Find the area of a rectangle with l = 36 cm and w = 9 cm.Find the area of a rectangle with l = 36 cm and w = 9 cm.

324 cm2324 cm2

A = lwA = lw

Find the area of a triangle with b = 23 cm and h = 14 cm.Find the area of a triangle with b = 23 cm and h = 14 cm.

161 cm2161 cm2

A = ½bhA = ½bh

Find the area of a circle with r = 12 cm.Find the area of a circle with r = 12 cm.

452.2 cm2452.2 cm2

A = pr2 A = pr2

Find the missing measure.Find the missing measure.

A = 2pr2 + s2A = 2pr2 + s2 10101010

A = ?A = ?

= 2p(52) + 102= 2p(52) + 102

= 50p + 100= 50p + 100

≈ 257 units2≈ 257 units2

99

= 84 − 24= 84 − 24= 60 units2= 60 units2

33

88

33

1111

A = (b1 + b2)h − bhA = (b1 + b2)h − bh1212

= (11 + 17)(6) − 3(8)= (11 + 17)(6) − 3(8)1212

Find the missing measure.Find the missing measure.A = ?A = ?

= 32 cm2= 32 cm2

Find the area of the colored region.Find the area of the colored region.

2 cm2 cm

4 cm4 cm 8 cm8 cm

3 cm3 cm

A = bh + bhA = bh + bh

A = 24 + 8A = 24 + 8

= 24 cm2= 24 cm2

A = s2 − s2A = s2 − s2

A = 72 − 52A = 72 − 52

7 cm7 cm

5 cm5 cm 7 cm7 cm

5 cm5 cm

Find the area of the colored region.Find the area of the colored region.

= 66 cm2= 66 cm2

A = bh − bhA = bh − bh1212

= 11(8) − (11)(4)= 11(8) − (11)(4)1212

= 88 − 22= 88 − 2211 cm11 cm

8 cm8 cm 4 cm4 cm

Find the area of the colored region.Find the area of the colored region.

= 51 m2= 51 m2

= (10 + 13)(6) −(9)2= (10 + 13)(6) −(9)21212

= 69 − 18= 69 − 18

A = (b1 + b2)h − bh A = (b1 + b2)h − bh 1212

10 m10 m

6 m6 m

13 m13 m

9 m9 m2 m2 m

Find the area of the colored region.Find the area of the colored region.

≈ 13.8 m2≈ 13.8 m2

A = s2 − pr2A = s2 − pr2

= 82 − p(42)= 82 − p(42)4 m4 m

= 64 − 16p= 64 − 16p

Find the area of the colored region.Find the area of the colored region.

p2 = 51 unitsp2 = 51 units

Using the similar triangles, find the perimeter of ∆XYZ.Using the similar triangles, find the perimeter of ∆XYZ.

2p2 = 34(3)2p2 = 34(3)

2p2 = 1022p2 = 102p = 34p = 34

AA

BBCC

XX

YYZZ

p = ?p = ?34p2

34p2

== 2323

3

2

A1= 16 units2A1= 16 units2

9A1 = 36(4)9A1 = 36(4)9A1 = 1449A1 = 144

( )( )A1

36A1

36== 2

323

2

== 4949

A1

36A1

36

AA

BBCC

XX

YYZZ

A = ?A = ?

A = 36A = 363

2

Using the similar triangles, find the area of ∆ABC.Using the similar triangles, find the area of ∆ABC.

At Fermilab in Batavia, Illinois, nuclear particles are accelerated around a circle that is 2 km in diameter. Determine the number of acres within this circular ring if 1 km2 = 247 acres. Round to the nearest acre.

At Fermilab in Batavia, Illinois, nuclear particles are accelerated around a circle that is 2 km in diameter. Determine the number of acres within this circular ring if 1 km2 = 247 acres. Round to the nearest acre.

776 acres776 acres

If the sides of polygon A are twice the length of the sides in a similar polygon B, what is the ratio of their perimeters? their areas?

If the sides of polygon A are twice the length of the sides in a similar polygon B, what is the ratio of their perimeters? their areas?

perimeter 2:1; area 4:1perimeter 2:1; area 4:1

S = pH + 2BS = pH + 2B

= 80 cm3= 80 cm3

Find the surface area and volume.Find the surface area and volume.

= [2(8 + 5)](2) + 2[8(5)]= [2(8 + 5)](2) + 2[8(5)]

= 52 + 80= 52 + 80

8 cm8 cm 5 cm5 cm

= 26(2) + 2(40)= 26(2) + 2(40)= 132 cm2= 132 cm2

V = BHV = BH= [8(5)](2)= [8(5)](2)

2 cm2 cm

S = 2prH + 2pr2S = 2prH + 2pr2

≈ 351.7 m3≈ 351.7 m3

= 2p(4)(7) + 2p(42)= 2p(4)(7) + 2p(42)

= 88p= 88p ≈ 276.3 m2≈ 276.3 m2

V = pr2HV = pr2H= p(42)(7) == p(42)(7) =

4 m4 m

7 m7 m

= 56p + 32p= 56p + 32p

= 112p= 112p

Find the surface area and volume.Find the surface area and volume.

The altitude of 8 and half the base of the triangular end form a right triangle with hypotenuse c.

The altitude of 8 and half the base of the triangular end form a right triangle with hypotenuse c.

10 mm10 mm6 mm6 mm

8 mm8 mm

Find the surface area and volume.Find the surface area and volume.

c2 = 82 + b2, where b = s = 3

c2 = 82 + 32c2 = 82 + 32

1212

= 73= 73c = 73c = 73

10 mm10 mm6 mm6 mm

8 mm8 mm

Find the surface area and volume.Find the surface area and volume.

≈ 279 mm2≈ 279 mm2

= 240 mm3= 240 mm3

S = pH + 2BS = pH + 2B

≈ 23.1(10) + 48≈ 23.1(10) + 48= (2 73 + 6)(10) + 2[ (6)(8)]= (2 73 + 6)(10) + 2[ (6)(8)]1

212

V = BHV = BH= [ (6)(8)](10)= [ (6)(8)](10)1

212

10 mm10 mm6 mm6 mm

8 mm8 mm

Find the surface area and volume.Find the surface area and volume.

= 96 cm2= 96 cm2

= 48 cm3= 48 cm3

= 60 + 36= 60 + 361313V = BHV = BH = (62)(4)= (62)(4)1

313

6 cm6 cm

4 cm4 cm

6 cm6 cm

5 cm5 cmS = pl + BS = pl + B1

212

= [4(6)](5) + 62= [4(6)](5) + 621212

Find the surface area and volume.Find the surface area and volume.

≈ 282.6 mm2≈ 282.6 mm2= 90p= 90p

S = prl + pr2S = prl + pr2

= p(5)(13) + p(52)= p(5)(13) + p(52)

5 mm5 mm

12 mm12 mm

13 mm13 mm

= 65p + 25p= 65p + 25p

Find the surface area and volume.Find the surface area and volume.

≈ 314 mm3≈ 314 mm3

1313V = pr2HV = pr2H

= p(52)(12)= p(52)(12)1313

5 mm5 mm

12 mm12 mm

13 mm13 mm

= 100p= 100p

Find the surface area and volume.Find the surface area and volume.

What is the volume of a cereal box 12 in. tall, 8 in. wide, and 2 in. thick?

What is the volume of a cereal box 12 in. tall, 8 in. wide, and 2 in. thick?

192 in.3 192 in.3

Find the volume of a waffle cone that is 15 cm tall and has a radius of 4 cm.

Find the volume of a waffle cone that is 15 cm tall and has a radius of 4 cm.

80 cm3 ≈ 251.2 cm3 80 cm3 ≈ 251.2 cm3

Give the mathematical significance of Genesis 6:22.Give the mathematical significance of Genesis 6:22.