Experiment 3
Transcript of Experiment 3
LOGODo you google?
Experiment 2Experiment 2Titration of Titration of
Amino AcidsAmino Acids
Sundusit Yangvisit
Edwin Hojillla
Jayson Doria
Renan Difuntorum
Dandelo De Guzman
Group 4
Sorensen’s Formol TitrationSorensen’s Formol Titration
In view of the presence of the amino group, it is not possible to titrate and estimate the total acidity of an amino acid solution, since the H+ ion formed by the ionisation of –COOH will be taken up by –NH2 and be present as –NH3
+. However, an amino acid solution could be titrated to the complete neutralisation point after the addition of excess of formalin (solution of formaldehyde in water).
Formaldehyde converts the basic –NH2 group of the amino acid forming a neutral dimethylol derivative thus overcoming the interference by –NH2 in the titration. After the addition of formaldehyde, an amino acid behaves as any ordinary organic acid. Thus, formalin makes available the entire H+ ions during titration against alkali.
PurposePurpose
to determine the acid base behavior of select amino acids during titration with an alkali and acid. The effect of formaldehyde on the titration curve of amino acids will also be determined.
(1) titration of the amino acid with HCl, (2) titration of the amino acid with NaOH, (3) titration of the formaldehyde-treated amino acid with HCl and (4) titration of the formaldehyde-treated amino acid with NaOH.
The experiment is divided into 4 parts:
Materials/ReagentsMaterials/Reagents
0.1N NaOH 0.1N HCl 0.1M glycine solution 0.1M lysine solution 0.1M aspartic acid solution Neutralized formaldehyde
ProcedureProcedure
1. Take two pipettes and fill the first with 0.1N HCl and the second with 0.1N NaOH.
2. Into each of the two beakers, introduce 10.0 mL of the amino acid solution and measure the resulting pH of the solution.
3. Titrate the first solution with 0.1N HCl adding 2.0 mL at a time and determining the pH after each addition, until a total of 10.0 mL is reached (for glycine and aspartic acid) or 20.0 mL (for lysine). In addition, measure the pH at 5 mL and 15 mL volumes.
4. Titrate the second solution in the same manner as the 1st using instead 0.1N NaOH, until 10.0 mL is reached (for glycine and lysine) or 20.0 mL is reached (for aspartic acid).
5. Plot the pH (ordinate) vs. the equivalent acid/base (abscissa). One mL of acid/base=0.1 mEq of acid/base. (Show how this value was obtained).
6. Repeat the above procedure, but add 5.0 mL of neutralized formaldehyde solution into each of the amino acid solutions before determining the pH of the solution. Titrate the solutions.
Procedure
7. Plot pH vs. the equivalent acid/base on the same graph as above. Construct your titration curves on graphing paper. Solve for the pI and pKa values of your amino acid.
www.themegallery.com
Procedure
1 mL of acid/base = 0.1 mEq of acid/base
0.1 N HCl = 0.1 M HCl = (0.1 mol/L)(36.5 g/mol) = 3.65 g/L
0.1 mEq = 0.1 x (36.5 g / (1 x 1000) = 0.1 x 0.0365 g = 0.00365 g
0.00365 g / (3.65 g/L) = 0.001 L = 1 mL
mEq =atomic weight
(g)valence x 1000
Glycine
Aspartic Acid
Lysine
QUESTIONSQUESTIONS
1. What can account for Sorensen’s discovery that the endpoint of titration between an amino acid and a standard
alkali (without formaldehyde) is not reached?
ANSWERANSWER
The free amino group at the alpha-carbon acts as a base and interferes with the end point of the titration using a standard alkali. Formaldehyde in excess is needed to modify the basic free amino group to modify it to a neutral group, a dimethylol derivative, which allows for the endpoint to be reached.
2. When an amino acid is titrated with an acid, example HCl, both with and without formaldehyde. How do you account for
this?
ANSWERANSWER
In the presence of formaldehyde, tritration curve was slight lower. This is due to the fact that formaldehyde ties down the amino groups, making the carboxyl hydrogen ion more available
3. Draw the titration curve of glycine and point the areas of maximum buffering capacity, the point of least buffering
capacity.
ANSWERANSWER
Maximum buffering capacity (pink) when pH = pKa +/- 1. In this region there is nearly equal amounts of proton donors and acceptors, i.e. weak acid/base and conjugate base/acid.
Least buffering capacity at the pI because both the amino and carboxyl group are protonated and deprotonated, respectively. Therefore any minute addition of H+ or OH- will result in a large change in pH.
4. From the titration curve of an amino acid, can you determine the nature of its
R group, explain why?
ANSWERANSWER
YesYes, a reactive side group can be determined from the
titration curve of an amino acid. When the amino acid is
titrated and graphed, three buffering regions will be
developed. The extra buffering region aside from the
alpha-amino (pKa = approx. 2) and alpha-carboxyl (pKa
= approx. 9) can be used to determine the identity of the
unknown side chain. If the R group has:
pKa < pH, it is basic
pKa > pH, it is acidic
pKa = pH, neutral because zwitterion forms
LOGO