Experiment 8 Reviewer
1
CHEM 17 Guide for Formal Report (Malgapo, M.P., Obligacion, J.V.) EXPERIMENT 8: Determination of the Solubility Product Constant of Calcium Hydroxide (Guide for Formal Report) In a saturated solution, a slightly soluble ionic solid such as calcium hydroxide exists in equilibrium with its ions: Ca(OH) 2 (s) Ca 2+ (aq) + 2 OH - (aq) 2 2 sp ] OH ][ Ca [ K In the experiment, Ca(OH) 2 will be suspended in 3 different media: 1. Distilled water 2. 0.10 M Ca(NO 3 ) 2 3. 0.5 M, 0.1 M, 0.05 M, 0.01 M, 0.005 M and 0.001 M KCl ■ Ca(OH) 2 in distilled water 2 ] OH [ ] Ca [ 2 2 ] OH [ K ] OH [ 2 ] OH [ ] OH ][ Ca [ K 3 sp 2 2 2 sp In terms of molar solubility: 3 2 sp s 4 ) s 2 )( s ( K 3 sp 4 K s ■ Ca(OH) 2 in 0.10 M Ca(NO 3 ) 2 2 2 ) 3 NO ( Ca from 2 sp 2 ) 3 NO ( Ca from 2 2 2 ) 3 NO ( Ca from 2 sp 2 2 sp ) s 2 )( ] Ca ([ K s ] Ca [ but ) s 2 )( ] Ca [ s ( K ] OH ][ Ca [ K 2 ) 3 NO ( Ca from 2 sp ] Ca [ 4 K s ■ Ca(OH) 2 in 0.5 M, 0.1 M, 0.05 M, 0.01 M, 0.005 M and 0.001 M KCl 2 ] OH [ ' K 3 sp In terms of molar solubility: 3 2 sp s 4 ) s 2 )( s ( ' K 3 sp 4 ' K s Note: Calculate s for the different concentrations of KCl then plot s vs. μ Other notes: 1. K sp is the solubility product constant of Ca(OH) 2 in water while K sp ’ is the solubility product constant of Ca(OH) 2 in the presence of KCl 2. [OH - ] can be obtained from titration data filtrate of volume V M ] OH [ HCl HCl
-
Upload
datupstudentdoe -
Category
Documents
-
view
475 -
download
0
Transcript of Experiment 8 Reviewer
CHEM 17 Guide for Formal Report (Malgapo, M.P., Obligacion, J.V.)
EXPERIMENT 8: Determination of the Solubility Product Constant of Calcium Hydroxide (Guide for Formal Report) In a saturated solution, a slightly soluble ionic solid such as calcium hydroxide exists in equilibrium with its ions:
Ca(OH)2(s) Ca2+ (aq) + 2 OH- (aq)
22sp ]OH][Ca[K
In the experiment, Ca(OH)2 will be suspended in 3 different media: 1. Distilled water 2. 0.10 M Ca(NO3)2
3. 0.5 M, 0.1 M, 0.05 M, 0.01 M, 0.005 M and 0.001 M KCl ■ Ca(OH)2 in distilled water
2
]OH[]Ca[ 2
2
]OH[K
]OH[2
]OH[]OH][Ca[K
3
sp
222sp
In terms of molar solubility:
32sp s4)s2)(s(K
3 sp
4
Ks
■ Ca(OH)2 in 0.10 M Ca(NO3)2
22)3NO(Cafrom
2sp
2)3NO(Cafrom2
22)3NO(Cafrom
2sp
22sp
)s2)(]Ca([K
s]Ca[but
)s2)(]Ca[s(K
]OH][Ca[K
2)3NO(Cafrom2
sp
]Ca[4
Ks
■ Ca(OH)2 in 0.5 M, 0.1 M, 0.05 M, 0.01 M, 0.005 M and 0.001 M KCl
2
]OH['K
3
sp
In terms of molar solubility:
32sp s4)s2)(s('K
3 sp
4
'Ks
Note: Calculate s for the different concentrations of
KCl then plot s vs. μ Other notes: 1. Ksp is the solubility product constant of Ca(OH)2 in water while Ksp’ is the solubility product constant of Ca(OH)2 in the presence of KCl 2. [OH-] can be obtained from titration data
filtrateofvolume
VM]OH[ HClHCl
