2

2

2 4

80.005 0.02

eq

P

LL QH f K f Q

D D D g

2

20.025 20 10P

m LH m

segL

seg

3 2

100101.325 2.35 1.6

13 10

1200 9.81D

KPaKPa bar KPa

barNPSH m m

kg m m seg

3 3

2

2

. (1000 )(1.2) 1200LR L H O R

H O

kg m kg m

A SUP VD S p

P P PNPSH H H

g

15.434DNPSH mcl

15.434 2

D RNPSH NPSH

mcl mcl

UNIVERSIDAD CATOLICA DE SANTA MARIA

PROGRAMA PROFESIONAL DE INGENIERIA MECANICA, MECANICA-ELECTRICA Y MECATRONICA

SEGUNDA EVALUACION DE TURBOMAQUINAS-CICLO 2013

Apellidos y Nombres:__________________________________________________________________________

Código:________________________

PROBLEMA 1:

( no existe cavitación! )

1W

1U

1 1mC C

11

2W

2U

2

2mC

2

2C

2UC 2

2tan

mC

0.5m

300mmHg

19mca

0.225AD m0.2ID m

2

2

2

0.3

0.025

1320

22

HID MAN

D m

b m

N rpm

2 2 2 2

2 2

m m

QQ D b C C

D b

22 2 2

2 2 2 2tan tan

mU

C QC U U

D b

2

2 2 1 1 2 2 2 2

2 2 2tan

U U UEULER

C U C U C U U UH Q

g g g g D b

22

(0.3 )(1320 )20.734

60 60

D N m rpmU m seg

2 2

2

I A I AUTIL I A

P P V VH Z Z

g

UTIL HID EULERH H

2

4I

I

QV

D

2

4A

A

QV

D

2 2

2 2

1 4 4

2

I AUTIL I A

I A

P P Q QH Z Z

g D D

2

4 4 2

1 1 80I A

UTIL I A

I A

P PQ H Z Z

D D g

22 2 2

4 4 2

2 2 2

1 1 80

tan

HID HID I AI A

I A

U U P PQ Q Z Z

D D g g D b g

10.33300 4.0776

760A

mcaP mmHg mca

mmHg

2

2

2 2

20.734 0.8 0.8 20.73419.40207 19 4.0776 0.5 0

9.81 0.3 0.025 tan 22 9.81

m seg Q m segQ m m m

m seg m m m seg

PROBLEMA 2:

Reemplazando datos:

219.40207 177.6165 11.4804 0Q Q

30.064186Q m seg

3

22 2

2

0.06418620.734 13.9915

tan 0.3 0.025 tan 22

mU

C m segC U m seg m seg

m m

2 2

2

13.9915 20.73429.5718

9.81

UEULER

m seg m segC UH m

g m seg

0.8 29.5718 23.657UTIL HID EULERH H m m

3 31000 0.064186 23.65714.887

102 102

UTILUTIL

Kgf m m seg mQHP KW

PROBLEMA 3: