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Example Saddle
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Transcript of Example Saddle
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Date Printed: 08/10/2015
Vessel designed with DesignCalcs, Version: 2015.0Vessel is ASME Code Stamped
Wind Analysis performed in accordance with ASCE 7-02Seismic Analysis performed in accordance with IBC 2006
Job No: ExampleVessel Number: Saddle
NAMEPLATE INFORMATIONVessel MAWP: 425.00 PSI at 100 F
MDMT: -20 F at 425.00 PSI
Serial Number(s): __________________________________
National Board Number(s): __________________________________Year Built: 2012
Radiography: NONEPostweld Heat Treated: NONE
Construction Type : W
Signatures
_______________________________________________________________ Date: ____/____/____
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Table of Contents
Shell 1 1
Head 1 2
Head 2 3
Nozzle 1 4
Nozzle 2 9
Nozzle 3 14
Nozzle 4 19
Nozzle 5 24
Threaded Coupling - 1" 29
Threaded Coupling - 1" 31
Nozzle 8 33
Nozzle 9 35
Nozzle 11 40
Nozzle 10 42
Threaded Coupling - 1" 47
Threaded Coupling - 1" 49
Nozzle 14 51
Threaded Coupling - 2" 56
Threaded Coupling - 2" 58
Threaded Coupling - 2" 60
Threaded Coupling - 1" 62
Saddle Information 64
ASME Flanges 65
Attachment/Loading Information 66
Zick Information - Saddle: Saddle 1 67
MDMT Summary 87
MAWP Summary 88
Summary Information 89
Hydrostatic Test Information Par. UG-99(b) 90
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Date Printed: 08/10/2015
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Shell 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: S1
Date Printed: 08/10/2015
Cylindrical Shell Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Long. Joint Efficiency: 100 %
Shell Material: SA-515 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI
Shell Length: 360.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 16304 PSI
Corrosion Allowance: 0.0000 in. Actual Circumferential Stress: 16575 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 8075 PSI
Inside Diameter (new): 96.0000 in. Extreme Fiber Elongation: 1.29 %Inside Diameter (corroded): 96.0000 in. Specific Gravity: 1.00
Shell Surface Area: 773.62 Sq. Ft. Weight of Fluid: 94247.57 lb.Shell Estimated Volume: 11281.65 Gal. Total Flooded Shell Weight:132743.07 lb.
Circ. Joint Efficiency: 100 % Shell Weight: 38495.51 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -38 F
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t = PR
2SE + 0.4P =
425.00 * 48.0000
2 * 20000 * 1.00 + 0.4 * 425.00 = 0.5078 + 0.0000 (corrosion) + 0.0000 (ext. corrosion) = minimum of 0.5078 in.
Circumferential Stress Calculations per UG-27(c)(1)
t = PR
SE - 0.6P=
425.00 * 48.0000
20000 * 1.00 - 0.6 * 425.00 = 1.0332 + 0.0000 (corrosion) + 0.0000 (ext. corrosion) = minimum of 1.0332 in.
External loads do not control design.
Nominal Shell Thickness Selected = 1.2500 in.
DesignCalcs version: 2015.0 CEI 2015Page 1 of 90
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Head 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: H1
Date Printed: 08/10/2015
Ellipsoidal Head Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Joint Efficiency: 100 %
Head Material: SA-515 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI
Corrosion Allowance: 0.0000 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 18176 PSI
Head Location: Left Straight Flange : 0.0000 in.Inside Diameter (new) : 96.0000 in. Head Depth (h) : 24.0000 in.
Inside Diameter (corroded) : 96.0000 in. Thin Out : 0.1250 in.
K = 1
6 [2 + (D/2h) ] : 1.00
Extreme Fiber Elongation: 5.67 %Head Surface Area: 71.59 Sq. Ft. Specific Gravity: 1.00
Head Estimated Volume: 501.41 Gal. Weight of Fluid: 4181.73 lb.Head Weight: 3608.06 lb. Total Flooded Head Weight: 7789.79 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -35 F
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(c)
t = PDK
2SE - 0.2P =
425.00 * 96.0000 * 1.00
2 * 20000 * 1.00 - 0.2 * 425.00 = 1.0222 + 0.0000 (corrosion) + 0.0000 (ext. corrosion) + 0.1250(thin out)
= minimum of 1.1472 in.
Nominal Head Thickness Selected = 1.2500 in.Minimum Thickness after forming, ts (uncorroded) = 1.1250 in.
DesignCalcs version: 2015.0 CEI 2015Page 2 of 90
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Head 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: H2
Date Printed: 08/10/2015
Ellipsoidal Head Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Joint Efficiency: 100 %
Head Material: SA-515 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI
Corrosion Allowance: 0.0000 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 18176 PSI
Head Location: Right Straight Flange : 0.0000 in.Inside Diameter (new) : 96.0000 in. Head Depth (h) : 24.0000 in.
Inside Diameter (corroded) : 96.0000 in. Thin Out : 0.1250 in.
K = 1
6 [2 + (D/2h) ] : 1.00
Extreme Fiber Elongation: 5.67 %Head Surface Area: 71.59 Sq. Ft. Specific Gravity: 1.00
Head Estimated Volume: 501.41 Gal. Weight of Fluid: 4181.73 lb.Head Weight: 3608.06 lb. Total Flooded Head Weight: 7789.79 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -35 F
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(c)
t = PDK
2SE - 0.2P =
425.00 * 96.0000 * 1.00
2 * 20000 * 1.00 - 0.2 * 425.00 = 1.0222 + 0.0000 (corrosion) + 0.0000 (ext. corrosion) + 0.1250(thin out)
= minimum of 1.1472 in.
Nominal Head Thickness Selected = 1.2500 in.Minimum Thickness after forming, ts (uncorroded) = 1.1250 in.
DesignCalcs version: 2015.0 CEI 2015Page 3 of 90
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Nozzle 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: N1ID Number: 1
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 12.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 15.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 24 Nozzle Pipe Schedule: 40Nozzle ID (new): 22.6260 in. Nozzle Wall Thickness(new): 0.6870 in.
Nozzle ID (corroded): 22.6260 in. Nozzle Wall Thickness(corroded): 0.6870 in.Developed Opening: 26.4840 in. Tangential Dimension L: 24.2583 in.
External Limit of Reinforcement: 2.9675 in. Upper Weld Leg Size(Weld 41): 0.3571 in.Internal Limit of Reinforcement: 1.7175 in. Internal Weld Leg Size(Weld 43): 0.3571 in.
Parallel Limit of Reinf (2Lpar): 52.9680 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: C Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 1.2500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.OD, Reinforcing Plate(Dp): 42.0000 in. Repad to Nozzle Groove Weld Depth: 1.2500 in.
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3571 in.
Internal Weld Leg Size(Weld 43): 0.3571 in.
Nozzle Wall Thickness(tn): 0.6870 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.
Repad Thickness(te): 1.2500 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 24 Schedule: 40
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 4 of 90
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Nozzle 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: N1ID Number: 1
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 11.3130
17100 * 1 - 0.6 * 425.00 = 0.2854 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 11.3130
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.2854 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3280 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3280 in.
tUG-45 = max( ta, tb ) = 0.3280 in.
Wall thickness = tn * 0.875(pipe) = 0.6010 is greater than or equal to UG-45 value of 0.3280
DesignCalcs version: 2015.0 CEI 2015Page 5 of 90
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Nozzle 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: N1ID Number: 1
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(26.4840, 11.3130 + 1.2500 + 0.6870) = 26.4840 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.2500, 2.5 * 0.6870 + 1.2500) = 2.9675 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.2500, 2.5 * 0.6870) = 1.7175 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [26.4840 * 1.0332 * 1.00 + 2 * 0.6870 * 1.0332 * 1.00 * (1 - 0.8550)], 0} = 27.5691 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 26.4840 - 26.4840) * (1.0000 * 1.2500 - 1.00 * 1.0332) - 2 * 0.6870 * (1.0000 * 1.2500 - 1.00 * 1.0332) * (1 - 0.8550), 0]
= 5.6985 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(12.0000, 2.9675) * [min(0.6870, 26.4840 - 0.5 * 26.4840) - 0.2854] * 0.8550, 0} = 2.0379 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(15.0000, 1.7175) * min(0.6870, 26.4840 - 0.5 * 26.4840) * 0.8550, 0} = 2.0177 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A42 = f r4 [L422 - (L42 - L42pareff)
2 - (L42 - L42noreff)2] =
1.0000 * [0.53572 - (0.5357 - 0.5357)2 - (0.5357 - 0.5357)2] = 0.2870 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(42.0000 , 2 * 26.4840) - 26.4840 - 2 * 0.6870] * min (1.2500, 2.9675) * 1.0000, 0} = 17.6775 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 27.9367 sq. in., which is >= A (27.5691)
DesignCalcs version: 2015.0 CEI 2015Page 6 of 90
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Nozzle 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: N1ID Number: 1
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.6870 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3571 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 1.2500 = 0.7500 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.7500 + 0.0000
0.7 = 0.5357 in.
Weld 42, actual weld leg = 0.5357 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.6870 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3571 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 23.3130 * 0.6870 * 11970 = 301000 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112800 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112700 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 42.0000 * 0.5357 * 9800 = 346200 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.
DesignCalcs version: 2015.0 CEI 2015Page 7 of 90
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Nozzle 1Job No: Example Vessel Number: Saddle
Number: 1 Mark Number: N1ID Number: 1
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [27.5691 - 5.6985 + 2 * 0.6870 * 0.8550 * (1.00 * 1.2500 - 1.00 * 1.0332)] * 20000 = 442500 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (2.0379 + 17.6775 + 0.1091 + 0.2870) * 20000 = 402200 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (2.0379 + 2.0177 + 0.1091 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 114800 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (2.0379 + 2.0177 + 17.6775 + 0.1091 + 0.2870 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 474100 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 346200 + 301000 = 647200 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 112800 + 596000 + 596000 + 112700 = 1417500 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 346200 + 112700 + 596000 = 1054900 lb.
Plate Strength = A5 * Sp = 17.6775 * 20000 = 353550 lb.
Outer fillet weld strength(346200) is less than plate strength(353550).
DesignCalcs version: 2015.0 CEI 2015Page 8 of 90
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Nozzle 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-53 Gr. S/B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 12.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 7.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 24 Nozzle Pipe Schedule: 40Nozzle ID (new): 22.6260 in. Nozzle Wall Thickness(new): 0.6870 in.
Nozzle ID (corroded): 22.6260 in. Nozzle Wall Thickness(corroded): 0.6870 in.Developed Opening: 23.6419 in. Tangential Dimension L: 24.0000 in.
External Limit of Reinforcement: 2.8125 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal Limit of Reinforcement: 1.7175 in. Internal Weld Leg Size(Weld 43): 0.3750 in.
Parallel Limit of Reinf (2Lpar): 47.2838 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: C Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
Reinforcing Pad Information
Reinforcing Material: SA-515 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 1.2500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.OD, Reinforcing Plate(Dp): 42.0000 in. Repad to Nozzle Groove Weld Depth: 1.2500 in.
Host Component: Head 2 - Head 2
Material: SA-515 Gr. 70 Head wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Head wall thickness - thin out (corroded): 1.1250 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal Weld Leg Size(Weld 43): 0.3750 in.
Nozzle Wall Thickness(tn): 0.6870 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.
Repad Thickness(te): 1.2500 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 24 Schedule: 40
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 9 of 90
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Nozzle 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 08/10/2015
Required Head Thickness per Paragraph UG-37(a)
tr = P K1 D
(2SE - 0.2P) =
425.00 * 0.9000 * 96.0000
(2 * 20000 * 1 - 0.2 * 425.00) = 0.9200 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 11.3130
17100 * 1 - 0.6 * 425.00 = 0.2854 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 11.3130
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.2854 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = P K D
(2SE - 0.2P) + Ca + ext. Ca =
425.00 * 1.0000 * 96.0000
(2 * 20000 * 1 - 0.2 * 425.00) + 0.0000 + 0.0000 = 1.0222 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3280 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3280 in.
tUG-45 = max( ta, tb ) = 0.3280 in.
Wall thickness = tn * 0.875(pipe) = 0.6010 is greater than or equal to UG-45 value of 0.3280
DesignCalcs version: 2015.0 CEI 2015Page 10 of 90
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Nozzle 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(23.6419, 11.3130 + 1.1250 + 0.6870) = 23.6419 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.1250, 2.5 * 0.6870 + 1.2500) = 2.8125 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.1250, 2.5 * 0.6870) = 1.7175 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [23.6419 * 0.9200 * 1.00 + 2 * 0.6870 * 0.9200 * 1.00 * (1 - 0.8550)], 0} = 21.9339 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 23.6419 - 23.6419) * (1.0000 * 1.1250 - 1.00 * 0.9200) - 2 * 0.6870 * (1.0000 * 1.1250 - 1.00 * 0.9200) * (1 - 0.8550), 0]
= 4.8057 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(12.0000, 2.8125) * [min(0.6870, 23.6419 - 0.5 * 23.6419) - 0.2854] * 0.8550, 0} = 1.9314 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(7.0000, 1.7175) * min(0.6870, 23.6419 - 0.5 * 23.6419) * 0.8550, 0} = 2.0177 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A42 = f r4 [L422 - (L42 - L42pareff)
2 - (L42 - L42noreff)2] =
1.0000 * [0.62502 - (0.6250 - 0.6250)2 - (0.6250 - 0.6250)2] = 0.3906 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(42.0000 , 2 * 23.6419) - 23.6419 - 2 * 0.6870] * min (1.2500, 2.8125) * 1.0000, 0} = 21.2301 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 30.6161 sq. in., which is >= A (21.9339)
DesignCalcs version: 2015.0 CEI 2015Page 11 of 90
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Nozzle 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.6870 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3750 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 1.2500 = 0.7500 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.7500 + 0.0000
0.7 = 0.5357 in.
Weld 42, actual weld leg = 0.6250 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.6870 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3750 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 23.3130 * 0.6870 * 11970 = 301000 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 24.0000 * 0.3750 * 8379 = 118400 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 24.0000 * 0.3750 * 8379 = 118400 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 42.0000 * 0.6250 * 9800 = 403900 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.
DesignCalcs version: 2015.0 CEI 2015Page 12 of 90
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Nozzle 2Job No: Example Vessel Number: Saddle
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [21.9339 - 4.8057 + 2 * 0.6870 * 0.8550 * (1.00 * 1.1250 - 1.00 * 0.9200)] * 20000 = 347400 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (1.9314 + 21.2301 + 0.1202 + 0.3906) * 20000 = 473400 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (1.9314 + 2.0177 + 0.1202 + 0.1202 + 2 * 0.6870 * 1.1250 * 0.8550) * 20000 = 110200 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (1.9314 + 2.0177 + 21.2301 + 0.1202 + 0.3906 + 0.1202 + 2 * 0.6870 * 1.1250 * 0.8550) * 20000 = 542600 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 403900 + 301000 = 704900 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 118400 + 596000 + 596000 + 118400 = 1428800 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 403900 + 118400 + 596000 = 1118300 lb.
Plate Strength = A5 * Sp = 21.2301 * 20000 = 424602 lb.
Outer fillet weld strength(403900) is less than plate strength(424602).
DesignCalcs version: 2015.0 CEI 2015Page 13 of 90
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Nozzle 3Job No: Example Vessel Number: Saddle
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-53 Gr. S/B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 12.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 5.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 24 Nozzle Pipe Schedule: 40Nozzle ID (new): 22.6260 in. Nozzle Wall Thickness(new): 0.6870 in.
Nozzle ID (corroded): 22.6260 in. Nozzle Wall Thickness(corroded): 0.6870 in.External Limit of Reinforcement: 2.9675 in. Upper Weld Leg Size(Weld 41): 0.3571 in.Internal Limit of Reinforcement: 1.7175 in. Internal Weld Leg Size(Weld 43): 0.3571 in.
Parallel Limit of Reinf (2Lpar): 45.2520 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: C Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 1.2500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.OD, Reinforcing Plate(Dp): 42.0000 in. Repad to Nozzle Groove Weld Depth: 1.2500 in.
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3571 in.
Internal Weld Leg Size(Weld 43): 0.3571 in.
Nozzle Wall Thickness(tn): 0.6870 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.
Repad Thickness(te): 1.2500 in.
Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 24 Schedule: 40
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 14 of 90
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Nozzle 3Job No: Example Vessel Number: Saddle
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 11.3130
17100 * 1 - 0.6 * 425.00 = 0.2854 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 11.3130
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.2854 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3280 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3280 in.
tUG-45 = max( ta, tb ) = 0.3280 in.
Wall thickness = tn * 0.875(pipe) = 0.6010 is greater than or equal to UG-45 value of 0.3280
DesignCalcs version: 2015.0 CEI 2015Page 15 of 90
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Nozzle 3Job No: Example Vessel Number: Saddle
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(22.6260, 11.3130 + 1.2500 + 0.6870) = 22.6260 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.2500, 2.5 * 0.6870 + 1.2500) = 2.9675 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.2500, 2.5 * 0.6870) = 1.7175 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [22.6260 * 1.0332 * 1.00 + 2 * 0.6870 * 1.0332 * 1.00 * (1 - 0.8550)], 0} = 23.5830 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 22.6260 - 22.6260) * (1.0000 * 1.2500 - 1.00 * 1.0332) - 2 * 0.6870 * (1.0000 * 1.2500 - 1.00 * 1.0332) * (1 - 0.8550), 0]
= 4.8621 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(12.0000, 2.9675) * [min(0.6870, 22.6260 - 0.5 * 22.6260) - 0.2854] * 0.8550, 0} = 2.0379 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(5.0000, 1.7175) * min(0.6870, 22.6260 - 0.5 * 22.6260) * 0.8550, 0} = 2.0177 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A42 = f r4 [L422 - (L42 - L42pareff)
2 - (L42 - L42noreff)2] =
1.0000 * [0.53572 - (0.5357 - 0.5357)2 - (0.5357 - 0.5357)2] = 0.2870 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(42.0000 , 2 * 22.6260) - 22.6260 - 2 * 0.6870] * min (1.2500, 2.9675) * 1.0000, 0} = 22.5000 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 31.9228 sq. in., which is >= A (23.5830)
DesignCalcs version: 2015.0 CEI 2015Page 16 of 90
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Nozzle 3Job No: Example Vessel Number: Saddle
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.6870 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3571 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 1.2500 = 0.7500 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.7500 + 0.0000
0.7 = 0.5357 in.
Weld 42, actual weld leg = 0.5357 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.6870 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3571 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 23.3130 * 0.6870 * 11970 = 301000 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112800 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112700 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 42.0000 * 0.5357 * 9800 = 346200 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.
DesignCalcs version: 2015.0 CEI 2015Page 17 of 90
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Nozzle 3Job No: Example Vessel Number: Saddle
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [23.5830 - 4.8621 + 2 * 0.6870 * 0.8550 * (1.00 * 1.2500 - 1.00 * 1.0332)] * 20000 = 379500 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (2.0379 + 22.5000 + 0.1091 + 0.2870) * 20000 = 498700 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (2.0379 + 2.0177 + 0.1091 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 114800 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (2.0379 + 2.0177 + 22.5000 + 0.1091 + 0.2870 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 570600 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 346200 + 301000 = 647200 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 112800 + 596000 + 596000 + 112700 = 1417500 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 346200 + 112700 + 596000 = 1054900 lb.
Plate Strength = A5 * Sp = 22.5000 * 20000 = 450000 lb.
Outer fillet weld strength(346200) is less than plate strength(450000).
DesignCalcs version: 2015.0 CEI 2015Page 18 of 90
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Nozzle 4Job No: Example Vessel Number: Saddle
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-53 Gr. S/B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 12.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 5.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 24 Nozzle Pipe Schedule: 40Nozzle ID (new): 22.6260 in. Nozzle Wall Thickness(new): 0.6870 in.
Nozzle ID (corroded): 22.6260 in. Nozzle Wall Thickness(corroded): 0.6870 in.External Limit of Reinforcement: 2.9675 in. Upper Weld Leg Size(Weld 41): 0.3571 in.Internal Limit of Reinforcement: 1.7175 in. Internal Weld Leg Size(Weld 43): 0.3571 in.
Parallel Limit of Reinf (2Lpar): 45.2520 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 1.2500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.OD, Reinforcing Plate(Dp): 42.0000 in. Repad to Nozzle Groove Weld Depth: 1.2500 in.
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3571 in.
Internal Weld Leg Size(Weld 43): 0.3571 in.
Nozzle Wall Thickness(tn): 0.6870 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.5357 in.
Repad Thickness(te): 1.2500 in.
Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 24 Schedule: 40
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 19 of 90
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Nozzle 4Job No: Example Vessel Number: Saddle
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 11.3130
17100 * 1 - 0.6 * 425.00 = 0.2854 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 11.3130
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.2854 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3280 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3280 in.
tUG-45 = max( ta, tb ) = 0.3280 in.
Wall thickness = tn * 0.875(pipe) = 0.6010 is greater than or equal to UG-45 value of 0.3280
DesignCalcs version: 2015.0 CEI 2015Page 20 of 90
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Nozzle 4Job No: Example Vessel Number: Saddle
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(22.6260, 11.3130 + 1.2500 + 0.6870) = 22.6260 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.2500, 2.5 * 0.6870 + 1.2500) = 2.9675 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.2500, 2.5 * 0.6870) = 1.7175 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [22.6260 * 1.0332 * 1.00 + 2 * 0.6870 * 1.0332 * 1.00 * (1 - 0.8550)], 0} = 23.5830 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 22.6260 - 22.6260) * (1.0000 * 1.2500 - 1.00 * 1.0332) - 2 * 0.6870 * (1.0000 * 1.2500 - 1.00 * 1.0332) * (1 - 0.8550), 0]
= 4.8621 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(12.0000, 2.9675) * [min(0.6870, 22.6260 - 0.5 * 22.6260) - 0.2854] * 0.8550, 0} = 2.0379 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(5.0000, 1.7175) * min(0.6870, 22.6260 - 0.5 * 22.6260) * 0.8550, 0} = 2.0177 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A42 = f r4 [L422 - (L42 - L42pareff)
2 - (L42 - L42noreff)2] =
1.0000 * [0.53572 - (0.5357 - 0.5357)2 - (0.5357 - 0.5357)2] = 0.2870 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.35712 - (0.3571 - 0.3571)2 - (0.3571 - 0.3571)2] = 0.1091 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(42.0000 , 2 * 22.6260) - 22.6260 - 2 * 0.6870] * min (1.2500, 2.9675) * 1.0000, 0} = 22.5000 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 31.9228 sq. in., which is >= A (23.5830)
DesignCalcs version: 2015.0 CEI 2015Page 21 of 90
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Nozzle 4Job No: Example Vessel Number: Saddle
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.6870 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3571 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 1.2500 = 0.7500 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.7500 + 0.0000
0.7 = 0.5357 in.
Weld 42, actual weld leg = 0.5357 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.6870 = 0.6870 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.6870 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3571 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 23.3130 * 0.6870 * 11970 = 301000 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112800 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 24.0000 * 0.3571 * 8379 = 112700 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 42.0000 * 0.5357 * 9800 = 346200 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 24.0000 * 1.2500 * 12654 = 596000 lb.
DesignCalcs version: 2015.0 CEI 2015Page 22 of 90
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Nozzle 4Job No: Example Vessel Number: Saddle
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [23.5830 - 4.8621 + 2 * 0.6870 * 0.8550 * (1.00 * 1.2500 - 1.00 * 1.0332)] * 20000 = 379500 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (2.0379 + 22.5000 + 0.1091 + 0.2870) * 20000 = 498700 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (2.0379 + 2.0177 + 0.1091 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 114800 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (2.0379 + 2.0177 + 22.5000 + 0.1091 + 0.2870 + 0.1091 + 2 * 0.6870 * 1.2500 * 0.8550) * 20000 = 570600 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 346200 + 301000 = 647200 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 112800 + 596000 + 596000 + 112700 = 1417500 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 346200 + 112700 + 596000 = 1054900 lb.
Plate Strength = A5 * Sp = 22.5000 * 20000 = 450000 lb.
Outer fillet weld strength(346200) is less than plate strength(450000).
DesignCalcs version: 2015.0 CEI 2015Page 23 of 90
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Nozzle 5Job No: Example Vessel Number: Saddle
Number: 5 Mark Number: N5ID Number: 5
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 70 %
Nozzle Material: SA-53 Gr. S/B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 10.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 5.5000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 18 Nozzle Pipe Schedule: 60Nozzle ID (new): 16.5000 in. Nozzle Wall Thickness(new): 0.7500 in.
Nozzle ID (corroded): 16.5000 in. Nozzle Wall Thickness(corroded): 0.7500 in.Developed Opening: 17.4799 in. Tangential Dimension L: 27.0000 in.
External Limit of Reinforcement: 2.8125 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal Limit of Reinforcement: 1.8750 in. Internal Weld Leg Size(Weld 43): 0.3750 in.
Parallel Limit of Reinf (2Lpar): 34.9597 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
Reinforcing Pad Information
Reinforcing Material: SA-515 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 1.2500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.OD, Reinforcing Plate(Dp): 42.0000 in. Repad to Nozzle Groove Weld Depth: 1.2500 in.
Host Component: Head 1 - Head 1
Material: SA-515 Gr. 70 Head wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Head wall thickness - thin out (corroded): 1.1250 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal Weld Leg Size(Weld 43): 0.3750 in.
Nozzle Wall Thickness(tn): 0.7500 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.
Repad Thickness(te): 1.2500 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 18 Schedule: 60
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 24 of 90
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Nozzle 5Job No: Example Vessel Number: Saddle
Number: 5 Mark Number: N5ID Number: 5
Date Printed: 08/10/2015
Required Head Thickness per Paragraph UG-37(a)
tr = P K1 D
(2SE - 0.2P) =
425.00 * 0.9000 * 96.0000
(2 * 20000 * 1 - 0.2 * 425.00) = 0.9200 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 8.2500
17100 * 1 - 0.6 * 425.00 = 0.2081 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 8.2500
17100 * 0.70 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.2993 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = P K D
(2SE - 0.2P) + Ca + ext. Ca =
425.00 * 1.0000 * 96.0000
(2 * 20000 * 1 - 0.2 * 425.00) + 0.0000 + 0.0000 = 1.0222 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3280 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3280 in.
tUG-45 = max( ta, tb ) = 0.3280 in.
Wall thickness = tn * 0.875(pipe) = 0.6560 is greater than or equal to UG-45 value of 0.3280
DesignCalcs version: 2015.0 CEI 2015Page 25 of 90
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Nozzle 5Job No: Example Vessel Number: Saddle
Number: 5 Mark Number: N5ID Number: 5
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(17.4799, 8.2500 + 1.1250 + 0.7500) = 17.4799 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.1250, 2.5 * 0.7500 + 1.2500) = 2.8125 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.1250, 2.5 * 0.7500) = 1.8750 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [17.4799 * 0.9200 * 1.00 + 2 * 0.7500 * 0.9200 * 1.00 * (1 - 0.8550)], 0} = 16.2816 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 17.4799 - 17.4799) * (1.0000 * 1.1250 - 1.00 * 0.9200) - 2 * 0.7500 * (1.0000 * 1.1250 - 1.00 * 0.9200) * (1 - 0.8550), 0]
= 3.5388 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(10.0000, 2.8125) * [min(0.7500, 17.4799 - 0.5 * 17.4799) - 0.2081] * 0.8550, 0} = 2.6062 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(5.5000, 1.8750) * min(0.7500, 17.4799 - 0.5 * 17.4799) * 0.8550, 0} = 2.4047 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A42 = f r4 L42pareff L42noreff = 1.0000 * 0.0000 * 0.6250 = 0.0000 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(42.0000 , 2 * 17.4799) - 17.4799 - 2 * 0.7500] * min (1.2500, 2.8125) * 1.0000, 0} = 19.9748 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 28.7650 sq. in., which is >= A (16.2816)
DesignCalcs version: 2015.0 CEI 2015Page 26 of 90
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Nozzle 5Job No: Example Vessel Number: Saddle
Number: 5 Mark Number: N5ID Number: 5
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 1.2500, or 0.7500 = 0.7500 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.7500 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3750 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 1.2500 = 0.7500 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.7500 + 0.0000
0.7 = 0.5357 in.
Weld 42, actual weld leg = 0.6250 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.7500 = 0.7500 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.7500 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3750 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 17.2500 * 0.7500 * 11970 = 243100 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 18.0000 * 0.3750 * 8379 = 88800 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 18.0000 * 1.2500 * 12654 = 447000 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 18.0000 * 0.3750 * 8379 = 88800 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 42.0000 * 0.6250 * 9800 = 403900 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 18.0000 * 1.2500 * 12654 = 447000 lb.
DesignCalcs version: 2015.0 CEI 2015Page 27 of 90
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Nozzle 5Job No: Example Vessel Number: Saddle
Number: 5 Mark Number: N5ID Number: 5
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [16.2816 - 3.5388 + 2 * 0.7500 * 0.8550 * (1.00 * 1.1250 - 1.00 * 0.9200)] * 20000 = 260100 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (2.6062 + 19.9748 + 0.1202 + 0.0000) * 20000 = 454000 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (2.6062 + 2.4047 + 0.1202 + 0.1202 + 2 * 0.7500 * 1.1250 * 0.8550) * 20000 = 133900 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (2.6062 + 2.4047 + 19.9748 + 0.1202 + 0.0000 + 0.1202 + 2 * 0.7500 * 1.1250 * 0.8550) * 20000 = 533400 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 403900 + 243100 = 647000 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 88800 + 447000 + 447000 + 88800 = 1071600 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 403900 + 88800 + 447000 = 939700 lb.
Plate Strength = A5 * Sp = 19.9748 * 20000 = 399497 lb.
Outer fillet weld strength(403900) is greater than plate strength(399497).
DesignCalcs version: 2015.0 CEI 2015Page 28 of 90
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Threaded Coupling - 1"Job No: Example Vessel Number: Saddle
Number: 6 Mark Number: 9cID Number: 9c
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 70 %
Nozzle Material: SA-105 Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 5.0000 in. Allowable Stress at Design Temperature (Sn): 20000 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 20000 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle ID (new): 1.3300 in. Nozzle Wall Thickness(new): 0.2175 in.Nozzle ID (corroded): 1.3300 in. Nozzle Wall Thickness(corroded): 0.2175 in.
External Limit of Reinforcement: 0.5437 in. Upper Weld Leg Size(Weld 41): 0.2175 in.Internal Limit of Reinforcement: 0.5437 in. Internal Weld Leg Size(Weld 43): 0.0000 in.
Parallel Limit of Reinf (2Lpar): 4.2650 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -155 F
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.2175 in.
Nozzle Wall Thickness(tn): 0.2175 in.
Outside Groove Weld Depth: 1.2500 in.
Nozzle passes through the vessel, attached by a groove weld.Nozzle is adequate for UG-45 requirements.
Opening is adequately reinforced for Internal Pressure.Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 29 of 90
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Threaded Coupling - 1"Job No: Example Vessel Number: Saddle
Number: 6 Mark Number: 9cID Number: 9c
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 0.6650
20000 * 1 - 0.6 * 425.00 = 0.0143 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000 fr2 = min
Sn
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 0.6650
20000 * 0.70 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0206 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.1270 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.1270 in.
tUG-45 = max( ta, tb ) = 0.1270 in.
Wall thickness = tn = 0.2180 is greater than or equal to UG-45 value of 0.1270
DesignCalcs version: 2015.0 CEI 2015Page 30 of 90
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Threaded Coupling - 1"Job No: Example Vessel Number: Saddle
Number: 7 Mark Number: 9dID Number: 9d
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 70 %
Nozzle Material: SA-105 Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 5.0000 in. Allowable Stress at Design Temperature (Sn): 20000 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 20000 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle ID (new): 1.3300 in. Nozzle Wall Thickness(new): 0.2175 in.Nozzle ID (corroded): 1.3300 in. Nozzle Wall Thickness(corroded): 0.2175 in.
External Limit of Reinforcement: 0.5437 in. Upper Weld Leg Size(Weld 41): 0.2175 in.Internal Limit of Reinforcement: 0.5437 in. Internal Weld Leg Size(Weld 43): 0.0000 in.
Parallel Limit of Reinf (2Lpar): 4.2650 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -155 F
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.2175 in.
Nozzle Wall Thickness(tn): 0.2175 in.
Outside Groove Weld Depth: 1.2500 in.
Nozzle passes through the vessel, attached by a groove weld.Nozzle is adequate for UG-45 requirements.
Opening is adequately reinforced for Internal Pressure.Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 31 of 90
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Threaded Coupling - 1"Job No: Example Vessel Number: Saddle
Number: 7 Mark Number: 9dID Number: 9d
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 0.6650
20000 * 1 - 0.6 * 425.00 = 0.0143 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000 fr2 = min
Sn
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 0.6650
20000 * 0.70 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0206 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.1270 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.1270 in.
tUG-45 = max( ta, tb ) = 0.1270 in.
Wall thickness = tn = 0.2180 is greater than or equal to UG-45 value of 0.1270
DesignCalcs version: 2015.0 CEI 2015Page 32 of 90
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Nozzle 8Job No: Example Vessel Number: Saddle
Number: 8 Mark Number: BID Number: B
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 70 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 8.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 2 Nozzle Pipe Schedule: XHNozzle ID (new): 1.9390 in. Nozzle Wall Thickness(new): 0.2180 in.
Nozzle ID (corroded): 1.9390 in. Nozzle Wall Thickness(corroded): 0.2180 in.Developed Opening: 2.2392 in. Tangential Dimension L: 24.2583 in.
External Limit of Reinforcement: 0.5450 in. Upper Weld Leg Size(Weld 41): 0.2180 in.Internal Limit of Reinforcement: 0.5450 in. Internal Weld Leg Size(Weld 43): 0.2180 in.
Parallel Limit of Reinf (2Lpar): 4.8750 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -155 F
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.2180 in.
Internal Weld Leg Size(Weld 43): 0.2180 in.
Nozzle Wall Thickness(tn): 0.2180 in.
Outside Groove Weld Depth: 1.2500 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 2 Schedule: XH
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 33 of 90
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Nozzle 8Job No: Example Vessel Number: Saddle
Number: 8 Mark Number: BID Number: B
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 0.9695
17100 * 1 - 0.6 * 425.00 = 0.0245 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 0.9695
17100 * 0.70 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0352 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.1350 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.1350 in.
tUG-45 = max( ta, tb ) = 0.1350 in.
Wall thickness = tn * 0.875(pipe) = 0.1910 is greater than or equal to UG-45 value of 0.1350
DesignCalcs version: 2015.0 CEI 2015Page 34 of 90
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Nozzle 9Job No: Example Vessel Number: Saddle
Number: 9 Mark Number: AID Number: A
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 8.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 4 Nozzle Pipe Schedule: 160Nozzle ID (new): 3.4380 in. Nozzle Wall Thickness(new): 0.5310 in.
Nozzle ID (corroded): 3.4380 in. Nozzle Wall Thickness(corroded): 0.5310 in.Developed Opening: 3.9710 in. Tangential Dimension L: 24.2583 in.
External Limit of Reinforcement: 1.9525 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal Limit of Reinforcement: 1.3275 in. Internal Weld Leg Size(Weld 43): 0.3750 in.
Parallel Limit of Reinf (2Lpar): 7.9420 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -135 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 0.6250 in. Repad to Vessel Weld Leg Size(Weld 42): 0.5000 in.OD, Reinforcing Plate(Dp): 6.0000 in. Repad to Nozzle Groove Weld Depth: 0.6250 in.
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal Weld Leg Size(Weld 43): 0.3750 in.
Nozzle Wall Thickness(tn): 0.5310 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.5000 in.
Repad Thickness(te): 0.6250 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 4 Schedule: 160
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 35 of 90
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Nozzle 9Job No: Example Vessel Number: Saddle
Number: 9 Mark Number: AID Number: A
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 1.7190
17100 * 1 - 0.6 * 425.00 = 0.0434 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 1.7190
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0434 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.2070 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.2070 in.
tUG-45 = max( ta, tb ) = 0.2070 in.
Wall thickness = tn * 0.875(pipe) = 0.4650 is greater than or equal to UG-45 value of 0.2070
DesignCalcs version: 2015.0 CEI 2015Page 36 of 90
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Nozzle 9Job No: Example Vessel Number: Saddle
Number: 9 Mark Number: AID Number: A
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(3.9710, 1.7190 + 1.2500 + 0.5310) = 3.9710 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.2500, 2.5 * 0.5310 + 0.6250) = 1.9525 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.2500, 2.5 * 0.5310) = 1.3275 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [3.9710 * 1.0332 * 1.00 + 2 * 0.5310 * 1.0332 * 1.00 * (1 - 0.8550)], 0} = 4.2619 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 3.9710 - 3.9710) * (1.0000 * 1.2500 - 1.00 * 1.0332) - 2 * 0.5310 * (1.0000 * 1.2500 - 1.00 * 1.0332) * (1 - 0.8550), 0]
= 0.8275 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(8.0000, 1.9525) * [min(0.5310, 3.9710 - 0.5 * 3.9710) - 0.0434] * 0.8550, 0} = 1.6280 sq. in.
A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) f r2, 0} = max{2 * min(2.0000, 1.3275) * min(0.5310, 3.9710 - 0.5 * 3.9710) * 0.8550, 0} = 1.2054 sq. in.
A41 = f r3 [L412 - (L41 - L41pareff)
2 - (L41 - L41noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A42 = f r4 [L422 - (L42 - L42pareff)
2 - (L42 - L42noreff)2] =
1.0000 * [0.50002 - (0.5000 - 0.5000)2 - (0.5000 - 0.5000)2] = 0.2500 sq. in.
A43 = f r2 [L432 - (L43 - L43pareff)
2 - (L43 - L43noreff)2] =
0.8550 * [0.37502 - (0.3750 - 0.3750)2 - (0.3750 - 0.3750)2] = 0.1202 sq. in.
A5 = max{C [min(Dp , 2 Lpar) - d - 2 t n] min(te, Lnoro) fr4, 0} = max{1 * [min(6.0000 , 2 * 3.9710) - 3.9710 - 2 * 0.5310] * min (0.6250, 1.9525) * 1.0000, 0} = 0.6044 sq. in.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 4.7557 sq. in., which is >= A (4.2619)
DesignCalcs version: 2015.0 CEI 2015Page 37 of 90
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Nozzle 9Job No: Example Vessel Number: Saddle
Number: 9 Mark Number: AID Number: A
Date Printed: 08/10/2015
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 0.6250, or 0.5310 = 0.5310 in.
Weld 41 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
(smaller of 0.25 or (0.5310 * 0.7)) + 0
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 41, actual weld leg = 0.3750 in.
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.2500, or 0.6250 = 0.6250 in.
Weld 42 Leg min. = 0.5 * tmin + ext. CA
0.7 =
0.5 * 0.6250 + 0.0000
0.7 = 0.4464 in.
Weld 42, actual weld leg = 0.5000 in.
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.2500, or 0.5310 = 0.5310 in.
Weld 43 Leg min. = (smaller of 0.25 or (tmin * 0.7)) + ca
0.7 =
(smaller of 0.25 or (0.5310 * 0.7)) + 0.0000
0.7 =
0.2500
0.7 = 0.3571 in.
Weld 43, actual weld leg = 0.3750 in.
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PSIUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSIInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PSIOuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 20000 = 9800 PSIRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 PSI
Strength of Connection ElementsNozzle wall in shear = * m * mean nozzle diameter * tn * Nozzle wall in shear unit stress = * m * 3.9690 * 0.5310 * 11970 = 39600 lb.Upper fillet in shear = * m * Nozzle OD * weld leg * upper fillet in shear unit stress = * m * 4.5000 * 0.3750 * 8379 = 22200 lb.Groove Weld in Tension = * m * Nozzle OD * groove depth * groove weld tension unit stress = * m * 4.5000 * 1.2500 * 12654 = 111800 lb.Inner fillet in shear = * m * Nozzle OD * weld leg * inner fillet in shear unit stress = * m * 4.5000 * 0.3750 * 8379 = 22200 lb.Outer fillet in shear = * m * Plate OD * weld leg * outer fillet in shear unit stress = * m * 6.0000 * 0.5000 * 9800 = 46200 lb.Repad groove weld = * m * Nozzle OD * Groove Depth * repad groove weld in tension unit stress = * m * 4.5000 * 0.6250 * 12654 = 55900 lb.
DesignCalcs version: 2015.0 CEI 2015Page 38 of 90
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Nozzle 9Job No: Example Vessel Number: Saddle
Number: 9 Mark Number: AID Number: A
Date Printed: 08/10/2015
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [4.2619 - 0.8275 + 2 * 0.5310 * 0.8550 * (1.00 * 1.2500 - 1.00 * 1.0332)] * 20000 = 72600 lb.W1-1 = (A2 + A5 + A41 + A42) * Sv = (1.6280 + 0.6044 + 0.1202 + 0.2500) * 20000 = 52100 lb.W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (1.6280 + 1.2054 + 0.1202 + 0.1202 + 2 * 0.5310 * 1.2500 * 0.8550) * 20000 = 84200 lb.W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv = (1.6280 + 1.2054 + 0.6044 + 0.1202 + 0.2500 + 0.1202 + 2 * 0.5310 * 1.2500 * 0.8550) * 20000 = 101300 lb.
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 46200 + 39600 = 85800 lb.Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear = 22200 + 55900 + 111800 + 22200 = 212100 lb.Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 46200 + 22200 + 111800 = 180200 lb.
Plate Strength = A5 * Sp = 0.6044 * 20000 = 12088 lb.
Outer fillet weld strength(46200) is greater than plate strength(12088).
DesignCalcs version: 2015.0 CEI 2015Page 39 of 90
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Nozzle 11Job No: Example Vessel Number: Saddle
Number: 11 Mark Number: DID Number: D
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 70 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 8.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 2 Nozzle Pipe Schedule: XHNozzle ID (new): 1.9390 in. Nozzle Wall Thickness(new): 0.2180 in.
Nozzle ID (corroded): 1.9390 in. Nozzle Wall Thickness(corroded): 0.2180 in.Developed Opening: 2.2392 in. Tangential Dimension L: 24.2583 in.
External Limit of Reinforcement: 0.5450 in. Upper Weld Leg Size(Weld 41): 0.2180 in.Internal Limit of Reinforcement: 0.5450 in. Internal Weld Leg Size(Weld 43): 0.2180 in.
Parallel Limit of Reinf (2Lpar): 4.8750 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -155 F
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.2180 in.
Internal Weld Leg Size(Weld 43): 0.2180 in.
Nozzle Wall Thickness(tn): 0.2180 in.
Outside Groove Weld Depth: 1.2500 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 2 Schedule: XH
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 40 of 90
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Nozzle 11Job No: Example Vessel Number: Saddle
Number: 11 Mark Number: DID Number: D
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 0.9695
17100 * 1 - 0.6 * 425.00 = 0.0245 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 0.9695
17100 * 0.70 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0352 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.1350 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.1350 in.
tUG-45 = max( ta, tb ) = 0.1350 in.
Wall thickness = tn * 0.875(pipe) = 0.1910 is greater than or equal to UG-45 value of 0.1350
DesignCalcs version: 2015.0 CEI 2015Page 41 of 90
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Nozzle 10Job No: Example Vessel Number: Saddle
Number: 10 Mark Number: CID Number: C
Date Printed: 08/10/2015
Nozzle Design Information
Design Pressure: 425.00 PSI Design Temperature: 100 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 8.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI
Inside Corrosion Allowance: 0.0000 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 4 Nozzle Pipe Schedule: 160Nozzle ID (new): 3.4380 in. Nozzle Wall Thickness(new): 0.5310 in.
Nozzle ID (corroded): 3.4380 in. Nozzle Wall Thickness(corroded): 0.5310 in.Developed Opening: 3.9570 in. Tangential Dimension L: 24.0000 in.
External Limit of Reinforcement: 1.9525 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal Limit of Reinforcement: 1.3275 in. Internal Weld Leg Size(Weld 43): 0.3750 in.
Parallel Limit of Reinf (2Lpar): 7.9140 in. Outside Groove Weld Depth: 1.2500 in.Minimum Design Metal Temperature
Min. Temp. Curve: Pressure at MDMT: 425.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -109 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 20000 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 0.6250 in. Repad to Vessel Weld Leg Size(Weld 42): 0.5000 in.OD, Reinforcing Plate(Dp): 6.0000 in. Repad to Nozzle Groove Weld Depth: 0.6250 in.
Host Component: Shell 1 - Shell 1
Material: SA-515 Gr. 70 Shell wall thickness(new): 1.2500 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 1.2500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal Weld Leg Size(Weld 43): 0.3750 in.
Nozzle Wall Thickness(tn): 0.5310 in.
Outside Groove Weld Depth: 1.2500 in.
Repad to Vessel Weld Leg Size(Weld 42): 0.5000 in.
Repad Thickness(te): 0.6250 in.
tangential to the vessel wall, attached by a groove weld.Pipe Size: 4 Schedule: 160
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.
Weld Strength Paths are adequate.
DesignCalcs version: 2015.0 CEI 2015Page 42 of 90
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Nozzle 10Job No: Example Vessel Number: Saddle
Number: 10 Mark Number: CID Number: C
Date Printed: 08/10/2015
Required Shell Thickness per Paragraph UG-37(a)
tr = PR
SE - 0.6P =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 = 1.0332 in.
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn = PRn
SE - 0.6P =
425.00 * 1.7190
17100 * 1 - 0.6 * 425.00 = 0.0434 in.
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr2 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550
fr3 = min
Sn
Sv, 1.0000
= min
17100
20000, 1.0000
= 0.8550 fr4 = min
Sp
Sv, 1.0000
= min
20000
20000, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion)
ta = PRn
SE - 0.6P + Ca + ext. Ca =
425.00 * 1.7190
17100 * 1.00 - 0.6 * 425.00 + 0.0000 + 0.0000 = 0.0434 in.
Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host
tb1 = PR
SE - 0.6P + Ca + ext. Ca =
425.00 * 48.0000
20000 * 1 - 0.6 * 425.00 + 0.0000 + 0.0000 = 1.0332 in.
Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.2070 in.
Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.2070 in.
tUG-45 = max( ta, tb ) = 0.2070 in.
Wall thickness = tn * 0.875(pipe) = 0.4650 is greater than or equal to UG-45 value of 0.2070
DesignCalcs version: 2015.0 CEI 2015Page 43 of 90
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Nozzle 10Job No: Example Vessel Number: Saddle
Number: 10 Mark Number: CID Number: C
Date Printed: 08/10/2015
Limits of Reinforcement (UG-40)
Lpar = max(d, Rn + t + tn) = max(3.9570, 1.7190 + 1.2500 + 0.5310) = 3.9570 in.Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 1.2500, 2.5 * 0.5310 + 0.6250) = 1.9525 in.Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 1.2500, 2.5 * 0.5310) = 1.3275 in.
Nozzle Reinforcement Calculations (Internal Pressure)
A = max{C [d t r F + 2 t n tr F (1 - f r1)], 0} = max{1.0000 * [3.9570 * 1.0332 * 1.00 + 2 * 0.5310 * 1.0332 * 1.00 * (1 - 0.8550)], 0} = 4.2475 sq. in.
A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn (E1 t - F tr) (1 - f r1), 0] =max[(2 * 3.9570 - 3.9570) * (1.0000 * 1.2500 - 1.00 * 1.0332) - 2 * 0.5310 * (1.0000 * 1.2500 - 1.00 * 1.0332) * (1 - 0.8550), 0]
= 0.8245 sq. in.
A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - t rn] fr2, 0} = max{2 * min(8.0000, 1.9525) * [min(0.5310, 3.9570 - 0.5 * 3.9570) - 0.0434] * 0.8550, 0} = 1.6280 sq. in.
A3 = max{2 min(h, Lnori) min(ti