Exp. #2 physics lab

2
Page 1 of 2 Experiment Name: To Determine the resistance of a galvanometer by half-deflection method. Theory: In the arrangement shown in Fig.1, if the shunt resistance S is very small compared to the galvanometer resistance G, then the potential difference (V) between the ends of the shunt resistance S remains nearly constant for all values of R 1 . Thus when R 1 =0, then the galvanometer current C g is given by = kd……………………. (1) Where d is the deflection on the scale in the galvanometer and k is the galvanometer constant. If now a resistance R 1 is introduced in the galvanometer circuit such that the deflection reduces to . Then C’ g = =k ………….…….. (2) Where C’ g is the new galvanometer current in the changed circumstances. Dividing (1) by (2), we get =2, or G+R 1 =2G or G = R 1 ………………………… (3) Here by simply measuring R 1 , G can be found out. Apparatus : Zero centre galvanometer, Shut box S, Resistances R and R₁, DC power supply E, Connecting wires. Procedure: I)Make the connection as shown in fig(1).Bring one sharp edge of the pointer of the galvanometer at the zero mark of the galvanometer scale. II)Insert a resistance (r) of the order by putting all the plugs in the box. Beginning with the smallest value(s=0.1 r) of the shunt resistance s, go on increasing s until you obtain a deflection. III)Keeping the resistance R constant, adjust the value of the resistance R₁ until the deflection is reduced to half of the former. Record this value of R₁ which is the value of the galvanometer resistance G. ıv) Stop the current in the circuit. Make the value of R₁ zero and keep R the same. Now reverse the current with the commutator K. repeat the whole operation to get another value of G. v) Keeping the value of the resistance R the same, change the value of the shunt resistance S to obtain a different deflection of round about 10 cm and similarly determine the value of G. vı) Repeat the operation three times with different value of R in the Dc power supply circuit and two value of S for each R.

Transcript of Exp. #2 physics lab

Page 1: Exp. #2 physics lab

Page 1 of 2

Experiment Name: To Determine the resistance of a galvanometer by half-deflection method.

Theory: In the arrangement shown in Fig.1, if the shunt resistance S is very small compared to the

galvanometer resistance G, then the potential difference (V) between the ends of the shunt resistance S

remains nearly constant for all values of R1 .

Thus when R1=0, then the galvanometer current Cg is given by

= kd……………………. (1)

Where d is the deflection on the scale in the galvanometer and k is the galvanometer constant. If now a

resistance R1 is introduced in the galvanometer circuit such that the deflection reduces to

.

Then C’g =

=k

………….…….. (2)

Where C’g is the new galvanometer current in the changed circumstances.

Dividing (1) by (2), we get

=2,

or G+R1=2G or G = R1………………………… (3)

Here by simply measuring R1, G can be found out.

Apparatus: Zero centre galvanometer, Shut box S, Resistances R and R₁, DC power supply E, Connecting

wires.

Procedure: I)Make the connection as shown in fig(1).Bring one sharp edge of the pointer of the

galvanometer at the zero mark of the galvanometer scale.

II)Insert a resistance (r) of the order by putting all the plugs in the box. Beginning with the

smallest value(s=0.1 r) of the shunt resistance s, go on increasing s until you obtain a deflection.

III)Keeping the resistance R constant, adjust the value of the resistance R₁ until the deflection

is reduced to half of the former. Record this value of R₁ which is the value of the galvanometer

resistance G.

ıv) Stop the current in the circuit. Make the value of R₁ zero and keep R the same. Now

reverse the current with the commutator K. repeat the whole operation to get another value of G.

v) Keeping the value of the resistance R the same, change the value of the shunt resistance S

to obtain a different deflection of round about 10 cm and similarly determine the value of G.

vı) Repeat the operation three times with different value of R in the Dc power supply circuit

and two value of S for each R.

Page 2: Exp. #2 physics lab

Page 2 of 2

Experimental data and calculation: In the following table R is the resistance in the DC power supply

circuit and R₁ is the resistance in the galvanometer circuit and G is the galvanometer resistance to be

determined.

Table

No of

obs.

currents Resistance

R

(ohms)

Shunt resistance

S

(ohms)

Resistance

R₁

(ohms)

Deflections Galvanometer resistance

G=R₁

(ohms)

Mean

G

(ohms)

1

Direct

Reverse

2

Direct

Reverse

3

Direct

Reverse

Result: The resistance of the given galvanometer is =---------------------ohms

Discussions: