Exercise Chapter 10

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Page 1 of 2 1. A B C D 35° 10 cm 4 cm 7 cm The diagram shows a quadrilateral ABCD. The area of triangle BCD is 12 cm 2 and BCD is acute. Calculate a. BCD. b. The length, in cm, of BD. c. ABD. d. The area, in cm 2 , quadrilateral ABCD. 2. 13.1 cm 6.4 cm 85° 28° P Q R S The diagram shows a trapezium PQRS. PS is parallel to QR and QRS is obtuse. Find a. The length, in cm, of QS. b. The length, in cm, of RS. c. QRS. d. The area, in cm 2 , of triangle QRS.

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Transcript of Exercise Chapter 10

Page 1 of 2

1.

A

B

C

D

35°

10 cm

4 cm

7 cm

The diagram shows a quadrilateral ABCD. The area of triangle BCD is 12 cm2 and ⦟BCD

is acute. Calculate

a. ⦟BCD.

b. The length, in cm, of BD.

c. ⦟ABD.

d. The area, in cm2, quadrilateral ABCD.

2.

13.1 cm

6.4 cm85°

28° P

Q

R

S

The diagram shows a trapezium PQRS. PS is parallel to QR and QRS is obtuse. Find

a. The length, in cm, of QS.

b. The length, in cm, of RS.

c. ⦟QRS.

d. The area, in cm2, of triangle QRS.

Page 2 of 2

3. The diagram below shows a triangle ABC.

70°

12 cm

16 cm

A

B

C

a. Calculate the length, in cm, of AC.

b. A quadrilateral ABCD is now formed so that AC is a diagonal, ⦟ACD = 45° and

AD = 4 cm. Calculate the two possible values of ⦟ADC.

c. By using the acute ⦟ADC from (b), calculate

i. The length, in cm, of CD.

ii. The area, in cm2, of the quadrilateral ABCD.

4. In the diagram below, ABC is a triangle. AGJB, AHC, and BKC are straight lines. The

straight line JK is perpendicular to BC.

85°

45°

J

GH

A

B CK

40 cm

30 cm33 cm

It is given that BG = 40 cm, GA = 33 cm, AH = 30 cm, GAH = 85° and JBK = 45°.

a. Calculate the length, in cm of

i. GH.

ii. HC.

b. The area of triangle GAH is twice the area of triangle JBK. Calculate the length, in

cm, of BK.

c. Sketch triangle which has a different shape from triangle ABC such that, A’B’ =

AB, A’C’ = AC and ⦟A’B’C’ = ⦟ABC.