FIN 685: Risk Management Topic 3: Non-Linear Hedging Larry Schrenk, Instructor.
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Transcript of FIN 685: Risk Management Topic 3: Non-Linear Hedging Larry Schrenk, Instructor.
FIN 685: Risk Management
Topic 3: Non-Linear Hedging
Larry Schrenk, Instructor
TOPICS
Black-Scholes Model
Greeks
Hedging
An Extended Example
The Black-Scholes Model
BLACK-SCHOLES FORMULA
1 2
2 1
1
2 1
( ) ( )
( ) ( )
2ln( / ) ( / 2)where
2ln( / ) ( / 2)
rt
rt
c S N d Xe N d
p Xe N d S N d
S X r td
t
S X r td d t
t
VARIABLES
S = Spot Price X = Exercise Price r = Risk Free Rate s = Standard Deviation of
Underlying t = Time to Maturity c = Price of a Call Option p = Value of a Put Option
EXAMPLE
Base Case Data– S = 100– K = 100– r = 5% – s = 30%– T = 3 months
BLACK-SCHOLES FORMULA
2
1
2
0.05 0.25
ln(100 / 100) 0.05 0.3 / 2 0.250.1583
0.3 0.25
0.1583 0.3 0.
$6.58
25 0.0083
100 (0.1583) 100 (0.0083) = 1 3
d
d
c N e N
The Greeks
THE GREEKS
Sensitivity Analysis
5 First Derivatives; 1 Second Derivative
Linear Approximations (except Gamma)
THE GREEKS
Delta (D) = Price Sensitivity Gamma (G) = 2nd Order Price
Sensitivity Rho (R) = Interest Rate
Sensitivity Theta ( )Q = Time Sensitivity Vega ( )n = Volatility Sensitivity
DELTA HEDGING
• The hedge position must be frequently rebalanced
• Delta hedging a written option involves a “buy high, sell low” trading rule
EUROPEAN CALL DELTA
8 8.5 9 9.5 10 10.5 11 11.5 120
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
S
Del
ta
(S=10, K=10, T=0.2, r=0.05, s=0.2)
GAMMA
• Gamma (G) is the rate of change of delta (D) with respect to the price of the underlying asset
• Gamma is greatest for options that are close to the money.
EUROPEAN CALL GAMMA
8 8.5 9 9.5 10 10.5 11 11.5 120
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
0.45
0.5
S
Gam
ma
(S=10, K=10, T=0.2, r=0.05, s=0.2)
INTERPRETATION OF GAMMA• For a delta neutral portfolio,
DP » Q Dt + ½GDS 2
DP
DS
Negative Gamma
DP
DS
Positive Gamma
THETA
• Theta (Q) of a derivative (or portfolio of derivatives) is the rate of change of the value with respect to the passage of time
• The theta of a call or put is usually negative. This means that, if time passes with the price of the underlying asset and its volatility remaining the same, the value of the option declines
EUROPEAN CALL THETA
(S=10, K=10, T=0.2, r=0.05, s=0.2)
8 8.5 9 9.5 10 10.5 11 11.5 12-1.4
-1.2
-1
-0.8
-0.6
-0.4
-0.2
0
S
The
ta
VEGA
• Vega (n) is the rate of change of the value of a derivatives portfolio with respect to volatility
• Vega tends to be greatest for options that are close to the money.
EUROPEAN CALL VEGA
(S=10, K=10, T=0.2, r=0.05, s=0.2)
8 8.5 9 9.5 10 10.5 11 11.5 120
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
1.8
S
Veg
a
MANAGING DELTA, GAMMA, & VEGA
· D can be changed by taking a position in the underlying
• To adjust G & n it is necessary to take a position in an option or other derivative
RHO
• Rho is the rate of change of the value of a derivative with respect to the interest rate
• For currency options there are 2 rhos
EUROPEAN CALL RHO
(S=10, K=10, T=0.2, r=0.05, s=0.2)
8 8.5 9 9.5 10 10.5 11 11.5 120
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
1.8
2
Rho
S
FORMULAE
)N(drXe t22
eσS- Theta Call 2
rt2
d21
2
etS Vega Call
2
d-
21
)N(dtXeRho Call 2rt
t2Sσ
eGamma Call
2
d21
1Delta Call dN
Hedging
HEDGING
Hedging is about the reduction of risk.
We will consider dynamic hedging in which a portfolio is dynamically traded in order to reduce risk.
Simply put, a portfolio is hedged against a certain risk if the portfolio value is not sensitive to that risk.
15.26
HEDGING IN PRACTICE
• Traders usually ensure that their portfolios are delta-neutral at least once a day
• Whenever the opportunity arises, they improve gamma and vega
• As portfolio becomes larger hedging becomes less expensive
DELTA
0 5 10 15-6
-4
-2
0
2
4
6
Stock Price
Call
Option P
rice
Delta Hedge
calldelta
Hedged Call Option Parameters: (K=10, T=0.2, s=0.3)
Current Price: S = 10, Risk Free Rate: r = 0.05
Position in Bonds
Slope =D
DELTA + GAMMA
0 5 10 15-6
-4
-2
0
2
4
6
Stock Price
Cal
l Opt
ion
Pric
e
Delta vs. Delta-Gamma Hedge
calldeltadelta-gamma
Hedged Call Option Parameters: (K=10, T=0.2, s=0.3)
Current Price: S = 10, Risk Free Rate: r = 0.05
2nd Call Option Parameters: (K=8, T=0.4, s=0.25)
EXAMPLES
Base Case Data– S = 100– K = 100– r = 5% – s = 30%– T = 3 months
Call Value for Black-Scholes: c = $6.5831
EXAMPLE 1: DELTA + GAMMA Using both delta and gamma for
the estimate, what is the change in value (c’) if the stock price increases by 5%?
221 0.1583d
2 2e eCall Gamma 0.0263
Sσ 2 t 100 0.3 2 (0.25)
c 100 0.05 0.5629 0.0263 100 0. $3.471105
1Call Delta 0.158 0.5629N d N
EXAMPLE 2: RHO
What is what is the change in value (c’) of the option if the interest rate increases by 5%?
rt2
0.05 0.25
Call Rho tXe N(d )
= 0.25 100e N(0.0083) =12.4268
c 0.05 0.05 12.4268 $0.0311
EXAMPLE 3: VEGA
What is what is the change in value (c’) of the option if the standard deviation increases by 5%?
21
2
d-
2
0.1583-
2
S teCall Vega
2
100 0.25e 19.6986
2
c 0.3 0.05 19.6986 $0.2955
EXAMPLE 4: THETA
What is what is the change in value (c’) of the above option if the time decreases by 5%?
σ
21
2
d
2rt
2
0.1583
20.05 0.25
S eCall Theta - rXe N(d )
2 2 t
100 0.3 e - 0.05 100 e N(0.0083) = -14.3045
2 2 0.25
c 0.25 0.05 14.304 $0.17885
An Extended Example
MANAGING THE RISK OF OPTIONS
• Here we talk about how option dealers hedge the risk of option positions they take.
• Assume a dealer sells 1,000 AOL June 125 calls at the Black-Scholes price of 13.5512 with a delta of .5692. Dealer will buy 569 shares and adjust the hedge daily.– To buy 569 shares at $125.9375 and sell 1,000
calls at $13.5512 will require $58,107.– We simulate the daily stock prices for 35 days,
at which time the call expires.
MANAGING THE RISK OF OPTIONS
• The second day, the stock price is 120.5442. There are now 34 days left. Using bsbin2.xls, we get a call price of 10.4781 and delta of .4999. We have– Stock worth 569($120.5442) = $68,590– Options worth -1,000($10.4781) = -$10,478– Total of $58,112– Had we invested $58,107 in bonds, we would have
had $58,107e.0446(1/365) = $58,114.• Table 5.9, p. 202 shows the remaining outcomes. We
must adjust to the new delta of .4999. We need 500 shares so sell 69 and invest the money ($8,318) in bonds.
MANAGING THE RISK OF OPTIONS
• At the end of the second day, the stock goes to 106.9722 and the call to 4.7757. The bonds accrue to a value of $8,319. We have– Stock worth 500($106.9722) = $53,486– Options worth -1,000($4.7757) = -$4,776– Bonds worth $8,319 (includes one days’ interest)– Total of $57,029– Had we invested the original amount in bonds, we
would have had $58,107e.0446(2/365) = $58,121. We are now short by over $1,000.
• At the end we have $56,540, a shortage of $1,816.
MANAGING THE RISK OF OPTIONS
• What we have seen is the second order or gamma effect. Large price changes, combined with an inability to trade continuously result in imperfections in the delta hedge.
• To deal with this problem, we must gamma hedge, i.e., reduce the gamma to zero. We can do this only by adding another option. Let us use the June 130 call, selling at 11.3772 with a delta of .5086 and gamma of .0123. Our original June 125 call has a gamma of .0121. The stock gamma is zero.
• We shall use the symbols 1, 2, 1 and 2. We use hS shares of stock and hC of the June 130 calls.
MANAGING THE RISK OF OPTIONS
• The delta hedge condition is– hS(1) - 1,0001 + hC 2 = 0
• The gamma hedge condition is– -1,0001 + hC 2 = 0
• We can solve the second equation and get hC and then substitute back into the first to get hS. Solving for hC and hS, we obtain
– hC = 1,000(.0121/.0123) = 984
– hS = 1,000(.5692 - (.0121/.0123).5086) = 68• So buy 68 shares, sell 1,000 June 125s, buy 985 June
130s.
MANAGING THE RISK OF OPTIONS
• The initial outlay will be– 68($125.9375) - 1,000($13.5512) +
985($11.3772) = $6,219• At the end of day one, the stock is at
120.5442, the 125 call is at 10.4781, the 130 call is at 8.6344. The portfolio is worth – 68($120.5442) - 1,000($10.4781) +
985($8.6344) = $6,224• It should be worth $6,219e.0446(1/365) = $6,220.• The new deltas are .4999 and .4384 and the
new gammas are .0131 and .0129.
MANAGING THE RISK OF OPTIONS• The new values are 1,012 130 calls so we buy 27. The
new number of shares is 56 so we sell 12. Overall, this generates $1,214, which we invest in bonds.
• The next day, the stock is at $106.9722, the 125 call is at $4.7757 and the 130 call is at $3.7364. The bonds are worth $1,214. The portfolio is worth– 56($106.9722) - 1,000($4.7757) + 1,012($3.7364) +
$1,214 = $6,210.• The portfolio should be worth $6,219e.0446(2/365) = $6,221.• Continuing this, we end up at $6,589 and should have
$6,246, a difference of $343. We are much closer than when only delta hedging.