Five-Minute Check (over Lesson...

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Transcript of Five-Minute Check (over Lesson...

Page 1: Five-Minute Check (over Lesson 2–7)mathlandinc.com/uploads/2/4/4/3/24431781/2.8_notes_hg_pdf.pdf · Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate.
Page 2: Five-Minute Check (over Lesson 2–7)mathlandinc.com/uploads/2/4/4/3/24431781/2.8_notes_hg_pdf.pdf · Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate.

Five-Minute Check (over Lesson 2–7) CCSS Then/Now Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate Example 1: Use the Angle Addition Postulate Theorems 2.3 and 2.4 Example 2: Real-World Example: Use Supplement or Complement Theorem 2.5: Properties of Angle Congruence Proof: Symmetric Property of Congruence Theorems 2.6 and 2.7 Proof: One Case of the Congruent Supplements Theorem Example 3: Proofs Using Congruent Comp. or Suppl. Theorems Theorem 2.8: Vertical Angles Theorem Example 4: Use Vertical Angles Theorems 2.9–2.13: Right Angle Theorems

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Over Lesson 2–7

A. Transitive Property

B. Symmetric Property

C. Reflexive Property

D. Segment Addition Postulate

Justify the statement with a property of equality or a property of congruence.

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Over Lesson 2–7

Justify the statement with a property of equality or a property of congruence.

A. Transitive Property

B. Symmetric Property

C. Reflexive Property

D. Segment Addition Postulate

Page 5: Five-Minute Check (over Lesson 2–7)mathlandinc.com/uploads/2/4/4/3/24431781/2.8_notes_hg_pdf.pdf · Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate.

Over Lesson 2–7

Justify the statement with a property of equality or a property of congruence. If H is between G and I, then GH + HI = GI.

A. Transitive Property

B. Symmetric Property

C. Reflexive Property

D. Segment Addition Postulate

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Over Lesson 2–7

A. WX > WZ

B. XW + WZ = XZ

C. XW + XZ = WZ

D. WZ – XZ = XW

State a conclusion that can be drawn from the statement given using the property indicated. W is between X and Z; Segment Addition Postulate.

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Over Lesson 2–7

A. B. C. D.

State a conclusion that can be drawn from the statements given using the property indicated. LM ≅ NO ___ ___

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Over Lesson 2–7

A. AB + BC = AC

B. AB + AC = BC

C. AB = 2AC

D. BC = 2AB

Given B is the midpoint of AC, which of the following is true?

___

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Page 10: Five-Minute Check (over Lesson 2–7)mathlandinc.com/uploads/2/4/4/3/24431781/2.8_notes_hg_pdf.pdf · Postulate 2.10: Protractor Postulate Postulate 2.11: Angle Addition Postulate.
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Use the Angle Addition Postulate

CONSTRUCTION Using a protractor, a construction worker measures that the angle a beam makes with a ceiling is 42°. What is the measure of the angle the beam makes with the wall? The ceiling and the wall make a 90° angle. Let ∠1 be the angle between the beam and the ceiling. Let ∠2 be the angle between the beam and the wall. m∠1 + m∠2 = 90 Angle Addition Postulate 42 + m∠2 = 90 m∠1 = 42 42 – 42 + m∠2 = 90 – 42 Subtraction Property of Equality m∠2 = 48 Substitution

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Use the Angle Addition Postulate

Answer: The beam makes a 48° angle with the wall.

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A. 32

B. 94

C. 104

D. 116

Find m∠1 if m∠2 = 58 and m∠JKL = 162.

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Use Supplement or Complement

TIME At 4 o’clock, the angle between the hour and minute hands of a clock is 120º. When the second hand bisects the angle between the hour and minute hands, what are the measures of the angles between the minute and second hands and between the second and hour hands?

Understand Make a sketch of the situation. The time is 4 o’clock and the second hand bisects the angle between the hour and minute hands.

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60 + 60 = 120

Use Supplement or Complement

Plan Use the Angle Addition Postulate and the definition of angle bisector.

Solve Since the angles are congruent by the definition of angle bisector, each angle is 60°.

Answer: Both angles are 60°.

Check Use the Angle Addition Postulate to check your answer. m∠1 + m∠2 = 120

120 = 120

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A. 20

B. 30

C. 40

D. 50

QUILTING The diagram shows one square for a particular quilt pattern. If m∠BAC = m∠DAE = 20, and ∠BAE is a right angle, find m∠CAD.

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Proofs Using Congruent Comp. or Suppl. Theorems

Given:

Prove:

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Proofs Using Congruent Comp. or Suppl. Theorems

1. Given 1. m∠3 + m∠1 = 180; ∠1 and ∠4 form a linear pair.

4. ∠s suppl. to same ∠ are ≅.

4. ∠3 ≅ ∠4

Proof: Statements Reasons

2. Linear pairs are supplementary.

2. ∠1 and ∠4 are supplementary.

3. Definition of supplementary angles

3. ∠3 and ∠1 are supplementary.

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In the figure, ∠NYR and ∠RYA form a linear pair, ∠AXY and ∠AXZ form a linear pair, and ∠RYA and ∠AXZ are congruent. Prove that ∠NYR and ∠AXY are congruent.

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Which choice correctly completes the proof? Proof: Statements Reasons

1. Given 1. ∠NYR and ∠RYA, ∠AXY and ∠AXZ form linear pairs.

2. If two ∠s form a linear pair, then they are suppl. ∠s.

2. ∠NYR and ∠RYA are supplementary. ∠AXY and ∠AXZ are supplementary.

3. Given 3. ∠RYA ≅ ∠AXZ 4. ∠NYR ≅ ∠AXY 4. ____________ ?

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A. Substitution

B. Definition of linear pair

C. ∠s supp. to the same ∠ or to ≅ ∠s are ≅.

D. Definition of supplementary ∠s

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Use Vertical Angles

If ∠1 and ∠2 are vertical angles and m∠1 = d – 32 and m∠2 = 175 – 2d, find m∠1 and m∠2. Justify each step.

1. Given 1. ∠1 and ∠2 are vertical ∠s. 2. Vertical Angles

Theorem 3. Definition of

congruent angles 4. Substitution

2. ∠1 ≅ ∠2

3. m∠1 = m∠2

4. d – 32 = 175 – 2d

Statements Reasons Proof:

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Use Vertical Angles

5. Addition Property 5. 3d – 32 = 175

6. Addition Property

7. Division Property

6. 3d = 207

7. d = 69

Statements Reasons

Answer: m∠1 = 37 and m∠2 = 37

m∠1 = d – 32 m∠2 = 175 – 2d

= 69 – 32 or 37 = 175 – 2(69) or 37

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A.

B.

C.

D.

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