangles.

The height of the triangle is the length of the longer leg.

Page 29: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Step 2 Find the length x of the shorter leg.

Hypotenuse = 2(shorter leg)6 = 2x3 = x Divide both sides by 2.

Step 3 Find the length h of the longer leg.

The pin is approximately 5.2 centimeters high. So the fastener will fit.

Page 30: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

What if…? A manufacturer wants to make a larger clock with a height of 30 centimeters. What is the length of each side of the frame? Round to the nearest tenth.Step 1 The equilateral triangle is divided into two 30º-60º-90º triangles.

The height of the triangle is the length of the longer leg.

Page 31: For Exercises 1 and 2, find the value of x. Give your answer in simplest radical form. 1. 2. Simplify each expression. 3.4.

Step 2 Find the length x of the shorter leg.

Rationalize the denominator.

Step 3 Find the length y of the longer leg.

Hypotenuse = 2(shorter leg)

y = 2x

Simplify.Each side is approximately 34.6 cm.