Equilibria involving acids and bases
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Transcript of Equilibria involving acids and bases
CHAPTER 17
Equilibria involving acids and bases
Acidity of Solutions
Lowry-Brønsted theory Acids are proton donors Bases are proton acceptors.
An acid base reaction involves the transfer of a proton from an acid to a base.
Some substances can both donate and accept protons, these are amphiprotic solutions.
The ionisation constant of water
Water will react with itself in a process called self-ionisation:H2O(l) + H2O(l) H3O+(aq) + OH-(aq)
Write the equilibrium constant for this reaction.
The concentration of water is usually fairly constant so we can write the equilibrium law the ionisation of water as:
Kw = [H3O+][OH-]
Where Kw is the ionisation of water
The ionisation constant of water
This law applies to both pure water and all aqueous solutions.
In pure water at 25°C, chemists have found that the concentration of both H3O+ and OH- ions is 10-7M.
The value of Kw at 25°C can be calculated:
Kw = [H3O+][OH-] = 10-7 x 10-7 = 1.0 x 10-14 M2
Acidic and Basic Solutions
In acidic solutions the concentration of H3O+ ions will be greater than 10-7 M at 25°C.
The opposite is true for basic solutions.In summary at 25°C:
In pure water and neutral solutions: [H3O+] = [OH-] = 10-
7 M In acidic solutions: [H3O+] > 10-7 M and [OH-] < 10-7 M
In basic solutions: [H3O+] < 10-7 M and [OH-] > 10-7 M
The higher the concentration of hydronium ions in a solution the more acid the solutions is.
pH
pH = -log10[H3O+]
[H3O+] = 10-pH
Remember for basic solutions we are given the OH- concentration
Can anyone remember how we can convert this to a H3O+
concentration?Lets look at the worked
examples on page 287
How is pH affected by temperature?
Remember:Kw = [H3O+][OH-] = 10-7 x 10-7 = 1.0 x 10-14 M2 at 25°CBut what happens if the temperature is not 25°CIonisation of water is endothermicSo:
As the temperature increases the equilibrium constant increases
This causes Kw to rise which results in a decrease in pH
If the temperature decreases it favours a reverse reaction which is exothermic Kw will decrease and the pH will increase
Your Turn
Page 288Questions 1 - 3
Acidity Constants
For the reactionHCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)The expression for the equilibrium constant can be
written as:
Water is the solvent in aqueous solutions and its concentration is virtually constant.
So we can remove water from the equilibrium constant and call it Ka instead
K =[H3O+][Cl-][HCl][H2O]
Acidity Constant
Ka is the acidity constant.
The value of Ka for HCl is 107 M at 25°C.This means that in HCl solutions, most of the
HCl has been converted to product.This is why HCl is classified as a strong acid.
Ka =[H3O+][Cl-]
[HCl]
Acidity Constants
These ideas can be generalised to solutions of any weak acid represented by HA:
HA(aq) + H2O(l) A-(aq) + H3O+(aq)
[H3O+] = [A-] and [HA] does not change during the ionisation
Calculations Involving Acidity Constants
Calculate the pH and percentage hydrolysis of a 0.50 M ethanoic acid solution, given that the Ka for ethanoic acid is 1.75 x 10-5 M
Your Turn
Page 292Question 4 and 5
Buffers: Using equilibrium to resist change
Buffers are solutions that can absorb the addition of acids or bases with little change of pH.
They can be made most easily by mixing a weak acid and a salt of its conjugate base.
Buffers are especially important in environmental and living systems where they maintain a delicate chemical balances essential to life.
Consider the equation for ethanoic acid in water as a buffer. What happens to the equilibrium when you add a strong
acid or a strong base???
pH in the body
A number of reactions that occur in the body involve acid-base reactions.
Without a means of controlling acidity the pH of body fluids could fluctuate from extremely basic to extremely acid.
Our bodily systems can only operate in a small range.
Turn to page 292 for an example.
Your Turn
Page 292Question 6End of Chapter questions are due