Final Exam Rooms:Wednesday, June 10, 2015

7:30 – 9:00 am

Chapter 11 Test Review

Directions: Leave answers in terms of where appropriate. 1. Find the area and perimeter of a rectangle with length 24 cm and width 3 cm.

2. Find the area and perimeter of a rectangle with base 24 ft and diagonal 25 ft.

A = lwA = (24)(3)A = 72 cm2

A = bhA = (24)(7)A = 168 ft2

24

257

P = 2l + 2wP = 2(24) + 2(7)

P = 62 ft

P = 2l + 2wP = 2(24) + 2(3)P = 54 cm

3. Find the area of a square with perimeter 36 m.

4. Find the area and perimeter of a rhombus with diagonals 8 and 14.

P = 4s36 = 4ss = 9

A = A =

A = 81 m2

A =

A =

A = 5 units2

P = 4 unitsP = 4s

65=𝑐2

=

74

√65

5. Find the area and perimeter of an isosceles right triangle with hypotenuse .

6. Find the area of an equilateral triangle with perimeter 48 ft.

A =

A =

A = 72 units2

12√245

45

12

12

= 3s = 3s = 16

16 16

16

830

60

A =

A = )

A = 8

P = s + s + sP = 12 + 12 +

P = (24 + ) units

7. Find the circumference and area of a circle with radius 5.

8. Find the area of a circle with circumference of 24.

A =

A = A = C=

= 𝑟=12

A = A =

A =

C=

C=

C=

9. Find the perimeter & area of a parallelogram with a 60 angle with sides 14 and 16.

A = bh

30

7

7

A = (16)(7

A = 1 units2

= 14 + 14 + 16 + 16= 60 units

10. Find the median, perimeter, and area of the following trapezoid.

12

5

m =

m =

P = P =

P =

5

m =

10

11. Find the median, perimeter and area of an isosceles trapezoid with legs 17 and bases 5 & 35.

5

35

17 17

15 15

8

160 units2

m = 20 units

P = s + s + s + sP =

P = 74 units

5

m =

m =

8

12. Find the area and perimeter of the total figure.

5

3

4

3A = bh

A = (10)(3)A = 30 units2

A =

A = 4)

A = units2

+ 12 = 42 units2

Rectangle Triangle

P = s + s + s + s + s + sP = 10 + 5 + 5 + 3 + 10 + 3 P = 36 units

13. The radius of a circle is 12 cm. What is the length of a arc?

𝐴𝑟𝑐 h𝐿𝑒𝑛𝑔𝑡 =60 °360

•2𝜋 𝑟

𝐴𝑟𝑐 h𝐿𝑒𝑛𝑔𝑡 =16•2𝜋 (12) 𝐴𝑟𝑐 h𝐿𝑒𝑛𝑔𝑡 =4𝜋 𝑐𝑚

14. Find the area of the shaded region only

𝐴𝑂𝑆=𝑥 °360

•𝜋𝑟 2

𝐴𝑂𝑆=330 °360

•𝜋 ¿

𝐴𝑂𝑆=539𝜋12

𝑢𝑛𝑖𝑡𝑠2

𝐴𝑂𝑆=1112• 49𝜋

15. Find the area of the shaded region only

𝑆 h𝑎𝑑𝑒𝑑𝑟𝑒𝑔𝑖𝑜𝑛=𝑠𝑞𝑢𝑎𝑟𝑒−𝑐𝑖𝑟𝑐𝑙𝑒

A = A =

8A = 64 units2

Square CircleA = A =

A = 16 units2

𝑆 h𝑎𝑑𝑒𝑑𝑟𝑒𝑔𝑖𝑜𝑛=(64−16𝜋 )𝑢𝑛𝑖𝑡𝑠2

4

16. Find the area of a 45 arc sector given the arc length is 6π .

𝐴𝑟𝑐 h𝐿𝑒𝑛𝑔𝑡 =𝑥 °360

∗2𝜋𝑟

6𝜋=45 °360

∗2𝜋𝑟

6𝜋=𝜋𝑟4

𝑟=24

𝐴𝑂𝑆=𝑥 °360

∗𝜋 𝑟2

𝐴𝑂𝑆=45360

∗𝜋 ¿

𝐴𝑂𝑆=72𝜋𝑢𝑛𝑖𝑡𝑠2