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Transcript of Ex 3.4 (Www.urdulovers123.Blogspot.com)
7/26/2019 Ex 3.4 (Www.urdulovers123.Blogspot.com)
http://slidepdf.com/reader/full/ex-34-wwwurdulovers123blogspotcom 1/8
Edited ByAdnan Shafique Exercise 3.4 (Solutions)
Integration by PartsIf u and v are function of , then
( )uv dx u vdx vdx u dx¢= - ×ò òò òQuestion # 1(i)
Let sin I x x dx= ò Integration by parts
( cos ) ( cos ) (1) I x x x dx= × - - - ×òcos cos x x x dx= - + òcos sin x x x c= - + +
Question # 1(ii)
Let ln I x dx= òln 1 x dx= ×ò
Integrating by parts
1ln I x x x dx
x= × - ×ò
ln x dx= - òln x x c= - +
Question # 1(iii)Let ln I x x dx= ò
Integrating by parts2 2 1
ln2 2
x x I x dx= × - ×ò
21
ln2 2
x x dx= - ò
2 21
ln2 2 2
x xc= - × +
2
1ln2 2
x cæ ö= - +ç ÷è ø
Question # 1(iv)
Let 2 ln I x x dx= ò Do yourself
Question # 1(v)
Let 3 ln I x x dx= ò Do yourself
Question # 1(vi)
Let 4 ln I x x dx= ò Do yourself
Question # 1(vii)
Let 1tan I x dx-= ò1tan 1 x dx-= ×ò
Integrating by parts
1
2
1tan
1
I x x x dx-= × - ×
+ò
1
2
1 2tan
2 1
x x dx
x
-= -+ò
2
1
2
(1 )1tan
2 1
d xdx x dx
-+
= -+ò
1 21tan ln 1
2 x x c
-= - + +
Question # 1(viii)
Let 2 sin I x x dx= òIntegrating by parts
2 ( cos ) ( cos ) 2 I x x x x dx= - - - ×ò2 cos 2 cos x x x x dx= - + ò
Again integrating by parts
( )2 cos 2 sin sin (1) I x x x x x dx= - + - ò 2 cos 2 sin 2( cos ) x x x x x c= - + - - +
2 cos 2 sin 2cos x x x x x c= - + + +
Question # 1(ix)
Let 2 1tan I x x dx-= òIntegrating by parts
3 31
2
1tan
3 3 1
x x I x dx
x
-= × - ×+ò
3 31
2
1tan
3 3 1
x x x dx
-= -+ò
31
2
1tan
3 3 1
x x x x dx
x
- æ ö= - -ç ÷+è øò
31
2
1 1tan
3 3 3 1
x x x x dx dx
x
-= - + -+ò ò
3 21
2
1 1 1 2tan
3 3 2 3 2 1
x x x x dx
x
-= - × + - ×
+ò2
3 21
2
(1 )1tan
3 6 6 1
d x x x dx x dx-
+= - + -
+ò3 2
1 21tan ln 1
3 6 6
x x x x c-= - + - + +
Question # 1(x)
Let 1tan I x x dx-= òIntegrating by parts
2 2
1
21tan
2 2 1 x x I x dx
x-= - ×
+ò2 2
1
2
1tan
2 2 1
x xdx
x
-= -+ò
2 21
2
1 1 1tan
2 2 1
x xdx
x
- + -= -
+ò2 2
1
2 2
1 1 1tan
2 2 1 1
x xdx
x x
- æ ö+= - -ç ÷+ +è ø
ò2
1
2
1 1tan 1
2 2 1
xdx
x
- æ ö= - -ç ÷+è øò
u x=sinv x=
lnu xv x
==
2
lnu x
v x
==
3lnu x
v x
==
4
lnu x
v x
==
1tan1
u xv
-==
2u x=
sinv x=
cosu xv x==
1
2
tanu x
v x
-==
1tanu xv x
-==
ln1
u xv
==
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7/26/2019 Ex 3.4 (Www.urdulovers123.Blogspot.com)
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FSc-II Ex- 3.4 -
21
2
1 1 1tan
2 2 2 1
xdx dx
x
-= - ++ò ò
21 11 1
tan tan2 2 2
x x x c- -= - + + Ans.
Question # 1(xi)
Let 3 1tan I x x dx-=
ò Integrating by parts4 4
1
2
1tan
4 4 1
x x I x dx-= × - ×
+ò
4 4
1
2
1tan
4 4 1
x xdx
x
-= - -+ò
41
2
2
tan4
1 11
4 1
x x
x dx x
-=
æ ö- - +ç ÷+è øò
4
1 2
2
1 1 1 1tan
4 4 4 4 1
x x dx dx dx
x
-= - + -+ò ò ò
4 31 11 1 1
tan tan4 4 3 4 4
x x x x c- -= - + - +
4 31 11 1
tan tan4 12 4 4
x x x x c- -= - + - +
Question # 1(xii)
Let 3 cos I x x dx= ò
Do yourself as Question # 1(viii). Integrate by parts three times.
Question # 1(xiii)1sin I x dx-= ò1sin 1 x dx-= ×ò
Integrating by parts
1
2
1sin
1 I x x x dx
x
-= × - ×-
ò1
1 2 2
sin (1 ) ( ) x x x x dx
--
= - -ò 11 2 21
sin (1 ) ( 2 )2
x x x x dx--= + - -ò
11 2 221
sin (1 ) (1 )2
d x x x x dx
dx
--= + - -ò1
12 21 (1 )1
sin12
12
x x x c
- +
- -= + +
- +
12 2
1 (1 )1
sin 122
x
x x c
- -= + +
1 2sin 1 x x x c-= + - +
Question # 1(xiv)
Let 1sin I x x dx-= ò Integrating by parts
2 21
2
1sin
2 2 1
x x I x dx
x
-= × - ×-
ò
2 21
2
1sin2 2 1
x x x dx
x
- -
= + -ò
2 21
2
1 1 1sin
2 2 1
x x x dx
x
- - -= +
-ò
2 21
2 2
1 1 1sin
2 2 1 1
x x x dx
x x
- æ ö-= + -ç ÷
- -è øò
21 2
2
1 1
sin 12 2 1
x
x x dx x
- æ ö
= + - -ç ÷-è øò
21 2
2
1 1 1sin 1
2 2 2 1
x x x dx dx
x
-= + - --
ò ò2
1 1
1
1 1sin sin
2 2 2
x I x I x- -Þ = + - ….. (i)
Where 21 1 I x dx= -ò
Put sin x q = cosdx d q q Þ =
21 1 sin cos I d q q q Þ = -ò
2cos cos d q q q = ò
2cos d q q = ò 1 cos 2
2 d
q q
+æ ö= ç ÷è øò
( )1
1 cos 22
d q q = +ò
1 sin 2
2 2 c
q q
é ù= + +ê úë û
1 2sin cos
2 2 c
q q q
é ù= + +ê úë û
21sin 1 sin
2 cq q q é ù= + - +ê úë û
1 21sin 1
2 x x c-é ù= + - +ê úë û
Using value of 1 I in ( )i
( )2
1 1 2
1
1 1sin sin 1
2 2 2
1sin
2
x I x x x x c- -
-
é ù= + + - +ê úë û
-
2
1 1 2
1
1 1 1sin sin 12 4 4 2
1sin
2
x x x x x c
x
- -
-
= + + - +
-
21 1 21 1 1
sin sin 12 4 4 2
x I x x x x c- -Þ = - + - +
Question # 1(xv)
Let sin cos x I e x x dx= ò1
2 sin cos2
xe x x dx= ×ò
1sin 2
2 x
e x dx= ò sin 2 2 sin cos x x x=Q
Integrating by parts
1 cos 2 cos 2
2 2 2 x x x x
I e e dx- -é ù= × - ×ê úë ûò
1 1cos 2 cos 2
4 4 x x
e x e x dx= - + òAgain integrating by parts
1 1 sin 2 sin 2cos2
4 4 2 2 x x x x x
I e x e eæ ö= - + × -ç ÷è øò
1sinu x-=v x=
xu e=
sin2v x=
2
2 4
4 2
2
2
1
1
1
1
x
x x
x x
x
x
- -
+ +
-
+
+
-
- -
3
cosu xv x
==
1
3
tanu x
v x
-=
=
1sin1
u xv
-==
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FSc-II Ex- 3.4 -
1 1 sin 2 1cos 2 sin 2
4 4 2 2 x x x x
e x e e xæ ö= - + × -ç ÷è øò
1 1 sin 2
cos24 4 2
x x xe x e I c
æ ö= - + × - +ç ÷è ø
1 1 1
cos 2 sin 24 8 4
x xe x e x I c= - + - +
1 1 1cos 2 sin 2
4 4 8 x x I I e x e x cÞ + = - + +
5 1 1cos 2 sin 2
4 4 8 x x I e x e x cÞ = - + +
1 1 4cos 2 sin 2
5 10 5 x x I e x e x cÞ = - + +
Question # 1(xvi)
Let sin cos I x x x dx= ò1
2 sin cos2 x x dx= ×
ò1sin2
2 x dx= ×ò
Integrating by parts
1 cos 2 cos 2(1)
2 2 2
x x I x dx
é - - ùæ ö æ ö= -ç ÷ ç ÷ê úè ø è øë ûò
Now do yourself
Question # 1(xvii)
Let 2cos I x x dx= ò1 cos 2
2 x dx+æ ö= ç ÷
è øò
( )1
1 cos 22
x x dx= +ò1 1
cos22 2
dx x xdx= +ò ò
21 1 sin 2 sin 2
(1)2 2 2 2 2
x x xdx
é ù= × + - ×ê úë ûò2
1 1sin 2 sin 2
4 4 4
x x x dx= + × - ò
2 1 1 cos 2
sin24 4 4 2
x x x c
-æ ö= + × - +ç ÷è ø
2 1 1sin 2 cos 2
4 4 8
x x x c= + × + +
Question # 1(xviii)
Let 2sin I x x dx= ò1 cos 2
2
x x dx
-æ ö= ç ÷è øò ( )
11 cos 2
2 x x dx= -ò
1 1 cos22 2
x dx x x dx= -ò ò
Integrating by parts21 1 sin 2 sin 2
.(1)2 2 2 2 2
x x x I x dx
é ù= - × -ê úë ûò2 1 1
sin 2 sin 24 4 4
x x x dx= - + ò
2 1 1 cos 2
sin 24 4 4 2
x x x c
-æ ö= - + +ç ÷è ø
2 1 1
sin 2 cos 24 4 8
x
x x c= - - +
Question # 1(xix)
Let 2(ln ) I x dx= ò( )
2ln 1 x dx= ×ò
Integrating by parts
( ) ( )2 1
ln 2 ln I x x x x dx
x
= × - × ×
ò( ) ( )2
ln 2 ln x x x dx= - ò Again integrating by parts
( )2 1
ln 2 ln I x x x x x dx x
é ù= - × - ×ê úë ûò
( )2
ln 2 ln 2 x x x x dx= - + ò( )
2ln 2 ln 2 x x x x x c= - + +
Question # 1(xx)
Let 2ln(tan ) sec I x x dx= òIntegrating by parts
21ln(tan ) tan tan sec
tan I x x x x dx
x= × - × ×ò
( ) 2tan ln tan sec x x x dx= - ò( )tan ln tan tan x x x c= - +
Question # 1(xxi)
Let1
2
sin
1
x x I dx
x
-
=
-
ò
1
2
1sin ( )
1 x x dx
x
-= ×-
ò
( )1
1 2 21sin 1 ( 2 )
2 x x x dx
--= - × - -òIntegrating by parts
112 2
1
1
12 2
2
(1 )1sin
121
2
(1 ) 1
1 112
x I x
xdx
x
- +
-
- +
é-ê
= - ×ê- +êë
ù- ú- × ú
-- + úû
ò
12 2
1
12 2
2
(1 )1sin
12
2
(1 ) 1
1 12
x x
xdx
x
-
é-ê
= - ×êêë
ù- ú
- × ú- úû
ò
12 12
12(1 ) sin 2
2 x dx-é ù
= - - -ê úë û
ò2 11 sin x x dx-= - - + ò
2 11 sin x x x c-= - - + +
2 11 sin x x x c-= - - +
Question # 2(i)
Let 4tan I xdx= ò2 2tan tan x x dx= ×ò
sin2u xv x
==
cos2u xv x
==
cos2u xv x==
( )2
ln1
u xv
==
2ln(tan )secu xv x
==
( )
1
22
1
1 ( 2 )
sin
x x
u x
v -
-
- -
=
=
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FSc-II Ex- 3.4 -
( )2 2tan sec 1 x dx= -ò( )2 2 2tan sec tan x x dx= -ò
2 2 2tan sec tan x dx x dx= -ò ò2 2tan (tan ) (sec 1)
d x dx x dx
dx= - -ò ò
2 12tan sec
2 1 x x dx dx
+= - -
+ ò ò31
tan tan3
x x c= - - +
Question # 2(ii)
Let 4sec I x dx= ò2 2(sec ) (sec ) x dx= ×ò
2 2(1 tan ) (sec ) x dx= + ×ò2 2 2sec tan secdx x x dx= +ò ò
2tan (tan ) (tan )d
x x dxdx
= + ò
3tan
tan3
xc= + +
Question # 2(iii)
Let sin2 cos x I e x x dx= ò
( )1
2 sin 2 cos2
xe x x dx= ò
( )1sin(2 ) sin(2 )
2 xe x x x x dx= + + -ò
( )1
sin 3 sin2
xe x x dx= +ò1 1
sin 3 sin2 2
x xe x dx e x dx= +ò ò
1 2
1 1
2 2 I I = + ………. (i)
Where 1 sin3 x I e x dx= ò and 2 sin x I e x dx= òSolve 1 I and 2 I as in Q # 1(xv) and put value of
1 I and 2 I in ( )i .
Question # 2(iv)3tan sec I x x dx= ×ò
2tan tan sec x x dx= × ×ò( )2sec 1 sec tan x x dx= - ×ò
Put sect x= sec tandt x x dxÞ =
So ( )2 1 I t dt = -ò3
3t t c= - +
3sec
sec3
xc= - +
Question # 2(v)
Let 3 5 x I x e dx= òIntegrating by parts
5 53 23
5 5
x xe e I x x dx= × - ×ò
3 5 2 51 3
5 5 x x x e x e dx= - ò
Again integrating by parts5 5
3 5 21 32
5 5 5 5
x x x e e
I x e x x dxé ù
= - × - ×ê úë û
ò
3 5 2 5 51 3 6
5 25 25
x x x x e x e x e dx= - +
òAgain integrating by parts
3 5 2 5
5 5
1 3
5 256
(1)25 5 5
x x
x x
I x e x e
e edx
= -
é ù+ × - ×ê ú
ë ûò
3 5 2 5 5 51 3 6 6
5 25 125 125 x x x x x e x e xe e dx= - + - ò
53 5 2 5 51 3 6 6
5 25 125 125 5
x x x x e
x e x e xe c= - + - × +
53 23 6 6
5 5 25 125
x
e x x x cæ ö= - + - +ç ÷è ø
Question 2(vi)
Let sin 2 x I e x dx-= òIntegrating by parts
cos 2 cos 2( 1)
2 2 x x x x
I e e dx- -- -= × - × -ò
1 1cos 2 cos 2
2 2 x xe x e x dx- -= - - ò
Again integrating by parts1 1 sin 2
cos22 2 2
sin2( 1)
2
x x
x
x I e x e
xe dx
- -
-
é= - - ×êëù- × - úûò
1 1 1
cos 2 sin 2 sin 22 4 4
x x xe x e x e x dx- - -= - - - ò
1 1 1
cos 2 sin 22 4 4
x x I e x e x I c- -Þ = - - - +
1 1 1cos 2 sin 2
4 2 4 x x I I e x e x c- -Þ + = - - +
5 1 1cos 2 sin 2
4 2 4 x x I e x e x c- -Þ = - - +
2 1 4
cos 2 sin 25 5 5
x x I e x e x c- -Þ = - - +
( )1 4
2cos 2 sin 25 5
xe x x c-= - + +
Question # 2(vii)
Let 2 cos3 x I e x dx= ×ò Do yourself as above
Question # 2(viii)3cosec I x dx= ò
2cosec cosec x dx= ×òIntegrating by parts
( ) ( )( )csc cot cot csc cot I x x i x x x dx= - - -ò2cosec cot cosec cot x x x x dx= - - ò
( )2cosec cot cosec cosec 1 x x x x dx= - - -ò
( )3cosec cot cosec cosec x x x x dx= - - -ò
3
x
u x
v e
==
2
x
u x
v e
==
sin2
xu ev x
-==
2cosec
cosec
u x
v x
==
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FSc-II Ex- 3.4 -
3cosec cot cosec cosec x x x dx x dx= - - +ò òcosec cot ln cosec cot x I x x c= - - + - +
cosec cot ln cosec cot I I x x x x cÞ + = - + - +
2 cosec cot ln cosec cot I x x x x cÞ = - + - +
1 1 1
csc cot ln csc cot2 2 2 I x x x x cÞ = - + - +
Question # 3
Let sinax I e bx dx= òIntegrating by parts
cos cos( )
ax axbx bx I e e a dx
b b
æ ö æ ö= - - - ×ç ÷ ç ÷è ø è øò
coscos
axaxe bx a
e bx dxb b
= - + òAgain integrating by parts
cos sin sinaxax axe bx a bx bx
I e e a dxb b b b
é ù= - + - ×ê úë ûò
2
2 2
cossin sin
axax axe bx a a
e bx e bx dxb b b
= - + - ò
2
12 2
cossin
axaxe bx a a
e bx I cb b b
= - + - +
2
12 2
cossin
axaxa e bx a
I I e bx cbb b
Þ + = - + +
( )
2 2
12 2cos sin
axb a e
I b bx a bx cb b
æ ö+Þ = - + +
ç ÷è ø
( ) ( )2 2 2
1sin cosax
b a I e a bx b bx b cÞ + = - +
Put cosa r q = & sinb r q =
Squaring and adding
( )2 2 2 2 2cos sina b r q q + = +
2 2 2 (1)a b r Þ + = 2 2r a bÞ = +
Also
sin
cos
b r
a r
q
q = tan
b
a q Þ =
1tan b
aq
-Þ =
So
( ) )(2 2
2
1
cos sin sin cosaxb a I e r bx r bx
b c
q q + = -
+
( ) )(2 2
2
1
sin cos cos sinaxb a I e r bx bx
b c
q q + = -
+
( ) ( )2 2 2
1sinax
a b I e r bx b cq Þ + = - +
Putting value of r and q
( )2 2 2 2 1 2
1sin tanax b
a b I e a b bx b ca
-æ ö+ = + - +ç ÷è ø
2 2 21
12 2 2 2sin tan
( )
axa b b b I e bx c
aa b a b
-+ æ öÞ = - +ç ÷+ +è ø
1
2 2
1sin tan
ax b I e bx c
aa b
-æ öÞ = - +ç ÷è ø+
Where2
12 2
bc c
a b=
+
Question # 4(i)
Let 2 2 I a x dx= -ò2 2 1a x dx= - ×ò
Integrating by parts
( ) ( )1
2 2 2 2 212
2 I a x x x a x x dx
-= - × - × - × -
ò
( )
22 2
12 2 2
xa x dx
a x
-= - -
-ò
( )
2 2 22 2
12 2 2
a x aa x dx
a x
- -= - -
-ò
( ) ( )
2 2 22 2
1 12 2 2 22 2
a x a x a x dx
a x a x
æ öç ÷-
= - - -ç ÷ç ÷- -è ø
ò
2
2 2 2 2
2 2
aa x a x dx dx
a x= - - - +
-ò ò
2 2 2
2 2
1 I x a x I a dx
a xÞ = - - +
-ò
2 2 2 1 x I I x a x a Sin ca
-Þ + = - + +
2 2 2 12 x
I x a x a Sin ca
-Þ = - + +
2 2 2 11 1 1
2 2 2
x I x a x a Sin ca
-
Þ = - + +
Review
2 2
2 2ln
dx x x a c
x a· = + - +
-ò
2 2
2 2ln
dx x a c
x a· = + + +
+ò
Question # 4(ii)
Let 2 2 I x a dx= -ò2 2 1a dx= - ×ò
Integrating by parts
( ) ( )1
2 2 2 2 212
2 I x a x x x a x dx
-= - × - × - ×ò
( )
22 2
12 2 2
x x x a dx
x a
= - -
-ò
( )
2 2 22 2
1
2 2 2
x a a x x a dx
x a
- += - -
-
ò
( ) ( )
2 2 22 2
1 12 2 2 22 2
x a a x x a dx
x a x a
æ öç ÷-
= - - +ç ÷ç ÷- -è ø
ò
2
2 2 2 2
2 2
a x x a x a dx dx
x a= - - - -
-ò ò
2 2 2
2 2
1 I x x a I a dx
x aÞ = - - -
-ò
2 2
1u a xv
= -=
sin
axu ev bx
==
2 2
1u x av
= -
=
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FSc-II Ex- 3.4 -
2 2 2 2 2ln I I x x a a x x a cÞ + = - - + - +
2 2
2 2ln
dx x x a c
x a= + - +
-òQ
2 2 2 2 22 ln I x x a a x x a cÞ = - - + - +
22 2 2 21 1ln
2 2 2a I x x a x x a cÞ = - - + - +
Question # 4(iii)
Let 24 5 I x dx= -ò24 5 1 dx= - ×ò
Integrating by parts1
2 2 214 5 (4 5 ) ( 10 )
2 I x x x x x dx
-= - × - × - × -ò
2
2254 5
(4 5 ) x x dx x-= - × - -ò
22
2
4 5 44 5
(4 5 )
x x dx
x
- -= - × -
-ò
22
1 12 22 2
4 5 44 5
(4 5 ) (4 5 )
x x x dx
x x
æ ö-ç ÷= - × - -
ç ÷ç ÷- -è øò
12 2 2
12
2
44 5 (4 5 )
(4 5 )
x x dx
x
æ öç ÷= - × - - -ç ÷ç ÷
-è ø
ò
2 2
2
14 5 4 5 4
4 5 x x x dx dx
x= - × - - +
-ò ò
2
2
14 5 4
45
5
I x x I dx
x
Þ = - × - +æ ö-ç ÷è ø
ò
2
2
14 5 4
45
5
I I x x dx
x
Þ + = - × +
-ò
2
2
2
4 12 4 55 2
5
I x x dx
x
Þ = - × +æ ö
-ç ÷è ø
ò
2 1
1
44 5
5 2 5
x x x Sin c
- æ ö= - × + +ç ÷
è ø
1
2 2
dx xSin
aa x
-=-
òQ
2 1
1
54 14 5
2 2 22 5
x x I x Sin c- æ ö
Þ = - + +ç ÷
è ø
2 1 524 5
2 25
x x x Sin c
- æ ö= - + +ç ÷
è ø
Where 1
1
2c c=
Question # 4(iv)
Let 23 4 I x dx= -òSame as above.
Question # 4(v)Same as Q # 4(ii)
Use 2
2ln 4
4
dx x c
x= + + +
+ò
Question # 4(vi)
Let
2 ax
I x e dx= ò Do yourself as Question # 2(v)
Important Formula
Since ( )( ) ( ) ( )ax ax axd d d e f x e f x f x e
dx dx dx= +
( ) ( ) ( )ax axe f x f x e a¢= + ×
[ ]( ) ( )axe a f x f x¢= +
On integrating
( ) [ ]( ) ( ) ( )ax axd
e f x dx e a f x f x dxdx
¢= +
ò ò[ ]( ) ( ) ( )ax axe f x e a f x f x dx¢Þ = +ò [ ]( ) ( ) ( )ax axe a f x f x dx e f x c¢Þ + = +ò
Question # 5(i)
Let1
ln x I e x dx x
æ ö= +ç ÷
è øò1
ln xe x dx x
æ ö= +ç ÷è øò
Put ( ) ln f x x= 1
( ) f x¢Þ =
So ( )( ) ( ) x I e f x f x dx¢= +ò ( ) xe f x c= + ln xe x c= +
Question # 5(ii)
Let ( )cos sin x I e x x dx= +ò( )sin cos xe x x dx= +ò
Put ( ) sin f x x= ( ) cos f x x¢Þ =
So ( )( ) ( ) x I e f x f x dx¢= +ò ( ) xe f x c= +
sin xe x c= +
Question # 5(iii)
Let 1
2
1sec
1
ax I e a x dx x x
-é ù= +ê ú
-ë ûò
Put 1( ) sec f x x-= 2
1( )
1
f x
x x
¢Þ =
-So [ ]( ) ( )ax I e a f x f x dx¢= +ò
( )axe f x c= + 1secaxe x c-= +
Question # 5(iv)
Let 3
2
3sin cos
sin
x x x I e dx
x
-æ ö= ç ÷è øò
3
2 2
3sin cos
sin sin
x x xe dx
x x
æ ö= -ç ÷
è ø
ò
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FSc-II Ex- 3.4 -
3 1 cos3
sin sin sin x x
e dx x x x
æ ö= -ç ÷×è øò
( )3 3csc csc cot xe x x x dx= -òPut ( ) csc f x x= ( ) csc cot f x x x¢Þ = -
( )3 3 ( ) ( ) x I e f x f x dx¢Þ = +ò 3 ( ) xe f x c= + 3 csc xe x c= +
Question 5(v)
Let ( )2 sin 2cos x I e x x dx= - +ò *Correction
( )2 2cos sin xe x x dx= -òPut ( ) cos f x x= ( ) sin f x x¢Þ = -
So ( )2 2 ( ) ( ) x I e f x f x dx¢= +ò 2 ( ) xe f x c= +
2 cos xe x c= +
Question # 5(vi)
Let( )
21
x xe
I dx x
=+
ò
2
(1 1)
(1 )
x x edx
x
+ -=
+ò
2 2
1 1
(1 ) (1 )
x xe dx
x x
é ù+= -ê ú+ +
ë û
ò
2
1 1
(1 ) (1 )
xe dx x x
é ù= -ê ú+ +ë û
ò
Put 11( ) (1 )
1 f x x
x-= = +
+
2
2
1( ) (1 )
(1 ) f x x
-¢Þ = - + = -+
So ( )( ) ( ) x I e f x f x dx¢= +ò ( ) xe f x c= +
1
1 xe c
xæ ö= +ç ÷+è ø
Question # 5(vii)
Let ( )cos sin x I e x x dx-= -ò( )( 1)sin cos xe x x dx-= - +ò
Put ( ) sin f x x= '( ) cos f x xÞ =
So ( )( 1) ( ) ( ) x I e f x f x dx- ¢= - +ò ( ) xe f x c-= +
sin xe x c-= +
Question # 5(viii)
Let
1
2
tan
1
m xe
I dx x
-
=+ò
1
2
tan 1
1
m xe dx-
= ×+ò
Put 1tant x-= 2
1
1dt dx
xÞ =
+
Somt
I e dt = ò
mt ec
m= +
1tan1 m xe cm
-= +
Important Integral
Let tan I x dx= òsin
cos
xdx
x= ò
Put cost x= sindt x dxÞ = -
sindt x dxÞ - =
Sodt
I t
-= ò
dt
t = -ò
ln t c= - +
ln cos x c= - +
1ln cos x c-= + ln ln mm x x=Q
1
lncos
c x
= + ln sec x c= +
tan ln sec x dx x cÞ = +òSimilarly, we have
cot ln sin x dx x c= +ò
Question # 5(ix)
Let 21 sin
x I dx x
=-ò
2 1 sin
1 sin 1 sin
xdx
x
+= ×
- +ò
2
2 (1 sin )
1 sin
x xdx
x
+=
-ò
2
2 2 sin )
cos
x x xdx
x
+= ò
2 2
2 2 sin
cos cos
x x xdx
x x
æ ö= +ç ÷
è øò
2
2 2 sincos coscos
x x xdx dx x x x
= +×ò ò
22 sec 2 sec tan x x dx x x x dx= +ò òIntegrating by parts
2 tan tan 1
2 sec sec (1)
I x x x dx
x x dx
é ù= × - ×ë ûé ù+ × -ë û
òò
2 tan ln sec
2 sec ln sec tan
x x x
x x x c
= é × - ùë û+ é × - + ù +ë û
2 tan 2ln sec2 sec 2ln sec tan
x x x x x x c
= -+ - + +
Question # 5(x)
Let2
(1 )
(2 )
xe x I dx
x
+=
+ò
2
(2 1)
(2 )
xe xdx
x
+ -=
+ò
2 2
2 1
(2 ) (2 )
x xe dx
x x
æ ö+= -ç ÷
+ +è ø
ò
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FSc-II Ex- 3.4 -
( )1 2(2 ) (2 ) xe x x dx- -= + - +òPut 1( ) (2 ) f x x -= + 2( ) (2 ) f x x -¢Þ = - +
So ( )( ) ( ) x I e f x f x dx¢= +ò ( ) xe f x c= +
1(2 ) xe x c-= + +
2
xe
c x
= ++
Question # 15(xi)
Let1 sin
1 cos x x
I e dx x
-æ ö= ç ÷-è øò
2
1 2sin cos2 2
2sin2
x
x x
e dx x
æ ö-ç ÷= ç ÷
ç ÷è ø
ò
2 2
2sin cos1 2 2
2sin 2sin2 2
x
x x
e dx x x
æ öç ÷
= -ç ÷ç ÷è ø
ò
21cosec cot
2 2 2 x x x
e dxæ ö= -ç ÷è øò
21cot cosec
2 2 2 x x x
e dxæ ö= - +ç ÷è øò
Put ( ) cot2
f x = - 2 1( ) cosec
2 2
x f x¢Þ = ×
21( ) cosec
2 2 f x¢Þ =
So ( )( ) ( ) x I e f x f x¢= +ò ( ) xe f x c= +
cot2
x xe c
æ ö= - +ç ÷è ø
cot2
x xe c= - + .
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