EXAMPLE 2
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EXAMPLE 2 Solve for unknown measures
Algebra The base of a triangle is twice its height. The area of the triangle is 36 square inches. Find the base and height.
36 = h2
Write formula.
Substitute 36 for A and 2h for b.
Simplify.
Let h represent the height of the triangle. Then the base is 2h.
36 = (2h)(h)21
A = bh21
6 = h Find positive square root of each side.
The height of the triangle is 6 inches, and the base is 6 2 = 12 inches.
ANSWER
![Page 2: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/2.jpg)
EXAMPLE 3Solve a multi-step problem
Painting
You can use a right triangle and a rectangle to approximate the area of the side of the barn.
SOLUTION
You need to buy paint so that you can paint the side of a barn. A gallon of paint covers 350 square feet. How many gallons should you buy?
![Page 3: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/3.jpg)
EXAMPLE 3Solve a multi-step problem
338 = x Solve for the positive value of x.
Find the approximate area of the side of the barn.
STEP 1 Find the length x of each leg of the triangle.
262 = x2 + x2
676 = 2x2
Use Pythagorean Theorem.
Simplify.
STEP 2
Area = Area of rectangle + Area of triangle
= 26(18) + 12
(338 ) (338 ) = 637 ft2
![Page 4: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/4.jpg)
EXAMPLE 3Solve a multi-step problem
STEP 3
Determine how many gallons of paint you need.
Use unit analysis.
Round up so you will have enough paint. You need to buy 2 gallons of paint.
637 ft2 1.82 gal
350 ft2 1 gal
![Page 5: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/5.jpg)
GUIDED PRACTICE for Examples 2 and 3
A parallelogram has an area of 153 square inches and a height of 17 inches. What is the length of the base?
4.
Let the length of the base be x
SOLUTION
A = b h
153 = x 17
x = 9
Write formula.
Substitute 153 for A and 17 for h and x for b.
Simplify.
ANSWER
Length of the base is 9 in.
![Page 6: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/6.jpg)
GUIDED PRACTICE for Examples 2 and 3
WHAT IF? In Example 3, suppose there is a 5 foot by 10 foot rectangular window on the side of the barn. What is the approximate area you need to paint?
5.
SOLUTION
You can use a right triangle and a rectangle to approximate the area of the side of the barn.
STEP 1 Find the length x of each leg of the triangle.
262 = x2 + x2
676 = 2x2
Use Pythagorean Theorem.
Simplify.
338 = x Solve for the positive value of x.
![Page 7: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/7.jpg)
GUIDED PRACTICE for Examples 2 and 3
Find the approximate area of the side of the barn.
STEP 2
Area = Area of rectangle + Area of triangle
2 (338 ) (338 )= 26(18) + 1
STEP 3 Find the area of window.
Write formula.
Substitute.
A = l b
= 5 10
Multiply.
= 637 ft2
= 50 ft2
![Page 8: EXAMPLE 2](https://reader035.fdocuments.in/reader035/viewer/2022072013/56812b45550346895d8f5d1b/html5/thumbnails/8.jpg)
GUIDED PRACTICE for Examples 2 and 3
STEP 4 Find the approximate area you need to paint.
Area of side of barn – Area of window
= 637 – 50
= 587
ANSWER
You need to paint an approximate area of 587 ft2.