Ex_2_2_FSC_part2
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Exercise 2.2 (Solutions) Calculus and Analytic Geometry, MATHEMATICS 12
Available online @ http://www.mathcity.org, Version: 1.0.0
Question # 1 (i) Let ( )3y ax b= +
( )3( )y y a x x bd d + = + + ( )3y ax b a x yd d = + + -
( )3 3( ) ( )ax b a x ax bd= + + - + 3 2 2 3 3( ) 3( ) ( ) 3( )( ) ( ) ( )ax b ax b a x ax b a x a x ax bd d d = + + + + + + - +
2 2 2 3 33 ( ) 3 ( )a ax b x a ax b x a xd d d= + + + + ( )2 2 3 23 ( ) 3 ( )x a ax b a ax b x a xd d d= + + + +
Dividing by xd
2 2 3 23 ( ) 3 ( )y a ax b a ax b x a xx
dd d
d= + + + +
Taking limit as 0xd 2 2 3 2
0 0lim lim 3 ( ) 3 ( )x x
y a ax b a ax b x a xxd d
dd d
d = + + + +
2 2 3 23 ( ) 3 ( )(0) (0)dy a ax b a ax b adx
= + + + +
23 ( ) 0 0dy a ax bdx
= + + + 23 ( )dy a ax bdx
= +
Question # 1 (ii) Let 5(2 3)y x= +
( )( )52 3y y x xd d + = + + ( )52 2 3y x x yd d = + + -
( )5 5(2 3) 2 (2 3)x x xd= + + - +
5 4 3 25 5 5(2 3) (2 3) (2 ) (2 3) (2 ) ....0 1 2x x x x xd d = + + + + + +
5 55... (2 ) (2 3)5 x xd + - +
( ) 5 4 3 25 51 (2 3) 2 (2 3) 4 (2 3) ....1 2x x x x xd d = + + + + + +
5 55... 32 (2 3)5 x xd + - +
4 3 2 55 5 52 (2 3) 4 (2 3) .... 321 2 5x x x x xd d d = + + + + +
Dividing by xd
4 3 45 5 52 (2 3) 4 (2 3) .... 321 2 5y x x x xx
dd d
d = + + + + +
Taking limit as 0xd 4 3 4
0 0
5 5 5lim lim 2 (2 3) 4 (2 3) .... 321 2 5x xy x x x xxd d
d d dd
= + + + + +
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FSc-II / Ex- 2.2 - 2
452 (2 3) 0 0 .... 01dy xdx
= + + + + +
42(5)(2 3)dy xdx
= + or 410(2 3)dy xdx
= +
Question # 1 (iii) Let ( ) 13 2y t -= +
( ) 23( ) 2y y t td d - + = + + ( ) 23 3 2y t t yd d - = + + - ( ) ( )2 2(3 2) 3 3 2y t t td d - - = + + - +
( )2
2 33 2 1 13 2
tttd -- = + + - +
( ) ( )2
2 2 2 13 33 2 1 ( 2) .... 13 2 2! 3 2
t ttt td d- - - - = + + - + + - + +
( ) ( )2
2 2 363 2 1 .... 13 2 2 3 2
t ty tt td d
d - - - = + - + - + - + +
( )2
2 6 33 2 3 ....3 2 3 2
t ttt td d- = + - + - + + +
( ) 1 3 33 2 2 3 ....3 2 3 2
t ttt td d- = + - + - + + +
Dividing by td
( ) 2 1 33 3 2 2 ....3 2
y ttt t
d dd
- - = + - + - + +
Taking limit when 0td , we have
( ) 30 0
3lim lim 3 3 2 2 ....3 2t t
y ttt td d
d dd
-
= + - + - +
( ) [ ]33 3 2 2 0 0 ....dy tdx
- = + - + - + ( ) 36 3 2dy tdx
- = - +
Question # 1 (iv) Let 5( )y ax b -= +
Do yourself
Question # 1 (vii)
Let 71
( )y
az b=
- 7( )az b -= -
( ) 7( )y y a z z bd d - + = + - ( ) ( )7 7( )y az b a z az bd d - - = - + - -
( )7
7 1 1( )
a zy az baz b
dd-
- = - + - -
Now do yourself
Made by: Atiq ur Rehman ([email protected]), http://www.mathcity.org