Exploring Rates Using a Three-Column Process Chart (Module 6) Guided Practice Situational Rate of...
-
Upload
morgan-miles -
Category
Documents
-
view
214 -
download
0
Transcript of Exploring Rates Using a Three-Column Process Chart (Module 6) Guided Practice Situational Rate of...
Exploring Rates Using a Three-Column Process
Chart (Module 6)
Guided PracticeSituational Rate of Change
Guided PracticeThe Yellow Submarine
Situational Rates of Change (Guided Practice)
For each of the following situations:
1) Complete the depends on sentence,
2) Complete a three column process chart and,
3) Write an equation that models the situation.
1 John went fishing and caught 2 fish in one hour. In two hours he caught 4 fish.
depends onNumber of fish caught number of hours.
Equation_____________y = 2x
1
4
Number of fish caught number of hours
one
2 two
221
22
1
ym
x
222
1 ( )12 ( )
xyy xx
( )
2 Anica is learning to crawl. She was 3 feet away from the door at five seconds. She was 6 feet away at 10 seconds.
Equation_____________
depends onAnica’s distance from door in feet the number of seconds
number of seconds
distance from door in feet
5
10
3
6
3
5y x
3
5( )x
3
5(5)
3
5(10)
353
5
ym
x
A left Hawaii at a constant speed.
After two hours, the submarine is 50
meters below sea level. After 5 hours, the
is 125 meters below sea
level. How fast is the submarine
traveling?
The Yellow Submarine(Guided Practice)
X
y
1 2 3 4 5
–50
–125
Number of Hours
Dis
tanc
e T
rave
led
Bel
ow S
ea L
evel
50
Distance traveled below sea level number of hours
A left Hawaii at a constant speed. After two hours, the
submarine is 50 meters below sea level. After 5 hours, the
is 125 meters below sea level. How fast is the
submarine traveling?
two
depends onDependent Independent
number of hoursDistance traveled below sea level
50
2
5
125
–50
–125–753
y
x
–753 – 25= – 25 – 25
( )2
( )5 – 25 ( )
xyx
x1 2 3 4 5
–50
–125
Number of HoursD
ista
nce
Bel
ow
Se
a L
eve
l (m
)#
hours
Distance below
sea level
5
- 50
- 125
2 - 50
- 125
- 25
- 50
- 75
∆X = 3
∆Y = - 75- 75
2
5
1 2 3
3
Δy= -25
ΔXSlope of the line.
Slope of –25 means …
the submarine goes DOWN under the sea at 25 meters per hour.
y
–25
–75
–100
Find the slope of the line given the points (–5, 2) and (10, –4).
(–5, 2)
(10, – 4)
–66 units down
15 units to the right15
∆y
∆x=
–6
15
÷ 3
÷ 3=
–2
5
1 2 3 4 5 6 7 8 9 10
1
2
3
4
5
6
7
-1-2-3-4-5-6-7-1
-2
-3
-4
-5
-6
-7
-8
-9
-10
-8-9-10
8
910
Slope = 2
5
Find the rate of change and equation of the given values in the table shown.
–3
–6
5
10
Equation
x y
–3
∆y∆x
= 5–3
=Rate of Change
5–3
53
– 53
– 53
– 53
–
y = x53
–
–3 ( )
–6 ( )
x ( )
The End